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SECTION 6-4
Rectangles
ESSENTIAL QUESTIONS
How do you recognize and apply properties of rectangles?
How do you determine if parallelograms are rectangles?
RECTANGLE
RECTANGLE
A parallelogram with four right angles.
RECTANGLE
A parallelogram with four right angles.
Four right angles
RECTANGLE
A parallelogram with four right angles.
Four right angles
Opposite sides are parallel and congruent
RECTANGLE
A parallelogram with four right angles.
Four right angles
Opposite sides are parallel and congruent
Opposite angles are congruent
RECTANGLE
A parallelogram with four right angles.
Four right angles
Opposite sides are parallel and congruent
Opposite angles are congruent
Consecutive angles are supplementary
RECTANGLE
A parallelogram with four right angles.
Four right angles
Opposite sides are parallel and congruent
Opposite angles are congruent
Consecutive angles are supplementary
Diagonals bisect each other
THEOREMS
6.13 - Diagonals of a Rectangle:
6.14 - Diagonals of a Rectangle Converse:
THEOREMS
6.13 - Diagonals of a Rectangle: If a parallelogram is a
rectangle, then its diagonals are congruent
6.14 - Diagonals of a Rectangle Converse:
THEOREMS
6.13 - Diagonals of a Rectangle: If a parallelogram is a
rectangle, then its diagonals are congruent
6.14 - Diagonals of a Rectangle Converse: If diagonals of a
parallelogram are congruent, then the parallelogram is a
rectangle
EXAMPLE 1
A rectangular garden gate is reinforced with diagonal
braces to prevent it from sagging. If JK = 12 feet and
LN = 6.5 feet, find KM.
EXAMPLE 1
A rectangular garden gate is reinforced with diagonal
braces to prevent it from sagging. If JK = 12 feet and
LN = 6.5 feet, find KM.
Since we have a rectangle, the
diagonals are congruent.
EXAMPLE 1
A rectangular garden gate is reinforced with diagonal
braces to prevent it from sagging. If JK = 12 feet and
LN = 6.5 feet, find KM.
Since we have a rectangle, the
diagonals are congruent.
The diagonals also bisect each other,
so JN = LN and KN = MN.
EXAMPLE 1
A rectangular garden gate is reinforced with diagonal
braces to prevent it from sagging. If JK = 12 feet and
LN = 6.5 feet, find KM.
Since we have a rectangle, the
diagonals are congruent.
The diagonals also bisect each other,
so JN = LN and KN = MN.
So JN = LN = KN = MN = 6.5 feet and KM = KN + MN.
EXAMPLE 1
A rectangular garden gate is reinforced with diagonal
braces to prevent it from sagging. If JK = 12 feet and
LN = 6.5 feet, find KM.
Since we have a rectangle, the
diagonals are congruent.
The diagonals also bisect each other,
so JN = LN and KN = MN.
So JN = LN = KN = MN = 6.5 feet and KM = KN + MN.
KM = 13 feet
EXAMPLE 2
Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)°
and m∠SUR = (3x βˆ’ 2)Β°, find x.
EXAMPLE 2
Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)°
and m∠SUR = (3x βˆ’ 2)Β°, find x.
m∠RTU + m∠SUR = 90
EXAMPLE 2
Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)°
and m∠SUR = (3x βˆ’ 2)Β°, find x.
m∠RTU + m∠SUR = 90
8x + 4 + 3x βˆ’ 2 = 90
EXAMPLE 2
Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)°
and m∠SUR = (3x βˆ’ 2)Β°, find x.
m∠RTU + m∠SUR = 90
8x + 4 + 3x βˆ’ 2 = 90
11x + 2 = 90
EXAMPLE 2
Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)°
and m∠SUR = (3x βˆ’ 2)Β°, find x.
m∠RTU + m∠SUR = 90
8x + 4 + 3x βˆ’ 2 = 90
11x + 2 = 90
βˆ’2 βˆ’2
EXAMPLE 2
Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)°
and m∠SUR = (3x βˆ’ 2)Β°, find x.
m∠RTU + m∠SUR = 90
8x + 4 + 3x βˆ’ 2 = 90
11x + 2 = 90
βˆ’2 βˆ’2
11x = 88
EXAMPLE 2
Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)°
and m∠SUR = (3x βˆ’ 2)Β°, find x.
m∠RTU + m∠SUR = 90
8x + 4 + 3x βˆ’ 2 = 90
11x + 2 = 90
βˆ’2 βˆ’2
11x = 88
11 11
EXAMPLE 2
Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)°
and m∠SUR = (3x βˆ’ 2)Β°, find x.
m∠RTU + m∠SUR = 90
8x + 4 + 3x βˆ’ 2 = 90
11x + 2 = 90
βˆ’2 βˆ’2
11x = 88
11 11
x = 8
EXAMPLE 3
Some artists stretch their own canvas over wooden
frames. This allows them to customize the size of a
canvas. In order to ensure that the frame is rectangular
before stretching the canvas, an artist measures the sides
of the diagonals of the frame. If AB = 12 inches, BC = 35
inches, CD = 12 inches, and DA = 35 inches, how long do
the lengths of the diagonals need to be?
EXAMPLE 3
Some artists stretch their own canvas over wooden
frames. This allows them to customize the size of a
canvas. In order to ensure that the frame is rectangular
before stretching the canvas, an artist measures the sides
of the diagonals of the frame. If AB = 12 inches, BC = 35
inches, CD = 12 inches, and DA = 35 inches, how long do
the lengths of the diagonals need to be?
The diagonal forms a right triangle
with legs of 12 and 35. We need to find
the hypotenuse.
EXAMPLE 3
EXAMPLE 3
a2
+ b2
= c2
EXAMPLE 3
a2
+ b2
= c2
122
+ 352
= c2
EXAMPLE 3
a2
+ b2
= c2
122
+ 352
= c2
144 +1225 = c2
EXAMPLE 3
a2
+ b2
= c2
122
+ 352
= c2
144 +1225 = c2
1369 = c2
EXAMPLE 3
a2
+ b2
= c2
122
+ 352
= c2
144 +1225 = c2
1369 = c2
1369 = c2
EXAMPLE 3
a2
+ b2
= c2
122
+ 352
= c2
144 +1225 = c2
1369 = c2
1369 = c2
c = 37
EXAMPLE 3
a2
+ b2
= c2
122
+ 352
= c2
144 +1225 = c2
1369 = c2
1369 = c2
c = 37
The diagonals must both be 37 inches
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
Diagonals must be congruent
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
Diagonals must be congruent
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
Diagonals must be congruent
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25
Diagonals must be congruent
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
Diagonals must be congruent
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
Diagonals must be congruent
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
Diagonals must be congruent
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
= 1+ 49
Diagonals must be congruent
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
= 1+ 49 = 50
Diagonals must be congruent
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
= 1+ 49 = 50
Diagonals must be congruent
Opposite sides parallel, consecutive sides perpendicular
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
= 1+ 49 = 50
m( JK) =
4 βˆ’ 3
1+ 2
Diagonals must be congruent
Opposite sides parallel, consecutive sides perpendicular
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
= 1+ 49 = 50
m( JK) =
4 βˆ’ 3
1+ 2
=
1
3
Diagonals must be congruent
Opposite sides parallel, consecutive sides perpendicular
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
= 1+ 49 = 50
m( JK) =
4 βˆ’ 3
1+ 2
=
1
3
m(LM) =
βˆ’3+ 2
0βˆ’ 3
Diagonals must be congruent
Opposite sides parallel, consecutive sides perpendicular
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
= 1+ 49 = 50
m( JK) =
4 βˆ’ 3
1+ 2
=
1
3
m(LM) =
βˆ’3+ 2
0βˆ’ 3
=
βˆ’1
βˆ’3
Diagonals must be congruent
Opposite sides parallel, consecutive sides perpendicular
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
= 1+ 49 = 50
m( JK) =
4 βˆ’ 3
1+ 2
=
1
3
m(LM) =
βˆ’3+ 2
0βˆ’ 3
=
βˆ’1
βˆ’3
=
1
3
Diagonals must be congruent
Opposite sides parallel, consecutive sides perpendicular
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
= 1+ 49 = 50
m( JK) =
4 βˆ’ 3
1+ 2
=
1
3
m(LM) =
βˆ’3+ 2
0βˆ’ 3
=
βˆ’1
βˆ’3
=
1
3
m(KL) =
βˆ’2 βˆ’ 4
3βˆ’1
Diagonals must be congruent
Opposite sides parallel, consecutive sides perpendicular
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
= 1+ 49 = 50
m( JK) =
4 βˆ’ 3
1+ 2
=
1
3
m(LM) =
βˆ’3+ 2
0βˆ’ 3
=
βˆ’1
βˆ’3
=
1
3
m(KL) =
βˆ’2 βˆ’ 4
3βˆ’1
=
βˆ’6
2
Diagonals must be congruent
Opposite sides parallel, consecutive sides perpendicular
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
= 1+ 49 = 50
m( JK) =
4 βˆ’ 3
1+ 2
=
1
3
m(LM) =
βˆ’3+ 2
0βˆ’ 3
=
βˆ’1
βˆ’3
=
1
3
m(KL) =
βˆ’2 βˆ’ 4
3βˆ’1
=
βˆ’6
2
= βˆ’3
Diagonals must be congruent
Opposite sides parallel, consecutive sides perpendicular
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
= 1+ 49 = 50
m( JK) =
4 βˆ’ 3
1+ 2
=
1
3
m(LM) =
βˆ’3+ 2
0βˆ’ 3
=
βˆ’1
βˆ’3
=
1
3
m(KL) =
βˆ’2 βˆ’ 4
3βˆ’1
=
βˆ’6
2
m( JM) =
βˆ’3βˆ’ 3
0+ 2
= βˆ’3
Diagonals must be congruent
Opposite sides parallel, consecutive sides perpendicular
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
= 1+ 49 = 50
m( JK) =
4 βˆ’ 3
1+ 2
=
1
3
m(LM) =
βˆ’3+ 2
0βˆ’ 3
=
βˆ’1
βˆ’3
=
1
3
m(KL) =
βˆ’2 βˆ’ 4
3βˆ’1
=
βˆ’6
2
m( JM) =
βˆ’3βˆ’ 3
0+ 2
=
βˆ’6
2
= βˆ’3
Diagonals must be congruent
Opposite sides parallel, consecutive sides perpendicular
EXAMPLE 4
Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2),
and M(0, βˆ’3). Determine whether JKLM is a rectangle by
using the distance formula, then slope.
JL = (βˆ’2 βˆ’ 3)2
+ (3+ 2)2
= (βˆ’5)2
+ 52
= 25 + 25 = 50
KM = (1βˆ’0)2
+ (4 + 3)2
= 12
+ 72
= 1+ 49 = 50
m( JK) =
4 βˆ’ 3
1+ 2
=
1
3
m(LM) =
βˆ’3+ 2
0βˆ’ 3
=
βˆ’1
βˆ’3
=
1
3
m(KL) =
βˆ’2 βˆ’ 4
3βˆ’1
=
βˆ’6
2
m( JM) =
βˆ’3βˆ’ 3
0+ 2
=
βˆ’6
2
= βˆ’3
= βˆ’3
Diagonals must be congruent
Opposite sides parallel, consecutive sides perpendicular

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Geometry Section 6-4

  • 2. ESSENTIAL QUESTIONS How do you recognize and apply properties of rectangles? How do you determine if parallelograms are rectangles?
  • 4. RECTANGLE A parallelogram with four right angles.
  • 5. RECTANGLE A parallelogram with four right angles. Four right angles
  • 6. RECTANGLE A parallelogram with four right angles. Four right angles Opposite sides are parallel and congruent
  • 7. RECTANGLE A parallelogram with four right angles. Four right angles Opposite sides are parallel and congruent Opposite angles are congruent
  • 8. RECTANGLE A parallelogram with four right angles. Four right angles Opposite sides are parallel and congruent Opposite angles are congruent Consecutive angles are supplementary
  • 9. RECTANGLE A parallelogram with four right angles. Four right angles Opposite sides are parallel and congruent Opposite angles are congruent Consecutive angles are supplementary Diagonals bisect each other
  • 10. THEOREMS 6.13 - Diagonals of a Rectangle: 6.14 - Diagonals of a Rectangle Converse:
  • 11. THEOREMS 6.13 - Diagonals of a Rectangle: If a parallelogram is a rectangle, then its diagonals are congruent 6.14 - Diagonals of a Rectangle Converse:
  • 12. THEOREMS 6.13 - Diagonals of a Rectangle: If a parallelogram is a rectangle, then its diagonals are congruent 6.14 - Diagonals of a Rectangle Converse: If diagonals of a parallelogram are congruent, then the parallelogram is a rectangle
  • 13. EXAMPLE 1 A rectangular garden gate is reinforced with diagonal braces to prevent it from sagging. If JK = 12 feet and LN = 6.5 feet, find KM.
  • 14. EXAMPLE 1 A rectangular garden gate is reinforced with diagonal braces to prevent it from sagging. If JK = 12 feet and LN = 6.5 feet, find KM. Since we have a rectangle, the diagonals are congruent.
  • 15. EXAMPLE 1 A rectangular garden gate is reinforced with diagonal braces to prevent it from sagging. If JK = 12 feet and LN = 6.5 feet, find KM. Since we have a rectangle, the diagonals are congruent. The diagonals also bisect each other, so JN = LN and KN = MN.
  • 16. EXAMPLE 1 A rectangular garden gate is reinforced with diagonal braces to prevent it from sagging. If JK = 12 feet and LN = 6.5 feet, find KM. Since we have a rectangle, the diagonals are congruent. The diagonals also bisect each other, so JN = LN and KN = MN. So JN = LN = KN = MN = 6.5 feet and KM = KN + MN.
  • 17. EXAMPLE 1 A rectangular garden gate is reinforced with diagonal braces to prevent it from sagging. If JK = 12 feet and LN = 6.5 feet, find KM. Since we have a rectangle, the diagonals are congruent. The diagonals also bisect each other, so JN = LN and KN = MN. So JN = LN = KN = MN = 6.5 feet and KM = KN + MN. KM = 13 feet
  • 18. EXAMPLE 2 Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)Β° and m∠SUR = (3x βˆ’ 2)Β°, find x.
  • 19. EXAMPLE 2 Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)Β° and m∠SUR = (3x βˆ’ 2)Β°, find x. m∠RTU + m∠SUR = 90
  • 20. EXAMPLE 2 Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)Β° and m∠SUR = (3x βˆ’ 2)Β°, find x. m∠RTU + m∠SUR = 90 8x + 4 + 3x βˆ’ 2 = 90
  • 21. EXAMPLE 2 Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)Β° and m∠SUR = (3x βˆ’ 2)Β°, find x. m∠RTU + m∠SUR = 90 8x + 4 + 3x βˆ’ 2 = 90 11x + 2 = 90
  • 22. EXAMPLE 2 Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)Β° and m∠SUR = (3x βˆ’ 2)Β°, find x. m∠RTU + m∠SUR = 90 8x + 4 + 3x βˆ’ 2 = 90 11x + 2 = 90 βˆ’2 βˆ’2
  • 23. EXAMPLE 2 Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)Β° and m∠SUR = (3x βˆ’ 2)Β°, find x. m∠RTU + m∠SUR = 90 8x + 4 + 3x βˆ’ 2 = 90 11x + 2 = 90 βˆ’2 βˆ’2 11x = 88
  • 24. EXAMPLE 2 Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)Β° and m∠SUR = (3x βˆ’ 2)Β°, find x. m∠RTU + m∠SUR = 90 8x + 4 + 3x βˆ’ 2 = 90 11x + 2 = 90 βˆ’2 βˆ’2 11x = 88 11 11
  • 25. EXAMPLE 2 Quadrilateral RSTU is a rectangle. If m∠RTU = (8x + 4)Β° and m∠SUR = (3x βˆ’ 2)Β°, find x. m∠RTU + m∠SUR = 90 8x + 4 + 3x βˆ’ 2 = 90 11x + 2 = 90 βˆ’2 βˆ’2 11x = 88 11 11 x = 8
  • 26. EXAMPLE 3 Some artists stretch their own canvas over wooden frames. This allows them to customize the size of a canvas. In order to ensure that the frame is rectangular before stretching the canvas, an artist measures the sides of the diagonals of the frame. If AB = 12 inches, BC = 35 inches, CD = 12 inches, and DA = 35 inches, how long do the lengths of the diagonals need to be?
  • 27. EXAMPLE 3 Some artists stretch their own canvas over wooden frames. This allows them to customize the size of a canvas. In order to ensure that the frame is rectangular before stretching the canvas, an artist measures the sides of the diagonals of the frame. If AB = 12 inches, BC = 35 inches, CD = 12 inches, and DA = 35 inches, how long do the lengths of the diagonals need to be? The diagonal forms a right triangle with legs of 12 and 35. We need to find the hypotenuse.
  • 30. EXAMPLE 3 a2 + b2 = c2 122 + 352 = c2
  • 31. EXAMPLE 3 a2 + b2 = c2 122 + 352 = c2 144 +1225 = c2
  • 32. EXAMPLE 3 a2 + b2 = c2 122 + 352 = c2 144 +1225 = c2 1369 = c2
  • 33. EXAMPLE 3 a2 + b2 = c2 122 + 352 = c2 144 +1225 = c2 1369 = c2 1369 = c2
  • 34. EXAMPLE 3 a2 + b2 = c2 122 + 352 = c2 144 +1225 = c2 1369 = c2 1369 = c2 c = 37
  • 35. EXAMPLE 3 a2 + b2 = c2 122 + 352 = c2 144 +1225 = c2 1369 = c2 1369 = c2 c = 37 The diagonals must both be 37 inches
  • 36. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope.
  • 37. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. Diagonals must be congruent
  • 38. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 Diagonals must be congruent
  • 39. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 Diagonals must be congruent
  • 40. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 Diagonals must be congruent
  • 41. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 Diagonals must be congruent
  • 42. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 Diagonals must be congruent
  • 43. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 Diagonals must be congruent
  • 44. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 = 1+ 49 Diagonals must be congruent
  • 45. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 = 1+ 49 = 50 Diagonals must be congruent
  • 46. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 = 1+ 49 = 50 Diagonals must be congruent Opposite sides parallel, consecutive sides perpendicular
  • 47. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 = 1+ 49 = 50 m( JK) = 4 βˆ’ 3 1+ 2 Diagonals must be congruent Opposite sides parallel, consecutive sides perpendicular
  • 48. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 = 1+ 49 = 50 m( JK) = 4 βˆ’ 3 1+ 2 = 1 3 Diagonals must be congruent Opposite sides parallel, consecutive sides perpendicular
  • 49. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 = 1+ 49 = 50 m( JK) = 4 βˆ’ 3 1+ 2 = 1 3 m(LM) = βˆ’3+ 2 0βˆ’ 3 Diagonals must be congruent Opposite sides parallel, consecutive sides perpendicular
  • 50. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 = 1+ 49 = 50 m( JK) = 4 βˆ’ 3 1+ 2 = 1 3 m(LM) = βˆ’3+ 2 0βˆ’ 3 = βˆ’1 βˆ’3 Diagonals must be congruent Opposite sides parallel, consecutive sides perpendicular
  • 51. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 = 1+ 49 = 50 m( JK) = 4 βˆ’ 3 1+ 2 = 1 3 m(LM) = βˆ’3+ 2 0βˆ’ 3 = βˆ’1 βˆ’3 = 1 3 Diagonals must be congruent Opposite sides parallel, consecutive sides perpendicular
  • 52. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 = 1+ 49 = 50 m( JK) = 4 βˆ’ 3 1+ 2 = 1 3 m(LM) = βˆ’3+ 2 0βˆ’ 3 = βˆ’1 βˆ’3 = 1 3 m(KL) = βˆ’2 βˆ’ 4 3βˆ’1 Diagonals must be congruent Opposite sides parallel, consecutive sides perpendicular
  • 53. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 = 1+ 49 = 50 m( JK) = 4 βˆ’ 3 1+ 2 = 1 3 m(LM) = βˆ’3+ 2 0βˆ’ 3 = βˆ’1 βˆ’3 = 1 3 m(KL) = βˆ’2 βˆ’ 4 3βˆ’1 = βˆ’6 2 Diagonals must be congruent Opposite sides parallel, consecutive sides perpendicular
  • 54. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 = 1+ 49 = 50 m( JK) = 4 βˆ’ 3 1+ 2 = 1 3 m(LM) = βˆ’3+ 2 0βˆ’ 3 = βˆ’1 βˆ’3 = 1 3 m(KL) = βˆ’2 βˆ’ 4 3βˆ’1 = βˆ’6 2 = βˆ’3 Diagonals must be congruent Opposite sides parallel, consecutive sides perpendicular
  • 55. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 = 1+ 49 = 50 m( JK) = 4 βˆ’ 3 1+ 2 = 1 3 m(LM) = βˆ’3+ 2 0βˆ’ 3 = βˆ’1 βˆ’3 = 1 3 m(KL) = βˆ’2 βˆ’ 4 3βˆ’1 = βˆ’6 2 m( JM) = βˆ’3βˆ’ 3 0+ 2 = βˆ’3 Diagonals must be congruent Opposite sides parallel, consecutive sides perpendicular
  • 56. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 = 1+ 49 = 50 m( JK) = 4 βˆ’ 3 1+ 2 = 1 3 m(LM) = βˆ’3+ 2 0βˆ’ 3 = βˆ’1 βˆ’3 = 1 3 m(KL) = βˆ’2 βˆ’ 4 3βˆ’1 = βˆ’6 2 m( JM) = βˆ’3βˆ’ 3 0+ 2 = βˆ’6 2 = βˆ’3 Diagonals must be congruent Opposite sides parallel, consecutive sides perpendicular
  • 57. EXAMPLE 4 Quadrilateral JKLM has vertices J(βˆ’2, 3), K(1, 4), L(3, βˆ’2), and M(0, βˆ’3). Determine whether JKLM is a rectangle by using the distance formula, then slope. JL = (βˆ’2 βˆ’ 3)2 + (3+ 2)2 = (βˆ’5)2 + 52 = 25 + 25 = 50 KM = (1βˆ’0)2 + (4 + 3)2 = 12 + 72 = 1+ 49 = 50 m( JK) = 4 βˆ’ 3 1+ 2 = 1 3 m(LM) = βˆ’3+ 2 0βˆ’ 3 = βˆ’1 βˆ’3 = 1 3 m(KL) = βˆ’2 βˆ’ 4 3βˆ’1 = βˆ’6 2 m( JM) = βˆ’3βˆ’ 3 0+ 2 = βˆ’6 2 = βˆ’3 = βˆ’3 Diagonals must be congruent Opposite sides parallel, consecutive sides perpendicular