Abstract
Paper hypothesis
- The moon has 2 orbits for its motion
- The second orbit is declined by 0.8 degrees on the 1st orbit (the moon orbital triangle)
- The 2 orbits are neighbor and define together the lunar eclipse umbra length (1.392 mkm)
- Venus axial tilt is an effective player in the moon orbital triangle structure
Paper argument
- The paper analyze the moon motion data to conclude this 2nd moon orbit place and direction.
Gerges Francis Tawdrous +201022532292
The Moon Uses Pythagoras Triangle Technique In Its Orbital Motion (Part No. 2)Gerges francis
Abstract
Paper Claim:
- The moon uses the equation (θ1= θ0 + 1.7 degrees) in its orbital motion, because of that, this equation should be considered a useful tool to define the moon position through its orbital motion.
The Claim Explanation:
- The equation depends the conclusion (The moon uses Pythagoras triangle in its orbital motion to decrease its daily displacement (88000 km) by creating an angle (θ) between its motion direction and the orbit horizontal level, which creates a real displacement through the orbit (L =88000 Cos θ), that enables the moon to move through more near orbits around the Earth, because the moon daily displacement (88000 km) if be used as a real displacement daily will cause the moon to move through apogee orbit only (r=0.406 mkm).
Paper Question:
- Why the Equation uses the angle (1.7 degrees)? The moon axial tilt declines on the Earth ecliptic line with 1.6 degrees which can be more consistent to be used in the equation, BUT the equation uses 1.7 degree! It's a questionable using which necessitates an answer.
- The paper tries to answer this question
Gerges Francis Tawdrous +201022532292
Uranus Is Perpendicular On Earth Moon Orbit (IV) Gerges francis
Paper hypothesis
The moon motion has 2 orbit which are found in perpendicularity on one another
Paper Idea
- As we have explained in the moon orbital triangle, Uranus axial tilt creates an angle 90.6 degrees above the moon diameter (under the green rectangle)
- But, Uranus orbital inclination =0.8 degrees, so the vertical value of it will be =90 degrees +0.8 degrees = 90.8 degrees – this value is so near to the previous one which is (90.6 degrees) and I try to discover if they can be the same value!
- We know that, the moon angular diameter consumes 0.5 degrees from the original angle between Uranus axial tilt (97.8 degrees) and the moon axial tilt (6.7 degrees) which =91.1 degrees and by consuming (0.5 degrees) the rest is (90.6 degrees) and now we want to make this value = 90.8 degrees! How?
- The moon diameter (3475 km) consumes (0.5 degrees), so what smaller diameter of the moon can consume only (0.2 degrees) to left the rest (90.8 degrees)?!
- (3475 km /5) x2 = 1390 km
Gerges Francis Tawdrous +201022532292
This document presents a hypothesis about Uranus' effects on the moon's orbital motion at its perigee point. It claims that Uranus helps create the perigee radius and works to keep the moon at this point, in order to align its axial tilt with the moon's. The document provides data and equations analyzing triangles involving distances between celestial bodies to show relationships between their orbital periods, diameters, and other properties, suggesting they influence each other. It aims to show Uranus has a direct effect on defining features of the moon's orbit through these geometric relationships.
This document analyzes the "Moon Orbital Triangle" in an attempt to better understand the moon's motion. It provides details of the triangle, including defining the distances between points and calculating angles. The analysis explores how Pythagorean theorem relates to the moon's daily displacement and orbital inclination. It is suggested that interactions between Venus and Mars affect the moon's regression and create differences in the rate of time, concentrating planetary motion energies into sunlight. References are provided for further related research.
Is There another Orbit For The Moon Motion? Gerges francis
Paper Hypothesis No. (1)
-Another Orbit must be found for the moon motion.
Paper Hypothesis No. (2)
-An interaction is found between Jupiter and the Earth moon motions, this interaction shows that another orbit must be found for the moon motion –
Paper Objective
-The paper tries to prove that, there's an interaction between Jupiter and the moon motion.
-And
-Based on this interaction, Jupiter effect on the moon motion suggests that another orbit is required necessary for the moon orbital motion.
Gerges Francis Tawdrous +201022532292
Why The Earth Moon Distance = The Planets Diameters Total (I) Gerges francis
The Earth Moon Motion has 4 basic points which are
Perigee radius (perigee is the nearest point, the moon can reach) =363000 km
Earth Moon Distance when the moon is in total solar eclipse point = 373000 km
The Moon Orbital Distance = 384000 km
Apogee radius (Apogee is the most far point, the moon can reach) = 406000 km
Paper Hypotheses
(1)
The Moon Motion 4 points are defined based on Pythagoras Rule
(2)
Jupiter & Saturn cooperate to build the Earth Moon Orbit
Paper Conclusion
There's A Geometrical Necessity Causes "The Earth Moon Distance = The Planets Diameters Total"
Gerges Francis Tawdrous +201022532292
Can Jupiter effect on the Earth Moon? (III)Gerges francis
Paper hypothesis
The Earth Moon is a unique Planet In The Solar System
i.e.
The Earth Moon practices a great effect on the solar system geometry more than any other moon in the solar group.
Paper Objective
The paper tries to prove that –
The Earth Moon Orbit Is Created By A Force has Geometrical Features can't be produced by The Masses Gravity
Gerges Francis Tawdrous +201022532292
The moon orbital motion geometry (revised) (2)Gerges francis
The document describes a geometric model of the moon's orbital motion called the "Moon Orbital Triangle". It consists of:
1) A base line connecting the Earth and a point on the moon's orbit.
2) A perpendicular line from the Earth to the base line, with a length of 86,000 km.
3) Angles and distances within the triangle that model aspects of the moon's orbit such as its inclination, distance from Earth at perigee and apogee, and motion between those points.
The triangle is used throughout the paper to analyze the moon's orbit and hypothesize explanations for orbital properties like regression and the influence of distant planets.
The Moon Uses Pythagoras Triangle Technique In Its Orbital Motion (Part No. 2)Gerges francis
Abstract
Paper Claim:
- The moon uses the equation (θ1= θ0 + 1.7 degrees) in its orbital motion, because of that, this equation should be considered a useful tool to define the moon position through its orbital motion.
The Claim Explanation:
- The equation depends the conclusion (The moon uses Pythagoras triangle in its orbital motion to decrease its daily displacement (88000 km) by creating an angle (θ) between its motion direction and the orbit horizontal level, which creates a real displacement through the orbit (L =88000 Cos θ), that enables the moon to move through more near orbits around the Earth, because the moon daily displacement (88000 km) if be used as a real displacement daily will cause the moon to move through apogee orbit only (r=0.406 mkm).
Paper Question:
- Why the Equation uses the angle (1.7 degrees)? The moon axial tilt declines on the Earth ecliptic line with 1.6 degrees which can be more consistent to be used in the equation, BUT the equation uses 1.7 degree! It's a questionable using which necessitates an answer.
- The paper tries to answer this question
Gerges Francis Tawdrous +201022532292
Uranus Is Perpendicular On Earth Moon Orbit (IV) Gerges francis
Paper hypothesis
The moon motion has 2 orbit which are found in perpendicularity on one another
Paper Idea
- As we have explained in the moon orbital triangle, Uranus axial tilt creates an angle 90.6 degrees above the moon diameter (under the green rectangle)
- But, Uranus orbital inclination =0.8 degrees, so the vertical value of it will be =90 degrees +0.8 degrees = 90.8 degrees – this value is so near to the previous one which is (90.6 degrees) and I try to discover if they can be the same value!
- We know that, the moon angular diameter consumes 0.5 degrees from the original angle between Uranus axial tilt (97.8 degrees) and the moon axial tilt (6.7 degrees) which =91.1 degrees and by consuming (0.5 degrees) the rest is (90.6 degrees) and now we want to make this value = 90.8 degrees! How?
- The moon diameter (3475 km) consumes (0.5 degrees), so what smaller diameter of the moon can consume only (0.2 degrees) to left the rest (90.8 degrees)?!
- (3475 km /5) x2 = 1390 km
Gerges Francis Tawdrous +201022532292
This document presents a hypothesis about Uranus' effects on the moon's orbital motion at its perigee point. It claims that Uranus helps create the perigee radius and works to keep the moon at this point, in order to align its axial tilt with the moon's. The document provides data and equations analyzing triangles involving distances between celestial bodies to show relationships between their orbital periods, diameters, and other properties, suggesting they influence each other. It aims to show Uranus has a direct effect on defining features of the moon's orbit through these geometric relationships.
This document analyzes the "Moon Orbital Triangle" in an attempt to better understand the moon's motion. It provides details of the triangle, including defining the distances between points and calculating angles. The analysis explores how Pythagorean theorem relates to the moon's daily displacement and orbital inclination. It is suggested that interactions between Venus and Mars affect the moon's regression and create differences in the rate of time, concentrating planetary motion energies into sunlight. References are provided for further related research.
Is There another Orbit For The Moon Motion? Gerges francis
Paper Hypothesis No. (1)
-Another Orbit must be found for the moon motion.
Paper Hypothesis No. (2)
-An interaction is found between Jupiter and the Earth moon motions, this interaction shows that another orbit must be found for the moon motion –
Paper Objective
-The paper tries to prove that, there's an interaction between Jupiter and the moon motion.
-And
-Based on this interaction, Jupiter effect on the moon motion suggests that another orbit is required necessary for the moon orbital motion.
Gerges Francis Tawdrous +201022532292
Why The Earth Moon Distance = The Planets Diameters Total (I) Gerges francis
The Earth Moon Motion has 4 basic points which are
Perigee radius (perigee is the nearest point, the moon can reach) =363000 km
Earth Moon Distance when the moon is in total solar eclipse point = 373000 km
The Moon Orbital Distance = 384000 km
Apogee radius (Apogee is the most far point, the moon can reach) = 406000 km
Paper Hypotheses
(1)
The Moon Motion 4 points are defined based on Pythagoras Rule
(2)
Jupiter & Saturn cooperate to build the Earth Moon Orbit
Paper Conclusion
There's A Geometrical Necessity Causes "The Earth Moon Distance = The Planets Diameters Total"
Gerges Francis Tawdrous +201022532292
Can Jupiter effect on the Earth Moon? (III)Gerges francis
Paper hypothesis
The Earth Moon is a unique Planet In The Solar System
i.e.
The Earth Moon practices a great effect on the solar system geometry more than any other moon in the solar group.
Paper Objective
The paper tries to prove that –
The Earth Moon Orbit Is Created By A Force has Geometrical Features can't be produced by The Masses Gravity
Gerges Francis Tawdrous +201022532292
The moon orbital motion geometry (revised) (2)Gerges francis
The document describes a geometric model of the moon's orbital motion called the "Moon Orbital Triangle". It consists of:
1) A base line connecting the Earth and a point on the moon's orbit.
2) A perpendicular line from the Earth to the base line, with a length of 86,000 km.
3) Angles and distances within the triangle that model aspects of the moon's orbit such as its inclination, distance from Earth at perigee and apogee, and motion between those points.
The triangle is used throughout the paper to analyze the moon's orbit and hypothesize explanations for orbital properties like regression and the influence of distant planets.
This document provides an overview of structural dynamics and free vibration analysis of single degree of freedom (SDOF) systems. It defines key terms like natural frequency, damping, and logarithmic decrement. Methods are presented for analyzing the free vibration of undamped and damped SDOF systems under initial displacement conditions. Examples are provided to demonstrate calculating the natural frequency, time period, amplitude, and displacement over time of vibrating SDOF structures.
The document discusses the direct stiffness method for analyzing truss structures. This method treats each individual truss element as a structure and develops the element stiffness matrix. Transformation matrices are used to relate element deformations to structure deformations. The total structure stiffness matrix is obtained by assembling the individual element stiffness matrices based on how the elements are connected at joints in the structure. This direct stiffness method forms the basis for computer programs to analyze truss structures.
This document discusses the direct stiffness method for structural analysis. It begins by introducing the direct stiffness method and its key aspects, including using member stiffness matrices to express actions and displacements at both ends of each member. It then provides examples of applying the direct stiffness method to analyze a plane truss member and plane frame member. This involves deriving the member stiffness matrices in local coordinates, and transforming displacement, load, and stiffness matrices between local and global coordinate systems using rotation matrices.
The sun data shows relativistic effects and motions Gerges francis
Abstract
- The Sun Data shows Relativistic Effects.
i.e.
- There's a physical point in the solar group moves with c velocity relative to another physical point in the solar group. and this high velocity causes the relativistic effects which are observed and recorded in this paper
- The Solar Planets Data Analysis shows that, Mars Original Orbital Distance was = 84 million km. but because of the relativistic effects, Mars had to immigrate from his original point to his new point at orbital distance = 227.9 million km.
- This paper provide analyzed data and explanations to prove these 2 facts which are:
1. There's motion with c velocity inside the solar group
2. Mars immigrated from his original point at orbital distance 84 million km to his new orbital distance 227.9 million km
This document discusses approximate analysis methods for multi-storey frames under vertical and lateral loads. It introduces the substitute frame method, portal method, and cantilever method for analyzing frames. An example problem demonstrates using the substitute frame method to analyze a frame for vertical loads, distributing fixed end moments using distribution factors. Homework is assigned to analyze another frame using the cantilever method under given loading conditions.
Why Earth moves Daily A Distance = The Moon Orbit CircumferenceGerges francis
The Moon Orbit Data shows A Geometrical Structure more complex than the Current theories can explain … Let's refer to it in following:
- Perigee Radius (R1) = Earth Moon Distance = 363000 km (Earth Nearest Point)
- Eclipse Radius (R2) = Earth Moon Distance = 377000km (Total Solar Eclipse Point)
- Average Radius (R3) = Earth Moon Distance = 384000 km (Registered Value)
- Apogee Radius (R4) =Earth Moon Distance = 406000km (The Most Far Point)
Earth Daily Motion 2.58 mkm = The Moon Orbit Circumference at apogee (R4)..why?
The Data
I. Earth Moon Distance at Perigee Point = The Outer Planets Diameters Total
II. Earth Moon Distance at Apogee Point = The Solar Planets Diameters Total
III. The Distance Between Perigee & Apogee Points = the inner planets Diameters total = Earth Circumference
IV. Earth Moon Distance (At Total Solar Eclipse Radius) = Saturn Circumference.
V. The Solar Planets Diameters Total = Saturn Diameter +2 Jupiter Diameters
The Moon Orbit Main Points: (Perigee - Solar Eclipse – Average- Apogee)
These points are defined based on the following geometrical rules:
1- (1st Rule) "R2n + (86000km)2= R2n+1" (Pythagoras Rule)
2- (2nd Rule) "2πRn= (1/Rn+1)" (Reflective Values)
3- (3rd Rule) "(2πRn+1/ 2πRn) =1.0725" (Relativities Effects)
(We should prove these rules in this paper)
The Conclusions
1- The Gravity Force Can't Create The Moon Orbit
2- The Space is A Geometrical Player In The Solar Group Geometry
3- There are relativistic effects in the solar Group
4- The Relativistic effects cause geometrical rules control the general geometrical structure (i.e. the higher velocity creates specific form for the space in which it travels)
Module1 1 introduction-tomatrixms - rajesh sirSHAMJITH KM
This document provides an introduction to matrix methods for structural analysis. It discusses key concepts such as flexibility and stiffness matrices, and their application to trusses, beams, and frames. It also covers types of framed structures, static indeterminacy, actions and displacements, equilibrium, compatibility conditions, and the relationships between flexibility, stiffness, actions and displacements. Matrix methods allow the analysis of statically indeterminate structures by transforming them into a set of simultaneous equations that can be solved using computer programs.
Module1 flexibility-2-problems- rajesh sirSHAMJITH KM
This document discusses the flexibility method for analyzing structures. It provides the definitions of flexibility and stiffness influence coefficients and describes how to develop flexibility matrices for truss, beam, and frame elements using the physical and energy approaches. It then shows how to assemble the total flexibility matrix of a structure and use it to analyze simple structures like plane trusses, continuous beams, and plane frames. The document includes an example problem of a two-member structure to illustrate the flexibility method steps, such as determining static indeterminacy, developing member and system flexibility matrices, evaluating joint displacements and member end actions.
This document discusses the stiffness method for structural analysis. It begins by introducing the stiffness method and its key concepts, such as using joint displacements as the primary unknowns and establishing a relationship between member forces and displacements through stiffness matrices. It then provides examples of calculating stiffness matrices for different structural elements, including beams, trusses, frames, grids, and space frames. The document also explains how to develop the total stiffness matrix of a structure by assembling the member stiffness matrices using a displacement transformation matrix. Finally, it formalizes the stiffness method through the governing equations relating member forces, displacements, and loads.
This document discusses the flexibility method for structural analysis. The flexibility method involves determining flexibility coefficients by applying unit loads corresponding to redundant forces and calculating the resulting displacements. These flexibility coefficients are then used to calculate the redundant forces needed to satisfy compatibility conditions. The flexibility matrices for different structural elements are developed. Joint displacements, member end actions, and support reactions can be determined by incorporating the flexibility coefficients into the basic computations. Examples are provided to illustrate the flexibility method for a continuous beam with one redundant and for determining various outputs like redundants, joint displacements, and reactions.
This document provides an overview of mechanics of solids (or strength of materials) including definitions of key terms like stress, strain, elasticity and their relationships. It discusses stress analysis for axially loaded members and introduces various stress conditions in 2D and 3D spaces. Stress is defined as internal resistance against deformation while strain is a measure of deformation. Different material types like isotropic, orthotropic and their elastic relationships are also covered.
This document provides an introduction to structural dynamics. It discusses single degree-of-freedom systems and their fundamental equation of motion. Key topics covered include free vibration of undamped and damped structures, forced response of SDOF systems, and the effects of damping. An example of a mass-spring system is used to illustrate concepts such as natural frequency, period of oscillation, and the effects of loading rate. The importance of considering structural dynamics in design is highlighted through case studies.
In light of the most recent Winter Olympic Games, mathematical modeling problems involving algebra, geometry, trigonometry & calculus are presented via dynamic geometry software in the context of pairs figure skating. An aesthetically pleasing & athletically demanding pairs figure skating element, the death spiral, is discussed. Activities related to the pairs death spiral which are suitable for middle & high school students are provided in this workshop. Teachers’ work on these problems are analyzed & discussed.
This document discusses mechanics of solids, specifically torsion and bending moment. It begins with an overview and objectives of Module II which covers torsion of circular elastic and inelastic bars, as well as axial force, shear force, and bending moment diagrams. It then provides explanations, equations, and examples relating to torsion, including assumptions in torsion theory, the torsion equation, torsional rigidity, power transmission in torsion, and example problems calculating torque and shaft diameters. It also discusses statically indeterminate shafts and torsion of inelastic circular bars.
This document provides an overview of plastic analysis for structural elements. It discusses key concepts like plastic hinges, plastic section modulus, shape factors, and load factors. Plastic analysis is used to determine the ultimate or collapse load of a structure by considering the redistribution of moments that occurs after sections yield. Common failure mechanisms for determinate and indeterminate beams involve the formation of one or more plastic hinges. Methods for plastic analysis include the static/equilibrium method and kinematic/mechanism method. Examples are given for calculating the collapse load of simple structural configurations using these methods.
We continue to summarize the main questions in my papers
The current paper deals with the papers questions starting from Paper No. 138 (Matter Creation Principle (Part V) to paper No. 99 (How the solar group is created?) (Discussion No.1)
Gerges Francis Tawdrous +201022532292
This document analyzes an indeterminate truss using the flexibility method. It first calculates the static degree of indeterminacy as 2. It then selects members OA and OD as redundant members. The truss is analyzed when each redundant member is given a force of 1 kN. A flexibility matrix equation is developed and solved to determine the redundant forces, which are then used to calculate the final forces in each member. The final forces show member OA in tension and member OD in compression.
The Moon Orbital Triangle (General discussion)(I) (Revised)Gerges francis
Paper Argument
- The Moon motion has 2 Orbits – we see one of them only
- The moon second orbit is declined by 0.8 degrees on the first one.
- The 2 orbits are neighbors and define together the Lunar Eclipse Umbra Length (1.392 mkm)
- Venus axial tilt is changed from 1.774 to 177.4 degrees because of Uranus axial tilt angle (91.1 degrees) with the moon axial tilt (6.7 deg) and because of Uranus axial tilt perpendicularity on the moon orbital triangle base.
- Venus original axial tilt (1.774 deg) is created as a rate between its diameter and Mars diameter – that shows Mars diameter rate effect on the planets motions
-The moon uses Pythagoras rule in its motion to define its daily displacement
Gerges Francis Tawdrous +201022532292
Paper Claim
- Uranus creates a perpendicularity on the moon orbit and creates an angle (91.1 degrees) with the moon axial tilt
- The moon orbit regresses because of Uranus perpendicularity
- Venus motion interacted with the moon motion under Uranus Perpendicularity to create the moon orbit regression
- The moon diameter is created as a function of its orbital distance as a result of Uranus perpendicularity on the moon orbit
Paper Objective
- The paper reviews and correct the moon orbital triangle data
And
- The paper tries to prove its claim
Gerges Francis Tawdrous +201022532292
Paper Hypothesis
-There's Another Similar Orbit For The Moon Motion
The Hypothesis explanation
- The triangle ACE shows that, a double value of the triangle perimeter is used for geometrical necessities in the moon orbital motion
- i.e.
- While the (ACE) triangle perimeter = 943817 km, the geometrical structure of the moon orbit uses the value 1887634 km (= 2 x 943817 km) as one of the basic motion values.
- There's one more reason for this hypothesis, because the moon orbital motion space area contains (50%) of the Jupiter Whole Energy, that tells if the energy is transported to the moon orbit why just (50%) only?
- I suggest that
- Another similar orbit of the moon must be found which we can't see. This idea is supported by our previous argument, where the moon moves daily 2.58 mkm (as Earth) and because of the contraction this value became 2.41 mkm, So the tries to cover this difference (0.17 mkm) by its daily displacement (88000km) which is not enough and the moon needs to move another displacement (88000km) to cover the different distance, where this last displacement (88000km) we can't see, and based on that I suppose the moon must have another similar orbit through which the moon moves this additional displacement (88000km).
- The paper tries to prove this fact
Gerges Francis Tawdrous +201022532292
Uranus Is Perpendicular On Earth Moon Orbit (III) Gerges francis
Paper hypothesis
- Uranus orbital inclination 0.8 degrees is created by an effect of the Earth moon orbital motion.
o Jupiter diameter 142984 km = 13.1 x 10921 km (the moon circumference)
o But
o Jupiter velocity =13.1 km/sec
o And
o Jupiter orbital circumference= Jupiter circumference x the moon circumference
o The data tells interesting ideas!
o Jupiter has to move during 10921 seconds to pass a distance = its diameter, now the moon circumference (10921 km) is used as time period! With some analysis we have found this behavior is followed by many other planets!
o The Earth moon also has to rotate around its axis 13.1 time to move a distance = 142984 km = Jupiter diameter – where the moon rotation period is 27.3 days, the 13.1 time consumes around one year – so it's interesting to rotate for a defined period of time!
o The value (13.1) has still has many interesting forms, for example 13.18 degrees = the moon motion degrees per solar day! Also
o 13.18 degrees = the moon motion degrees per solar day/ 0.526 degrees (Mars motion degrees per solar day) =25.2 (where Mars axial tilt =25.2 deg)
Gerges Francis Tawdrous +201022532292
Uranus Is Perpendicular On Earth Moon Orbit (II) Gerges francis
Paper Claim
-Uranus Axial Tilt created an angle = 91.1 degrees with the Earth Moon Axial Tilt
But
- Uranus Axial Tilt is perpendicular (90 degrees) on the moon orbit, at the radius Perigee Point (r= 0.363 mkm)
- This perpendicularity (90 degrees), Uranus Axial Tilt performed because of using the value (1.1 degrees) to create an angle between the moon orbit horizontal base and the horizontal level…
- The angle (1.1 degrees) effects causes the moon orbit regression (19 degrees) per year
Paper Conclusion
- The moon orbit regression is a result of Uranus Axial Tilt perpendicularity on The moon orbit.
Gerges Francis Tawdrous +201022532292
This document provides an overview of structural dynamics and free vibration analysis of single degree of freedom (SDOF) systems. It defines key terms like natural frequency, damping, and logarithmic decrement. Methods are presented for analyzing the free vibration of undamped and damped SDOF systems under initial displacement conditions. Examples are provided to demonstrate calculating the natural frequency, time period, amplitude, and displacement over time of vibrating SDOF structures.
The document discusses the direct stiffness method for analyzing truss structures. This method treats each individual truss element as a structure and develops the element stiffness matrix. Transformation matrices are used to relate element deformations to structure deformations. The total structure stiffness matrix is obtained by assembling the individual element stiffness matrices based on how the elements are connected at joints in the structure. This direct stiffness method forms the basis for computer programs to analyze truss structures.
This document discusses the direct stiffness method for structural analysis. It begins by introducing the direct stiffness method and its key aspects, including using member stiffness matrices to express actions and displacements at both ends of each member. It then provides examples of applying the direct stiffness method to analyze a plane truss member and plane frame member. This involves deriving the member stiffness matrices in local coordinates, and transforming displacement, load, and stiffness matrices between local and global coordinate systems using rotation matrices.
The sun data shows relativistic effects and motions Gerges francis
Abstract
- The Sun Data shows Relativistic Effects.
i.e.
- There's a physical point in the solar group moves with c velocity relative to another physical point in the solar group. and this high velocity causes the relativistic effects which are observed and recorded in this paper
- The Solar Planets Data Analysis shows that, Mars Original Orbital Distance was = 84 million km. but because of the relativistic effects, Mars had to immigrate from his original point to his new point at orbital distance = 227.9 million km.
- This paper provide analyzed data and explanations to prove these 2 facts which are:
1. There's motion with c velocity inside the solar group
2. Mars immigrated from his original point at orbital distance 84 million km to his new orbital distance 227.9 million km
This document discusses approximate analysis methods for multi-storey frames under vertical and lateral loads. It introduces the substitute frame method, portal method, and cantilever method for analyzing frames. An example problem demonstrates using the substitute frame method to analyze a frame for vertical loads, distributing fixed end moments using distribution factors. Homework is assigned to analyze another frame using the cantilever method under given loading conditions.
Why Earth moves Daily A Distance = The Moon Orbit CircumferenceGerges francis
The Moon Orbit Data shows A Geometrical Structure more complex than the Current theories can explain … Let's refer to it in following:
- Perigee Radius (R1) = Earth Moon Distance = 363000 km (Earth Nearest Point)
- Eclipse Radius (R2) = Earth Moon Distance = 377000km (Total Solar Eclipse Point)
- Average Radius (R3) = Earth Moon Distance = 384000 km (Registered Value)
- Apogee Radius (R4) =Earth Moon Distance = 406000km (The Most Far Point)
Earth Daily Motion 2.58 mkm = The Moon Orbit Circumference at apogee (R4)..why?
The Data
I. Earth Moon Distance at Perigee Point = The Outer Planets Diameters Total
II. Earth Moon Distance at Apogee Point = The Solar Planets Diameters Total
III. The Distance Between Perigee & Apogee Points = the inner planets Diameters total = Earth Circumference
IV. Earth Moon Distance (At Total Solar Eclipse Radius) = Saturn Circumference.
V. The Solar Planets Diameters Total = Saturn Diameter +2 Jupiter Diameters
The Moon Orbit Main Points: (Perigee - Solar Eclipse – Average- Apogee)
These points are defined based on the following geometrical rules:
1- (1st Rule) "R2n + (86000km)2= R2n+1" (Pythagoras Rule)
2- (2nd Rule) "2πRn= (1/Rn+1)" (Reflective Values)
3- (3rd Rule) "(2πRn+1/ 2πRn) =1.0725" (Relativities Effects)
(We should prove these rules in this paper)
The Conclusions
1- The Gravity Force Can't Create The Moon Orbit
2- The Space is A Geometrical Player In The Solar Group Geometry
3- There are relativistic effects in the solar Group
4- The Relativistic effects cause geometrical rules control the general geometrical structure (i.e. the higher velocity creates specific form for the space in which it travels)
Module1 1 introduction-tomatrixms - rajesh sirSHAMJITH KM
This document provides an introduction to matrix methods for structural analysis. It discusses key concepts such as flexibility and stiffness matrices, and their application to trusses, beams, and frames. It also covers types of framed structures, static indeterminacy, actions and displacements, equilibrium, compatibility conditions, and the relationships between flexibility, stiffness, actions and displacements. Matrix methods allow the analysis of statically indeterminate structures by transforming them into a set of simultaneous equations that can be solved using computer programs.
Module1 flexibility-2-problems- rajesh sirSHAMJITH KM
This document discusses the flexibility method for analyzing structures. It provides the definitions of flexibility and stiffness influence coefficients and describes how to develop flexibility matrices for truss, beam, and frame elements using the physical and energy approaches. It then shows how to assemble the total flexibility matrix of a structure and use it to analyze simple structures like plane trusses, continuous beams, and plane frames. The document includes an example problem of a two-member structure to illustrate the flexibility method steps, such as determining static indeterminacy, developing member and system flexibility matrices, evaluating joint displacements and member end actions.
This document discusses the stiffness method for structural analysis. It begins by introducing the stiffness method and its key concepts, such as using joint displacements as the primary unknowns and establishing a relationship between member forces and displacements through stiffness matrices. It then provides examples of calculating stiffness matrices for different structural elements, including beams, trusses, frames, grids, and space frames. The document also explains how to develop the total stiffness matrix of a structure by assembling the member stiffness matrices using a displacement transformation matrix. Finally, it formalizes the stiffness method through the governing equations relating member forces, displacements, and loads.
This document discusses the flexibility method for structural analysis. The flexibility method involves determining flexibility coefficients by applying unit loads corresponding to redundant forces and calculating the resulting displacements. These flexibility coefficients are then used to calculate the redundant forces needed to satisfy compatibility conditions. The flexibility matrices for different structural elements are developed. Joint displacements, member end actions, and support reactions can be determined by incorporating the flexibility coefficients into the basic computations. Examples are provided to illustrate the flexibility method for a continuous beam with one redundant and for determining various outputs like redundants, joint displacements, and reactions.
This document provides an overview of mechanics of solids (or strength of materials) including definitions of key terms like stress, strain, elasticity and their relationships. It discusses stress analysis for axially loaded members and introduces various stress conditions in 2D and 3D spaces. Stress is defined as internal resistance against deformation while strain is a measure of deformation. Different material types like isotropic, orthotropic and their elastic relationships are also covered.
This document provides an introduction to structural dynamics. It discusses single degree-of-freedom systems and their fundamental equation of motion. Key topics covered include free vibration of undamped and damped structures, forced response of SDOF systems, and the effects of damping. An example of a mass-spring system is used to illustrate concepts such as natural frequency, period of oscillation, and the effects of loading rate. The importance of considering structural dynamics in design is highlighted through case studies.
In light of the most recent Winter Olympic Games, mathematical modeling problems involving algebra, geometry, trigonometry & calculus are presented via dynamic geometry software in the context of pairs figure skating. An aesthetically pleasing & athletically demanding pairs figure skating element, the death spiral, is discussed. Activities related to the pairs death spiral which are suitable for middle & high school students are provided in this workshop. Teachers’ work on these problems are analyzed & discussed.
This document discusses mechanics of solids, specifically torsion and bending moment. It begins with an overview and objectives of Module II which covers torsion of circular elastic and inelastic bars, as well as axial force, shear force, and bending moment diagrams. It then provides explanations, equations, and examples relating to torsion, including assumptions in torsion theory, the torsion equation, torsional rigidity, power transmission in torsion, and example problems calculating torque and shaft diameters. It also discusses statically indeterminate shafts and torsion of inelastic circular bars.
This document provides an overview of plastic analysis for structural elements. It discusses key concepts like plastic hinges, plastic section modulus, shape factors, and load factors. Plastic analysis is used to determine the ultimate or collapse load of a structure by considering the redistribution of moments that occurs after sections yield. Common failure mechanisms for determinate and indeterminate beams involve the formation of one or more plastic hinges. Methods for plastic analysis include the static/equilibrium method and kinematic/mechanism method. Examples are given for calculating the collapse load of simple structural configurations using these methods.
We continue to summarize the main questions in my papers
The current paper deals with the papers questions starting from Paper No. 138 (Matter Creation Principle (Part V) to paper No. 99 (How the solar group is created?) (Discussion No.1)
Gerges Francis Tawdrous +201022532292
This document analyzes an indeterminate truss using the flexibility method. It first calculates the static degree of indeterminacy as 2. It then selects members OA and OD as redundant members. The truss is analyzed when each redundant member is given a force of 1 kN. A flexibility matrix equation is developed and solved to determine the redundant forces, which are then used to calculate the final forces in each member. The final forces show member OA in tension and member OD in compression.
The Moon Orbital Triangle (General discussion)(I) (Revised)Gerges francis
Paper Argument
- The Moon motion has 2 Orbits – we see one of them only
- The moon second orbit is declined by 0.8 degrees on the first one.
- The 2 orbits are neighbors and define together the Lunar Eclipse Umbra Length (1.392 mkm)
- Venus axial tilt is changed from 1.774 to 177.4 degrees because of Uranus axial tilt angle (91.1 degrees) with the moon axial tilt (6.7 deg) and because of Uranus axial tilt perpendicularity on the moon orbital triangle base.
- Venus original axial tilt (1.774 deg) is created as a rate between its diameter and Mars diameter – that shows Mars diameter rate effect on the planets motions
-The moon uses Pythagoras rule in its motion to define its daily displacement
Gerges Francis Tawdrous +201022532292
Paper Claim
- Uranus creates a perpendicularity on the moon orbit and creates an angle (91.1 degrees) with the moon axial tilt
- The moon orbit regresses because of Uranus perpendicularity
- Venus motion interacted with the moon motion under Uranus Perpendicularity to create the moon orbit regression
- The moon diameter is created as a function of its orbital distance as a result of Uranus perpendicularity on the moon orbit
Paper Objective
- The paper reviews and correct the moon orbital triangle data
And
- The paper tries to prove its claim
Gerges Francis Tawdrous +201022532292
Paper Hypothesis
-There's Another Similar Orbit For The Moon Motion
The Hypothesis explanation
- The triangle ACE shows that, a double value of the triangle perimeter is used for geometrical necessities in the moon orbital motion
- i.e.
- While the (ACE) triangle perimeter = 943817 km, the geometrical structure of the moon orbit uses the value 1887634 km (= 2 x 943817 km) as one of the basic motion values.
- There's one more reason for this hypothesis, because the moon orbital motion space area contains (50%) of the Jupiter Whole Energy, that tells if the energy is transported to the moon orbit why just (50%) only?
- I suggest that
- Another similar orbit of the moon must be found which we can't see. This idea is supported by our previous argument, where the moon moves daily 2.58 mkm (as Earth) and because of the contraction this value became 2.41 mkm, So the tries to cover this difference (0.17 mkm) by its daily displacement (88000km) which is not enough and the moon needs to move another displacement (88000km) to cover the different distance, where this last displacement (88000km) we can't see, and based on that I suppose the moon must have another similar orbit through which the moon moves this additional displacement (88000km).
- The paper tries to prove this fact
Gerges Francis Tawdrous +201022532292
Uranus Is Perpendicular On Earth Moon Orbit (III) Gerges francis
Paper hypothesis
- Uranus orbital inclination 0.8 degrees is created by an effect of the Earth moon orbital motion.
o Jupiter diameter 142984 km = 13.1 x 10921 km (the moon circumference)
o But
o Jupiter velocity =13.1 km/sec
o And
o Jupiter orbital circumference= Jupiter circumference x the moon circumference
o The data tells interesting ideas!
o Jupiter has to move during 10921 seconds to pass a distance = its diameter, now the moon circumference (10921 km) is used as time period! With some analysis we have found this behavior is followed by many other planets!
o The Earth moon also has to rotate around its axis 13.1 time to move a distance = 142984 km = Jupiter diameter – where the moon rotation period is 27.3 days, the 13.1 time consumes around one year – so it's interesting to rotate for a defined period of time!
o The value (13.1) has still has many interesting forms, for example 13.18 degrees = the moon motion degrees per solar day! Also
o 13.18 degrees = the moon motion degrees per solar day/ 0.526 degrees (Mars motion degrees per solar day) =25.2 (where Mars axial tilt =25.2 deg)
Gerges Francis Tawdrous +201022532292
Uranus Is Perpendicular On Earth Moon Orbit (II) Gerges francis
Paper Claim
-Uranus Axial Tilt created an angle = 91.1 degrees with the Earth Moon Axial Tilt
But
- Uranus Axial Tilt is perpendicular (90 degrees) on the moon orbit, at the radius Perigee Point (r= 0.363 mkm)
- This perpendicularity (90 degrees), Uranus Axial Tilt performed because of using the value (1.1 degrees) to create an angle between the moon orbit horizontal base and the horizontal level…
- The angle (1.1 degrees) effects causes the moon orbit regression (19 degrees) per year
Paper Conclusion
- The moon orbit regression is a result of Uranus Axial Tilt perpendicularity on The moon orbit.
Gerges Francis Tawdrous +201022532292
This document presents a hypothesis that Earth's motion is the source of light energy in the solar system. The author proposes that Earth's velocity around the sun produces a beam of light equal to the supposed velocity of light. Various equations are presented analyzing distances, velocities, and time periods related to Earth's orbit and the orbits of other planets and celestial bodies. The author concludes that Earth is the source of energy for the entire solar system. References are provided for the author's other works on similar topics analyzing planetary motion and trajectories.
The Moon Orbital Motion More Analysis (II) (Revised) Gerges francis
Abstract
Paper hypothesis No. (1)
There's 2nd force effects on The Earth Moon Orbital Motion
Paper hypothesis No. (2)
Uranus Motion effects on the Earth moon orbital motion and creates Metonic Cycle
Paper Argument
- The moon displacement daily = 88000 km
- During 29.5 days (The Moon Day Period), the total displacements will =2.59 mkm this distance should be = the moon orbital circumference, and this distance = the moon orbital circumference at apogee orbit radius (r=0.406 mkm) (Error 1%)
- That means, if the moon uses this displacement (88000 km) as a real displacement through its orbit, the moon would revolve around Earth only through its apogee orbit (r=0.406 mkm), and be always on the most far point from Earth and can't revolve around Earth through any near orbits.
- To solve this dilemma, the moon uses Pythagoras triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level, So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit although the moon actual displacement = 88000 km daily.
- By Pythagoras technique using the moon can revolve around Earth through more near orbits as perigee orbit (r=0.363 mkm)
- The moon using of Pythagoras triangle technique causes the moon orbit to be created in a triangle form, which we analyze in this paper
- The moon orbital triangle data analysis lead to the following hypothesis (A 2nd Force must effect on the Moon Orbital Motion in addition to Earth Gravity Force)
- Also the 2nd hypothesis is created based on this first one, (Uranus effects on the moon orbital motion, causing to create Metonic Cycle).
Gerges Francis Tawdrous +201022532292
The Moon Orbital Triangle (General discussion) (Revised) (II)Gerges francis
Paper Argument
- The Moon motion has 2 Orbits – we see one of them only
- The moon second orbit is declined by 0.8 degrees on the first one.
- The 2 orbits are neighbors and define together the Lunar Eclipse Umbra Length (1.392 mkm)
- The second orbit is found because the moon moves 2 daily displacements each = (88000 km) but we see one of them only
- Venus Axial Tilt is changed from 1.774 to 177.4 degrees because of Uranus Axial Tilt angle (91.1 degrees) with The Moon Axial Tilt (6.7 deg).
- Venus original axial tilt (1.774 deg) is created as a rate between its diameter and Mars diameter – that shows Mars diameter rate effect on the planets motions
- Mars diameter effect explains the reason why Kepler equation (P2/d3 = Constant) uses (25) as a constant while (25.2 deg = Mars Axial Tilt)
- The moon uses Pythagoras rule in its motion to define its real displacement through its orbit which can be less or equal the value 88000 km.
Gerges Francis Tawdrous +201022532292
The moon uses pythagoras triangle technique in its orbital motionGerges francis
The Moon Uses Pythagoras Triangle Technique In Its Orbital Motion
Abstract
Paper hypothesis:
- The moon uses Pythagoras triangle as one of the moon orbital motion techniques
The hypothesis Explanation:
- The moon uses Pythagoras triangle to do the following job. While the moon moves a daily displacement =88000 km, The moon real displacement through its orbit can be less than (88000 km) by using Pythagoras triangle technique.
- The moon needs to decrease its daily displacement (88000 km) through its orbit to enable the moon to revolve around Earth in more near orbits to Earth
- That means, if the moon displacement (88000 km) can't be decreased and be its daily orbital displacement through its, the moon would revolve around Earth through only its orbit apogee (r=0.406 mkm) and can't revolve through any more near orbits.
- The moon using of Pythagoras triangle in its orbital motion, creates a great Pythagoras triangle controls the moon orbital motion and its orbit geometrical structure.
Paper objective:
- The paper proves this fact and discusses the geometrical basics based on which the moon orbital triangle is created.
Gerges Francis Tawdrous +201022532292
Uranus Is Perpendicular On Earth Moon Orbit (VI) Gerges francis
Paper hypothesis
The Earth moon motion has 2 orbits
The hypothesis explanation
- The Earth moon is so specific planet in the solar system and so effective in its general geometry
- Uranus and Neptune effect on the moon orbit creation and cause its regression by 19 degrees yearly
- Uranus and Neptune orbital inclinations are created by the effect on their interactions in the moon orbit
- Mars orbital inclination is created based on the moon orbit interactions
- The moon orbital motion has 2 orbits both perpendicular on one another
- Venus axial tilt and orbital inclination are created as a result of Uranus perpendicularity on the moon orbits.
Paper conclusion
- Many of Planets data can be created by their values only if there are 2 orbits for the moon motion.
Gerges Francis Tawdrous +201022532292
The Moon Uses Pythagoras Triangle Technique In Its Orbital Motion (Revised)Gerges francis
Paper hypothesis:
-The moon uses Pythagoras triangle as one of the moon orbital motion techniques
The hypothesis Explanation:
-The moon uses Pythagoras triangle to do the following job. While the moon moves a daily displacement =88000 km, The moon real displacement through its orbit can be less than (88000 km) by using Pythagoras triangle technique.
-The moon needs to decrease its daily displacement (88000 km) through its orbit to enable the moon to revolve around Earth in more near orbits to Earth
- That means, if the moon displacement (88000 km) can't be decreased and be its daily orbital displacement through its, the moon would revolve around Earth through only its orbit apogee (r=0.406 mkm) and can't revolve through any more near orbits.
- The moon using of Pythagoras triangle in its orbital motion, creates a great Pythagoras triangle controls the moon orbital motion and its orbit geometrical structure.
Paper objective:
- The paper proves this fact and discusses the geometrical basics based on which the moon orbital triangle is created.
Gerges Francis Tawdrous +201022532292
The Moon Orbit Geometrical Structure Proves The Following Conclusions:
Primary Conclusions
(1) Solar Group Can't be created neither by Big Bang Theory Nor Sun Gravity Concept.
(2) The Solar Group is created of Only One Energy travels through the group
(3) This one Energy creates planets matters (E=mc2 supports that) and planets orbital distances (because Space = Energy –my hypothesis)
(4) Solar Group can be similar to one train and each planet is a carriage of it.
(5) Solar Group can be similar to one machine and each planet is a gear in it
(6) Solar Group can be similar to one building and each planet is a part of it
(7) So, when a planet moves – means - this planet moves as a carriage in one train –all solar planets move together in one general motion
Paper Basic Conclusion:
Energy must be Transported from Jupiter to Earth Moon Orbit
The paper tries to prove this fact
The moon motion basic equation (modified) (revised)Gerges francis
The Moon Motion Basic Equation (modified) (Revised)
Abstract
A Modification In
The Moon Orbital Motion Equation
The Old Form
θ1 (Per Solar Day) = θ0 (of Previous Day) + 0.98562 degrees
The Modified form
θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.6 degrees
- The Equation uses 1.5 degrees in place of the angle (0.98562 degrees) because the moon axial tilt (6.7 degrees) declines on the Earth Ecliptic line with 1.6 degrees.
- This paper tests the new modification on the equation accuracy
- The modified equation defines the moon position with an accuracy =96.12 %
(where the error is (3.88 %))
The Equation Concept
- The moon uses Pythagoras triangle to do the following job. While the moon moves a daily displacement =88000 km, The moon real displacement (L) through its orbit can be less than (88000 km) where (L =88000 Cos (θ))
- The moon needs to decrease its daily displacement (88000 km) through its orbit to enable the moon to revolve around Earth in more near orbits to Earth
- The angle (θ) defines the moon real displacement and its distance to perigee radius (r=0.363 mkm).
- For that reason the equation depends on the angle (θ).
Gerges Francis Tawdrous +201022532292
A Modification In
The Moon Orbital Motion Equation
The Old Form
θ1 (Per Solar Day) = θ0 (of Previous Day) + 0.98562 degrees
The Modified form
θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.5 degrees
- The Equation uses 1.5 degrees in place of the angle (0.98562 degrees) because the moon axial tilt declines on the Earth Ecliptic line with 1.5 degrees.
- This paper tests the new modification on the equation accuracy
- The modified equation defines the moon position with an accuracy =96.12 %
(where the error is (3.88 %))
The Equation Concept
- The moon uses Pythagoras triangle to do the following job. While the moon moves a daily displacement =88000 km, The moon real displacement (L) through its orbit can be less than (88000 km) where (L =88000 Cos (θ))
- The moon needs to decrease its daily displacement (88000 km) through its orbit to enable the moon to revolve around Earth in more near orbits to Earth
- The angle (θ) defines the moon real displacement and its distance to perigee radius (r=0.363 mkm).
- For that reason the equation depends on the angle (θ).
Gerges Francis Tawdrous +201022532292
Uranus Is Perpendicular On Earth Moon Orbit (V) Gerges francis
Paper Question
How can the moon motion is done in 2 different orbits?
Paper main idea summary
- Uranus axial tilt has an angle (91.1 degrees) with the Earth moon axial tilt
- Uranus creates a triangle with decline (1.1 degrees) on the horizontal level and the rest angle (90 degrees) Uranus uses to be perpendicular on the moon orbit
- Uranus basic effect on the moon orbit is done on perigee point –
- Under the triangle Uranus created for the moon orbit, Uranus used 2 parts as stuffing to consume this angle (1.1 degrees) (1st part) is the green rectangle and it's created by Jupiter and Saturn cooperation, it consumes 0.6 degrees. The (2nd) part is the moon itself where the moon diameter consumes an angle = 0.5 degrees
- i.e., Uranus axial tilt angle on the triangle base = 90 degrees, but under the base immediately this same angle will be 90.6 degrees and the moon diameter consumes 0.5 degrees (i.e.) under the moon the angle is 91.1 degrees on the horizontal level which is the moon axial tilt.
- What we need is the angle 90.8 degrees? How to find it?
- Uranus axial tilt penetrates the moon diameter till reach to a diameter =1390 km around the moon center (inside the moon body) – why? because the moon diameter (3475 km) consumes (0.5 degrees) – so the diameter (1390 km) will consume only (0.2 degrees) – so Uranus axial tilt angle will be (90.9 =90.8+0.1)
Gerges Francis Tawdrous +201022532292
Paper Hypothesis
-Uranus axial tilt is perpendicular on the moon axial tilt, and this perpendicularity created the moon motion range (Perigee r=0.363 mk & Apogee r=0.406 mk)
Paper Main Idea
- The moon orbital triangle is declined by 1.1 degrees on the horizontal base to save the triangle values from Uranus perpendicularity effect on the moon orbit
- (Uranus axial tilt 97.8 deg – The moon axial tilt 6.7 deg =1.1 deg)
- The value 1.1 degrees is consumed in (0.5 deg "the moon angular diameter") and (0.6 degrees ")
- The value (0.6 degrees) shows Jupiter and Saturn motions effect on Mars motion, but this interaction between the 3 planets motions (Mars, Jupiter and Saturn) depends on the moon angular diameter "0.5 degrees". And because of that, the moon motion data effects and effected greatly by Mars motion… for example
o 687 days (Mars orbital period) = 27.3 days (the moon orbital period) x 25.2
o 13.18 deg (the moon motion daily)/ 0.526 deg (Mars motion daily) = 25.2 deg (Mars axial tilt) =
- This interaction of Mars and Moon motions is created because Jupiter and Saturn motions effect on Mars Motion is done based on the moon angular diameter "0.5 degrees", so this both values (0.5 degrees +0.6 degrees = 1.1 degrees) consisted together one result 1.1 degrees which Uranus aimed to create between both axial tilts (Uranus axial tilt and the moon axial tilt).
Gerges Francis Tawdrous +201022532292
Why The Earth Moon Distance = The Planets Diameters Total (III) Gerges francis
Paper Question
Why The Earth Moon Distance (At Apogee Radius) = The Planets Diameters Total?
Because
(1)
The Matter Is Created Based On Its Motion –
That means
The moon daily displacement =88000 km – is the reason based on which– the moon diameter is created to be = 3475 km –
This fact can be proved by analyze Saturn Creation and Motion Data
(Point No. 2 of this paper discusses this question)
(2)
We Still Analyze The Moon Orbit Geometrical Structure, Where the moon orbit shows that there's a geometrical design forces the moon to move specific motion and specific displacement daily
Gerges Francis Tawdrous +201022532292
(Preprint No. 2) The Moon Orbital Motion EquationGerges francis
Abstract
Paper hypothesis
The moon uses Pythagorean triangle in its orbital motion.
The hypothesis explanation
- The moon daily displacement =88000 km, during 29.53 days the displacements total be = 2598693 km.
- This distance should be the moon apogee orbital circumference, and if be so, 2 results should be produced (1st The moon orbit apogee radius =413600 km) and (2nd the moon has to revolve around the Earth through its apogee orbit only and can't revolve through any near orbit because the distance 2598693 km is so long)
- The moon creates an angle (θ) between its motion direction and its orbit horizontal level, by that the real displacement (L) through the orbit be (88000 km Cos θ) less than 88000 km and the total displacements be less than 2.5986 mkm
- The angle (θ) controls the moon motion features, because
- With great angle (θ), the real displacement (L) be shorter and the moon can revolve around Earth through more near orbits (as perigee orbit r=363000 km)
- With small angle (θ), the real displacement (L) be longer and the moon has to revolve around Earth through more far orbits (as apogee orbit r=406000 km).
- Because of that the moon orbital motion equation depends on the angle (θ).
Mr. Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Paper Objective
The Moon Motion Trajectory Rules Definition
- There 3 basic rules are known in the moon motion trajectory, which can help us in our investigation to discover the moon motion trajectory…
- The 1st rule
o "There Is Another Force Equal Earth Gravity Force Effect On The Moon Motion Trajectory, This force Is expressed By point (A) in The moon orbital triangle, This Point (A) is found beyond apogee point with 43000 km, i.e. The distance between the Earth and this point (A) = 449000 km"
- The 2nd rule
o The moon orbital triangle shows that, the moon motion 4 basic radius (which are Perigee, Apogee, total solar eclipse, and the orbital distance), these 4 points are defined based on each other by using Pythagoras rule (the Pythagoras equation should use the term 86000 km as a right triangle dimension and the other dimension should be any radius of the 4 radiuses and the result will be another radius of them) – so is this the way by which the moon move? i.e. does the moon move through its motion trajectory based on Pythagoras rule?)
- The 3r rule
o The Cycle 1290 days of the moon motion, this cycle gives us a clear light about how the moon moves through its orbital motion trajectory
- Because we know the rules No 1 and 3, the paper will discuss only the rule no. 3 and review both old rules.
Gerges Francis Tawdrous +201022532292
The Moon Orbital Triangle (General discussion) (IV) Gerges francis
Paper hypothesis:
-The moon orbital motion causes the moon orbit regression 19 degrees per sidereal year (365.25 days)
Paper Argument:
The Moon Orbital Triangle Basic Uses:
(1) The moon uses Pythagoras triangle as one of its orbital motion techniques, based on that, the triangle supports the moon motion equation definition.
(2) There's 2nd force effects on the moon orbital motion and this force can be concluded from the moon orbital triangle
(3) There's 2nd orbit for the moon motion, and this orbit can be discovered by the moon orbital triangle data analysis
(4) The moon orbital triangle declination angle (1.1 degrees) on the horizontal level has a massive geometrical effect on the moon motion.
(5) The triangle shows that, the moon daily displacement (88000 km) is defined based on geometrical rules.
(6) The Triangle shows why the moon can't move beyond apogee orbit (r= 0.406 mkm).
Paper conclusion:
- Earth Does A Displacement As A Result Of The Moon Orbit Regression 19 Degrees Per A Sidereal Year (365.25 Days)
Gerges Francis Tawdrous +201022532292
Similar to The Moon Orbital Triangle (General discussion) (I) (20)
2012 Phenomenon Has Told Facts Because (The Sun Is A Phenomenon).pdfGerges francis
Best greetings –
2012 Phenomenon has told Facts Because (The Sun Is A Phenomenon)
Abstract
Paper hypothesis
The sun is a phenomenon created by the planets motions – means - the sun is not doing nuclear fusion to create its rays but the sun rays be created by Planets Motions Energies total- As a result – the sun is created after all planets creation and motion which disproves Newton theory of the sun gravity where no planet moves by the sun gravity –
The hypothesis explanation
The sun creation as a phenomenon depends on the planets motions energies shows a great gab between the solar system motion description and the real facts of this motion –for that reason – I provide 2 more points to confirm this gab existence while the 2 points be less strange in meaning can prove clearly this gab is found deeply in the description– not only for the sun rays source of energy but also for the basic ideas of the solar system motion.
(Point No. I)
The Mass Gravity Force Can't Cause The Solar System Motion
The planet moves by the force which caused its creation otherwise this planet will be broken by its motion because 2 forces affect on it- Newton Is Wrong In Logic – But –
I wish to move beyond this point –because – I refuse generally the mass gravity force using as a reason for the solar system motion – the idea is wrong in concept –
Basically because
The mass gravity force is so limited force in range and can't provide the solar system motion features – we need one more powerful and intelligent force – the eclipse phenomenon may help this explanation –the force which created the planets diameters in proportionality with specific distances – and the sun diameter be used also in this process- the force considers each planet motion and velocity – thinking about the whole process to produce the total solar eclipse by many players their creation data be created for this purpose.
Usually the total solar eclipse be considered as pure coincidence result and the beauty of geometry be removed- the paper analyzes the eclipse geometrical data to show a small part of the beauty –
Can the mass gravity poor concept do that? the description Newton told can explain how the matter be created? or how is planet data created? why is the moon diameter =3475 km? because if it be 5000 km the whole geometry will be changed….
The moon creation can help to see another part of this force beauty – the moon be created by planets collision but the moon diameter be created based one exact equations – means- the force works geometrically even through the collisions
In fact
This idea also shows the gab between the solar system facts and the current theory because – while – the current description supposes the planets data be created by random process, initial conditions and unknown historical factors that fact is that the planets data be created based on exact equations
Gerges Francis Tawdrous +201022532292
Peoples' Friendship university of Russia – Moscow (2010-2013)
The Sun Rays Production Theory
Abstract
Paper hypothesis
The Sun Rays Energy Source Is The Planets Motions Energy – means- The Sun Is Not doing nuclear fusion to create its rays – instead – the planets motions energies total be used to create the sun rays.
The hypothesis explanation
I- The Sun Rays Creation Depend On The Relative Motion Concept
This point provides the method by which the sun rays be created – the rays creation depend on the relative motion – that means- we need to find 2 motions in the solar system move relative one another and the different velocity between the 2 motions be = Light Velocity = 300000 km/sec
Regardless – this is possible or not – our job be defined clearly –
We need 2 motions move relative one another and the different velocity between these 2 motions be = Light Velocity = 300000 km/sec
II- Can We Attribute Mechanical Features For The Space?
Here we try to produce the 2 relative motions –
(Let's suppose the sun isn't found but the planets still revolve around its space point)
We have to attribute mechanical features for the space – let's do that in following
We suppose the space be similar to a sea water and the planet be similar to a stick moves perpendicularly through the sea water – this is similar to – a spoon turns water in a vessel - the spoon motion through the water causes a wave in the water –
The theory supposes the planet motion causes a wave in the space –
let's use this hypothesis in our analysis…
Mercury revolves around the sun (point) with velocity 47.4 km/sec – how to see that in our description?
Mercury (a stick moves through water perpendicularly) revolves around the sun point and causes to create a wave by its motion – Mercury velocity is 47.4 km/sec and that causes the wave velocity to be (47.4 km/sec)
And -
Venus (a stick moves through water perpendicularly) revolves around the sun point and causes to create a wave by its motion – Venus velocity (35 km/s) – by that the wave velocity be (47.4 km/sec +35 km/sec = 82.4 km/sec)
And – The Earth moon (a stick moves through water perpendicularly) revolves around the sun point and causes to create a wave by its motion –the moon velocity (29.8 km/s) – by that the wave velocity be (47.4 km/sec +35 km/sec +29.8 = 112.2 km/sec) (continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
The Sun Is a Phenomenon, Created By The Planets Motions Energies (revised).pdfGerges francis
Paper hypothesis
The solar planets distribution between the sun and Pluto depends on one design – this design uses the distance 90000 million km as a distance unit.
The hypothesis explanation
The hypothesis tells – the planets distribution uses one design and this one design gives a chance for the planets to make their distances total equal 90000 million km for a unit period of time – there's a necessity to use this distance we explain here.
The data shows 2 facts
(1st Fact) One Map (One Design) Controls The Planets Distribution Between The Sun And Pluto –
(2nd Fact) This One Design Uses The Distance 90000 Million Km As A Unit
Paper first question
Why does the solar system design use the distance 90000 million km as a unit?
Let's answer in following…
If (c =300000 km/sec = light velocity) how can we measure the value (c2)?
Let's suppose we use the value (c2) for one second – how can we measure it?
In this case the value (c2) will be = 90000 million km
Now
The hypothesis tells, the planets motions aim to pass this distance (90000 million km) and to use this distance based on A Motion For A Period Of Time = One Second
(We Discover In The Paper Discussion How This Motion Can Be Created)
As a result –
The distance 90000 million km will be a equivalent to the value (c2)
And
The value (c2) is the source of energy from which the sun rays be created.
Based on that
The Sun Rays Be Created By The Planets Motions Energies Total
Means,
The Sun Is Not Doing Nuclear Fusion - Instead – the planets motions energies total be accumulated and be used as energy source to produce the sun rays- then the sun disc and body be created from the sun rays energy.
And
Because the planets motions aim to create the sun rays they aim to pass the required distance 90000 million km and the solar system design causes this distance to be used by a motion depends on one second
Paper second question
Can Light Beam Be Produced By Matters Relative Motion?
The planets motions distances total per solar day (=17.75 million km)
(This distance contains the Earth moon velocity which is equal Earth velocity)
During 1461 days the planets motions distances total be =25920 million km
Light (300000 km/s) travels in one day (86400 s) a distance =25920 million km
But the Earth Cycle is (365 +365+365+366 =1461 days)
The idea tells us – if 1461 seconds of the Earth motion = 1 second of the sun motion – the velocities difference between the 2 motions will be= Light Velocity (300000km/s)
The paper discusses how that can be possible- but – here – we discuss the conceptual question- can light beam be created by matters relative motion?
The planets data tells about a new method which is (Motions Use Different Rate Of Time) (continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Paper hypothesis
The Sun Is Not Doing Nuclear Fusion
Saturn motion causes to produce the sun rays
means, Saturn moves by light velocity relative to the sun point –
The hypothesis Proof
The paper hypothesis tells Saturn motion causes to produce the sun rays
Let's prove that in following
(1)
The Planets Motions Use Different Rates Of Time Where
One hour of Mercury motion be = 24 hours of any planet motion (except Saturn)
One hour of Any Planet motion be = 24 hours of Saturn
These rates of time be proved in the paper discussion.
(2)
Saturn moves a distance =90000 million km in a period = 107470 days
The period 107470 days (of Saturn) = 576 x 186.6 days (Of Mercury)
Means this period (107470 days) be seen on Mercury as (186.6 days)
(3)
The 9 planets velocities total be =176 km/sec –
This total be created relative to the point of space on which the sun will be created –
Means
We suppose the sun isn't found and the planets still revolve around the point of space on which the sun will be created-
Mercury (47.4 km/s) revolves around this point of space and creates a different in velocity with it = (47.4km/s)
Venus (35 km/s) revolves around this point and creates a different in velocity = 47.4km/s + 35km/s =82.4 km/s
The 9 planets velocities total 176 km/s causes to create a different velocity =176 km/s with this point of space
Now
The rate of time be created based on the rate of velocities –means
1day of this point of Space be =176 days of Mercury
(Mercury controls this velocities total 176 km/s)
But
107470 days (of Saturn) be =186.6 days (of Mercury) = 1.0725 days of the point of space
We know the rate (1.0725) effect on the solar system – for example – this rate effect on 40% of all distances and 60% 0f all planets axial tilts and effect on many other data-
By this rate (1.0725) the period (1.0725 days) will be = one day
Means
107470 days (of Saturn) be =186.6 days (of Mercury) = one day of the point of space
But
The solar system creation theory tells– the planets matters and their distances be created from one energy and this energy be provided by one light beam and the planets move with this light beam based on the rate of time (One Second of Light motion be = One Solar day of Planet Motion)
This must be the same rate be used with the space because the matter and space be created together.
As a result
107470 days (of Saturn) be =186.6 days (of Mercury) = one day of the point of space =one second of light motion
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Paper hypothesis
(1)
The Sun Rays Be Produced By Planets Velocities Total - The Sun Is Not Doing Nuclear Fusion
Light (300000 km/sec) travels in one solar day a distance = the solar planets motions distances total in 1461 solar days–
The solar planets velocities total uses this rate of time (1=1461) and produces light velocity (300000 km/sec) from the planets velocities total
(2)
If the solar planets motions can't produce light velocity the solar system would be destroyed.
Paper conclusion
Because the sun rays energy be provided by the planets motions energies total and the planets move in cycles – that necessitates – the sun creation and death depend on a cycle –means- after this sun be dead another sun will be created because the sun is a phenomenon created based on a cycle (as the eclipse)
The hypothesis explanation
(1)
The Planets Matters And Their Distances Be Created Out Of One Energy -
This idea can be acceptable simply by the physics book because it's known that the matter and space be created of energies – here – I add one idea only tells that-from the same one energy the planets matters and their distances be created –
The matter and space have different forms spite they be created from the same energy because the creation rules be different for them- as the oil and coal - they be created from the same source but the creation rules be different and the forms be different as a result
The idea causes basic change in the solar system motion description–because –instead of the separated planets as separated points – we deal with one energy which causes to create a continuum of data – by that –the data can be transported among the planets (in fact it does).
The idea doesn't create any new thing– but – it discovers the unjustifiable description for the planets motions – where it be believed that the planets are separated from one another as islands in a sea and no connection can be available – this description is mistaken in concept because the matter is created of energy and the space is created of energy and it's illogical to prevent the contact between them -here – the transportation of data among the planets should be a proved fact depend on the planets motions.
Shortly
The continuum of data of the solar system is a logical fact should be proved, and the separated points description should be considered unjustifiable vision.
A Conclusion
From one energy the planets matters and their distances be created
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
The Sun Is A Phenomenon
Abstract
Paper hypothesis
The solar planets velocities total be equivalent to light velocity 300000 km/s
The hypothesis explanation
- The Sun Is A Phenomenon Created By The Planets Motions –
- Means-
- The Sun Rays Energy Source Isn't Any Nuclear Interaction Found Inside The Sun – But – The Sun Rays Energy Be Found By The Planets Motions Energies Total
- Shortly
- The Planets Velocities Total Be Used As One Motion Velocity – And This Motion Uses A Rate Of Time To Reach To Light Velocity.
- Let's explain that in details in following…
- (1)
- We need to suppose that (One Hour Of Mercury Motion =24 Hours Of Any Planet Motion) and
- (One Hour Of Mercury Motion = 24 Solar Days Of Saturn Motion)
- These rates of time be proved in the discussion clearly –
- (2)
- The 9 planets velocities total be =176 km/sec – this value be seen in Mercury Data as (176 solar days = Mercury Day Period)
- We conclude that, Mercury controls this velocities total 176 km/s
- And
- After The Earth Moon Creation, the moon velocity 29.8 km/sec be added to the 9 planets velocities total (176 +29.8 =205.8 km/s)
- The total 205.8 km/s be seen in the moon motion data as (205.8 x π =655.7) (error 1.4%) where (655.7 hours = the moon rotation period)
- That tells the velocities total be seen also in the moon rotation period (a cycle period as Mercury)
- But
- Why for Mercury used (DAYS) but for the moon used (HOURS)??
- Because
- (One Hour Of Mercury Motion = 24 Hours Of The Moon Motion)
- (3)
- The total (205.8 km/s) can create the velocity 300000 km/s only if the rate of time (1=1461) be created – let's see the light velocity creation -
- 300000 km = 205.8s x 9.7 km/s x 24 x 2π
- Let's explain how the light velocity (300000 km/s) be created.
- The planets velocities total (205.8km/s) moves for 1second and passes 205.8 km, this distance be sent from the moon to Saturn in a period form (205.8 seconds)
- But (one hour of any planet motion = 24 hours of Saturn motion) for that reason the period (205.8 s of the moon motion) be equal = (205.8 s x 24) of Saturn motion.
- The rate (2π) be found by the geometrical design
- The data tells, each second Saturn moves, passes a distance =9.7 km but the solar system passes a distance =300000 km
- If the solar system moves (one motion) and uses (one velocity) for this distance (300000 km) for each second - The Solar System Velocity Should Be Equivalent To Light Velocity (300000 km/s) – means – The Planets Velocities Total Should Be Equivalent To Light Velocity (300000 km/s) (continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
National Bank Of Egypt Practice The Fraud (2020-2022).pdfGerges francis
Please help (1-9-2022)
National Bank Of Egypt Practice The Fraud (2020-2022)
National bank of Egypt practice Fraud and Breach of Trust
Because
It refused the judgment issued by The French ministry of Justice and denies the money by judged and disregarded the Foreign Court Judgment.
Sent to the honorable united Nations Secretary – General
António Guterres
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Passport No./ A11263731 ID. No./27410090102716
best Greetings
The Sun Creation Process
Abstract
Paper hypothesis
From One Light Beam Energy The Solar System Be Created
And
This Light Beam travels with 1.16 million km per second
The hypothesis explanation..
- (1)
- The solar system be created out of one light beam energy –
- The solar planets matters and their distances be created of one energy and this one energy be provided by one light beam and this light beam travels with velocity 1160000 km/s –
- Shortly
- The physics book accepts that (matter and space be created of energies)
- The hypothesis adds one idea only tells
- (from the same one energy the solar planets matters and their distances be created) this is the hypothesis main idea –
- Matter and Space creation be done from the same stuff (energy) but by using different geometrical rules –the idea is similar to the creation of the oil and coal both be created from the same source but they have 2 different forms because the creation process depend on 2 different geometrical rules.
- The matter and space creation process can be summarized by the following data
- (light 1.16 million/s = matter + space + light 300000 km/s)
- The data tells the input energy be a light beam its velocity 1160000 km/s, from this energy the matter and space be created and the light known velocity 300000 km/s be created as a side product from the process.
- Briefly
- If we find Matters in the universe – we can't find the light velocity 1160000 km/s because its energy be consumed in the matter and space creation process and produced the known light beam velocity 300000 km/s as a side product.
- Based on this vision
- The matter be a geometrical point found on a trajectory of energy or (on a light beam) – by that – the matter moves by light motion –
- Imagine a rock in a tube form be found in some sea water and the water passes through this rock tube and pushes the rock itself to move with the water-
- That answers the question (how does planet move?) no sun gravity be used here – instead – the planet moves by light motion from its energy the planet be created.
- Here we disprove Newton theory of the sun gravity – because
- By one force the planet be created and moving otherwise this planet will be broken by effect of 2 forces on it – here – the force caused the planet creation is the light beam energy and the force causes the planet motion is this same light beam motion- that explains the safe planet motion.
(continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Paper hypothesis
Venus motion effect on the moon motion and causes the moon orbital period to be = the moon rotation period =27.3 days
The hypothesis explanation..
- The hypothesis explanation can be summarized in 3 questions:
- (1) Can Planet Data Depend On Exaction Equations?
- (2) By What Equation Planet Diameter Can Be Defined?
- (3) How Can Planet Diameter Equation Change The Solar System Vision?
- Let's try to answer these questions in following…
(1st Question)
Can Planet Data Depend On Exaction Equations?
- (1)
- Planet Data Be Created Based On Exact Equations –
- As a plane or rocket manufacture – the manufacturer needs exact equations to define this plane length, width, weight and all specifications, otherwise this plane can't fly safely.
- The moving planet under the physical laws has to define its diameter, mass, orbital distance, period, inclination, rotation period, axial tilt …and all data based on Exact Equations otherwise this planet can't move safely.
- I have discovered 5 equations can conclude Planets Data theoretically without observation which prove this fact decisively.
- Then we have to ask (How Planet Data Be Created In Order?)
- (2)
- Planet orbital distance be defined before this planet creation - because – the planets motions leave an empty place for the new planet – by that- each planet orbital distance be defined by the other planets orbital distances and motions trajectories.
- My first equation proves this fact – because – it proves each planet orbital distance depends on its neighbor planet orbital distance –
- d2=4d0 (d-d0) where d= planet orbital distance and d0= its neighbor orbital distance
- Example (Venus orbital distance)2= 4 (Mercury orbital distance) x50.3 million km (Venus orbital distance=108.2 million km Mercury orbital distance =57.9 million km)
- This equation be tested and discussed in this paper – but its concept is a clear one – it tells the planets leave an empty space for the new planet – for that reason each planet orbital distance depends on its neighbor planet orbital distance.
- Logically the new planet can't disturb the current planets positions or motions trajectories – by that –the orbital distance be defined by the neighbors positions –
- (3)
- The new planet has to revolve around the sun based on its orbital distance which be defined obligatorily where no data of this planet be taken into consideration in its orbital distance definition –neither mass nor diameter – instead – the distance be defined based on the neighbor distance.
- But
- Planet diameter should be a function in its orbital distance – otherwise – this planet will be broken through its motion –
- The function between planet diameter and its orbital distance is the necessary requirement to cause the planet safe motion
Gerges Francis Tawdrous +201022532292
Vodafone-Egypt Practices a fraud and breach of trust during 2013-2022.pdfGerges francis
Vodafone –Egypt practices a fraud and breach of trust during (2013-2022)
Vodafone –Egypt practices a fraud and breach of trust during (2013-2022)
2013-2022: Egypt authority prevented any job from me and prevented me to travel abroad- They Torture My Mother By Electric Shock And Try To Kill Her By Insulin Injection- they threaten our lives –Please Help
2010-2013: I have studied in Faculty of physics & Math– Physics Department – Peoples Friendship University of Russia – Moscow – Russian Federation.
2013-2022 (Details) - Because I couldn't return to Moscow - I have performed an interesting research in astrophysics- many international physicists interested for it – while Egypt authority realized my research importance they:
(I) torture my mother by electric shocks to force me stop publishing my papers
(II) They practice hacking on my accounts & Telephone Calls (+201022532292).
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Petition (with signature) (Egypt Persecution Against The Coptic).pdfGerges francis
Please help
Egypt Authority Persecutes The Coptic -Please Help
EGYPT AUTHORITY TRIES TO KILL MY MOTHER – PLEASE HELP
(Also they force my family to send me to the madhouse)
Because
Egypt Authority tries to STEAL my astrophysics research results, I worked in it since 2013 till now –Egypt authority torture us to steal my research – they hanged many of my accounts and even prevent me to write my research papers by using torture.
(They try to burn my laptop- which is my only source for all my research materials)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Passport No./ A11263731 ID. No./27410090102716
Address /11 Mohamed Rageb st- Madenet El Saada – EL Materiya District – Cairo – Egypt
Planet Diameter Be A Function In Its Rotation PeriodGerges francis
Abstract
Paper hypothesis
- Planet Diameter Be Created As A Function In Its Rotation Period
The hypothesis Explanation
- (1)
- Planet Data Be Created Based On Exact Equations –
- As a plane manufacture – the maker needs exact equations to define this plane length, width, weight …etc otherwise this plane can't fly safely.
- The moving planet under the physical laws has to define its data based on exact equations otherwise this planet can't move safely.
- I have discovered 5 equations can conclude Planets Data theoretically prove this fact decisively.
- (2)
- Planet orbital distance be defined before this planet creation - because – the planets motions leave an empty place for the new planet – by that- each planet orbital distance be defined by the other planets orbital distances and motions trajectories.
- My first equation proves each planet orbital distance depends on its previous neighbor planet orbital distance –
- d2 = 4d0 (d-d0) where d= planet orbital distance and d0= its neighbor orb. distance
- We test and discuss this equation in the current paper–
- As a result –
- The planet found itself in an obligatory position be defined by other planets data and the planet data itself has no role in its orbital distance definition.
- (3)
- Planet motion can be a dangerous one if this planet diameter isn't in harmony with its orbital distance – means- the wrong diameter can cause the planet to be broken (The mass can decrease planet velocity – but the wrong diameter can break it) – for that reason – the planet has to create its diameter as a function in its orbital distance to move safely.
- But
- If the function has only 2 variables (planet diameter and its orbital distance), If this planet changes its orbital distance for any reason its diameter will be broken as a result –
- The designer had to create the function between planet diameter and its orbital distance as indirect function contains many other variables and by that if the planet changes its orbital distance the other variables will be changed but the diameter will be saved.
- As a result
- Planet diameter be created as a function in its rotation period and the rotation period be a function in its velocity and the velocity be a function in its orbital distance – by that – the function between planet diameter and its orbital distance be created but contains also other variables to protect the diameter.
- My fourth equation proves this fact let's see it
- (4)
- Planet Diameter Definition Equation (My Fourth Equation)
- (v1/v2) = (s/r) =I
- v = Planet Velocity
- r= Planet Diameter
- s= Planet Rotation Periods Number In Its Orbital Period
- I= Planet Orbital Inclination (a rate to inclination unit)
- v2, s, r and I be belonged to one planet and v1 be belonged to another planet
- we test, discuss and analyze this equation in this current paper.
Gerges Francis Tawdrous +201022532292
-Physics and Mathematics Faculty - Peoples' Friendship university of Russia –
Gerges Francis Tawdrous (Curriculum Vitae).pdfGerges francis
Gerges Francis Tawdrous (Curriculum Vitae)
My Research Argument
(Why Should We Refuse Newton Theory Of The Sun Gravity?)
1-Planet Data Be Created Based On Exact Equations
Planet diameter, mass, orbital distance, period, inclination, rotation period and axial tilt – All planet data be created based on exact equations and geometrical rules - No single data be created based on random process, initial condition nor unknown historical factors.
As in a plane or a rocket manufacture, the maker needs exact equations to define this plane length, width, weight and all its specifications and dimensions –
If this plane data be created by inaccurate dimensions, this plane can't fly
Similar to that
Planet moves through the space under physical laws and if its data be not created based on exact equations this planet will be broken through its motion – because – the safe motion necessitates a full harmony between planet data one another and with the physical laws controls the motions through space
In this investigation we try to define how Planet creates its data – or in more accurate words – By What Order Planet Data Be Created? what data be created at first and what be later? – by that – we can discover the harmony original point.
I have discovered 5 equations by which we can conclude planet data theoretically without observation that proves the idea decisively
2- Planet Orbital Distance Be Defined Before Its Creation
This simple fact be proved by 2 basic proves – "First Proof" The Logical Analysis
The current planets positions define the new planet position
The balancing effect of the planets motions forces the new planet to take the left place for it – because the planets revolve around the sun in their trajectories of motions – for that – the new planet has to find a place far from these trajectories.
Imagine you are in some crowded bus – the people pushed you to the last place in this bus because it's the only free place there – you came later and this is the only available place for you – by that – you are forced to accept this place
Planet orbital distance be defined before the planet creation – the logic proves this fact clearly
"Second Proof"
My First Equation tells (d2 = 4d0 (d-d0))
d = Planet Orbital Distance and d0 = its neighbor planet orbital distance
My equation tells– Planet Orbital Distance Depends On Its Neighbor Distance
It's a simple and a trustee equation – let's use Venus as example
(108.2 million km)2 = 4 (57.9 million km) (50.3 million km)
where
108.2 million km = Venus orbital distance and
57.9 million km = Mercury orbital distance and (50.3 = 108.2 -57.9)
(There are 3 exceptions – Earth depends on Mercury – Mars depends on Venus and Pluto depends on Uranus –
(continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Planet Motion Logic Disproves Newton Theory Of The Sun Gravity.pdfGerges francis
Planet Motion Logic Disproves Newton Theory Of The Sun Gravity
Abstract
Paper Argument
- Planet Motion Logic Disproves Newton Theory Of The Sun Gravity
- (1)
- By one force planet be created and moving – means - the force which created the Planet– it causes its motion – as a result
- (No Planet Moves By The Sun Gravity) because (The Sun Had Created No Planet)
- One more force caused the planets creation and their motions
- For that reason
- Planet creation and motion data be in harmony one another –
- For example (Mercury creation and motion data be in harmony one another) and Mercury moves safely and isn't broken
- But -we don't have 9 forces in the solar system – One force for each planet – instead – We have one force only caused All Planets Creation And Motion
- Now- let's ask
- How Can One Force Create 9 Planets And Causes Their Motions?
- This force needs to use One Geometrical Design to do this job – as 9 gears be moving by one motor we need a machine to do this job
- Based on this analysis – No planet moves by the sun gravity – Newton is wrong
- (2)
- The gravitation equation is wrong because no planet orbital distance be defined based on it- and that explains the contradiction between the planets masses order and their orbital distances
- This fact is a powerful against Newton – but the logic still more power
- Because
- The planet orbital distance be defined before this planet creation – because – the distance be defined by other planets distances – means - the new planet orbital distance be defined based on the balancing of the current planets motions trajectories and by that the new planet will find itself in a position defined obligatory by other planets –
- This fact be proved also by my first equation which proves that each planet orbital distance depends on its neighbor planet orbital distance (Not On Its Mass)
- My First Equation tells (d2 = 4d0 (d-d0))
- d = Planet Orbital Distance and d0 = its neighbor planet orbital distance
- (My 5 Equations Be Tested And Discussed In The Paper)
- I want to say
- The principle idea is wrong because the distance be defined obligatory by other planets motions trajectories and planet mass can do nothing to change it
- (3)
- The logic still moves against Newton because
- The planet is found itself in an obligatory position and has to revolve around the sun from this position – now what about this planet diameter – because
- If the planet diameter isn't in harmony with its orbital distance this planet will be broken – here – Newton idea is wrong completely because he looked at the mass but planet mass can decrease its velocity where the wrong diameter can cause the planet to be broken – by that – the planet has to create a function between its orbital distance and its diameter to move safely otherwise it will be broken – the point is Newton defined the mass as the basic player! (continued)
Gerges Francis Tawdrous +201022532292
Physics Department
,Why Does Planet Orbit Define Its Velocity, (Kepler Law Analysis).pdfGerges francis
The document discusses Kepler's law that a planet's orbit defines its velocity. It provides 5 points to explain this: 1) Planet data is based on exact equations, not random factors. 2) A planet's diameter should be indirectly related to its orbital distance to avoid breaking during motion. 3) A planet's mass affects its orbital inclination and limits variables in diameter equations. 4) A function is needed between a planet's orbit and velocity to connect variables like rotation period. 5) Newton's gravity theory and the Big Bang theory are incorrect because planet data requires exact geometrical rules, not chaos. The document aims to show planetary motions result from one precise geometrical design, not random forces.
The Solar Eclipse (Questions And Answers).pdfGerges francis
The Solar Eclipse (Questions And Answers)
Abstract
Paper objective
The paper answers the following questions
1. Can each planet orbital distance depend on its neighbor planet orbital distance? In this case how the distance between the sun and Pluto be created? (Can One Map Be Drawn For All Planets Orbital Distances?)
2. Is There a necessity to create a proportionality between planet diameter and orbital distance?
3. Can Planet rotation period be defined based on its velocity?
4. Correct The wrong sentence (Planet Diameter Should Be A Direct Function In Its Orbital Distance And By That This Planet Will Not Be Broken Through Its Motion?)
5. Why Does Venus Have The Longest Rotation Period In The Solar System?
6. Can Planet orbital Distance be Defined before this planet creation? where planet orbital distance be defined based on its neighbor orbital distance?
7. Why Doesn't The Planet Break After Its Creation?
8. Planet data be (Mass – Diameter- Orbital Distance- Period –Inclination….etc) what data be created at first and what be created later?
9. Explain The Relationship Between Planet Diameter And Orbital Distance?
10. Why does the moon orbital period = the moon rotation period (No For Tidal Locking – this idea is wrong)?
11. Can The Planets Velocities Total Be Defined At First And Each Planet Velocity Be A Function In This Total?
12- Can Solar System Depend On One Geometrical Design?
13- Why Does The Moon Orbital Apogee Radius = 406000 km?
14- Can Mars Orbital Distance Be Changed From 84 million km to 228 million km?
15- Did Newton realize The Solar system Motion Logic?
16- How Be The Sun Disc Created?
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
The Solar Eclipse Phenomenon Analysis (Revised).pdfGerges francis
The Solar Eclipse Phenomenon Analysis (Revised)
Abstract
Paper Argument
The planets motions can be explained only based on the concept (One Geometrical Design Be found Behind the Solar System)
The Argument explanation
The solar planets are created complementary one another and their motions be integrated into one unified motion – by that- the planets be similar to members of one creature - Their creation data depends on one design and their motions be integrated together into one unified motion (as a machine of gears – many gears motions but the machine produces One Unified Motion)
Because of that
Any planet motion can be explained only through the concept (One Geometrical Design Be found Behind the Solar System), because based on this one design the planets be created and by this one design the planets motions be integrated and produced one unified motion.
Paper objective
- We have proved the one geometrical design before
- In this current paper we examine the one geometrical design details – by that the paper provides rich points of discussion because we discuss the geometrical details of this one design and their effects on the planets creation and motion data.
- The paper discussions points be summarized in following:
- (1)
- The paper proves the one design uses one map for the distance - means
- The solar system design uses the distance from the sun to Pluto as one piece of distance be distributed based on one map –
- (2)
- The paper proves the solar system design uses one more map for the velocities. by that, the design considers the planets motions be integrated into one unified motion as a machine of gears and this (unified velocity) be distributed for the planets velocities based on one more map.
- (3)
- The paper answers the question (why does the design use 2 different maps?) and explains the massive importance for this using
- The paper analyzes also my fourth equation to prove that – planet diameter be created as a function in its rotation period and the rotation period be created a function in its velocity and the velocity be a function in its orbital distance.
- (4)
- The paper disproves the tidal locking claim as a reason for the moon cycles periods equality – the idea is wrong – where – the moon orbital period = the moon rotation period because of the solar system one design effect on the moon motion.
(continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
The Dancing Planets
Abstract
Paper hypothesis
From One Energy The Solar Planets Matters And Their Distances Be Created
The hypothesis explanation
- (1)
- Newton Theory of the sun gravity is wrong in its logic because by one force the planet should be created and moving –otherwise this planet will be broken -means- The force which created the planet it causes its motion – by that no planet moves by the sun gravity
- (2)
- The Big Bang Theory Is Wrong Because – It Supposed – The First Energy Was In A Chaos Form Resulting From The First Explosion – in Fact – The First Energy (Of The Solar System) was in A Geometrical Design Form.
- (3)
- The physics book accepts (Matter and Space be Created Of Energies) – The paper hypothesis adds one idea tells (From One Energy They Were Created) – means - The planets matters and their distances be created from The Same One Energy
- Let's see the paper basic ideas in following
- (A)
- Planet Data Be Created Based On Exact Equations- As any plane or rocket creation – the maker needs exact equations to define this plane length, width and All Other Specifications-
- Similar to that,
- Planet mass, diameter, orbital distance, period, velocity, inclination, rotation period and axial tilt – all data be created based on exact equations and no data be created by any random process, initial conditions or historical unknown factors.
- By that, the planets data can be concluded by mathematical calculations only
- My 5 equations prove this fact (The 5 equations be tested in point no. 3)
- (B)
- The Planet data Exact equations depend on One Geometrical Design –means-
- Because the solar system creation and motion depends on One Geometrical Design, the planets data be created based on exact equations
- The One Geometrical Design is the basic argument of the paper –
- It's similar to the electron and positron be created from Gamma ray (The double production experiment), The 2 particles charges total be (Zero) because gamma ray charge is (Zero)
- By that, one law controls the 2 particles motions – and similar to that – one law or One Geometrical Design controls the solar planets creations and motions
- Also, from Planet motion analysis- we can reach to this same conclusion
- We accept that, one force only be used for planet creation and motion, and the force which created the planet causes its motion –otherwise this planet will be broken because 2 forces effect on it- but
- We don't have 9 forces create the 9 solar planets and cause their motions – instead- we have only one force causes all planets creation and motion –
- This one force can do this job only by using One Geometrical Design -
(continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Planet Diameter Definition Equation
Abstract
Planet Diameter Definition Equation (My Fourth Equation)
(v1/v2) = (s/r) = I
v = Planet Velocity
r= Planet Diameter
s= Planet Rotation Periods Number In Its Orbital Period
I= Planet Orbital Inclination
v2, s, r and I be belonged to one planet and v1 be belonged to another planet
The Equation Role
- The equation proves that, Planet diameter be created based on geometrical rule and as a function in this planet motion data –
- That tells, the motion was found and defined before this planet creation and for that the planet diameter be created depending on this planet motion data
The Equation Significance
- The Equation proves the argument
- By One Force The Solar Planets Be Created And Moving
- The sun didn't cause any planet creation, So (No planet moves by the sun gravity)
- By One Force and From One Energy All Planets Matters And Their Distances Be Created And This Energy Causes The Planets Motions.
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
Geometry Of Light Motion
Abstract
Paper hypothesis
- The planets matters and their distances be created from The Same One Energy.
- This one energy is provided by one light beam
- This light beam travels with a velocity =1.16 million km per second
Paper objective
- The paper is consisted of 2 parts
- Part no. (I) provides My Research Presentation Summary
- Part no. (II) discusses The Geometry Of Light Motion
- Let's refer to them in following..
Part No. (I) Research Presentation Summary
My research presentation is consisted of 6 points which are
(1)
Planet Orbital Distance Equation (My 1st Equation)
(2)
The Refutation Of Newton Theory Of The Sun Gravity
(No Planet moves by The Sun Gravity)
(3)
The Research Method explanation And Using to prove 2 basic new discoveries which are:
(Mars Migration Theory) and
(The moon using of an angle θ between its motion direction and its orbit level)
(4)
The Research hypothesis (The planets matters and their distances be created from One Energy)
That's why (The Solar System Be Created Based On One Geometrical Design)
Means (One Geometrical Design was found before the solar system creation)
That refutes (The Big Bang Theory)
(5)
The One Energy Is Provided By One Light Beam
(6)
The light beam travels with a velocity 1.16 million km per second.
That refutes (The hypothesis of the Special Theory of Relativity)
Part No. (II) Geometry Of Light Motion
What's the direct question behind this paper?
The matter and space are created from one light beam – means – the matter and space are forms of light forms –
Now, if this is a fact,
Why do we need to fight so hard to prove this very simple and clear fact?
Because
The light uses unknown geometrical rules –
By that this paper should be similar to a book of Geometry – because – it shows types of geometrical rules are unknown for us and not found in our Geometry books
It's a direct answer but not clear
Why don't we know these rules? Why can't we catch them in lab experiments? If so many unknown geometrical rules of light motion are found, and we couldn't catch them during the empirical physics history why can we do that now? Can any one stole at end the Geometry book from the heaven library?!
I have brought with me the planets data and later I have discovered that all unknown geometrical rules be hidden in them.
Shortly
The light creates the matter and space by using unknown geometrical rules – and – we can discover these geometrical rules by using planets data analysis – means – we can know these geometrical rules only if we can read correctly the planets data – for example – if we can answer the question (why the moon diameter =3475 km?) that will help us to discover the rules based on which the moon diameter be created.
So I will present my research summary then we should discuss these unknown geometrical rules.
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
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Immersive Learning That Works: Research Grounding and Paths ForwardLeonel Morgado
We will metaverse into the essence of immersive learning, into its three dimensions and conceptual models. This approach encompasses elements from teaching methodologies to social involvement, through organizational concerns and technologies. Challenging the perception of learning as knowledge transfer, we introduce a 'Uses, Practices & Strategies' model operationalized by the 'Immersive Learning Brain' and ‘Immersion Cube’ frameworks. This approach offers a comprehensive guide through the intricacies of immersive educational experiences and spotlighting research frontiers, along the immersion dimensions of system, narrative, and agency. Our discourse extends to stakeholders beyond the academic sphere, addressing the interests of technologists, instructional designers, and policymakers. We span various contexts, from formal education to organizational transformation to the new horizon of an AI-pervasive society. This keynote aims to unite the iLRN community in a collaborative journey towards a future where immersive learning research and practice coalesce, paving the way for innovative educational research and practice landscapes.
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Thematic analysis in qualitative research is a time-consuming and systematic task, typically done using teams. Team members must ground their activities on common understandings of the major concepts underlying the thematic analysis, and define criteria for its development. However, conceptual misunderstandings, equivocations, and lack of adherence to criteria are challenges to the quality and speed of this process. Given the distributed and uncertain nature of this process, we wondered if the tasks in thematic analysis could be supported by readily available artificial intelligence chatbots. Our early efforts point to potential benefits: not just saving time in the coding process but better adherence to criteria and grounding, by increasing triangulation between humans and artificial intelligence. This tutorial will provide a description and demonstration of the process we followed, as two academic researchers, to develop a custom ChatGPT to assist with qualitative coding in the thematic data analysis process of immersive learning accounts in a survey of the academic literature: QUAL-E Immersive Learning Thematic Analysis Helper. In the hands-on time, participants will try out QUAL-E and develop their ideas for their own qualitative coding ChatGPT. Participants that have the paid ChatGPT Plus subscription can create a draft of their assistants. The organizers will provide course materials and slide deck that participants will be able to utilize to continue development of their custom GPT. The paid subscription to ChatGPT Plus is not required to participate in this workshop, just for trying out personal GPTs during it.
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The Moon Orbital Triangle (General discussion) (I)
1. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Moon Orbital Triangle (General discussion) (I)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –26th
November 2020
Abstract
Paper hypothesis
- The moon has 2 orbits for its motion
- The second orbit is declined by 0.8 degrees on the 1st
orbit (the moon orbital
triangle)
- The 2 orbits are neighbor and define together the lunar eclipse umbra length (1.392
mkm)
- Venus axial tilt is an effective player in the moon orbital triangle structure
Paper argument
- The paper analyze the moon motion data to conclude this 2nd
moon orbit place and
direction.
2. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
2
1- The Moon Orbital Triangle Data
Let's review The Earth Moon Orbital Triangle because we use it
Figure No. (1) (my figure)
Please Note
(1) SZ = 7665 km ZF = 2414 km
- CZS = 77.8 degrees CZF =102.195 degrees
(2) DY = 3475 km BCY = 28.39 degrees
(3) XB = 16203 km XCB = 10.67
- XCE = 66 degrees CX = 87513 km
3. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
3
Let's Review The Moon Orbital Triangle Data
(1st
Point)
- The figure I brought from internet to use in the Explanation -
- We have supposed that the inner circle is Perigee orbit and
the outer circle is apogee orbit – and we have calculated the
tangent DB = 181843 km
- AB = 363686 km (= perigee radius approximately)
- Perigee radius r =0.363 mkm Apogee radius r =0.406 mkm
- Based on that, the triangle (ODB) is a specific Pythagoras
triangle (1, 2 and 51/2
)
- The triangle (ODB) angles are 26.564 deg. and 63.435 deg.
(2nd
Point) The Moon Orbital Triangle Data Correction
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373000 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT
the moon position in T. solar eclipse, because the distance BC= 86000 km but the
distance between perigee point and total solar eclipse point = 11000 km)
- BS= (the moon Circumference) =10921 km
- BZ = 18586 km BF =21000 km
- BD = DA = 43000 km (BY =46475 km)
- BA = BC = 86000 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF= 88526.8 km CD =96150.9 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg)
(ACD = 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.92 deg) (
- (Uranus axial tilt = 97.8 degrees = FSC 0.6 degrees)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees
4. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
4
Figure No. 2 (The Moon Diameter Division)
- The moon diameter is divided into small diameters as following:
- The Blue Circle its diameter R1= 1390 km and r1 =695 km
- The Red Circle its diameter R2= 2085 km and r2 =1042.5 km
- The Black Circle its diameter R3= 2185 km and r3 =1092.5 km
- The Brown Circle its diameter R4= 3208 km and r4 =1604 km
- The Orange Circle is the moon itself its diameter R5= 3475 km
- The red horizontal line is the moon orbital triangle base (AE = 449197 km)
- The blue vertical line is Uranus axial tilt (97.8 degrees), and in the center of the
moon diameter is found the moon axial tilt (6.7 degrees), i.e. the angle in the
center is 91.1 degrees and the value 1.1 degrees is consumed in the moon diameter
(0.5 degrees) and in the green box (0.6 degrees) (the green box shows a
cooperation between Jupiter and Saturn to produce the moon orbit)
- The angle at (S) = 90 degrees (Perpendicularity).
- The angle above the moon diameter = 90.6 degrees
- The moon consumes 0.5 degrees for its diameter (3475 km) for that, I have cut its
diameter into smaller diameters to decrease the consumed value (0.5 degrees), for
that, at R1 = 1390 km, the consumed angle will be 0.2 degrees i.e. the angle above
The Blue Circle = 90.9 degrees.
5. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
5
- R2= 2085 km (60% of the moon diameter) and because of that, the consumed angle
will be only 0.3 degrees, means, the angle above The Red Circle =90.8 degrees
i.e.
- 90.8 degrees = 90 degrees + 0.8 degrees (Uranus orbital inclination), by that the
rest degree of Uranus axial tilt = its orbital inclination vertically.
Notice No. 1
- 149.6 mkm (Earth Orbital Distance) = 3475 km (the moon diameter) x 43000 km
(the distance from perigee to apogee)
- 149.6 mkm (Earth Orbital Distance) = 2085 km (R2) x 71492 km (Jupiter Radius)
Notice No. 2
- We will need these 2 figure in our following investigation because of that I insert
them here to be our discussion reference – let's start our discussion.
6. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
6
2-Venus Effect On The Moon Orbital Triangle
2-1 The Triangle BCF Analysis
- BC =86000 km
- BF = 21000 km
- CF =88527 km
- BCF = 13.7 degrees
- BFC = 76.3 degrees
- The line CB is perpendicular on FB (90 degrees) but
- The line CB has an angle 91.1 degrees on the black line
base (under the blue circle "the moon")
Equation No. (1)
1259.3 degrees = 91.9 degrees x 13.7 degrees
- The angle 13.7 degrees (=BCF)
- We have no 91.9 degrees! We have only 91.1 degrees and that means there's
another angle is added here (0.8 degrees) what's this angle? This is our
(1st
Question)
- We have 2 points here to investigate… which are
o (1st
point) To analyze the triangle BCF because of the angle 13.7 degrees
And
o (2nd
point) To analyze the angle 1259.3 degrees other using…
(1st
point)
The triangle BCF
- Its perimeter = 195527 km but (2x 195527 = 391054 km) …..And
- BF = 21000 km and EB = perigee radius = 363000 km means EF = 384000 km
- (384000 km)2
+ (86000 km)2
= 393512 km
- The difference between the 2 values = 0.6% or around 2500 km while the
distance from perigee to apogee =43000 km, means the rate around 5.7%.
7. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
7
- The calculation is clear and puzzled, because the double value of the triangle
perimeter = The Triangle Base + Perigee Radius
- What geometrical reason behind this calculation, because it tells us that, the
triangle perimeter (knows!!) the perigee radius r= 363000 km, which is not part of
this triangle at all-
- Any way the dimension (86000 km) is part of the triangle but how this dimension
tells to the triangle perimeter about the perigee radius?!
- What's common between the triangle EBC (which has the perigee radius as one
dimension) and the triangle BFC (whose its double perimeter is produced by
Pythagoras rule? (Why does the moon use Pythagoras rule, Do we remember?)
what's the common value between these 2 triangles ( EBC and BFC)??
o 13.328 degrees the angle (E) in the triangle EBC
o 13.7 degrees the angle (BCF) in the triangle BCF
Equation No. (2)
I - (365.25 days /354.39 days) = 13.736 /13.328
II- (2.6 degrees /2.5 degrees) = 13.7 /13.18
- Equation (2) (I), shows that, the required rate is used between the lunar synodic
year and the sidereal year
- Equation (2) (II), shows that, 2.5 degrees = Saturn Orbital Inclination) deals with
(2.6 degrees = 180 deg – 177.4 deg (Venus Axial Tilt). We know that, the moon
daily motion =13.18 degrees.
- What's the useful result for this equation no. (2)? Why we searched for it? the
triangle (BCF) tells us that, its perimeter (or circumference) knows perigee radius
dimension which is not included in this triangle, we don't know how this triangle
catch this information – so we have searched for something common between the
2 triangles, the most near value is the angles (13.328 and 13.7), and we analyze
them here to know how these 2 angles connects the triangle BCF with the great
triangle EBC?
8. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
8
- Equation no (20 (I) tells that the value (13.7 deg) depends on the value (13.3)! if
365.25 days depends on 354.39 days or vice versa?
- We accept that the moon motion depends on earth motion and that may cause the
rate (365.25/354.39) is created by some dependency…
- That means, there's some hidden machine connects the angle 13.3 and 13.7 degrees
and that causes perigee radius to be included in the triangle BCF perimeter, may
later we can discover this geometrical machine.
(2nd
Point)
Let's analyze this value angle (1259.3 degrees)
- 177.4 deg (Venus axial tilt) +2.5 deg (Saturn orbital inclination) = 179.9 degrees
- 179.9 degrees x 7 deg (Mercury orbital inclination) =1259.3 degrees2
- We know this value, let's remember it here
o Because of the planets (Mars And Pluto) migration, the solar system basic
geometrical structure has changed, and because of that, the value 180
degrees is destroyed in the solar system
o Venus and Saturn together unified their powers to create another (180 deg)
but
o The available value was only 179.9 degrees, so the solar system has to use
this value 179.9 degrees in the geometrical process in place of 180 degrees
o As a proof for that
o 180 degrees x 0.8 =225 but 179.9 degrees x 0.8 = 224.7 degrees (224.7 days
= Venus Orbital Period)
i.e.
o The solar geometrical structure depends on 179.9 degrees in place of
180 degrees.
9. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
9
Equation No. (3)
2094 degrees x 0.6 degree = 1259.3 degrees2
- 0.6 degrees is the angle created by the green box in figures (no. 1 and 2), it's found
above the moon and under the moon orbital triangle base (AE) = 449197 km -
- 2094 mkm = Jupiter Uranus Distance
- We know that 1 mkm = 1 degree, where Mercury orbital circumference =360 mkm
= 360 degrees, and the solar system is one machine, so any planet use this rate.
- i.e. 2094 mkm = 2094 degrees
- But
- The distance 2094 mkm (Jupiter Uranus Distance) is so important in our
discussion about the moon orbital triangle, because the data tells that this distance
effects on the triangle data- but how – because it's just a distance?! Let's review its
analysis as possible to see what effect this distance (2094 mkm) can practice on
the moon orbital motion…
o Light known velocity (0.3 mkm/sec) travels this distance in 6939.75 seconds
o The value 6939.75 seconds = 71 x 97.8 seconds
o We know that 71 is Lorentz Length Contraction Effect Rate
o 97.8 degrees = Uranus Axial Tilt, the blue line in figure no. 2, and we
know that, light motion can use the time periods as distances (because x =ct
and if c=1 so x=t) (where 1 mkm=1 degree, so 97.8 s= 97.8 mkm =97.8 deg)
where (97.8 s x 0.3 mkm/s =29.33 mkm and 29.33 mkm x 97.8 = 2872.5
mkm = Uranus Orbital Distance – that means Uranus orbital distance also is
created base on (97.8s) and not only Uranus axial tilt.
Also
o 2094 seconds x 0.3 mkm /sec (light known velocity) =627 mkm = Earth
Jupiter distance – that means, by using this distance (2094 mkm) as a period
of time (2094 seconds) the light travels from Jupiter to Earth
10. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
10
Notice No. 1
o Based on that, the light almost travels from Earth to Jupiter and then to
Uranus, it's one light beam starts from Earth to Jupiter and then to Uranus,
how we know this is the direction and not the reversed one? because 1.2
mkm = 40080 seconds x 29.8 km/sec (Earth velocity), where Earth saves a
value 40080 and rest (1.16 mkm/sec) Earth sent to Jupiter, this is Jupiter
light supposed velocity (1.16 mkm/sec), that means Earth motion is Jupiter
source of energy…
Notice No. 2
o Earth orbital distance (149.6 mkm) = Jupiter diameter (142984 km) x 1047
(where 1047 = the sun mass / Jupiter mass), that shows Earth orbital
distance is defined by Jupiter mass effect on the sun gravity
Also
o 14298 km (Jupiter diameter) = 13.1 x 10921 seconds, the Equation tells that
Jupiter velocity 13.1 km/sec needs to move during 10921 seconds to pass a
distance = 142984 km, (where the Earth moon circumference =10921 km).
Notice No. 3
o Please remember in the moon diameter division we have found 2 diameters
(R2) =2085 km and we know that the moon orbital diameter =1 mkm
because of that this value 2085 km can be 2085 million km and be the
distance which we deal with here… Please remember, above this diameter
(2085 km) the blue line has an angle =90.8 degrees accurately which =
Uranus orbital inclination vertically (0.8 deg + 90 deg) – can be there a
geometrical connection between these 2 values 2085 mkm and 2085 km?
Notice No. 4
o The distance (2094 mkm) is very puzzled one, because it has different
values as (2094 mkm –2088 mkm- 2082 mkm – 2107 mkm), the differences
11. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
11
are so small (less than 1%) but these are different values because they are
used by these values in very accurate equations….
o For example
o Light known velocity (0.3 mkm/sec) during 6939.75 s moves 2082 mkm
But
o Light supposed velocity (1.16 mkm/sec) during 3600 s moves 2088 mkm
o Because of light motion, I prefer to use the value 2082 or 2088 mkm.
But
- 2073 degrees = 2073 mkm = 0.99 x 2094 mkm
o 2073 mkm = 1153 mkm (the planets motion distances total during their
days periods) x 1.8 deg (Neptune orbital inclination)
o 2073 mkm = 175.94 mkm x 11.8 deg (11.8 deg=6.7 deg the moon axial tilt
+ 5.1 deg = the moon orbital inclination) but (175.94 days = Mercury day
period, where Venus moves during 365.25 days a distance=2π x 175.94mkm
o 2073 degrees = 1440 x 1.44 deg (the moon orbit regression monthly)
o 2073 degrees=12.195 degrees (the moon daily motion deg13.18– 0.985 deg)
x 170 where (170 deg = 6.7 deg x 25.2 deg Mars Axial Tilt = 11.8 deg (the
moon axial tilt + orbital inclination) x 14.4 degrees (in the moon orbital
triangle this angle = E angle (13.3 deg +1.1 deg) the angle under E
- Please remember, Uranus axial tilt (97.8 degrees) has an angle (91.1 degrees)
with the moon axial tilt (6.7 deg).. but Uranus is perpendicular on the moon orbital
triangle based (EA =449197 km), because Uranus creates an angle 1.1 degrees
between the triangle base and the horizontal level (where this horizontal level is
the moon axial tilt 6.7). and this angle (1.1 degrees) is found under (E) as shown in
the moon orbital triangle. So (E angle =13.3 degrees +1.1 = 14.4 degrees)
12. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
12
Also
Equation No. (4)
2073 degrees/1259.3 degrees = 327.6 /540
- 327.6 days = the lunar sidereal year
- 540 seconds x 1.16 mkm/sec (light supposed velocity) = 627 mkm = Earth Jupiter
distance
- Equation no. (4) makes the days are equivalent to seconds, it's an application my
research 2nd
hypothesis which is (light motion for 1 second cause planet motion for
1 solar day) –
- I try to show that, it's a complex machine by which the planets move, i.e. planet
motion can't be considered as result of rigid body mechanics, because the light
motion is part can't be departed from planet motion and planet motion depends on
light motion…
Please Note.
- The Equation (2073 degrees = 2073 mkm = 0.99 x 2094 mkm) gives us again the
rate 0.99 which we have found frequently in different data and I supposed this rate
is found by light motion effect- now this puzzle is solve because
o Uranus Axial Tilt =97.8 degrees
o Sin (97.8) = 0.99
o That means, all values used the rate 0.99 are effected by Uranus Axial Tilt,
and we know that Uranus axial tilt is so strong value and it's produced
directly by light motion as we remember (6939.75 =71 x 97.8)
13. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
13
2-2- The Angle 1259.3 Deg
We still discuss equation no. 1 but before let's take look on one more equation
Equation No. (5)
1259.3 degrees = 95.6 degrees x 13.18 degrees
- 95.6 degrees =90+5.6 degrees and 5.6 degrees = 0.5 degree +5.1 degrees (the
moon orbital inclination), and that means, the value 5.6 degrees is measured above
the moon diameter (the moon diameter consumes 0.5 degree).
- 13.18 degrees = The Moon Motion Daily
- Equation no. (5) tells that, the value 1259.3 degrees is defined based on the moon
motion data!
- But
- We know that 1259.3 deg =7 deg x 179.9 deg and 179.9 deg =177.4 deg+2.5 deg,
so it's some strange to define this value by the moon motion data, because the
value (1259.3 deg) is consisted of many players and how can be defined only by
the moon motion data?!
Let's now return to Equation no. (1) it may help our investigation greatly
Equation No. (1) (continued)
1259.3 degrees = 91.9 degrees x 13.7 degrees
- What's the key of this equation? It's the value 91.9 degrees
- We have no this value in the moon orbital triangle, Uranus Axial Tilt (97.8 deg)
creates and angle =91.1 degrees with the Moon Axial Tilt (6.7 deg) and this angle
91.1 deg is decreased by the moon diameter with 0.5 degree and by the green box
(in the figure) by 0.6 degrees and then the angle between the triangle base (EA)
and Uranus axial tilt will be 90 degrees
- So how to find this angle 91.9 degrees we need 0.8 deg +91.1 deg to produce this
angle 91.9 degrees? So from where we can find this angle (0.8 degree )
- From the 2nd
orbit of the moon motion
Let's summarize this idea in following:
14. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
14
The 2nd
Orbit For The Moon Motion:
- The moon does 2 displacement each equal (88000 km) so the total displacements =
2 x 88000 km (why?)
- One displacement we see because the moon moves it through its orbit very near to
Earth, but the other displacement the moon moves on earth orbital circumference
revolving around the sun, so we don't see it
- So another displacement is passed by the moon in addition to the one which we see
(88000 km).
- This second displacement is moved in 2nd
orbit for the moon motion –
- So where is the orbit – spite we don't see the displacement motion we can conclude
the 2nd
orbit position based on the moon orbital triangle
- So where is this 2nd
orbit …?
- The 2nd
moon orbit direction is defined by Equation no. (1)
Equation No. (1) (continued 2)
1259.3 degrees = 91.9 degrees x 13.7 degrees
- The angle 91.9 degrees =91.1 degrees +0.8 degrees
- We have the angle 91.1 degrees and then will add also 0.8 degree and this will
be the moon orbit direction …
- The 2nd
orbit should be a neighbor for the 1st
one – simply the 2 moon motion
orbits together define the lunar eclipse umbra length (1.392 mkm)
- In the moon orbital triangle, after the point(A) in the opposite direction to of Earth,
the distance from this point (A) to the end of the lunar eclipse umbra length
defined the second orbit…
- Shortly
- The distance from the point (A) to the End of the lunar eclipse umbra = 1.392
mkm – 449197 km = 942803 km
- And this value 942803 km = the moon orbital triangle (ABC) Perimeter,
- That means the point (A) separates between 2 orbits of the moon motion,
15. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
15
- That also explains why this triangle (ABC) perimeter x 2 =1.88 mkm which is
equivalent to 1.9 degrees (Mars orbital inclination).
- But why the value 1259.3 degrees is defined by the moon motion?
Equation No. (6)
- 180.8 degrees – 91.9 degrees = 88.9 degrees
- 180.8 degrees = 177.4 deg (Venus axial tilt) + 3.4 deg (Venus orbital inclination)
- 91.9 degrees our angle (Equation n. 1)
- 88.9 degrees is the angle ECZ
- Why this angle 88.9 deg is distinguished? Because the hypotenuse CZ =88000 km
the moon daily displacement –
- That tells, Venus data (177.4+3.4) is created in this interaction under the moon
orbital triangle – basically Venus diameter =1.774 x Mars diameter and Venus
axial tilt be 1.774 x 100 = 177.4 deg because of the interaction occurred under the
moon orbital triangle and by that Venus axial tilt became 1.774 and because of the
Green box in the figure (shows Jupiter and Saturn Interaction), because of that, a
deep interaction is happened between Saturn and Venus based on it the value 179.9
deg is created (177.4 deg +2.5 deg) – and the moon orbital inclination be created in
consistency with this data 180-177.4 =2.6 x 2=5.2 (where 5.1 the moon orbital
inclination + 0.1 degree is consumed for mars orbital inclination which was 1.8
degrees and became 1.9 degrees)
Conclusion
- The moon has 2 orbits for its motion
- The second orbit is declined by 0.8 degrees on the 1st
orbit (the moon orbital
triangle)
- The 2 orbits are neighbor and define together the lunar eclipse umbra length (1.392 mkm)
- Venus axial tilt is an effective player in the moon orbital triangle structure
16. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
16
The Moon Orbital Motion (Revision)
- Please remember why we need the moon orbital triangle….
o The moon daily displacement =88000 km but the moon doesn’t use it as its
real displacement but instead the moon uses Pythagoras triangle to define its
real displacement
o Based on that
o The moon uses the right triangle dimension (L= 88000 km Cos θ) where
this (L) is the moon real displacement through its orbit daily
o The angle (θ) is the smallest angle in the right triangle, and it effects on the
moon real displacement and its height in motion above perigee radius!
o Why?
o Because the displacement 88000 km during 29.53 days is a great distance
can be provided only by the apogee orbit whose radius (r=0.406 mkm) so if
the moon uses only 88000 km as a real displacement daily, the moon would
move only through apogee radius
o But
o Because the moon uses real displacement technique (L= 88000 km Cos θ)
so the moon has the ability to move through lower orbits with the Earth, and
based on that, when the angle θ be smaller the real displacement be greater
and needs more wide orbit to be performed which force the moon to move
in high orbits above perigee radius (r=0.363 mkm).
o Then based on that I have suggested the moon motion equation which is
Gerges Equation For The Moon Orbital Motion
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
o Then by more analysis, we have discovered that, a 2nd
force effects on the
moon orbital motion and this force effects on the point (A) in the moon
orbital triangle – where this point is an essential part of the triangle while it's
far from apogee radius with 43000 km
o The 2nd
force is a result of interaction gravity forces between the sun, Earth
and Jupiter on 2 points (Earth and its moon), and because of this interaction
Jupiter causes some gravity force (10% of Earth gravity force) to be effected
on the point (A) and causes the moon motion to apogee radius.
o Then Uranus axial tilt perpendicularity effects analysis gives us the
suggestion that another orbit must be found for the moon motion and this
orbit is found under the first one as described in the following figure.
17. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
17
References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
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