This document presents a hypothesis that Earth's motion is the source of light energy in the solar system. The author proposes that Earth's velocity around the sun produces a beam of light equal to the supposed velocity of light. Various equations are presented analyzing distances, velocities, and time periods related to Earth's orbit and the orbits of other planets and celestial bodies. The author concludes that Earth is the source of energy for the entire solar system. References are provided for the author's other works on similar topics analyzing planetary motion and trajectories.

1. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Light Energy Source
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –22nd
November 2020
Abstract
Paper hypothesis
The light supposed velocity 1.16 mkm/sec energy source is Earth motion
The hypothesis explanation
- 29.8 km /sec (Earth velocity) x 40080 seconds (Earth circumference 40080 km is
used as a period of time) = 1.2 million /km
- The result 1.2 mkm = 1.16 mkm/sec + 40080 km /sec
- A light beam 1.16 mkm/sec is sent from Earth to Jupiter – this is Jupiter Energy
source
- 40080 k/sec is a velocity used by Earth in the sun rays production equation.
Paper conclusion
- Earth is the source of the solar system energy.

2. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
2
1- Earth Circumference Analysis
Earth Circumference 40080 km
I- Data
Equation No. 1
51118 km Uranus Diameter = 4.7 km/sec (Pluto velocity) x 10921 seconds
Equation No. 2
2π x 51118 km Uranus Diameter= 2π x 4.7 km/s (29.8 km/s Earth velocity) x 10921s
(29.8 times x 29.53 days =880 days= 10 x 88 days)
Equation No. 3
2π x 51118 km Uranus Diameter = 8 x 40080 km (Earth Circumference)
Equation No. 4
346.6 days (Nodal Year) = 8 x 43.3 days
43.3 days = 1042.5 hours = (153.3 h x 6.8) Because 51118 km = 6.8 km/s x 7511
Equation No. 5
2.58 mkm = 7511 x 346.6 (Error 1%) (346.6/153.3)= 2.26
Equation No. 6
2.58 mkm per solar day x 10 = 2390 km (Pluto diameter) x 10921 (1%)
(2.58 mkm = Earth motion distance per solar day = Pluto motion distance during its
day period = the earth moon motion distance during its day period)
10921 km = 1.0725 x 10182
Equation No. 7
300000 km /s (light velocity) = 29.8 km/s (Earth velocity) x 10067 (10182) (1%)
Equation No. 8
300000 km /sec (light velocity) = 29.8 km/sec (Earth velocity) x 5040 x 2
Equation No. 9
2.58 mkm = 2π x 51118 km Uranus Diameter x 8
2.58 mkm = 40080 km (Earth Circumference) x 82
= 64
Please remember
Equation No. 10
10921 km = 4.7 km/sec (Pluto velocity) x7511 seconds (2.8%)
Equation No. 11
2x 378674 km = 4.7 km/sec (Pluto velocity) x 160592 seconds

3. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
3
II- Discussion
How To Understand The Previous Data?
Please consider the following order for these 4 equations:
Equation No. 10
10921 km = 4.7 km/sec (Pluto velocity) x7511 seconds (2.8%)
Equation No. 1
51118 km Uranus Diameter = 4.7 km/sec (Pluto velocity) x 10921 seconds
Equation No. 11
2x 378674 km = 4.7 km/sec (Pluto velocity) x 160592 seconds
Equation No. 2
2π x 51118 km Uranus Diameter= 2π x 4.7 km/s (29.8 km/s Earth velocity) x 10921s
(29.8 times x 29.53 days =880 days= 10 x 88 days)
Equation No. 6
2.58 mkm per solar day x 10 = 2390 km (Pluto diameter) x 10921 (1%)
(2.58 mkm = Earth motion distance per solar day = Pluto motion distance during its
day period = the earth moon motion distance during its day period)
What is happening here?
- Pluto uses its circumference (7511 km) as a period of time to move a distance
=10921 km = the Earth moon circumference (equation No. 10)
- Then Pluto uses this distance (10921) as a period of time to produce a distance =
51118 km (Uranus diameter) (equation No. 1)
- Then Pluto uses this distance (51118 x π) as a period of time to produce a distance
= 2 x 378674 km (Saturn circumference) (equation No. 11)
- Then Pluto uses this distance (51118 x 2π) relative to 10921 value to produce the
velocity (29.8 km/s Earth velocity) (equation No. 2)
- The rate 10 is transported from Equation No. (2) to Equation No. (6)
- That's why Earth velocity can be equal light velocity only by using Mercury day
period data (5040 seconds x 2)
- Simply the planets circumference is used as a period of time in the solar system
geometrical structure –

4. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
4
Let's review The Earth Moon Orbital Triangle because we use it
Figure No. (1) (my figure)
Please Note
(1) SZ = 7665 km ZF = 2414 km
- CZS = 77.8 degrees CZF =102.195 degrees
(2) DY = 3475 km BCY = 28.39 degrees
(3) XB = 16203 km XCB = 10.67
- XCE = 66 degrees CX = 87513 km

5. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
5
Let's Review The Moon Orbital Triangle Data
(1st
Point)
- The figure I brought from internet to use in the Explanation -
- We have supposed that the inner circle is Perigee orbit and the
outer circle is apogee orbit – and we have calculated the tangent
AB = 181843 km
- AB = 363686 km (= perigee radius approximately)
- Perigee radius r =0.363 mkm Apogee radius r =0.406 mkm
- Based on that, the triangle (ODB) is a specific Pythagoras triangle (1, 2 and 51/2
)
- i.e. the triangle (ODB) angles are 26.564 degrees and 63.435 degrees
NOTE
- for these 2 angles (26.564 deg and 63.435 deg) we have searched, because these 2
angles will correct many data in the orbital triangle.
(2nd
Point) The Moon Orbital Triangle Data Correction
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373000 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT
the moon position in T. solar eclipse, because the distance BC= 86000 km but the
distance between perigee point and total solar eclipse point = 11000 km)
- BS= (the moon Circumference) =10921 km
- BZ = 18586 km BF =21000 km
- BD = DA = 43000 km (BY =46475 km)
- BA = BC = 86000 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF= 88526.8 km CD =96150.9 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg)
(ACD = 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.92 deg) (
- (Uranus axial tilt = 97.8 degrees = FSC 0.6 degrees)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees

6. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
6
The Moon Orbital Motion
- Please remember why we need the moon orbital triangle….
o The moon daily displacement =88000 km but the moon doesn’t use it as its
real displacement but instead the moon uses Pythagoras triangle to define its
real displacement
o Based on that
o The moon uses the right triangle dimension (L= 88000 km Cos θ) where
this (L) is the moon real displacement through its orbit daily
o The angle (θ) is the smallest angle in the right triangle, and it effects on the
moon real displacement and its height in motion above perigee radius!
o Why?
o Because the displacement 88000 km during 29.53 days is a great distance
can be provided only by the apogee orbit whose radius (r=0.406 mkm) so if
the moon uses only 88000 km as a real displacement daily, the moon would
move only through apogee radius
o But
o Because the moon uses real displacement technique (L= 88000 km Cos θ)
so the moon has the ability to move through lower orbits with the Earth, and
based on that, when the angle θ be smaller the real displacement be greater
and needs more wide orbit to be performed which force the moon to move
in high orbits above perigee radius (r=0.363 mkm).
o Then based on that I have suggested the moon motion equation which is
Gerges Equation For The Moon Orbital Motion
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
o Then by more analysis, we have discovered that, a 2nd
force effects on the
moon orbital motion and this force effects on the point (A) in the moon
orbital triangle – where this point is an essential part of the triangle while it's
far from apogee radius with 43000 km
o The 2nd
force is a result of interaction gravity forces between the sun, Earth
and Jupiter on 2 points (Earth and its moon), and because of this interaction
Jupiter causes some gravity force (10% of Earth gravity force) to be effected
on the point (A) and causes the moon motion to apogee radius.
o Then Uranus axial tilt perpendicularity effects analysis gives us the
suggestion that another orbit must be found for the moon motion and this
orbit is found under the first one as described in the following figure.

7. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
7
A Model For The Moon Motion 2 Orbits

8. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
8
References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
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