Describes the geometrical
       formulas ball and cone


Members :
1. Andre djisa alhesi samosir
2. Dicky rachmat fauzi
3. Erlangga putra ramadhan
4. Haekal roja
5. Jihan fachry widyatmoko
6. Yogas adi pratama
   Cone
    1. Geometrical cone is bounded by a circular base side and a
       curved side .                                       T


    = elements of cone =
    1. A cone has 2 planes . Namely the
       base and the right planes
    2. A cone has an edge , that is the base
       edge which is in the form of circle
    3. The line segment joining point t and
       T1 is called the height of the cone       A         T1      B
    4. TA and TB are called slant heights.
= cone net =
1. To know the net of a cone              T
   suppose the cone in figure 2 is
   cut along segment TA and its
   base circumference , the cuts     s
   will produce the figure on the
   figure 1.                              1
2. The figure 1 shows the net of a                2
   cone , the cone consist of a    A          B
   circle and a curved surface in
   the form of a circle sector .

                                         T1
= surface area of a cone =
We need to know that, the surface of         L = surface area
the cone consists of two fields, namely      Ba = base area
the curved area (blanket) and a              Cs = curved area
circular base field.                         Sa = surface area


Formula of the surface area of a cone :
L = area of curved surface + circle area
L = ∏ r s + ∏ r2
L=∏r (s+r)

Example :
Known : d : 10 , t : 12 , Cs : 204,1 , Ba : 78,5
Find : Sa
Answer :
L = Cs + Ba => 204,1 + 78,5 = 282,6 cm2
= volume of cone =
Formula of volume of cone :
 ∏ x r x r x h : 3 (∏ x r2 x h x 1/3)


 Example :
 Known : d : 14 , t : 18 , ∏ : 22/7
 Find : volume
 Answer :
 Volume : ∏ x r2 x h x 1/3 => 22/7 x 7 x7 x 18 x 1/3 = 924
=the ratio of cone because of the change=
                   in radius
Figure 1 illusrates a cone of base radius r1 and
height t .                                         1
If the base radius r1 is extended twice longer
while the hight is constant , we have a cone in
figure 2 of base radius r2 = 2 r1 and height t

Then :
 v1 = 1/3 ∏ r21 t

 v2       1/3 ∏ r2 2 t                             2

 v1   =   1/3 ∏ r21 t        v1 = r21

 v2       1/3 ∏ (2r 2 ) t      v2   4 r2 1
 v1   =   1  v2 = 4 v 1
 v2       4
Example :
Known : r : 6 , ∏ : 22/7
Find : the volume of the cone if the becomes 2x the original
Answer :
V = 1/3 ∏ r2 t  1/3 x 22/7 x 6 x 6 x 21 792
r1= 2r then v1 = 22 v  4 x 792 = 3.168
Cones in daily life
   Sphere
Sphere represent a curved surface


= elements of sphere =
1. Point O is the centre of the sphere
2. DO , AO ,BO , CO etc called radius of sphere
3 .DC , AB etc is called diameter of sphere
4. A sphere only has one curved surface
5. A sphere doesn’t have a vertex nor an edge         C


                                                  A   O   B



                                                      D
= sphere net =
We can’t make a net from a sphere
= the surface area of a sphere =
 Sa of a sphere= 2 x the area hemisphere  2 x ( 2 x ∏ r2 ) =
 4∏r2
 example :
 Known : r : 10,5 , ∏ : 22/7
 Find : Sa
 Answer :
 L = 4∏r2  4 x 22/7 x 10,5 x 10,5 = 1,386
= volume of sphere =
v = 4 x the cone volume  4 x 1/3 ∏ r2 t  4/3 ∏ r2 t
Since the height of the cone = the ball radius , or t = r
The ball volume : 4/3 ∏ r2 t = 4/3 ∏ r3

Example :
Known : d : 12 , ∏ : 3,14
Answer :
V : 4/3 x ∏ x r3  4/3 x 3,14 x 6 x 6 x 6 = 904,32 cm cm3
the ratio of the sphere volume because of
               the change in radius
 If the radius of a sphere is extented n times the original , then
 the
 volume of the sphere enlarges n3 times the original volume , in
 other words v1 : v1 = 1 : n3

Example :
Known : v : 113,04 cm3
find : 3/2 times the original length
Answer :
 r1 = 3/2 r => v1 = (3/2)3 v = 27/8 x 113,04 = 381,51
Thank you for your attention




Success comes to those who would still try though never do
 wrong. Those who never give up, because the spirit is still
                         there.

Rangga 9e

  • 1.
    Describes the geometrical formulas ball and cone Members : 1. Andre djisa alhesi samosir 2. Dicky rachmat fauzi 3. Erlangga putra ramadhan 4. Haekal roja 5. Jihan fachry widyatmoko 6. Yogas adi pratama
  • 2.
    Cone 1. Geometrical cone is bounded by a circular base side and a curved side . T = elements of cone = 1. A cone has 2 planes . Namely the base and the right planes 2. A cone has an edge , that is the base edge which is in the form of circle 3. The line segment joining point t and T1 is called the height of the cone A T1 B 4. TA and TB are called slant heights.
  • 3.
    = cone net= 1. To know the net of a cone T suppose the cone in figure 2 is cut along segment TA and its base circumference , the cuts s will produce the figure on the figure 1. 1 2. The figure 1 shows the net of a 2 cone , the cone consist of a A B circle and a curved surface in the form of a circle sector . T1
  • 4.
    = surface areaof a cone = We need to know that, the surface of L = surface area the cone consists of two fields, namely Ba = base area the curved area (blanket) and a Cs = curved area circular base field. Sa = surface area Formula of the surface area of a cone : L = area of curved surface + circle area L = ∏ r s + ∏ r2 L=∏r (s+r) Example : Known : d : 10 , t : 12 , Cs : 204,1 , Ba : 78,5 Find : Sa Answer : L = Cs + Ba => 204,1 + 78,5 = 282,6 cm2
  • 5.
    = volume ofcone = Formula of volume of cone : ∏ x r x r x h : 3 (∏ x r2 x h x 1/3) Example : Known : d : 14 , t : 18 , ∏ : 22/7 Find : volume Answer : Volume : ∏ x r2 x h x 1/3 => 22/7 x 7 x7 x 18 x 1/3 = 924
  • 6.
    =the ratio ofcone because of the change= in radius Figure 1 illusrates a cone of base radius r1 and height t . 1 If the base radius r1 is extended twice longer while the hight is constant , we have a cone in figure 2 of base radius r2 = 2 r1 and height t Then : v1 = 1/3 ∏ r21 t v2 1/3 ∏ r2 2 t 2 v1 = 1/3 ∏ r21 t  v1 = r21 v2 1/3 ∏ (2r 2 ) t v2 4 r2 1 v1 = 1  v2 = 4 v 1 v2 4
  • 7.
    Example : Known :r : 6 , ∏ : 22/7 Find : the volume of the cone if the becomes 2x the original Answer : V = 1/3 ∏ r2 t  1/3 x 22/7 x 6 x 6 x 21 792 r1= 2r then v1 = 22 v  4 x 792 = 3.168
  • 8.
  • 9.
    Sphere Sphere represent a curved surface = elements of sphere = 1. Point O is the centre of the sphere 2. DO , AO ,BO , CO etc called radius of sphere 3 .DC , AB etc is called diameter of sphere 4. A sphere only has one curved surface 5. A sphere doesn’t have a vertex nor an edge C A O B D
  • 10.
    = sphere net= We can’t make a net from a sphere
  • 11.
    = the surfacearea of a sphere = Sa of a sphere= 2 x the area hemisphere  2 x ( 2 x ∏ r2 ) = 4∏r2 example : Known : r : 10,5 , ∏ : 22/7 Find : Sa Answer : L = 4∏r2  4 x 22/7 x 10,5 x 10,5 = 1,386
  • 12.
    = volume ofsphere = v = 4 x the cone volume  4 x 1/3 ∏ r2 t  4/3 ∏ r2 t Since the height of the cone = the ball radius , or t = r The ball volume : 4/3 ∏ r2 t = 4/3 ∏ r3 Example : Known : d : 12 , ∏ : 3,14 Answer : V : 4/3 x ∏ x r3  4/3 x 3,14 x 6 x 6 x 6 = 904,32 cm cm3
  • 13.
    the ratio ofthe sphere volume because of the change in radius If the radius of a sphere is extented n times the original , then the volume of the sphere enlarges n3 times the original volume , in other words v1 : v1 = 1 : n3 Example : Known : v : 113,04 cm3 find : 3/2 times the original length Answer : r1 = 3/2 r => v1 = (3/2)3 v = 27/8 x 113,04 = 381,51
  • 14.
    Thank you foryour attention Success comes to those who would still try though never do wrong. Those who never give up, because the spirit is still there.