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The 3.4 Chain Rule
2 
Composite Functions
3 
The Chain Rule
4 
Example 1 – Using the Chain Rule 
Find F '(x) if F (x) = . 
Solution 1: 
F (x) = (f ° g)(x) = f (g(x)) where f (u) = and g(x) = x2 + 1. 
Since 
and g¢(x) = 2x 
we have F ¢(x) = f ¢(g(x))  g¢(x)
5 
Chain Rule - Exercise
Generalizing Differentiation Rules 
In general, if y = sin u, where u is a differentiable function of 
x, then, by the Chain Rule, 
6 
Thus 
In a similar fashion, all of the formulas for differentiating 
functions can be combined with the Chain Rule.
7 
Generalized Power Rule
Example 3 – Using the Chain Rule with the Power Rule 
Differentiate y = (x3 – 1)100. 
8 
Solution: 
Taking u = g(x) = x3 – 1 and n = 100 in (4), we have 
= (x3 – 1)100 
= 100(x3 – 1)99 (x3 – 1) 
= 100(x3 – 1)99  3x2 
= 300x2(x3 – 1)99
9 
Power Rule - Exercise
10 
Exponentials base other than e 
We can use the Chain Rule to differentiate an exponential 
function with any base a > 0. Recall that a = eln a. So 
ax = (eln a)x = e(ln a)x 
and the Chain Rule gives 
(ax) = (e(ln a)x) = e(ln a)x (ln a)x 
= e(ln a)x  ln a = ax ln a 
because ln a is a constant. So we have the formula
11 
Exponentials - Example
The Chain Rule-Multiple Iterations 
Suppose that y = f(u), u = g(x), and x = h(t), where f, g, and h 
are differentiable functions. 
Then, to compute the derivative of y with respect to t, we use 
the Chain Rule twice: 
12
13 
Multiple Chain Rule - Example

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Lecture 10 chain rule - section 3.4

  • 3. 3 The Chain Rule
  • 4. 4 Example 1 – Using the Chain Rule Find F '(x) if F (x) = . Solution 1: F (x) = (f ° g)(x) = f (g(x)) where f (u) = and g(x) = x2 + 1. Since and g¢(x) = 2x we have F ¢(x) = f ¢(g(x))  g¢(x)
  • 5. 5 Chain Rule - Exercise
  • 6. Generalizing Differentiation Rules In general, if y = sin u, where u is a differentiable function of x, then, by the Chain Rule, 6 Thus In a similar fashion, all of the formulas for differentiating functions can be combined with the Chain Rule.
  • 8. Example 3 – Using the Chain Rule with the Power Rule Differentiate y = (x3 – 1)100. 8 Solution: Taking u = g(x) = x3 – 1 and n = 100 in (4), we have = (x3 – 1)100 = 100(x3 – 1)99 (x3 – 1) = 100(x3 – 1)99  3x2 = 300x2(x3 – 1)99
  • 9. 9 Power Rule - Exercise
  • 10. 10 Exponentials base other than e We can use the Chain Rule to differentiate an exponential function with any base a > 0. Recall that a = eln a. So ax = (eln a)x = e(ln a)x and the Chain Rule gives (ax) = (e(ln a)x) = e(ln a)x (ln a)x = e(ln a)x  ln a = ax ln a because ln a is a constant. So we have the formula
  • 11. 11 Exponentials - Example
  • 12. The Chain Rule-Multiple Iterations Suppose that y = f(u), u = g(x), and x = h(t), where f, g, and h are differentiable functions. Then, to compute the derivative of y with respect to t, we use the Chain Rule twice: 12
  • 13. 13 Multiple Chain Rule - Example