This learning plan discusses teaching students about the distance formula in mathematics. The objectives are for students to apply the relationship of distance, solve for distance between two points using the distance formula, and show enthusiasm during class discussions. An activity is outlined where students plot coordinates on a Cartesian plane to form a right triangle, and identify the hypotenuse and sides. The teacher then explains how to calculate the length of sides of the triangle using the distance formula by taking the difference between the x- and y-coordinates of two points.

1. LEARNING PLAN IN MATHEMATICS
INSTRUCTIONAL SEQUENCES
I. Objectives:
At the end of the discussion, the students with at least 85% of mastery will be able to:
a. Apply the relationship of distance;
b. Solve the value of distance between two points by the use of distance formula;
c.
d. Show enthusiasm during class discussion.
II. Subject Matter
a. Topic: Distance Formula
b. Reference: Benes, Salita (2008). Painless Math Geometry. Anvil Publishing Inc.
pp. 118-119
III. Procedures:
Daily Routine
 Prayer
 Checking of Attendance
Teacher’s Activity
A. Activity
Before we proceed to our lesson proper for
the day. Let’s have an activity.
Plot these coordinates on our Cartesian
plane.
 (3,2)
 (8,7)
 (8,2)
Who wants to plot the coordinates?
Who wants to name the points?
Students’ Activity
(3,2)
(8,7)
(8,2)
(3,2)
(3,2)

2. Very good. Now who wants to connect the
points?
Very good class! What figure did we form?
Exactly.
Analysis
Based on our activity, what do you call the
̅퐴̅̅퐵̅ in the right triangle?
Very good!
How about ̅퐴̅̅퐶̅ and 퐵̅̅̅퐶̅? What do you call
these line segments?
Very good!
From the figure in the activity, how can we
get the length of ̅퐴̅̅퐶̅?
Who wants to solve on the board?
A right triangle!
Hypotenuse!
Sides of the right triangle!
B
C
B
C
Since ̅퐴̅̅퐶̅ is plotted on the x- axis, we have
to get the difference between x2 and x1.
x2=8, x1=3
x2-x1
= 8-3
= 5
(3,2)
(8,7)
A (8,2)
(3,2)
(8,7)
A (8,2)

3. Very good! How about 퐵̅̅̅퐶̅? How can we get
the length of 퐵̅̅̅퐶̅?
Who wants to solve on the board?
Since 퐵̅̅̅퐶̅ is plotted on the y-axis, we have to
get the difference between y2 and y1.
y2=8, y1=3
y2-y1
= 7-2
= 5