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Gandhinagar Institute of
Technology
Numerical & Statistical Methods
For Information Technology (2140706)
Active Learning Assignment
“Topic : Interpolation for unequal intervals and Lagrange's interpolation”
Name: Vaani Pathak (170120107131)
Branch : CE
Div : B3
Interpolation with unequal intervals
• If the values of x are unequally spaced then interpolation formulae for
equally spaced points cannot be used. It is therefore, desirable to
develop interpolation formulae for unequally spaced values of x.
• There are two such formulae for unequally spaced values of x.
i. Lagrange's interpolation formula.
ii. Newton’s interpolation formula with divided difference.
Lagrange
• Lagrange’s formula is applicable to problems where the independent
variable occurs at equal and unequal intervals, but preferably this
formula is applied in a situation where there are unequal intervals for
the given independent series.
Lagrange's interpolation formula
f(x) = (x-x1 ) (x-x2 )…. (x-xn) y0 + (x- x0) (x-x2)….(x- xn) y1
(x0 - x1 ) (x0 - x2)….(x0 - xn) (x1 – x0)(x1 – x2)….(x1 - xn)
+ (x- x0) (x- x1)….(x- xn-1) yn
(xn – x0) (xn – x1)….(xn – xn-1)
Example :
Compute f(9.2) by using Lagrange's interpolation method from the
following data :
• Solution : By Lagrange's interpolation formula,
f(x) = (x - x1) (x - x2) f(x0) + (x- x0) (x- x2) f(x1) +
(x0- x1)(x0 – x2) (x1- x0)(x1 – x2)
(x – x0) (x – x1) f(x2)
(x2 – x0) (x2- x1)
x 9 9.5 11
f(x) 2.1972 2.2513 2.3973
f(9.2) = (9.2 – 9.5) (9.2 - 11) (2.1972) +
(9 - 9.5) (9 - 11)
(9.2 – 9) (9.2-11) (2.2513) +
(9.5 – 9) (9.5 – 11)
(9.2 – 9) (9.2 - 9.5) (2.3979)
(11 – 9) (11 - 9.5)
= 1.1865 + 1.0806 + 0.048
=2.2191
Thank you

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interpolation of unequal intervals

  • 1. Gandhinagar Institute of Technology Numerical & Statistical Methods For Information Technology (2140706) Active Learning Assignment “Topic : Interpolation for unequal intervals and Lagrange's interpolation” Name: Vaani Pathak (170120107131) Branch : CE Div : B3
  • 2. Interpolation with unequal intervals • If the values of x are unequally spaced then interpolation formulae for equally spaced points cannot be used. It is therefore, desirable to develop interpolation formulae for unequally spaced values of x. • There are two such formulae for unequally spaced values of x. i. Lagrange's interpolation formula. ii. Newton’s interpolation formula with divided difference.
  • 3. Lagrange • Lagrange’s formula is applicable to problems where the independent variable occurs at equal and unequal intervals, but preferably this formula is applied in a situation where there are unequal intervals for the given independent series.
  • 4. Lagrange's interpolation formula f(x) = (x-x1 ) (x-x2 )…. (x-xn) y0 + (x- x0) (x-x2)….(x- xn) y1 (x0 - x1 ) (x0 - x2)….(x0 - xn) (x1 – x0)(x1 – x2)….(x1 - xn) + (x- x0) (x- x1)….(x- xn-1) yn (xn – x0) (xn – x1)….(xn – xn-1)
  • 5. Example : Compute f(9.2) by using Lagrange's interpolation method from the following data : • Solution : By Lagrange's interpolation formula, f(x) = (x - x1) (x - x2) f(x0) + (x- x0) (x- x2) f(x1) + (x0- x1)(x0 – x2) (x1- x0)(x1 – x2) (x – x0) (x – x1) f(x2) (x2 – x0) (x2- x1) x 9 9.5 11 f(x) 2.1972 2.2513 2.3973
  • 6. f(9.2) = (9.2 – 9.5) (9.2 - 11) (2.1972) + (9 - 9.5) (9 - 11) (9.2 – 9) (9.2-11) (2.2513) + (9.5 – 9) (9.5 – 11) (9.2 – 9) (9.2 - 9.5) (2.3979) (11 – 9) (11 - 9.5) = 1.1865 + 1.0806 + 0.048 =2.2191