This document discusses electric potential energy and electric potential. It aims to help readers understand the concepts of electric potential, differentiate it from electric potential energy, and solve problems involving electric potential. It provides examples of calculating electric potential energy and electric potential using the equations U=kq1q2/r and V=kq/r, where U is electric potential energy, V is electric potential, k is Coulomb's constant, q1 and q2 are charges, r is distance. It also gives several practice problems for readers to calculate electric potential energy and electric potential using the provided values and equations.

1. Electric Potential Energy
&
Electric Potential

2. LESSON GOALS
• Understanding the concept of electric potential;
• Differentiate electric potential energy from electric potential; and
• Solving problems involving electric potential.

3. Gravitational Potential Energy

4. 10m
20m
30m
40m
50m
60m
(10m)(9.8m/s2)(2kg) = 196J
(20m)(9.8m/s2)(2kg) = 392 J
(30m)(9.8m/s2)(2kg) = 588 J
(40m)(9.8m/s2)(2kg) = 784 J
(50m)(9.8m/s2)(2kg) = 980 J
(60m)(9.8m/s2)(2kg) = 1176 J
Gravitational Potential Energy
(10m)(9.8m/s2) = 98 J/kg
(20m)(9.8m/s2) = 196 J/kg
(30m)(9.8m/s2) = 294 J/kg
(40m)(9.8m/s2) = 392 J/kg
(50m)(9.8m/s2) = 490 J/kg
(60m)(9.8m/s2= 588 J/kg
Gravitational Potential

5. Real Life Example
Low Potential Region to
High Potential Region,
Work is done.
Gravitational Potential
High Potential
Region
Low Potential
Region
When ball falls from High
Potential Region to Low
Potential Region, it has
K.E.
Change in
position =
G.P.E.

6. High Potential
Region
low Potential
Region
Electric Potential
Low Potential Region to
High Potential Region,
Work is done.
Change in position =
Electric Potential Energy
From High Potential
Region to Low Potential
Region, it has K.E.

7. ELECTRIC POTENTIAL
 It is the amount of work needed to move a unit charge from low
potential to high potential region against an electric field.
 It is simple the measure of the electric potential energy per unit of
charge. (J/C)
𝑉 =
𝐾𝑞
𝑟
or 𝑉 =
𝑈
𝑞
𝑉 = 𝑒𝑙𝑒𝑐𝑡𝑟𝑖𝑐 𝑝𝑜𝑡𝑒𝑛𝑡𝑖𝑎𝑙 𝑖𝑛 𝑣𝑜𝑙𝑡𝑠
𝑘 = 𝐶𝑜𝑢𝑙𝑜𝑚𝑏′
𝑠 𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡 = 9 × 109
𝑁 ∙ 𝑚2
/𝐶2
𝑞 = 𝑐ℎ𝑎𝑟𝑔𝑒 𝑖𝑛 𝐶𝑜𝑢𝑙𝑜𝑚𝑏
𝑟 = 𝑑𝑖𝑠𝑡𝑎𝑛𝑐𝑒 𝑖𝑛 𝑚𝑒𝑡𝑒𝑟

8. ELECTRIC POTENTIAL ENERGY
 It is the energy that is needed to move an electric
charge against an electric field. (J)
𝑈 =
𝐾𝑞1𝑞2
𝑟
𝑈 = 𝑒𝑙𝑒𝑐𝑡𝑟𝑖𝑐 𝑝𝑜𝑡𝑒𝑛𝑡𝑖𝑎𝑙 𝑒𝑛𝑒𝑟𝑔𝑦 𝑖𝑛 𝐽𝑜𝑢𝑙𝑒𝑠
𝑘 = 𝐶𝑜𝑢𝑙𝑜𝑚𝑏′
𝑠 𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡 = 9 × 109
𝑁 ∙ 𝑚2
/𝐶2
𝑞 = 𝑐ℎ𝑎𝑟𝑔𝑒 𝑖𝑛 𝐶𝑜𝑢𝑙𝑜𝑚𝑏
𝑟 = 𝑑𝑖𝑠𝑡𝑎𝑛𝑐𝑒 𝑖𝑛 𝑚𝑒𝑡𝑒𝑟

9. 1. If a charge of magnitude 6.5x10-17C is being
held in place 2x10-8m from a charge of -8x10-19C
which is also being held in place, what is the
electric potential energy of the system?
Given:
Unknown:
Soln:
Final Answer:
Formula:

10. 2. Find the electric potential at a distance of 8cm
from a 7.58pC charge.
Given:
Unknown:
Soln:
Final Answer:
Formula:

11. 3. Calculate the amount of electric potential
energy possessed by 2.52x10-10C at a point
where the electric potential is 4.70 Volts.
Given:
Unknown:
Soln:
Final Answer:
Formula:

12. 4. A particle with a charge of 5nC has a distance
of 0.5m away from a charge of 9.5nC. What is its
electric potential energy?
Given:
Unknown:
Soln:
Final Answer:
Formula:

13. 5. What is the electric potential given 0.58m
away from an 18uC charge?
Given:
Unknown:
Soln:
Final Answer:
Formula: