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Block 1
Circle Tactics
Basic Tactics
If given an equation find
Centre
Radius
Draw diagrams
Straight line stuff vital
If finding equation need
Centre
Radius
esp. dist formula
x2
+ y2
+ 2gx + 2fy + c = 0
(x – a)2
+ (y – b)2
= r2
Terminology
Concentric circles?
Same centre
Congruent
Same shape and size
Diametrically Opposite
Opposite ends of diameter
A
B
Circle Tactics
If given an equation find
Centre
Radius
Draw diagrams
Straight line stuff vital
If finding equation need
Centre
Radius
using x2
+ y2
+ 2gx + 2fy + c = 0
(unless equation given with brackets)
then use (x – a)2
+ (y – b)2
= r2
- especially distance formula
Terminology
Concentric circles?
Same centre
Congruent
Same shape and size
Diametrically Opposite
Opposite ends of diameter
Using Common Sense!
A(1 , 4) and B are diametrically opposite
Centre is (6 , 10) B?
(1,4)
B
(6,10)
use
steps
5
6
5
6
(11,16)
Using Common Sense!
A(2 , 6) and B are diametrically opposite
Centre is (5 , 13) B?
(2,6)
B
(5,13)
use
steps
3
7
3
7
(8,20)
Reminder
Perpendicular Bisector
cut line in half at
right angles x1+x2 y1+y2
2 2
m1m2 = -1
Finding Equation From Points On Circle
If we have three points on a circle A,B and C
then perpendicular bisectors will meet in the
centre.
We can use this to find the equation of a
circle
A (0 , 2) B(1 , 5) and C(4 , 4) lie on a circle.
Find its equation.
Radius
A
B
C
(0 , 2)
(1 , 5)
(4 , 4)
(½, 7
/2)
m1 = 3 m2 = -1
/3
3y = -x + 11
(5
/2 , 9
/2)
m1 = -1
/3
m2 = 3
y = 3x – 3 Lines meet at (2 , 3)
(2 , 3)
√5 (x – 2)2
+ (y – 3)2
= 5
Finding Equation From Points On Circle
If we have three points on a circle A,B and C
then perpendicular bisectors will meet in the
centre.
We can use this to find the equation of a
circle
Equation from 3 Points
Perpendicular Bisectors
m1m2 = -1 mid pt
Centre – Point
of Intersection
Radius
Distance Formula
(y = y or
sim. equations)
Closest Distance
Find the closest distance between
circle A x2
+ y2
– 6x – 2y + 9 = 0
and B x2
+ y2
– 14x – 8y + 61 = 0
(3 , 1)
(7 , 4)
1
2
2
A
B
5
Closest Distance
Closest distance between 2 circles
(given equations)
?
Dist between centres – (sum of radii)
Get centres
Proving Circles Touch Externally
Prove these touch externally
A x2
+ y2
– 6x – 4y – 23 =
0 B x2
+ y2
– 18x – 20y +
165 = 0
(3 , 2) (9 , 10)
A
B
6
4
10
Proving Circles Touch Internally
Prove these touch internally
A x2
+ y2
– 4x – 6y – 51 =
0 B x2
+ y2
– 12x – 12y + 63
= 0
(2 , 3)
(6 , 6) 8
3
5
Proving circles touch at one point
Externally
Dist between centres = Sum of Radii
Proving Circles Touch
Distance between centres
= difference between radii
Internally

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Circle tactics

  • 2. Basic Tactics If given an equation find Centre Radius Draw diagrams Straight line stuff vital If finding equation need Centre Radius esp. dist formula x2 + y2 + 2gx + 2fy + c = 0 (x – a)2 + (y – b)2 = r2
  • 3. Terminology Concentric circles? Same centre Congruent Same shape and size Diametrically Opposite Opposite ends of diameter A B
  • 4. Circle Tactics If given an equation find Centre Radius Draw diagrams Straight line stuff vital If finding equation need Centre Radius using x2 + y2 + 2gx + 2fy + c = 0 (unless equation given with brackets) then use (x – a)2 + (y – b)2 = r2 - especially distance formula
  • 5. Terminology Concentric circles? Same centre Congruent Same shape and size Diametrically Opposite Opposite ends of diameter
  • 6. Using Common Sense! A(1 , 4) and B are diametrically opposite Centre is (6 , 10) B? (1,4) B (6,10) use steps 5 6 5 6 (11,16)
  • 7. Using Common Sense! A(2 , 6) and B are diametrically opposite Centre is (5 , 13) B? (2,6) B (5,13) use steps 3 7 3 7 (8,20)
  • 8. Reminder Perpendicular Bisector cut line in half at right angles x1+x2 y1+y2 2 2 m1m2 = -1
  • 9. Finding Equation From Points On Circle If we have three points on a circle A,B and C then perpendicular bisectors will meet in the centre. We can use this to find the equation of a circle
  • 10. A (0 , 2) B(1 , 5) and C(4 , 4) lie on a circle. Find its equation. Radius A B C (0 , 2) (1 , 5) (4 , 4) (½, 7 /2) m1 = 3 m2 = -1 /3 3y = -x + 11 (5 /2 , 9 /2) m1 = -1 /3 m2 = 3 y = 3x – 3 Lines meet at (2 , 3) (2 , 3) √5 (x – 2)2 + (y – 3)2 = 5
  • 11. Finding Equation From Points On Circle If we have three points on a circle A,B and C then perpendicular bisectors will meet in the centre. We can use this to find the equation of a circle
  • 12. Equation from 3 Points Perpendicular Bisectors m1m2 = -1 mid pt Centre – Point of Intersection Radius Distance Formula (y = y or sim. equations)
  • 13. Closest Distance Find the closest distance between circle A x2 + y2 – 6x – 2y + 9 = 0 and B x2 + y2 – 14x – 8y + 61 = 0 (3 , 1) (7 , 4) 1 2 2 A B 5
  • 14. Closest Distance Closest distance between 2 circles (given equations) ? Dist between centres – (sum of radii) Get centres
  • 15. Proving Circles Touch Externally Prove these touch externally A x2 + y2 – 6x – 4y – 23 = 0 B x2 + y2 – 18x – 20y + 165 = 0 (3 , 2) (9 , 10) A B 6 4 10
  • 16. Proving Circles Touch Internally Prove these touch internally A x2 + y2 – 4x – 6y – 51 = 0 B x2 + y2 – 12x – 12y + 63 = 0 (2 , 3) (6 , 6) 8 3 5
  • 17. Proving circles touch at one point Externally Dist between centres = Sum of Radii
  • 18. Proving Circles Touch Distance between centres = difference between radii Internally