The Distance and
Midpoint Formulas!
To be used when you want to find the
 distance between two points or the
    midpoint between two points
You have learned…
         1
                         The Pythagorean
     a            c           Theorem
                            a2 + b2 = c 2
                 b    2
When we are finding c we are really finding
  the distance between angles 1 and 2
If we solve for c we get c = √(a2 + b2)
This is how the distance formula is derived –
  it is useful when we know coordinates
The Distance Formula!
          The distance formula is
        d = √((y2 – y1)2 + (x2 – x1)2)
And is used to find the distance between two
        points on the coordinate plane

             Let’s practice one!
Example:
What is the distance between (2, -6) and (-3, 6)?
First, identify x1, y1, x2 and y2
x1 = 2                    y1 = -6
x2 = -3                y2 = 6


Now, we use the formula:
d = √((6 – -6)2 + (-3 – 2)2) = √(122 + (-52))
d = 13
The Midpoint Formula!
  The midpoint formula is used to find the
coordinate that is the exact midpoint between
            two other coordinates

The x-coordinate of the midpoint is found by
                (x2 + x1)/2
The y-coordinate of the midpoint is found by
                (y2 + y1)/2
   So, the coordinate of the midpoint is:
          (x2 + x1)/2, (y2 + y1)/2
Example:
What is the coordinate of the midpoint between
  (1, 2) and (-5, 6)?
Again, identify x1, y1, x2 and y2
x1 = 1                   y1 = 2
x2 = -5                y2 = 6
Now use the formula:
x-coordinate: (1 + -5)/2 = -2
y-coordinate: (2 + 6)/2 = 8
So, the midpoint is located at the coordinate (-2, 8)
Another Example
On the coordinate plane, it is given that the
 midpoint of points A and B is (5, 7). If point
 A is located at (-1, 2), where is point B
 located?

In this case, we know the midpoint and the
  coordinate of point A. In a sense, we need
  to work backwards. Let’s define what we
  have:
x1 = -1                 y1 = 2
 x2 = ?                  y2 = ?


So we know…
(-1 + x2)/2 = 5          (2 + y2)/2 = 7
-1 + x2 = 10             (2 + y2) = 14
x2 = 11                  y2 = 12


So the coordinate of point B is (11, 12)

Distance and midpoint notes

  • 1.
    The Distance and MidpointFormulas! To be used when you want to find the distance between two points or the midpoint between two points
  • 2.
    You have learned… 1 The Pythagorean a c Theorem a2 + b2 = c 2 b 2 When we are finding c we are really finding the distance between angles 1 and 2 If we solve for c we get c = √(a2 + b2) This is how the distance formula is derived – it is useful when we know coordinates
  • 3.
    The Distance Formula! The distance formula is d = √((y2 – y1)2 + (x2 – x1)2) And is used to find the distance between two points on the coordinate plane Let’s practice one!
  • 4.
    Example: What is thedistance between (2, -6) and (-3, 6)? First, identify x1, y1, x2 and y2 x1 = 2 y1 = -6 x2 = -3 y2 = 6 Now, we use the formula: d = √((6 – -6)2 + (-3 – 2)2) = √(122 + (-52)) d = 13
  • 5.
    The Midpoint Formula! The midpoint formula is used to find the coordinate that is the exact midpoint between two other coordinates The x-coordinate of the midpoint is found by (x2 + x1)/2 The y-coordinate of the midpoint is found by (y2 + y1)/2 So, the coordinate of the midpoint is: (x2 + x1)/2, (y2 + y1)/2
  • 6.
    Example: What is thecoordinate of the midpoint between (1, 2) and (-5, 6)? Again, identify x1, y1, x2 and y2 x1 = 1 y1 = 2 x2 = -5 y2 = 6 Now use the formula: x-coordinate: (1 + -5)/2 = -2 y-coordinate: (2 + 6)/2 = 8 So, the midpoint is located at the coordinate (-2, 8)
  • 7.
    Another Example On thecoordinate plane, it is given that the midpoint of points A and B is (5, 7). If point A is located at (-1, 2), where is point B located? In this case, we know the midpoint and the coordinate of point A. In a sense, we need to work backwards. Let’s define what we have:
  • 8.
    x1 = -1 y1 = 2 x2 = ? y2 = ? So we know… (-1 + x2)/2 = 5 (2 + y2)/2 = 7 -1 + x2 = 10 (2 + y2) = 14 x2 = 11 y2 = 12 So the coordinate of point B is (11, 12)