The document contains questions and answers related to chemistry concepts. It includes questions about the names of compounds containing certain functional groups, drawing Lewis structures, oxidation states, acid-base reactions, and calculating pH. The questions cover topics like organic chemistry, biochemistry, electrochemistry, equilibrium, kinetics and thermodynamics.

1. 2010-1A12a. What is the name given to a compound containing a COOH functional group? b. Name the following compound: CH3COOH

2. 2010-1A12a. What is the name given to a compound containing a COOH functional group? b. Name the following compound: CH3COOH Answer: a. Carboxylic Acidb. Acetic Acid or Ethanoic Acid

3. 2010-1A13If a negatively charged rod is held near an uncharged metal ball, the metal ball a. becomes negatively chargedb. becomes positively chargedc. becomes polard. is unaffected e. affect cannot be determined

4. 2010-1A13If a negatively charged rod is held near an uncharged metal ball, the metal ball a. becomes negatively chargedb. becomes positively chargedc. becomes polard. is unaffected e. affect cannot be determined Answer: C

5. 2010-1A15Which of the following mixtures would create a buffer?a. HCland NaCl b. HNO3 and NaNO3c. H3PO4 and NaH2PO4d. H2SO4 and CH3COOHe. NH3 and NaOH

6. 2010-1A15Which of the following mixtures would create a buffer?a. HCl and NaCl b. HNO3 and NaNO3c. H3PO4 and NaH2PO4d. H2SO4 and CH3COOHe. NH3 and NaOH Answer: C Gives a mixture of a weak acid (H3PO4) and its conjugate weak base (H2PO4-).

7. 2010-1A16How many electrons per minute traverse any cross-section of a wire which carries a current of 2 amperes? The charge of an electron is 1.6 X 10-19 coulomb. Answer: 7.5 x 1020 electrons/minute i = q / t 2 amp = (2 coul/sec)(1 elect/1.6x10-19coul)(60 sec/min)

8. 2010-1A16How many electrons per minute traverse any cross-section of a wire which carries a current of 2 amperes? The charge of an electron is 1.6 X 10-19 coulomb. Answer: 7.5 x 1020 electrons/minutei = q / t 2 amp = (2 coul/sec)(1 elect/1.6x10-19coul)(60 sec/min)

9. 2010-1A18Which species is the reducing agent in the following balanced reaction?Mn2+(aq) + S2O82-(aq) + 2H2O(l)  MnO2(s) + 4H+(aq) + 2SO42-(aq)

10. 2010-1A18Which species is the reducing agent in the following balanced reaction?Mn2+(aq) + S2O82-(aq) + 2H2O(l)  MnO2(s) + 4H+(aq) + 2SO42-(aq) Answer: Mn2+Mn2+ gets oxidized to Mn4+ and in the process reduces S+7 to S+6

11. 2010-1C15Which of the following compounds have the ability to form hydrogen bonds? (there may be more than one) a. H2Ob. BF3c. NH3d. HF e. CH4

12. 2010-1C15Which of the following compounds have the ability to form hydrogen bonds? (there may be more than one) a. H2Ob. BF3c. NH3d. HF e. CH4 Answer: A, C, and D

13. 2010-1C18Calculate the molar mass of the amino acid, glycine, which has the following structure:

14. 2010-1C18Calculate the molar mass of the amino acid, glycine, which has the following structure: Answer: 75 g/mol = 2 C + 5 H + 1 N + 2 O = 2 (12 g/mol) + 5 (1 g/mol) + 1 (14 g/mol) + 2 (16 g/mol)

15. 2010-2A12What is the common name for acetylsalicylic acid?

16. 2010-2A12What is the common name for acetylsalicylic acid?Answer: Aspirin

17. 2010-2A14During the metabolic process, what is the name of the molecules that carry energy from the citric acid cycle (Kreb’s cycle) pathway to the electron transport system?

18. 2010-2A14During the metabolic process, what is the name of the molecules that carry energy from the citric acid cycle (Kreb’s cycle) pathway to the electron transport system? Answer: NADH or FADH or FADH2

19. 2010-2A15What is the name of the polyatomic anion MnO4- ?

20. 2010-2A15What is the name of the polyatomic anion MnO4- ?Answer: Permanganate

21. 2010-2A18What element has 10 protons?

22. 2010-2A18What element has 10 protons? Answer: Neon

23. 2010-2C12What is the ground state electron configuration for Sr (Atomic Number = 38)?

24. 2010-2C12What is the ground state electron configuration for Sr (Atomic Number = 38)? Answer: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2or 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 5s2

25. 2010-2C15Which element in the periodic table has the largest electronegativity?

26. 2010-2C15Which element in the periodic table has the largest electronegativity?Answer: Fluorine or F

27. 2010-2C17The oxygen released during photosynthesis originates from what compound?

28. 2010-2C17The oxygen released during photosynthesis originates from what compound? Answer: Water (H2O)

29. 2010-2C18What is the oxidation number of carbon in formaldehyde?

30. 2010-2C18What is the oxidation number of carbon in formaldehyde?Answer: ZeroEach hydrogen is +1, for a total of +2. Oxygen is -2.The carbon must have an oxidation number of zero to have a neutral compound.

31. 2010-3A13What is the common name for elements in Group 2A (second column) in the periodic table?

32. 2010-3A13What is the common name for elements in Group 2A (second column) in the periodic table? Answer: Alkaline Earth Metals

33. 2010-3A14Draw the Lewis structure for BF3. [Boron is in group 3A and fluorine is in group 7A.]

34. 2010-3A14Draw the Lewis structure for BF3. [Boron is in group 3A and fluorine is in group 7A.]Must have the 3 fluorines positioned around the boron (left, right, top, or bottom) with single bonds. Each fluorine should have 3 lone pairs (or 6 lone pair electrons).NOT ACCEPTABLE!!!!

35. 2010-1B32Calculate G for the combustion of propane in units of kJ. C3H8(g) + 5O2(g)  3CO2(g) + 4H2O(g)

36. 2010-1B32Calculate G for the combustion of propane in units of kJ. C3H8(g) + 5O2(g)  3CO2(g) + 4H2O(g) Answer: -2073.1 kJ DG° = [3 mol (-394.4 kJ/mol) + 4 mol (-228.6 kJ/mol)] – [1 mol (-24.5 kJ/mol) + 5 mol (0 kJ/mol)]

37. 2010-1D32A 0.2688 g sample of a triprotic weak acid (abbreviate H3A) is required to completely react with 49.2 mL of a 0.08133 M KOH solution. Calculate the molar mass of the weak acid.

38. 2010-1D32A 0.2688 g sample of a triprotic weak acid (abbreviate H3A) is required to completely react with 49.2 mL of a 0.08133 M KOH solution. Calculate the molar mass of the weak acid. Answer: 201.5 g/mol H3A + 3 OH- 3 H2O + A3-Molar Mass = 0.2688 g / 1.33 x 10-3 molMolar Mass = 201.5 g/mol

39. 2010-2B32The concentration of a compound is 1.0 x 10-2 M. If the first order reaction rate constant (k) for the compound is 0.497 days-1, calculate the concentration 2 days later, assuming first order kinetics.

40. 2010-2B32The concentration of a compound is 1.0 x 10-2 M. If the first order reaction rate constant (k) for the compound is 0.497 days-1, calculate the concentration 2 days later, assuming first order kinetics. Answer: 3.7 x 10-3 M

41. 2010-2D32Calculate the molarity of concentrated HNO3 given the following: molar mass = 63.01 g/mol, wt% = 70.4, and density = 1.41 g/mL.

42. 2010-2D32Calculate the molarity of concentrated HNO3 given the following: molar mass = 63.01 g/mol, wt% = 70.4, and density = 1.41 g/mL. Answer: 15.8 mol/L

43. 2010-3B3225.0 g of C3H8 (g) is mixed with 25.0 g of O2 (g). If these compounds react according to the balanced chemical equation given below, how many grams of excess reactant remain after the reaction is complete? [C3H8 = 44.1 g/mol; O2 = 32.0 g/mol; CO2 = 44.0 g/mol; H2O = 18.0 g/mol] C3H8(g) + 5O2(g)  3CO2(g) + 4H2O(g)

44. 2010-3B3225.0 g of C3H8 (g) is mixed with 25.0 g of O2 (g). If these compounds react according to the balanced chemical equation given below, how many grams of excess reactant remain after the reaction is complete? [C3H8 = 44.1 g/mol; O2 = 32.0 g/mol; CO2 = 44.0 g/mol; H2O = 18.0 g/mol] C3H8(g) + 5O2(g)  3CO2(g) + 4H2O(g) Answer: 18.11 g C3H8remaining25.0 g of C3H8 – 6.9 g of C3H8 = 18.1 g C3H8 remaining

45. Citric acid (abbreviate as H3A for this problem) is a weak acid with the Ka and Kb values listed below. Calculate the equilibrium pH if 0.100 moles of sodium citrate (Na3A) are dissolved in 1.00 L of water. Ka1 = 7.44 x 10-4Ka2 = 1.73 x 10-5Ka3 = 4.02 x 10-7Kb1 = 2.49 x 10-8Kb2 = 5.78 x 10-10Kb3 = 1.34 x 10-11 Answer: 9.7 Kb1 Reaction: A3- + H2O  HA2- + OH-At Equilibrium: 100 – x xx(ignore x in the denominator) X = [OH-] = 4.99 x 10-5 M pOH = 4.3pH = 14.0 – 4.3 = 9.7

46. Citric acid (abbreviate as H3A for this problem) is a weak acid with the Ka and Kb values listed below. Calculate the equilibrium pH if 0.100 moles of sodium citrate (Na3A) are dissolved in 1.00 L of water. Ka1 = 7.44 x 10-4Ka2 = 1.73 x 10-5Ka3 = 4.02 x 10-7Kb1 = 2.49 x 10-8Kb2 = 5.78 x 10-10Kb3 = 1.34 x 10-11 Answer: 9.7 Kb1 Reaction: A3- + H2O  HA2- + OH-At Equilibrium: 100 – x xx(ignore x in the denominator) X = [OH-] = 4.99 x 10-5 M pOH = 4.3pH = 14.0 – 4.3 = 9.7