Here are the answers to the quiz questions:
1. In real mode addressing, the physical address is calculated by multiplying the segment by 10h and adding the offset. So for 1234:1001, the physical address would be 1234 * 10h + 1001 = 123C001h.
2. Given the registers and memory:
DI = 1234h
SI = 1236h
Memory:
1236h contains 24
So mov AL, [SI] would move the value 24 from memory location 1236h into AL. Therefore, the value of AL would be 24.