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1. Isobaric Process ( P = C): An Isobaric Process is an internally
reversible constant pressure process.
A. Closed System:(Nonflow)
P
V
21P
dV
Q = U + W  1 any substance
W = PdV  2 any substance
U = m(U2 - U1)  3 any substance
W = P(V2 - V1)  4 any substance
Q = h = m(h2-h1)  5 any substance
T
S
1
2
dS
T
P = C
PROCESSES OF FLUIDS
For Ideal Gas:
PV = mRT
W =mR(T2-T1)  5
U = mCv(T2-T1)  6
Q = h = mCP (T2-T1)  7
Entropy Change
S = dQ/T  8 any substance
dQ = dh
For Ideal Gas
dh = mCPdT
S = dQ/T
S = mCP dT/T
S = mCP ln(T2/T1)  9
B. Open System:
Q = h + KE + PE + W  10 any substance
W = - VdP - KE - PE  11 any substance
- VdP = 0
Q = h  12
W = - KE - PE  13
If KE = 0 and PE = 0
W = 0  14
Q = mCP(T2-T1)  15 Ideal Gas
2. Isometric Process (V = C): An Isometric process is internally
reversible constant volume process.
A. Closed System: (Nonflow)
P
V
1
2
T
S
T
dS
1
2V = C
Q = U + W  1 any substance
W = PdV at V = C; dV = 0
W = 0
Q = U = m(U2 - U1)  2 any substance
h = m(h2-h1)  3 any substance
For Ideal Gas:
Q = U = mCv(T2-T1)  4
h = mCP(T2-T1)  5
Entropy Change:
S = dQ/T  6 any substance
dQ = dU
dU = mCvdT for ideal gas
S = dU/T = mCvdT/T
S = mCv ln(T2/T1)  6
B. Open System:
Q = h + KE + PE + W  7 any substance
W = - VdP - KE - PE  8 any substance
-VdP = -V(P2-P1)  9 any substance
Q = U = m(U2 - U1)  10 any substance
h = m(h2-h1)  11 any substance
For Ideal Gas:
-VdP = -V(P2-P1) = mR(T1-T2)
Q = U = mCv(T2-T1)  12
h = mCP(T2-T1)  13
If KE = 0 and PE = 0
Q = h + W  14 any substance
W = - VdP  15
W = -VdP = -V(P2-P1)  16 any substance
W = mR(T1-T2)  16 ideal gas
h = mCP(T2-T1)  17 ideal gas
3. Isothermal Process(T = C): An Isothermal process is a reversible
constant temperature process.
A. Closed System (Nonflow)
dS
T
S
T
1 2
P
V
1
2P
dV
PV = C or
T = C
Q = U + W  1 any substance
W = PdV  2 any substance
U = m(U2 - U1)  3 any substance
For Ideal Gas:
dU = mCv dT; at T = C ; dT = 0
Q = W  4
W = PdV ; at PV = C ;
P1V1 = P2V2 = C; P = C/V
Substituting P = C/V to W = PdV
W = P1V1 ln(V2/V1)  5
Where (V2/V1) = P1/P2
W = P1V1 ln(P1/P2)  6
P1V1 = mRT1
Entropy Change:
dS = dQ/T  7
S = dQ/T
dQ = TdS ;at T = C
Q = T(S2-S1)
(S2-S1) = S = Q/T  8
S = Q/T = W/T  9 For Ideal Gas
B. Open System (Steady Flow)
Q = h + KE + PE + W  10 any substance
W = - VdP - KE - PE  11 any substance
-VdP = -V(P2-P1)  12 any substance
h = m(h2-h1)  13 any substance
For Ideal Gas:
-VdP = -P1V1ln(P2/P1)  14
-VdP = P1V1ln(P1/P2)  15
P1/P2 = V2/V1  16
dh = CPdT; at T = C; dT = 0
h = 0  16
If KE = 0 and PE = 0
Q = h + W  17 any substance
W = - VdP = P1V1ln(P1/P2)  18
For Ideal Gas
h = 0  19
Q = W = - VdP = P1V1ln(P1/P2)  20
4. Isentropic Process (S = C): An Isentropic Process is an internally
“Reversible Adiabatic” process in which the entropy remains constant
where S = C and PVk = C for an ideal or perfect gas.
For Ideal Gas
1
2
1
1
1
2
1
2
2
22
1






















k
k
k
k
22
k
11
11
k
V
V
P
P
T
T
VPVPand
T
VP
T
VP
CPVandC
T
PV
Using
A. Closed System (Nonflow)
T
S
1
2
P
V
1
2
dV
P
S = C or
PVk = C
Q = U + W  1 any substance
W = PdV  2 any substance
U = m(U2 - U1)  3 any substance
Q = 0  4
W = - U = U = -m(U2 - U1)  5
For Ideal Gas
U = mCV(T2-T1)  6
From PVk = C, P =C/Vk, and substituting P =C/Vk
to W = ∫PdV, then by integration,
 














































1
1
1
1
1
1
1
211
1
1
21
k
k
VP
k
k
12
1122
P
P
k
PdV
P
P
k
mRT
k-1
T-TmR
PdV
k
VP-VP
PdVW  7
 8
 9
Q = 0
Entropy Change
S = 0
S1 = S2
B. Open System (Steady Flow)
Q = h + KE + PE + W  10 any substance
W = - VdP - KE - PE  11 any substance
h = m(h2-h1)  12 any substance
Q = 0
W = -h - KE - PE  13
From PVk = C ,V =[C/P]1/k, substituting V to
-∫VdP, then by integration,
 
 















































1
1
1
1
1
1
1
211
1
1
21
k
k
k
k
12
1122
P
P
k
VkP
VdP
P
P
k
kmRT
k-1
T-TkmR
VdP
k
VP-VPk
VdP
PdVkVdP
 14
 15
 16
If KE = 0 and PE = 0
0 = h + W  17 any substance
W = - VdP = - h  18 any substance
h = m(h2-h1)  19 any substance
Q = 0
 
 
 12P
k
k
k
k
12
1122
T-TmChW
P
P
k
VkP
W
P
P
k
kmRT
k-1
T-TkmR
W
k
VP-VPk
PdVkVdPW















































1
1
1
1
1
1
1
211
1
1
21
 20
 22
 21
 23
P
V
dP
V
Area = -VdP
S = C
1
2
1
1
1
2
1
2
2
22
1






















n
n
n
n
22
n
11
11
n
V
V
P
P
T
T
VPVPand
T
VP
T
VP
CPVandC
T
PV
Using
5. Polytropic Process ( PVn = C): A Polytropic Process is an
internally reversible process of an Ideal or Perfect Gas in which
PVn = C, where n stands for any constant.
A. Closed System: (Nonflow)
Q = U + W  1
W = PdV  2
U = m(U2 - U1)  3
Q = mCn(T2-T1)  4
U = m(U2 - U1)  5
P
V
1
2
dV
P
PVn = C
T
S
2
1
dS
T
PVn = C
K-kg
KJ
or
C-kg
KJ
heatspecificpolytropicC
n1
nk
CC
n
vn











From PVn = C, P =C/Vn, and substituting
P =C/Vn to W = ∫PdV, then by integration,
 














































1
1
1
1
1
1
1
211
1
1
21
n
n
VP
n
n
12
1122
P
P
n
PdVW
P
P
n
mRT
n-1
T-TmR
PdVW
n
VP-VP
PdVW
Entropy Change
dS = dQ/T
dQ = mCndT
S = mCnln(T2/T1)
 6
 8
 9
 10
B. Open System (Steady Flow)
Q = h + KE + PE + W  11
W = - VdP - KE - PE  12
h = m(h2-h1)  13
Q = mCn(T2-T1)  14
dQ = mCn dT
W = Q - h - KE - PE  15
From PVn = C ,V =[C/P]1/n, substituting V to
-∫VdP, then by integration,
 
n
VP-VPn
VdP
PdVnVdP
1122



1
 16
 












































1
1
1
1
1
1
211
1
1
21
n
n
n
n
12
P
P
n
VnP
VdP
P
P
n
nmRT
n-1
T-TnmR
VdP
If KE = 0 and PE = 0
Q = h + W  19 any substance
W = - VdP = Q - h  20 any substance
h = m(h2-h1)  21 any substance
h = mCp(T2-T1)
Q = mCn(T2-T1)  22
 17
 18
 












































1
1
1
1
1
1
211
1
1
21
n
n
n
n
12
P
P
n
VnP
W
P
P
n
nmRT
n-1
T-TnmR
W
 24
 23
6. Isoenthalpic or Throttling Process: It is a steady - state, steady
flow process in which Q = 0; PE = 0; KE = 0; W = 0 and the
enthalpy remains constant.
h1 = h2 or h = C
Throttling valve
Main steam line
thermometer
Pressure Gauge
Pressure Gauge
To main steam line
Throttling Calorimeter
Irreversible or Paddle Work
m
W
Q
U
Wp
Q = U + W - Wp
where: Wp - irreversible or paddle work

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Chapter 7 Processes of Fluids

  • 1. 1. Isobaric Process ( P = C): An Isobaric Process is an internally reversible constant pressure process. A. Closed System:(Nonflow) P V 21P dV Q = U + W  1 any substance W = PdV  2 any substance U = m(U2 - U1)  3 any substance W = P(V2 - V1)  4 any substance Q = h = m(h2-h1)  5 any substance T S 1 2 dS T P = C PROCESSES OF FLUIDS
  • 2. For Ideal Gas: PV = mRT W =mR(T2-T1)  5 U = mCv(T2-T1)  6 Q = h = mCP (T2-T1)  7 Entropy Change S = dQ/T  8 any substance dQ = dh For Ideal Gas dh = mCPdT S = dQ/T S = mCP dT/T S = mCP ln(T2/T1)  9 B. Open System: Q = h + KE + PE + W  10 any substance W = - VdP - KE - PE  11 any substance - VdP = 0
  • 3. Q = h  12 W = - KE - PE  13 If KE = 0 and PE = 0 W = 0  14 Q = mCP(T2-T1)  15 Ideal Gas 2. Isometric Process (V = C): An Isometric process is internally reversible constant volume process. A. Closed System: (Nonflow) P V 1 2 T S T dS 1 2V = C
  • 4. Q = U + W  1 any substance W = PdV at V = C; dV = 0 W = 0 Q = U = m(U2 - U1)  2 any substance h = m(h2-h1)  3 any substance For Ideal Gas: Q = U = mCv(T2-T1)  4 h = mCP(T2-T1)  5 Entropy Change: S = dQ/T  6 any substance dQ = dU dU = mCvdT for ideal gas S = dU/T = mCvdT/T S = mCv ln(T2/T1)  6
  • 5. B. Open System: Q = h + KE + PE + W  7 any substance W = - VdP - KE - PE  8 any substance -VdP = -V(P2-P1)  9 any substance Q = U = m(U2 - U1)  10 any substance h = m(h2-h1)  11 any substance For Ideal Gas: -VdP = -V(P2-P1) = mR(T1-T2) Q = U = mCv(T2-T1)  12 h = mCP(T2-T1)  13 If KE = 0 and PE = 0 Q = h + W  14 any substance W = - VdP  15 W = -VdP = -V(P2-P1)  16 any substance W = mR(T1-T2)  16 ideal gas h = mCP(T2-T1)  17 ideal gas
  • 6. 3. Isothermal Process(T = C): An Isothermal process is a reversible constant temperature process. A. Closed System (Nonflow) dS T S T 1 2 P V 1 2P dV PV = C or T = C Q = U + W  1 any substance W = PdV  2 any substance U = m(U2 - U1)  3 any substance For Ideal Gas: dU = mCv dT; at T = C ; dT = 0 Q = W  4
  • 7. W = PdV ; at PV = C ; P1V1 = P2V2 = C; P = C/V Substituting P = C/V to W = PdV W = P1V1 ln(V2/V1)  5 Where (V2/V1) = P1/P2 W = P1V1 ln(P1/P2)  6 P1V1 = mRT1 Entropy Change: dS = dQ/T  7 S = dQ/T dQ = TdS ;at T = C Q = T(S2-S1) (S2-S1) = S = Q/T  8 S = Q/T = W/T  9 For Ideal Gas
  • 8. B. Open System (Steady Flow) Q = h + KE + PE + W  10 any substance W = - VdP - KE - PE  11 any substance -VdP = -V(P2-P1)  12 any substance h = m(h2-h1)  13 any substance For Ideal Gas: -VdP = -P1V1ln(P2/P1)  14 -VdP = P1V1ln(P1/P2)  15 P1/P2 = V2/V1  16 dh = CPdT; at T = C; dT = 0 h = 0  16 If KE = 0 and PE = 0 Q = h + W  17 any substance W = - VdP = P1V1ln(P1/P2)  18 For Ideal Gas h = 0  19 Q = W = - VdP = P1V1ln(P1/P2)  20
  • 9. 4. Isentropic Process (S = C): An Isentropic Process is an internally “Reversible Adiabatic” process in which the entropy remains constant where S = C and PVk = C for an ideal or perfect gas. For Ideal Gas 1 2 1 1 1 2 1 2 2 22 1                       k k k k 22 k 11 11 k V V P P T T VPVPand T VP T VP CPVandC T PV Using
  • 10. A. Closed System (Nonflow) T S 1 2 P V 1 2 dV P S = C or PVk = C Q = U + W  1 any substance W = PdV  2 any substance U = m(U2 - U1)  3 any substance Q = 0  4 W = - U = U = -m(U2 - U1)  5
  • 11. For Ideal Gas U = mCV(T2-T1)  6 From PVk = C, P =C/Vk, and substituting P =C/Vk to W = ∫PdV, then by integration,                                                 1 1 1 1 1 1 1 211 1 1 21 k k VP k k 12 1122 P P k PdV P P k mRT k-1 T-TmR PdV k VP-VP PdVW  7  8  9 Q = 0
  • 12. Entropy Change S = 0 S1 = S2 B. Open System (Steady Flow) Q = h + KE + PE + W  10 any substance W = - VdP - KE - PE  11 any substance h = m(h2-h1)  12 any substance Q = 0 W = -h - KE - PE  13 From PVk = C ,V =[C/P]1/k, substituting V to -∫VdP, then by integration,
  • 14.      12P k k k k 12 1122 T-TmChW P P k VkP W P P k kmRT k-1 T-TkmR W k VP-VPk PdVkVdPW                                                1 1 1 1 1 1 1 211 1 1 21  20  22  21  23
  • 16. 1 2 1 1 1 2 1 2 2 22 1                       n n n n 22 n 11 11 n V V P P T T VPVPand T VP T VP CPVandC T PV Using 5. Polytropic Process ( PVn = C): A Polytropic Process is an internally reversible process of an Ideal or Perfect Gas in which PVn = C, where n stands for any constant.
  • 17. A. Closed System: (Nonflow) Q = U + W  1 W = PdV  2 U = m(U2 - U1)  3 Q = mCn(T2-T1)  4 U = m(U2 - U1)  5 P V 1 2 dV P PVn = C T S 2 1 dS T PVn = C K-kg KJ or C-kg KJ heatspecificpolytropicC n1 nk CC n vn           
  • 18. From PVn = C, P =C/Vn, and substituting P =C/Vn to W = ∫PdV, then by integration,                                                 1 1 1 1 1 1 1 211 1 1 21 n n VP n n 12 1122 P P n PdVW P P n mRT n-1 T-TmR PdVW n VP-VP PdVW Entropy Change dS = dQ/T dQ = mCndT S = mCnln(T2/T1)  6  8  9  10
  • 19. B. Open System (Steady Flow) Q = h + KE + PE + W  11 W = - VdP - KE - PE  12 h = m(h2-h1)  13 Q = mCn(T2-T1)  14 dQ = mCn dT W = Q - h - KE - PE  15 From PVn = C ,V =[C/P]1/n, substituting V to -∫VdP, then by integration,   n VP-VPn VdP PdVnVdP 1122    1  16
  • 20.                                               1 1 1 1 1 1 211 1 1 21 n n n n 12 P P n VnP VdP P P n nmRT n-1 T-TnmR VdP If KE = 0 and PE = 0 Q = h + W  19 any substance W = - VdP = Q - h  20 any substance h = m(h2-h1)  21 any substance h = mCp(T2-T1) Q = mCn(T2-T1)  22  17  18
  • 22. 6. Isoenthalpic or Throttling Process: It is a steady - state, steady flow process in which Q = 0; PE = 0; KE = 0; W = 0 and the enthalpy remains constant. h1 = h2 or h = C Throttling valve Main steam line thermometer Pressure Gauge Pressure Gauge To main steam line Throttling Calorimeter
  • 23. Irreversible or Paddle Work m W Q U Wp Q = U + W - Wp where: Wp - irreversible or paddle work