ME 12 Assignment No. 1
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This document contains a thermodynamics assignment with 10 problems related to concepts like specific weight, acceleration due to gravity at different elevations, pressure and force exerted by fluids, density and specific volume of mixtures, heat transfer between materials, mass and energy balances, and work calculations for steam turbines. Students are asked to solve these 10 problems and submit their solutions to the given email address by the provided due date.
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Here are the key steps to solve this problem:
1) Use Bernoulli's equation between points 1 and 2:
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- There are three main temperature scales: Celsius (C), Fahrenheit (F), and Kelvin (K)
- Celsius and Kelvin have the same increments but different reference points, with 0°C being the freezing point of water and 100°C being the boiling point, while 0K is absolute zero
- Fahrenheit has a different increment than the other two scales, with 32°F being the freezing point of water and 212°F being the boiling point
- Conversions between the scales can be done using the following relationships:
(C − 0°C) = (F − 32°F) × 5/9 = (K − 273
Ideal gas-processes
The document describes various thermodynamic processes including:
1) Isometric processes which occur at constant volume with changes in temperature and pressure.
2) Isobaric processes which occur at constant pressure with changes in volume and temperature.
3) Isothermal processes which occur at constant temperature with changes in pressure and volume.
4) Isentropic processes which are reversible adiabatic processes with no heat transfer and constant entropy.
Several examples are provided to calculate temperature, pressure, volume, work, heat, internal energy and entropy changes during these different thermodynamic processes.
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An isobaric process is a constant pressure process where pressure (P) remains constant. Work (W) done is equal to pressure (P) times the change in volume (ΔV). For an ideal gas, the change in internal energy (ΔU) is equal to heat (Q) added.
An isometric process is a constant volume process where volume (V) remains constant. Work (W) done is zero since there is no change in volume. For any substance, the change in internal energy (ΔU) is equal to the heat (Q) added.
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This document discusses the expansion of gases and the relationships between pressure, volume, temperature, and number of moles in gases. It introduces the ideal gas law (PV=nRT) and describes some key gas processes including isobaric (constant pressure), isothermal (constant temperature), and isometric (constant volume) processes. Examples are provided to demonstrate how to use the ideal gas law and gas equations of state to calculate pressure, volume, temperature, or number of moles given values of the other variables.
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Mechanical engineer's manual(by. engr. yuri g. melliza)
1. This document defines common mechanical engineering terms such as mass, velocity, acceleration, force, pressure, and temperature scales. Conversion factors are provided.
2. Properties of fluids such as density, specific volume, specific gravity, and equations of state for gases are defined. Characteristics including viscosity, elasticity, and surface tension are also explained.
3. Ten sample problems are worked through as examples of applying the definitions and concepts to calculations involving forces, densities, pressures, temperatures, and manometers.
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This document contains 11 problems related to thermodynamics concepts like steam tables, properties of steam at different conditions, processes involving gases in closed systems. The problems involve determining states, properties, energies and sketching processes on p-v diagrams. The document provides the questions and expects the answers to be provided using concepts of thermodynamics.
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Thermodynamics is the science dealing with energy transformation between heat and work. It studies systems, which can be open or closed to matter flow, and their surroundings. For a closed system, there is no exchange of mass between the system and surroundings, while an open system allows mass flow. A process is a change in state of a substance, and a cycle occurs when the initial and final states are the same. Thermodynamics analyzes the various forms of energy including work, heat, internal energy, and flow energy. It also examines the properties of pure substances and how they vary with changes in temperature and pressure through different phases like solid, liquid, and gas.
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The document discusses temperature, heat, and phase changes. It defines temperature as a measure of the average kinetic energy of particles in an object. Temperature scales like Fahrenheit, Celsius, and Kelvin are introduced. Heat is a form of energy that transfers between objects due to temperature differences. Equations are provided to calculate heat transfer during temperature changes and phase changes using values like specific heat and latent heat. Examples demonstrate using the equations to solve heat and temperature problems involving substances like water, ice, and metals.
ME 12 F1 (MODULE 1)
Thermodynamics deals with energy transformation between different forms. A system is the portion of the universe being studied, and can be open or closed to transfers with the surroundings. Properties can be intensive or extensive, and phases of a substance include solid, liquid, and gas. Temperature is a measure of heat intensity, while pressure is force per unit area. Pascal's law states that pressure is equal in all directions in a fluid at rest. Manometers use liquid columns to measure pressure differences.
Hydraulics for engineers
Here are the key steps to solve this problem:
1) Use Bernoulli's equation between points 1 and 2:
P1/γ + V12/2g + Z1 = P2/γ + V22/2g + Z2 + HL
2) Given: P1 = 200 kPa, Q = 30 L/sec, HL = 20 kPa
3) Use continuity equation: A1V1 = A2V2
4) Solve for P2
The pressure at point 2 is 180 kPa.
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Mechanical engineer's manual(by. engr. yuri g. melliza)
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This document contains a 50 question physics exam with multiple choice answers for each question. The questions cover topics including forces, motion, energy, electricity, optics, heat, and properties of matter. The exam tests understanding of fundamental physics concepts as well as problem solving abilities.
CH EN 3453 Heat Transfer 2014 Fall Utah Homework HW 09 Assignment
Chemical Engineering CH EN 3453 Heat Transfer
from University of Utah, 2014 Fall
Homework HW 09 Assignment
A109212102 mechanicsoffluids1
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Me2202 engineering thermodynamics uq - nov dec 2014
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Engineering Fluid Mechanics 10th Edition Elger Solutions Manual
Full download : http://alibabadownload.com/product/engineering-fluid-mechanics-10th-edition-elger-solutions-manual/ Engineering Fluid Mechanics 10th Edition Elger Solutions Manual
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Here are the key steps to solve this problem:
1. Given: TH = 817°C = 817 + 273 = 1090 K
TL = 25°C = 25 + 273 = 298 K
QR = 25 kW
2. Use the Carnot efficiency equation:
η = (TH - TL)/TH = (1090 - 298)/1090 = 0.726
3. Set up an equation for the heat input using the efficiency and heat rejected:
QA = QR/(1-η) = 25000/(1-0.726) = 87500 kW
Therefore, the heat input (QA) required is 87500 kW.
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ME 12 Assignment No. 1
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