The document discusses interpreting ionization energy (IE) data to determine an element's electronic configuration. It states that a large jump in IE indicates removal of an electron from an inner shell, while a small jump indicates removal from an inner subshell. It provides an example of using IE data to deduce an element is in group 5 with a possible configuration of 1s22s22p5. It also shows how the electronic configuration of magnesium can be used to sketch its IE trend by determining what type of electron is removed at each stage.

1. Ionization Energies © my-chem-tutor.blogspot.com Interpretation of Ionization Data Compute the energy difference in successive IEs. Big jump in IE  e - removed from inner quantum shell. Small jump in IE  e- removed from inner subshell. In answering Ionization Energy questions, remember to account for (explain): General trend. (i.e. successive IE  ) big jumps small jumps TIPS

2. Ionization Energies © my-chem-tutor.blogspot.com (I) Ionization Data  Electronic Configuration (i) From the ionization data provided, deduce the group to which the element belongs to. (ii) Suggest a possible electronic configuration. 8 th IE 12300 7 th IE 10300 6 th IE 8500 5 th IE 5400 4 th IE 4350 3 rd IE 2460 2 nd IE 1610 1 st IE 703 IE (kJ /mol)

3. Ionization Energies © my-chem-tutor.blogspot.com (I) Ionization Data  Electronic Configuration Step 1: Compute difference in successive IEs. Step 2: Account for big jump. Big jump in IE between 5th IE  6th IE implies that the 6th electron is removed from an inner quantum shell. Element has 5 valence electrons Element is in group 5. Possible configuration: 1s 2 2s 2 2p 5 7 th IE  8 th IE 2000 6 th IE  7 th IE 1800 5 th IE  6 th IE 3100 4 th IE  5 th IE 1050 3 rd IE  4 th IE 1890 2 nd IE  3 rd IE 850 1 st IE  2 nd IE 907 IE (kJ /mol)

4. Ionization Energies © my-chem-tutor.blogspot.com (II) Electronic Configuration  Ionization Data Given the electronic configuration of 12 Mg (1s 2 2s 2 2p 6 3s 2 ), sketch IE versus order of electrons removed. Step 1: Determine the type of electron removed. 1s 11, 12 2s 9, 10 2p 3 – 8 3s 1, 2 Type of e  removed Electron

5. Ionization Energies © my-chem-tutor.blogspot.com (II) Electronic Configuration  Ionization Data Step 2: Deduce features. Successive IE  Big jump expected for 2nd IE  3rd IE and 10th IE  11th IE (electron removed from inner quantum shell) 10th IE  11th IE larger than 2nd IE  3rd IE (E n=1  2 > E n=2  3 ) Small jump expected for 8th IE  9th IE (electron removed from inner subshell)

6. Ionization Energies © my-chem-tutor.blogspot.com (II) Electronic Configuration  Ionization Data Step 3: Sketch 1 2 3 4 5 6 7 8 9 10 11 12 IE / kJ mol  1 Order of e  removed