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Algebraic Operations
Simplest Form
Adding / Sub Fractions
Multiple / Divide Fractions
Subject of Formula
Harder Subject of Formula
Starter Questions
1. Simplify the following fractions :
9 10
(a) (b)
27 35
2. Find the lowest multiple of 2 and3
1 1 3 5
3. Calculate (a) (b)
2 4 4 6
3
4. Calculate 8
Learning Intention Success Criteria
1. To explain how to simplify
algebraic fractions.
1. Understand term
Highest Common Factor.
Algebraic Operations
2. Simplify algebraic fractions
by identifying HCF.
Fraction in
Simplest form
We can sometimes reduce fractions to a simpler form if
the numerator and denominator have a number or letter
in common.
Examples
12
15
3 4
3 5
4
5
HCF = 3
2
y
y
y y
y 1
y
y
HCF = Y
Fraction in
Simplest form
Examples
2
2
6
b
b
2
6
b
b b
1
3b
3
2
a
a
a a a
a a 1
a
a
3
1
1
1
1
1
1
1
Fraction in
Simplest form
Examples
2
3
( 1)
( 1)
y
y
( 1)( 1)
( 1)( 1)( 1)
y y
y y y
1
( 1)y
1
1
1
1
Starter Questions
1. Simplify the following fractions :
3
4
3g 5e
(a) (b)
9g 2e
2. Find the lowest multiple of 4 and 9
1 1 3 5
3. Calculate (a) (b)
2 5 10 6
3
4. Calculate 27
Learning Intention Success Criteria
1. To explain how to add and
subtract algebraic
fractions.
1. Know how to add and sub
simple fractions
Algebraic Operations
2. Apply same knowledge to add
and sub algebraic fractions.
Adding Algebraic Fractions
3 1
5 5
3 1
5
4
5
LCM = 5
Example 1a
3 1
d d
3 1
d
4
d
LCM = d
Example 1b
Subtract Algebraic Fractions
3 2
4 5
15 8
20 20
7
20
LCM = 20
Example 2a
3 2
p q
3 2q p
pq
LCM = pq
Example 2b
23 pq
pq qp
23 pq
p q q p
3 5 2 4
4 5 5 4
Adding Algebraic Fractions
3 1
4 6
9 2
12 12
11
12
LCM = 12
Example 3a
2
3 1
2x x
2
3 2
2
x
x
LCM = 2x2
Example 3b
2 2
3 2
2 2
x
x x
2
3 1 2
2 2
x
x x x
3 3 1 2
4 3 6 2
3 4
3. -
2a 3a
Starter Questions
Calculate the following :
1 1
1. +
2 3
2 5
2. +
h h
2
4 3
4. -
y y
Learning Intention Success Criteria
1. To explain how to multiply
and divide by algebraic
fractions.
1. Know rules for multiplication
and division of simple
fractions.
Algebraic Operations
2. Apply knowledge to algebraic
fractions.
Multiplication and division
3 4
8 5
3
10
Example 1a
2
5 3
6
a
a
5
2a
Example 1b
Algebraic Fractions
Multiplication and division
3 4
8 5
2
1
2
5 3
6
a
a2
11
a
4 5
9 6
8
15
Example 2a
2 5
3
xy x
y
2
2
15
y
Example 2b
Algebraic Fractions
Multiplication and division
4 6
9 5
3
2 2
3 5
xy y
x
1
1
3 a
3.
2a 4
Starter Questions
Calculate the following :
1 1
1.
2 3
2 5
2.
h h
2
4 3
4.
y y
Learning Intention Success Criteria
1. To explain how to change
the subject of a formula
using
“change side change sign”
method.
1. Know change sign change sign
for solving equations.
Algebraic Operations
2. Apply knowledge to change
subject of a formula.
The Subject of a Formula
Algebraic Fractions
The Subject of a Formula
The formula below is used to work out
the circumference of a circle
C D
Since the formula works out C , then C is called
the subject of the formula.
Algebraic Fractions
The Subject of a Formula
We can make D the subject of the formula
by using the rule
“ opposite side opposite side “
C D
C
D
C
D
What Goes In The Box ?
1
y = x - 1
4
Make y the subject of the formulae below :
x + y = 8
x = y - 9
-x + 2y = 2
x = 4( y + 1 )
y = 8- x
y = x + 9
1
y = x + 1
2
3 a
3.
2a 4
Starter Questions
Calculate the following :
1 1
1.
2 3
2 5
2.
h h
2
4 3
4.
y y
Learning Intention Success Criteria
1. To explain how to change
the subject of a formula
containing square and
square root terms.
1. Know change sign change sign
for solving equations.
Algebraic Operations
2. Apply knowledge to change
subject of harder formulae
including square and square
root terms.
The Subject of a Formula
Algebraic Fractions
The Subject of a Formula
Example : The force of the air against a train is
given by the formula below.
Make the speed (S) the subject of the formula.
2 F
S
k
F
S
k
Algebraic Fractions
The Subject of a Formula
Example : The thickness of a rope T cm to lift a
weight W tonnes can be worked out
by the formula below.
Make W the subject of the formula.
4
9
W
T
9
4
T
W
2
9
4
T
W
2
9
4
T
W

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Algebraic fractionns 2

  • 1. Algebraic Operations Simplest Form Adding / Sub Fractions Multiple / Divide Fractions Subject of Formula Harder Subject of Formula
  • 2. Starter Questions 1. Simplify the following fractions : 9 10 (a) (b) 27 35 2. Find the lowest multiple of 2 and3 1 1 3 5 3. Calculate (a) (b) 2 4 4 6 3 4. Calculate 8
  • 3. Learning Intention Success Criteria 1. To explain how to simplify algebraic fractions. 1. Understand term Highest Common Factor. Algebraic Operations 2. Simplify algebraic fractions by identifying HCF.
  • 4. Fraction in Simplest form We can sometimes reduce fractions to a simpler form if the numerator and denominator have a number or letter in common. Examples 12 15 3 4 3 5 4 5 HCF = 3 2 y y y y y 1 y y HCF = Y
  • 5. Fraction in Simplest form Examples 2 2 6 b b 2 6 b b b 1 3b 3 2 a a a a a a a 1 a a 3 1 1 1 1 1 1 1
  • 6. Fraction in Simplest form Examples 2 3 ( 1) ( 1) y y ( 1)( 1) ( 1)( 1)( 1) y y y y y 1 ( 1)y 1 1 1 1
  • 7. Starter Questions 1. Simplify the following fractions : 3 4 3g 5e (a) (b) 9g 2e 2. Find the lowest multiple of 4 and 9 1 1 3 5 3. Calculate (a) (b) 2 5 10 6 3 4. Calculate 27
  • 8. Learning Intention Success Criteria 1. To explain how to add and subtract algebraic fractions. 1. Know how to add and sub simple fractions Algebraic Operations 2. Apply same knowledge to add and sub algebraic fractions.
  • 9. Adding Algebraic Fractions 3 1 5 5 3 1 5 4 5 LCM = 5 Example 1a 3 1 d d 3 1 d 4 d LCM = d Example 1b
  • 10. Subtract Algebraic Fractions 3 2 4 5 15 8 20 20 7 20 LCM = 20 Example 2a 3 2 p q 3 2q p pq LCM = pq Example 2b 23 pq pq qp 23 pq p q q p 3 5 2 4 4 5 5 4
  • 11. Adding Algebraic Fractions 3 1 4 6 9 2 12 12 11 12 LCM = 12 Example 3a 2 3 1 2x x 2 3 2 2 x x LCM = 2x2 Example 3b 2 2 3 2 2 2 x x x 2 3 1 2 2 2 x x x x 3 3 1 2 4 3 6 2
  • 12. 3 4 3. - 2a 3a Starter Questions Calculate the following : 1 1 1. + 2 3 2 5 2. + h h 2 4 3 4. - y y
  • 13. Learning Intention Success Criteria 1. To explain how to multiply and divide by algebraic fractions. 1. Know rules for multiplication and division of simple fractions. Algebraic Operations 2. Apply knowledge to algebraic fractions. Multiplication and division
  • 14. 3 4 8 5 3 10 Example 1a 2 5 3 6 a a 5 2a Example 1b Algebraic Fractions Multiplication and division 3 4 8 5 2 1 2 5 3 6 a a2 11 a
  • 15. 4 5 9 6 8 15 Example 2a 2 5 3 xy x y 2 2 15 y Example 2b Algebraic Fractions Multiplication and division 4 6 9 5 3 2 2 3 5 xy y x 1 1
  • 16. 3 a 3. 2a 4 Starter Questions Calculate the following : 1 1 1. 2 3 2 5 2. h h 2 4 3 4. y y
  • 17. Learning Intention Success Criteria 1. To explain how to change the subject of a formula using “change side change sign” method. 1. Know change sign change sign for solving equations. Algebraic Operations 2. Apply knowledge to change subject of a formula. The Subject of a Formula
  • 18. Algebraic Fractions The Subject of a Formula The formula below is used to work out the circumference of a circle C D Since the formula works out C , then C is called the subject of the formula.
  • 19. Algebraic Fractions The Subject of a Formula We can make D the subject of the formula by using the rule “ opposite side opposite side “ C D C D C D
  • 20. What Goes In The Box ? 1 y = x - 1 4 Make y the subject of the formulae below : x + y = 8 x = y - 9 -x + 2y = 2 x = 4( y + 1 ) y = 8- x y = x + 9 1 y = x + 1 2
  • 21. 3 a 3. 2a 4 Starter Questions Calculate the following : 1 1 1. 2 3 2 5 2. h h 2 4 3 4. y y
  • 22. Learning Intention Success Criteria 1. To explain how to change the subject of a formula containing square and square root terms. 1. Know change sign change sign for solving equations. Algebraic Operations 2. Apply knowledge to change subject of harder formulae including square and square root terms. The Subject of a Formula
  • 23. Algebraic Fractions The Subject of a Formula Example : The force of the air against a train is given by the formula below. Make the speed (S) the subject of the formula. 2 F S k F S k
  • 24. Algebraic Fractions The Subject of a Formula Example : The thickness of a rope T cm to lift a weight W tonnes can be worked out by the formula below. Make W the subject of the formula. 4 9 W T 9 4 T W 2 9 4 T W 2 9 4 T W