The document defines direct variation and provides examples of how to determine if a relationship is direct variation. It explains that direct variation can be represented by an equation in the form of y=kx, where k is the constant of variation. It gives examples of determining the constant of variation from tables of x and y values and using the constant to find unknown values. It also provides examples of solving word problems using direct variation.
May this presentation could help you, the pictures here is not mine I get it from YouTube videos, I upload this ppt because
most the ppt here help me a lot in my teaching mathematics. This topics is different kinds variation direct variation, inverse variation, joint variation and combined variation.
PROJECT (PPT) ON PAIR OF LINEAR EQUATIONS IN TWO VARIABLES - CLASS 10mayank78610
THIS A PROJECT BEING MADE BY INFORMATION COLLECTED FROM CLASS 10 MATHS NCERT BOOK.
THANK YOU FOR SEEING MY PROJECT ... I THINK THIS MIGHT HELP YOU IN YOUR HOLIDAY HOMEWORK PROJECTS .
May this presentation could help you, the pictures here is not mine I get it from YouTube videos, I upload this ppt because
most the ppt here help me a lot in my teaching mathematics. This topics is different kinds variation direct variation, inverse variation, joint variation and combined variation.
PROJECT (PPT) ON PAIR OF LINEAR EQUATIONS IN TWO VARIABLES - CLASS 10mayank78610
THIS A PROJECT BEING MADE BY INFORMATION COLLECTED FROM CLASS 10 MATHS NCERT BOOK.
THANK YOU FOR SEEING MY PROJECT ... I THINK THIS MIGHT HELP YOU IN YOUR HOLIDAY HOMEWORK PROJECTS .
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2. Definition: Y varies directly as x means that y = kx where k is the constant of variation. (see any similarities to y = mx + b?) Another way of writing this is k = In other words: * As X increases in value, Y increases or * As X decreases in value, Y decreases.
3. Examples of Direct Variation: Note: X increases, 6 , 7 , 8 And Y increases. 12, 14, 16 What is the constant of variation of the table above? Since y = kx we can say Therefore: 12/6=k or k = 2 14/7=k or k = 2 16/8=k or k =2 Note k stays constant. y = 2x is the equation!
4. Note: X decreases, 30, 15, 9 And Y decreases. 10, 5, 3 What is the constant of variation of the table above? Since y = kx we can say Therefore: 30/10=k or k = 3 15/5=k or k = 3 9/3=k or k =3 Note k stays constant. y = 3x is the equation! Examples of Direct Variation:
5. Note: X decreases, -4, -16, -40 And Y decreases. -1,-4,-10 What is the constant of variation of the table above? Since y = kx we can say Therefore: -1/-4=k or k = ¼ -4/-16=k or k = ¼ -10/-40=k or k = ¼ Note k stays constant. y = ¼ x is the equation! Examples of Direct Variation:
6.
7. Is this a direct variation? If yes, give the constant of variation (k) and the equation. Yes! k = 6/4 or 3/2 Equation? y = 3/2 x
8. Yes! k = 25/10 or 5/2 k = 10/4 or 5/2 Equation? y = 5/2 x Is this a direct variation? If yes, give the constant of variation (k) and the equation.
9. No! The k values are different! Is this a direct variation? If yes, give the constant of variation (k) and the equation.
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12. Using Direct Variation to find unknowns (y = kx) Given that y varies directly with x, and y = 28 when x=7, Find x when y = 52. HOW??? 2 step process 1. Find the constant variation k = y/x or k = 28/7 = 4 k=4 2. Use y = kx. Find the unknown (x). 52= 4x or 52/4 = x x= 13 Therefore: X =13 when Y=52
13. Given that y varies directly with x, and y = 3 when x=9, Find y when x = 40.5. HOW??? 2 step process 1. Find the constant variation. k = y/x or k = 3/9 = 1/3 K = 1/3 2. Use y = kx. Find the unknown (x). y= (1/3)40.5 y= 13.5 Therefore: X =40.5 when Y=13.5 Using Direct Variation to find unknowns (y = kx)
14. Given that y varies directly with x, and y = 6 when x=-5, Find y when x = -8. HOW??? 2 step process 1. Find the constant variation. k = y/x or k = 6/-5 = -1.2 k = -1.2 2. Use y = kx. Find the unknown (x). y= -1.2(-8) x= 9.6 Therefore: X =-8 when Y=9.6 Using Direct Variation to find unknowns (y = kx)
15. Using Direct Variation to solve word problems Problem: A car uses 8 gallons of gasoline to travel 290 miles. How much gasoline will the car use to travel 400 miles? Step One : Find points in table Step Two: Find the constant variation and equation: k = y/x or k = 290/8 or 36.25 y = 36.25 x Step Three: Use the equation to find the unknown. 400 =36.25x 400 = 36.25x 36.25 36.25 or x = 11.03
16. Using Direct Variation to solve word problems Problem: Julio wages vary directly as the number of hours that he works. If his wages for 5 hours are $29.75, how much will they be for 30 hours Step One: Find points in table. Step Two: Find the constant variation. k = y/x or k = 29.75/5 = 5.95 Step Three: Use the equation to find the unknown. y=kx y=5.95(30) or Y=178.50
17. Direct Variation and its graph y = mx +b, m = slope and b = y-intercept With direction variation the equation is y = kx Note: m = k or the constant and b = 0 therefore the graph will always go through…
