I would like  to give credit to the following people below for the wonderful PowerPoint presentation.  Thank you very much, Ms. Garcia Moy Yee Ping  3 Szeto Kwok Fai  2 Chau Ping 1
Trigonometry ( 三角幾何 )  means “ Triangle” and “Measurement” Introduction Trigonometric Ratios
Adjacent , Opposite Side and Hypotenuse of a Right Angle Triangle .
Adjacent side Opposite side hypotenuse 
hypotenuse Adjacent side Opposite side 
Three Types Trigonometric Ratios There are 3 kinds of trigonometric ratios we will learn. sine ratio cosine ratio tangent ratio
Sine Ratios Definition of Sine Ratio. Application of Sine Ratio.
Definition of  Sine Ratio . 1 If the hypotenuse equals to 1 Sin   =   Opposite sides
Definition of  Sine Ratio . For any right-angled triangle Sin   =   Opposite side hypotenuses
Exercise 1 In the figure, find sin   Sin   =  Opposite Side hypotenuses = 4 7    =  34.85   (corr to 2 d.p.)   4 7
Exercise 2 11 In the figure, find y Sin35   =  Opposite Side hypotenuses y 11 y =  6.31 (corr to 2.d.p.) 35 ° y Sin35   =  y =  11 sin35 
Cosine Ratios Definition of Cosine. Relation of Cosine to the sides of right angle triangle.
Definition of  Cosine Ratio . 1 If the hypotenuse equals to 1 Cos   =   Adjacent Side
Definition of  Cosine Ratio . For any right-angled triangle Cos   =   hypotenuses Adjacent Side
Exercise 3  3 8 In the figure, find cos   cos   =  adjacent Side hypotenuses = 3 8    =  67.98   (corr to 2 d.p.)
Exercise 4 6 In the figure, find x Cos 42   =  Adjacent Side hypotenuses 6 x x =  8.07 (corr to 2.d.p.) 42 ° x Cos 42   =  x = 6 Cos 42 
Tangent Ratios Definition of Tangent.  Relation of Tangent  to the sides of right angle triangle.
Definition of Tangent Ratio. For any right-angled triangle tan   =   Adjacent Side Opposite Side
Exercise 5  3 5 In the figure, find tan   tan   =  adjacent Side Opposite side = 3 5    =  78.69   (corr to 2 d.p.)
Exercise 6 z 5 In the figure, find z tan  22   =  adjacent Side Opposite side 5 z z =  12.38 (corr to 2 d.p.)  22  tan  22   =  5 tan  22  z =
Conclusion Make Sure that the triangle is right-angled
The END

Trigo Ratios

  • 1.
    I would like to give credit to the following people below for the wonderful PowerPoint presentation. Thank you very much, Ms. Garcia Moy Yee Ping 3 Szeto Kwok Fai 2 Chau Ping 1
  • 2.
    Trigonometry ( 三角幾何) means “ Triangle” and “Measurement” Introduction Trigonometric Ratios
  • 3.
    Adjacent , OppositeSide and Hypotenuse of a Right Angle Triangle .
  • 4.
    Adjacent side Oppositeside hypotenuse 
  • 5.
    hypotenuse Adjacent sideOpposite side 
  • 6.
    Three Types TrigonometricRatios There are 3 kinds of trigonometric ratios we will learn. sine ratio cosine ratio tangent ratio
  • 7.
    Sine Ratios Definitionof Sine Ratio. Application of Sine Ratio.
  • 8.
    Definition of Sine Ratio . 1 If the hypotenuse equals to 1 Sin  =  Opposite sides
  • 9.
    Definition of Sine Ratio . For any right-angled triangle Sin  =  Opposite side hypotenuses
  • 10.
    Exercise 1 Inthe figure, find sin  Sin  = Opposite Side hypotenuses = 4 7  = 34.85  (corr to 2 d.p.)  4 7
  • 11.
    Exercise 2 11In the figure, find y Sin35  = Opposite Side hypotenuses y 11 y = 6.31 (corr to 2.d.p.) 35 ° y Sin35  = y = 11 sin35 
  • 12.
    Cosine Ratios Definitionof Cosine. Relation of Cosine to the sides of right angle triangle.
  • 13.
    Definition of Cosine Ratio . 1 If the hypotenuse equals to 1 Cos  =  Adjacent Side
  • 14.
    Definition of Cosine Ratio . For any right-angled triangle Cos  =  hypotenuses Adjacent Side
  • 15.
    Exercise 3 3 8 In the figure, find cos  cos  = adjacent Side hypotenuses = 3 8  = 67.98  (corr to 2 d.p.)
  • 16.
    Exercise 4 6In the figure, find x Cos 42  = Adjacent Side hypotenuses 6 x x = 8.07 (corr to 2.d.p.) 42 ° x Cos 42  = x = 6 Cos 42 
  • 17.
    Tangent Ratios Definitionof Tangent. Relation of Tangent to the sides of right angle triangle.
  • 18.
    Definition of TangentRatio. For any right-angled triangle tan  =  Adjacent Side Opposite Side
  • 19.
    Exercise 5 3 5 In the figure, find tan  tan  = adjacent Side Opposite side = 3 5  = 78.69  (corr to 2 d.p.)
  • 20.
    Exercise 6 z5 In the figure, find z tan 22  = adjacent Side Opposite side 5 z z = 12.38 (corr to 2 d.p.) 22  tan 22  = 5 tan 22  z =
  • 21.
    Conclusion Make Surethat the triangle is right-angled
  • 22.