This document provides instructions and objectives for a chemistry lesson on converting between grams and atoms using molecular mass and Avogadro's number as conversion factors. The lesson begins with directions to get prepared for the lesson by taking a seat and gathering materials. The objective for the lesson is stated as being able to convert between grams and atoms using molecular mass and Avogadro's number as conversion factors. Students are then given time to review notes in preparation for an upcoming quiz and warned that the quiz will start immediately if students are not using the study time productively.
How large is an atom? How many atoms are in the leads of 12 lead pencils? Pencil leads are made of carbon atoms. Carbon has an atomic mass of 12. how can we visual this ?
How large is an atom? How many atoms are in the leads of 12 lead pencils? Pencil leads are made of carbon atoms. Carbon has an atomic mass of 12. how can we visual this ?
This activity is designed to introduce a convenient unit used by.docxhowardh5
This activity is designed to introduce a convenient unit used by chemists and to illustrate uses of the unit.
Part I: What Is a Mole And Why Are Chemists Interested in It?
Counting things is a normal part of everyday life. How many days left until vacation? How many eggs do I need for the recipe? If large numbers of things are involved, we use grouping
strategies to make the numbers easier to manage. For example, 4 more
weeks
until vacation, tells
us that there are twenty-eight days. One
dozen
eggs is the common way of expressing the quantity
12.
Half of a dozen of anything would be 6 units. One
gross
is 144 items (12 dozen) and a
ream
of paper contain 500 sheets.
Chemist are faced with a unique problem when dealing with numbers of atoms or molecules. The particles are so small that any amount of them that we are able to physically handle contains a number of particles so large that there is nothing else in our experience that contains so many units. This
incredibly
large number calls for a special counting group -
the MOLE.
A
MOLE
is
6.022
x
1023
particles
. This is often referred to as
Avogadro=s
number
. Let=s make sure we understand how big this is. One mole of the element carbon has a mass of 12.01 grams. The smallest particle of an element is an atom. So one mole of carbon contains 602,200,000,000,000,000,000,000 atoms of carbon.
Look for the element carbon on the periodic table. Do you notice anything special about the value 12.01? Explain
The mass of one mole of the element magnesium is 24.30 grams. How many atoms does a sample of magnesium with a mass of 24.30 grams contain?
Stated in general terms, the mass of one mole of any element is equal to the
of that element expressed in grams. The mass of a mole of any element can be found by looking on .
The mass of 0.5000 moles of carbon is and contains
atoms of carbon.
Remember when dividing numbers written in scientific notation the number portion is divided
normally and the exponents are subtracted.
6.022x1023
divided by 2 is the same as 6.022 x1023/2
x
100.
So the answer is found by dividing 6.022 by 2 = 3.011 and the subtracting exponent 0
from exponent 23.
The answer in scientific notation is 3.011x1023
atoms
of carbon.
Calculator tip
: for exponential notation use the EE or EXP key (not 10^)
If you have a bottle containing 8.10 grams of magnesium, how many Mg atoms are present in the bottle? Show your work. What is different about this problem compared to the last one involving carbon?
Remember that some elements, when alone, exist in the form of diatomic molecules: H2, O2, N2, I2, F2, Cl2, Br2, Their smallest piece is a molecule containing two atoms. If one mole of oxygen were required for an experiment you would be using O2 the gas. One mole of O2 would have a mass of
and contain particles (molecules).
The characteristic unit of the compound CO2 is a molecule. Each CO2 molecule has atoms. In order to find the mass .
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12 4 Conversions Review
1. Launch: 12/4
Grab your binder and immediately take a seat!
Place homework (practice questions), binder paper, and
a pen/pencil on your desk.
Today’s Objective: I can convert between grams and
atoms using both molecular mass and
Avogadro’s number as a conversion factors
Tonight’s HW: Relax!
2. Launch 12/4
Take the next three minutes to look over you notes
(11/23 to 12/1) and prepare for the quiz.
Warning: If people are not taking advantage of the
study time, we will start the quiz immediately!
4. Launch 12/4
2. Which conversion factor would need to be used to
convert gramsmoles?
a. Avogadro’s number
b. 6.02 X 1023 atoms/mole
c. Molecular mass
d. Atomic mass
5. Launch 12/4
3. Which conversion factor would need to be used to
convert atomsmoles? Why?
9. How many atoms?
Conversion factors… ..or particles, or molecules
are used to convert one unit to another unit
sum of
atomic Molar Mass Avogadro’s #
masses
? grams/mole 6.02 X 1023 atoms/mole
? grams 6.02 X 1023 atoms
1 mole 1 mole
1 mole 1 mole
? grams 6.02 X 1023 atoms
Grams Moles Atoms Moles
10. How many atoms?
What if we want to convert grams atoms?
Need to use both conversion factors!
11. How many atoms?
There is a 3-step process for conversions:
1. Write down the starting unit and look at the ending unit.
2. Write the conversion factor with the starting units on the
bottom.
If grams, start with molar mass
If atoms (or particles, or molecules), start with Avogadro’s #
3. Cancel like terms and multiply across the top and bottom.
12. Example #1
How many atoms are there in 12.01 grams of carbon (C)?
Step #1: Write down the starting unit and look at the
ending unit.
12.01 grams
13. Example #1
How many atoms are there in 12.01 grams of carbon (C)?
Step #2: Write the conversion factor with the starting units
on the bottom.
1 mol 6.02 X 1023 atoms
12.01 g X X =
12.01 g 1 mol
Start with Then use
molecular Avogadro’s #
mass
14. Example #1
How many atoms are there in 12.01 grams of carbon (C)?
Step #3: Cancel like terms and multiply across the top
and bottom
1 mol 6.02 X 1023 atoms
12.01 g X X =
12.01 g 1 mol
Ignore
1 X 6.02 X 1023 atoms
=
1
6.02 X 1023 atoms =
15. Example #3
How many grams of CH4 are there in 12.04 X 1023 molecules?
Step #1: Write down the starting unit and look at the ending
unit.
12.04 X 1023 molecules
16. Example #3
How many grams of CH4 are there in 12.04 X 1023 molecules?
Step #2: Write the conversion factor with the starting units
on the bottom.
1 mol 16.05 g
12.04 X 1023 molecules X X
1 mol
=
6.02 X 10 23 molecules
Then use
Start with molecular
Avogadro’s # mass
17. Example #3
How many grams of CH4 are there in 12.04 X 1023 molecules?
Step #3: Cancel like terms and multiply across the top
and bottom
1 mol 16.05 g
12.04 X 1023 molecules X X
1 mol
=
6.02 X 10 23 molecules
12.04 X 1 X 16.05 g
=
6.02 X 1
32.10 g = 2 X 16.05 g =
18. Example #2
How many atoms are there in 16.00 grams of O2?
Step #1: Write down the starting unit and look at the
ending unit.
16.00 grams
19. Example #2
How many atoms are there in 16.00 grams of O2?
Step #2: Write the conversion factor with the starting units
on the bottom.
1 mol 6.02 X 1023 atoms
16.00 g X X =
32.00 g 1 mol
Start with Then use
molecular Avogadro’s #
mass
20. Example #2
How many atoms are there in 16.00 grams of O2?
Step #3: Cancel like terms and multiply across the top
and bottom
1 mol 6.02 X 1023 atoms
16.00g X X =
32.00 g 1 mol
Ignore
16.00 X 6.02 X 1023 atoms
=
32.00 X 1
3.01 X 1023 atoms = .5 X 6.02 X 1023 atoms =
21. Whiteboards
Work in pairs
Trade-off marker every question
You have 60 seconds to solve the question
Show all of your work!
Don’t forget units!
Lift board only when prompted
27. Exit Slip
1. Which conversion factor would need to be used to
convert between gramsmoles?
a. Avogadro’s number
b. 6.02 X 1023 atoms/mole
c. Molecular mass
d. Atomic weight
28. Exit Slip
2. Which conversion factor would need to be used to
convert grams into atoms?
a. Avogadro’s number
b. Atomic weight
c. Molecular mass
d. both a & c
29. Exit Slip
3. Which of the following correctly shows how to convert
64.00g of O2 to atoms?
6.02 X 1023 atoms
a. 32.00g X
32.00g
1 mole
b. 64.00g X 32.00 g
1 mole 6.02 X 1023 atoms
c. 64.00g X 32.00 g X 1 mole
1 mole 1 atoms
d. 64.00 g X X
6.02 X 10 23 g
32.00 moles
30. Exit Slip
4. How many atoms of nitrogen (N) are there in 14.01g?
a. 3.01 X 1023 atoms
b. 6.02 X 1023 atoms
c. 9.03 X 1023 atoms
d. 1.204 X 1024 atoms
31. Exit Slip
5. How many grams does 12.04 X 1023 molecules of
H2O weigh?
a. 9.01g
b. 18.02g
c. 27.03g
d. 36.04g