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Launch: 12/4
  Grab your binder and immediately take a seat!
  Place homework (practice questions), binder paper, and
  a pen/pencil on your desk.



Today’s Objective: I can convert between grams and
  atoms using both molecular mass and
  Avogadro’s number as a conversion factors
Tonight’s HW: Relax!
Launch 12/4
Take the next three minutes to look over you notes
      (11/23 to 12/1) and prepare for the quiz.

Warning: If people are not taking advantage of the
   study time, we will start the quiz immediately!
Launch 12/4
1.  How did Avogadro define the mole?
Launch 12/4
2.  Which conversion factor would need to be used to
   convert gramsmoles?
  a.  Avogadro’s number
  b.  6.02 X 1023 atoms/mole
  c.  Molecular mass
  d.  Atomic mass
Launch 12/4
3.  Which conversion factor would need to be used to
   convert atomsmoles? Why?
Launch 12/4
3.  How many grams of H2 are there in 8.08g of H2?
Announcements
  Quiz on Friday
    The mole
    Conversions

  Unit exam in 2 weeks
How many atoms? – Part II
          Mr. Heffner
           12/1/09
How many atoms?
     Conversion factors…                 ..or particles, or molecules

       are used to convert one unit to another unit
sum of
atomic     Molar Mass                    Avogadro’s #
masses
          ? grams/mole              6.02 X 1023 atoms/mole
            ? grams                   6.02 X 1023 atoms
             1 mole                         1 mole
             1 mole                         1 mole
            ? grams                   6.02 X 1023 atoms
         Grams  Moles               Atoms  Moles
How many atoms?
  What if we want to convert grams  atoms?
    Need to use both conversion factors!
How many atoms?
  There is a 3-step process for conversions:
  1.  Write down the starting unit and look at the ending unit.
  2.  Write the conversion factor with the starting units on the
      bottom.
      If grams, start with molar mass
      If atoms (or particles, or molecules), start with Avogadro’s #
  3.  Cancel like terms and multiply across the top and bottom.
Example #1
   How many atoms are there in 12.01 grams of carbon (C)?

  Step #1: Write down the starting unit and look at the
  ending unit.



  12.01 grams
Example #1
    How many atoms are there in 12.01 grams of carbon (C)?

  Step #2: Write the conversion factor with the starting units
   on the bottom.
                    1 mol        6.02 X 1023 atoms
  12.01 g X                    X                   =
                   12.01 g             1 mol


      Start with               Then use
      molecular              Avogadro’s #
        mass
Example #1
   How many atoms are there in 12.01 grams of carbon (C)?

  Step #3: Cancel like terms and multiply across the top
   and bottom
                  1 mol         6.02 X 1023 atoms
  12.01 g X                   X                   =
                 12.01 g              1 mol
                                                   Ignore

                            1 X 6.02 X 1023 atoms
                                                  =
                                      1

                                 6.02 X 1023 atoms =
Example #3
 How many grams of CH4 are there in 12.04 X 1023 molecules?

Step #1: Write down the starting unit and look at the ending
                             unit.


  12.04 X 1023 molecules
Example #3
  How many grams of CH4 are there in 12.04 X 1023 molecules?

  Step #2: Write the conversion factor with the starting units
   on the bottom.

                                     1 mol              16.05 g
12.04 X   1023   molecules X                        X
                                                         1 mol
                                                                  =
                             6.02 X 10 23 molecules




                                                  Then use
                     Start with                   molecular
                    Avogadro’s #                   mass
Example #3
  How many grams of CH4 are there in 12.04 X 1023 molecules?

  Step #3: Cancel like terms and multiply across the top
   and bottom

                                     1 mol              16.05 g
12.04 X   1023   molecules X                        X
                                                         1 mol
                                                                  =
                             6.02 X 10 23 molecules



                                       12.04 X 1 X 16.05 g
                                                                  =
                                            6.02 X 1

                                        32.10 g = 2 X 16.05 g =
Example #2
       How many atoms are there in 16.00 grams of O2?

  Step #1: Write down the starting unit and look at the
  ending unit.



  16.00 grams
Example #2
       How many atoms are there in 16.00 grams of O2?

  Step #2: Write the conversion factor with the starting units
   on the bottom.
                    1 mol        6.02 X 1023 atoms
  16.00 g X                    X                   =
                   32.00 g             1 mol


      Start with               Then use
      molecular              Avogadro’s #
        mass
Example #2
       How many atoms are there in 16.00 grams of O2?

  Step #3: Cancel like terms and multiply across the top
   and bottom
                  1 mol         6.02 X 1023 atoms
  16.00g X                    X                   =
                 32.00 g              1 mol
                                                   Ignore

                        16.00 X 6.02 X 1023 atoms
                                                  =
                                32.00 X 1

     3.01 X 1023 atoms = .5 X 6.02 X 1023 atoms =
Whiteboards
  Work in pairs
    Trade-off marker every question
  You have 60 seconds to solve the question
    Show all of your work!
    Don’t forget units!

  Lift board only when prompted
How many atoms are there in
8.00 grams of helium (He) ?
How many molecules are
there in 4.04 grams of H2?
What is the mass (in grams)
 of 6.02 X 10  23 particles

        of gold (Au)?
How many grams does
3.01 X 1023 molecules

    of HCl weight?
Practice Questions
  Practice question worksheet
Exit Slip
1.  Which conversion factor would need to be used to
   convert between gramsmoles?
  a.  Avogadro’s number
  b.  6.02 X 1023 atoms/mole
  c.  Molecular mass
  d.  Atomic weight
Exit Slip
2.  Which conversion factor would need to be used to
   convert grams into atoms?
  a.  Avogadro’s number
  b.  Atomic weight
  c.  Molecular mass
  d.  both a & c
Exit Slip
3.  Which of the following correctly shows how to convert
   64.00g of O2 to atoms?
               6.02 X 1023 atoms
  a.  32.00g X
                    32.00g
                  1 mole
  b.  64.00g X    32.00 g
                  1 mole      6.02 X 1023 atoms
  c.  64.00g X    32.00 g X        1 mole
                     1 mole            1 atoms
  d.  64.00 g X                  X
                  6.02 X 10 23 g
                                     32.00 moles
Exit Slip
4.  How many atoms of nitrogen (N) are there in 14.01g?
  a.    3.01 X 1023 atoms
  b.    6.02 X 1023 atoms
  c.    9.03 X 1023 atoms
  d.    1.204 X 1024 atoms
Exit Slip
5.  How many grams does 12.04 X 1023 molecules of
   H2O weigh?
  a.  9.01g
  b.  18.02g
  c.  27.03g
  d.  36.04g
Homework
  Finish practice questions
  Study for Friday’s Quiz!

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12 4 Conversions Review

  • 1. Launch: 12/4   Grab your binder and immediately take a seat!   Place homework (practice questions), binder paper, and a pen/pencil on your desk. Today’s Objective: I can convert between grams and atoms using both molecular mass and Avogadro’s number as a conversion factors Tonight’s HW: Relax!
  • 2. Launch 12/4 Take the next three minutes to look over you notes (11/23 to 12/1) and prepare for the quiz. Warning: If people are not taking advantage of the study time, we will start the quiz immediately!
  • 3. Launch 12/4 1.  How did Avogadro define the mole?
  • 4. Launch 12/4 2.  Which conversion factor would need to be used to convert gramsmoles? a.  Avogadro’s number b.  6.02 X 1023 atoms/mole c.  Molecular mass d.  Atomic mass
  • 5. Launch 12/4 3.  Which conversion factor would need to be used to convert atomsmoles? Why?
  • 6. Launch 12/4 3.  How many grams of H2 are there in 8.08g of H2?
  • 7. Announcements   Quiz on Friday   The mole   Conversions   Unit exam in 2 weeks
  • 8. How many atoms? – Part II Mr. Heffner 12/1/09
  • 9. How many atoms?   Conversion factors… ..or particles, or molecules   are used to convert one unit to another unit sum of atomic Molar Mass Avogadro’s # masses ? grams/mole 6.02 X 1023 atoms/mole ? grams 6.02 X 1023 atoms 1 mole 1 mole 1 mole 1 mole ? grams 6.02 X 1023 atoms Grams  Moles Atoms  Moles
  • 10. How many atoms?   What if we want to convert grams  atoms?   Need to use both conversion factors!
  • 11. How many atoms?   There is a 3-step process for conversions: 1.  Write down the starting unit and look at the ending unit. 2.  Write the conversion factor with the starting units on the bottom.   If grams, start with molar mass   If atoms (or particles, or molecules), start with Avogadro’s # 3.  Cancel like terms and multiply across the top and bottom.
  • 12. Example #1 How many atoms are there in 12.01 grams of carbon (C)?   Step #1: Write down the starting unit and look at the ending unit. 12.01 grams
  • 13. Example #1 How many atoms are there in 12.01 grams of carbon (C)?   Step #2: Write the conversion factor with the starting units on the bottom. 1 mol 6.02 X 1023 atoms 12.01 g X X = 12.01 g 1 mol Start with Then use molecular Avogadro’s # mass
  • 14. Example #1 How many atoms are there in 12.01 grams of carbon (C)?   Step #3: Cancel like terms and multiply across the top and bottom 1 mol 6.02 X 1023 atoms 12.01 g X X = 12.01 g 1 mol Ignore 1 X 6.02 X 1023 atoms = 1 6.02 X 1023 atoms =
  • 15. Example #3 How many grams of CH4 are there in 12.04 X 1023 molecules? Step #1: Write down the starting unit and look at the ending unit. 12.04 X 1023 molecules
  • 16. Example #3 How many grams of CH4 are there in 12.04 X 1023 molecules?   Step #2: Write the conversion factor with the starting units on the bottom. 1 mol 16.05 g 12.04 X 1023 molecules X X 1 mol = 6.02 X 10 23 molecules Then use Start with molecular Avogadro’s # mass
  • 17. Example #3 How many grams of CH4 are there in 12.04 X 1023 molecules?   Step #3: Cancel like terms and multiply across the top and bottom 1 mol 16.05 g 12.04 X 1023 molecules X X 1 mol = 6.02 X 10 23 molecules 12.04 X 1 X 16.05 g = 6.02 X 1 32.10 g = 2 X 16.05 g =
  • 18. Example #2 How many atoms are there in 16.00 grams of O2?   Step #1: Write down the starting unit and look at the ending unit. 16.00 grams
  • 19. Example #2 How many atoms are there in 16.00 grams of O2?   Step #2: Write the conversion factor with the starting units on the bottom. 1 mol 6.02 X 1023 atoms 16.00 g X X = 32.00 g 1 mol Start with Then use molecular Avogadro’s # mass
  • 20. Example #2 How many atoms are there in 16.00 grams of O2?   Step #3: Cancel like terms and multiply across the top and bottom 1 mol 6.02 X 1023 atoms 16.00g X X = 32.00 g 1 mol Ignore 16.00 X 6.02 X 1023 atoms = 32.00 X 1 3.01 X 1023 atoms = .5 X 6.02 X 1023 atoms =
  • 21. Whiteboards   Work in pairs   Trade-off marker every question   You have 60 seconds to solve the question   Show all of your work!   Don’t forget units!   Lift board only when prompted
  • 22. How many atoms are there in 8.00 grams of helium (He) ?
  • 23. How many molecules are there in 4.04 grams of H2?
  • 24. What is the mass (in grams) of 6.02 X 10 23 particles of gold (Au)?
  • 25. How many grams does 3.01 X 1023 molecules of HCl weight?
  • 27. Exit Slip 1.  Which conversion factor would need to be used to convert between gramsmoles? a.  Avogadro’s number b.  6.02 X 1023 atoms/mole c.  Molecular mass d.  Atomic weight
  • 28. Exit Slip 2.  Which conversion factor would need to be used to convert grams into atoms? a.  Avogadro’s number b.  Atomic weight c.  Molecular mass d.  both a & c
  • 29. Exit Slip 3.  Which of the following correctly shows how to convert 64.00g of O2 to atoms? 6.02 X 1023 atoms a.  32.00g X 32.00g 1 mole b.  64.00g X 32.00 g 1 mole 6.02 X 1023 atoms c.  64.00g X 32.00 g X 1 mole 1 mole 1 atoms d.  64.00 g X X 6.02 X 10 23 g 32.00 moles
  • 30. Exit Slip 4.  How many atoms of nitrogen (N) are there in 14.01g? a.  3.01 X 1023 atoms b.  6.02 X 1023 atoms c.  9.03 X 1023 atoms d.  1.204 X 1024 atoms
  • 31. Exit Slip 5.  How many grams does 12.04 X 1023 molecules of H2O weigh? a.  9.01g b.  18.02g c.  27.03g d.  36.04g
  • 32. Homework   Finish practice questions   Study for Friday’s Quiz!