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MapYourTech.com
MapYourTech.com
 The switching delay for the unidirectional signal fail in the
worst case can be evaluated for a 16 nodes ring with a
maximum length of 1200 Km.
 Let Dp be the processing delay in a pass-through node, J*Dp
the processing delay in a switching node, 0,375 ms the time it
takes to validate a new message (three frames) and
assuming that transmission
 delay over a fiber system be 5 ms/Km the contributions to the
delay are:
 Consider A link between A-B-C-D-E-F
MapYourTech.com
 Time it takes to node F to generate first request: J*Dp
 Time it takes to the intermediate nodes to move to pass-through:
14*(Dp+0,375)
 Time it takes to node E to process the request: J*Dp+0,375
 Time it takes to node E to generate the acknowledgement request:
J*Dp
 Time it takes to the intermediate nodes to pass-through the message
from E (see note): 14*Dp
 Time it takes to node F to process the request from node E: J*Dp+0,375.
 The transmission delay over the fiber is (long path) : (15/16)*1200*0.005
 Then the total switching delay Sd is:
Sd = 4 *J* Dp + 28* Dp +16* 0.375+ 2*(15/16)* 1200*0.005
 NOTE: A node in pass-through state is supposed not to check the
incoming K-bytes for three
frames before relaying them on the outgoing signal.
MapYourTech.com
MapYourTech.com
MapYourTech.com
MapYourTech.com

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Switching time for telecom circuits a small introduction

  • 3.  The switching delay for the unidirectional signal fail in the worst case can be evaluated for a 16 nodes ring with a maximum length of 1200 Km.  Let Dp be the processing delay in a pass-through node, J*Dp the processing delay in a switching node, 0,375 ms the time it takes to validate a new message (three frames) and assuming that transmission  delay over a fiber system be 5 ms/Km the contributions to the delay are:  Consider A link between A-B-C-D-E-F MapYourTech.com
  • 4.  Time it takes to node F to generate first request: J*Dp  Time it takes to the intermediate nodes to move to pass-through: 14*(Dp+0,375)  Time it takes to node E to process the request: J*Dp+0,375  Time it takes to node E to generate the acknowledgement request: J*Dp  Time it takes to the intermediate nodes to pass-through the message from E (see note): 14*Dp  Time it takes to node F to process the request from node E: J*Dp+0,375.  The transmission delay over the fiber is (long path) : (15/16)*1200*0.005  Then the total switching delay Sd is: Sd = 4 *J* Dp + 28* Dp +16* 0.375+ 2*(15/16)* 1200*0.005  NOTE: A node in pass-through state is supposed not to check the incoming K-bytes for three frames before relaying them on the outgoing signal. MapYourTech.com