This document is a marking scheme for the Additional Mathematics Paper 1 trial examination for SPM 2009 in Kedah Darul Aman. It provides the solutions, workings, and marks allocated for each question on the exam. The marking scheme has 25 questions and guides examiners on accurately and consistently marking student responses.

1. SULIT JPNKd/2006/3472/1
Nama Pelajar : ………………………………… Tingkatan 5 : …………………….
3472/1
Additional
Mathematics
September 2009
PERSIDANGAN KEBANGSAAN PENGETUA-PENGETUA
SEKOLAH MENENGAH
NEGERI KEDAH DARUL AMAN
PEPERIKSAAN PERCUBAAN SPM 2009
ADDITIONAL MATHEMATICS
Paper 1
.
MARKING SCHEME
SULIT 3472/1

2. SULIT JPNKd/2006/3472/1
SPM Trial Examination 2009 Kedah Darul Aman
Marking Scheme
Additional Mathematics Paper 1
Question Solution/ Marking Scheme Answer Marks
1 (a) 3 1
(b) 81 1
2
3 x (a) 18 2
(a) B1: 3 or f ( x) 3 5x
5
(b) 2 2
3 ( 7)
(b) B1: 3 5 p 7 or p
5
3
B2: b 4 or 3a 9 a = −3
3
B1: 2(2 x a) a b=4
4
B2: ( 4) 2 4(1)( k 1) 0 or k 1 4
5 3
B1 : x 2 4 x k 1 0 or x 2 k 4x 1
5
8 ( 4)
B2: m or 6 y 6x 8 3
0 2
B1: P (0,8) or Q(2, 4)
6
(c) B1: 9 2 2(7) (a) 9 1
(b) 7 1
(c) 67 2

3. SULIT JPNKd/2006/3472/1
Question Solution/ Marking Scheme Answer Marks
7
B3: x 3x 3 10x 1
x= 4
2
3x 3 10 x
B2 : 2 or 2
B1: 2 x (2 3 ) x 1 (2 2 ) 5 x
8
B2: x y 22 x 10, y 12
2 5 7 9 11 x y 3
B1: 8 x 9, y 13
7
9 B2: log 3 x 2 y 4 or log 9 x 2 y 2
81
y 3
log 3 y log 9 x x2
B1: log 3 x 2 or log 9 y 2
log 3 9 log 9 3
10
B2: a 13 and d 5
62 3
B1: a 5d 12 or a 10d 37
11
36 p 1 (a) 48 2
(a) B1:
36 3
(b) 4 1
12 1
B3: r or a 48
2
1
a a 48, r 4
B2: 32(1 r ) 96r 0 or 32 2
a
1
96
a
B1: 32
1 r

4. SULIT JPNKd/2006/3472/1
Question Solution/ Marking Scheme Answer Marks
13
3x 2 7 3y ( −6, 3) 3
B2 : 4 and 4
4 4
3x 2 7 3y
B1 : 4 or 4
4 4
14
2 k 4
B2 : k 2 or 3 or 2 3h 2 h= 3
h 0 3
B1 : log10 y 3x 2 k = −2
1
(a) 6
15
(b) (11, 4) 1
16
B2: p 2 0
p = −2 3
B1: ( p 2)i 3 j
17
B3: 90 0 , 270 0 ,210 0 , 330 0 ( any 2 out of 4 )
900 , 2100 , 4
1
B2 : cos x 0 , sin x (both )
2 2700 ,
cos x 3300
B1 : 2 cos x 0
sin x
18 2
B3 : S 6( ) 12.57 cm 4
3
( 4 ) cm
B2 : r 6
1 2 2
B1: r ( ) 12
2 3
19 3
B2: 8(1) 13
2(1) 2 3
2
dy 3
B1: 8x
dx 2x2

5. SULIT JPNKd/2006/3472/1
Question Solution/ Marking Scheme Answer Marks
20 B1: y 2x 1
or
dy (2 x 1)(8 x) 2(4 x 2 1) 2 2
dx 2
(2 x 1)
21
3 3 5
B3 : 2 1 c y x2
2(2 x 1) 2 4
2
3(2 x 1) 1 2x2
B2: and
2 2
1 2
3(2 x 1) 2x
B1: or
2 2
22
dy 5(2 x 3) 4 2 32 units per second 3
B2 : 2
dt 10
dy 5( 2 x 3) 4 2 dx
B1 : or 2
dx 10 dt
23 (a) 0.18 1
(b) B1: 5 C1 (0.18)1 (0.82) 4
(b) 0.4069 2
24 B2: 3 P 4
P3
1
72 3
B1: 3 P or
1
4
P3
25 355 370
(a) B1 : (a) −1.5 2
10
367 370 (b) 0.3821 2
(b) B1 :
10
END OF MARKING SCHEME