ppr maths nbk


SULIT                                                  1449/2
1449
SULIT                                                  1449/1
1449/1
Matematik
Kertas1
Peraturan
Pemarkahan
Oktober
2007




             SEKTOR SEKOLAH BERASRAMA PENUH
                    BAHAGIAN SEKOLAH
             KEMENTERIAN PELAJARAN MALAYSIA




                  PERATURAN PEMARKAHAN
             PEPERIKSAAN DIAGNOSTIK TAHUN 2007
                       TINGKATAN 4



                        MATEMATIK

                        KERTAS 1 & 2

                           1449/1
QUESTION   ANSWER       QUESTION   ANSWER
    1        B              21       C
    2        D              22       B
    3        D              23       D
    4        B              24       D
    5        B              25       C
    6        A              26       D
    7        D              27       A
    8        B              28       D
    9        A              29       C
    10       A              30       A
    11       B              31       A
    12       D              32       C
    13       B              33       C
    14       C              34       B
    15       C              35       A
    16       A              36       C
    17       A              37       B
    18       D              38       D
    19       A              39       C
    20       B              40       A



                    2
Section A
                                              [ 52 marks ]

No                                          Marking Scheme                 Marks

    1   3 x 2 − 5 x −` = 0
                     12                                                   K1

        (3x + 4)( x − 3) = 0                                              K1
                4
        x = − ,x = 3
                3                                                        N1N1      4


    2   4 p − 6q = 12 or 6 p − 9q = 18                                    K1
           − 15q = 15 or     10 p = 15                                    K1
               q = −1
                                                                          N1
                    3
               p=                                                         N1       4
                    2

        (a) False                                                         P1
    3
        (b) Implication 1 : If 4m > 20, then m > 5                        P1
            Implication 2 : If m > 5, then 4m > 20                        P1

        (c) n + 4n2 , n = 1,2, 3, ….
                                                                         P1, P1    5


4       8 x 7 x 16                                                        K1

        1 22 7 7
         × × × × 16                                                       K1
        2 7 2 2

                       1 22 7 7
        8 x 7 x 16 +    × × × × 16                                        K1
                       2 7 2 2
        1204
                                                                          N1       4

    5   (a)    P′∩R′                                         (b) Q∩R∪P




                                                                         P1 P2



                                                                                   3




                                                     3
No                                         Marking Scheme   Marks

6    Identify ∠EAD                                          P1


     Tan ∠EAD =
                          6
                                                            K2
                          8
     ∠EAD = 36.87° or 36°52′                                N1      4


7    (a) P(3,0)                                             P1

     (b) mPQ =
                      3+3
                                                            K2
                      0+3
                 = 2                                        N1

     (c)   mRS = 2                                          K1

           y−6
               = 2 or equivalent                            K1
           x−0
           y = 2x + 6                                       N1      6


8    (a) Antecedent : A triangle has two equal sides        P1
         Consequent: It is an isoceles triangle             P1

                                                            P1
     (b) If      x2   > 25, then   x>5
                                                            P1
     (c) x is an angle in a semicircle

     (d) If M⊂ N, then M∩N = M                              P1      7

           1
9    (a)                                                    P1
           5

           3         2+ x
     (b)        =                                           K2
           7        10 + x
            x   = 4                                         N1      4


10           1     22                                       K1
     (a)       × 2× ×7
             2     7

                          1     22
            14(4)     +     × 2× ×7                         K1
                          2     7
            78                                              N1

            1 22
     (b)     × ×7×7
            2 7
                                                            K1




                                                   4
No                                              Marking Scheme                                   Marks
              1 22                                                                               K1
               × × 14 × 14
              4 7
                                                                                                 K1
              1 22                    1 22
               × × 7 × 7 + ( 14 X 14 − ×   × 14 × 14 )                                           N1
              2 7                     4 7
                                                                                                              7
              119



11    ∠VPR or ∠VPT                                                                               P1

        6 2 + 8 2 ( seen )                                                                       K1
                    5
      Tan ∠VPR =                                                                                 K2
                    5
             ∠ VPR = 45°                                                                         N1
                                                                                                          5


                                                     Section B
                                                     [48 marks]

 No                                             Marking Scheme                                   Marks
 12    (a)

        Age (years)          Frequency         Cumulative frequency    Upper boundary
                                                       (I)                   ( II )
        10 – 14                   0                      0                   14.5
        15 - 19                   10                    10                   19.5
        20 – 24                   20                    30                   24.5
        25 – 29                   50                    80                   29.5
        30 – 34                   60                   140                   34.5
        35 - 39                   36                   176                   39.5
        40 - 44                   18                   194                   44.5
        45 - 49                   6                    200                   49.5
                                                                                            P1
       All values in Column ( I ) correct excluding Row I correct.
                                                                                            P2
       All values in Column ( II ) correct excluding Row I correct.

       (b) x-axis is drawn with the right direction and in uniform scale from
                                                                                            K1
          14.5 ≤ x ≤ 49.5

         y-axis is drawn with the right direction and in uniform scale from
                                                                                            K1
         0 ≤ y ≤ 200
                                                                                            K2
         All eight points* plotted correctly.
         Note : Seven or six points* plotted correctly. 1         P1
                                                                                            K1
         (14.5, 0) plotted or passed through
                                                                                            N1
         All the right eight points plotted correctly and ogive is drawn smoothly passing
          through all the points.
                                                                                            K1
       (c) (i) 35.5 – 27.5
                                                                                            N1
               8–9
                                                                                            N1           12
             (ii) 150 participants aged 35.5 ± 0.5

 13




                                                         5

F4 Final Sbp 2007 Maths Skema P 1 & P2

  • 1.
    ppr maths nbk SULIT 1449/2 1449 SULIT 1449/1 1449/1 Matematik Kertas1 Peraturan Pemarkahan Oktober 2007 SEKTOR SEKOLAH BERASRAMA PENUH BAHAGIAN SEKOLAH KEMENTERIAN PELAJARAN MALAYSIA PERATURAN PEMARKAHAN PEPERIKSAAN DIAGNOSTIK TAHUN 2007 TINGKATAN 4 MATEMATIK KERTAS 1 & 2 1449/1
  • 2.
    QUESTION ANSWER QUESTION ANSWER 1 B 21 C 2 D 22 B 3 D 23 D 4 B 24 D 5 B 25 C 6 A 26 D 7 D 27 A 8 B 28 D 9 A 29 C 10 A 30 A 11 B 31 A 12 D 32 C 13 B 33 C 14 C 34 B 15 C 35 A 16 A 36 C 17 A 37 B 18 D 38 D 19 A 39 C 20 B 40 A 2
  • 3.
    Section A [ 52 marks ] No Marking Scheme Marks 1 3 x 2 − 5 x −` = 0 12 K1 (3x + 4)( x − 3) = 0 K1 4 x = − ,x = 3 3 N1N1 4 2 4 p − 6q = 12 or 6 p − 9q = 18 K1 − 15q = 15 or 10 p = 15 K1 q = −1 N1 3 p= N1 4 2 (a) False P1 3 (b) Implication 1 : If 4m > 20, then m > 5 P1 Implication 2 : If m > 5, then 4m > 20 P1 (c) n + 4n2 , n = 1,2, 3, …. P1, P1 5 4 8 x 7 x 16 K1 1 22 7 7 × × × × 16 K1 2 7 2 2 1 22 7 7 8 x 7 x 16 + × × × × 16 K1 2 7 2 2 1204 N1 4 5 (a) P′∩R′ (b) Q∩R∪P P1 P2 3 3
  • 4.
    No Marking Scheme Marks 6 Identify ∠EAD P1 Tan ∠EAD = 6 K2 8 ∠EAD = 36.87° or 36°52′ N1 4 7 (a) P(3,0) P1 (b) mPQ = 3+3 K2 0+3 = 2 N1 (c) mRS = 2 K1 y−6 = 2 or equivalent K1 x−0 y = 2x + 6 N1 6 8 (a) Antecedent : A triangle has two equal sides P1 Consequent: It is an isoceles triangle P1 P1 (b) If x2 > 25, then x>5 P1 (c) x is an angle in a semicircle (d) If M⊂ N, then M∩N = M P1 7 1 9 (a) P1 5 3 2+ x (b) = K2 7 10 + x x = 4 N1 4 10 1 22 K1 (a) × 2× ×7 2 7 1 22 14(4) + × 2× ×7 K1 2 7 78 N1 1 22 (b) × ×7×7 2 7 K1 4
  • 5.
    No Marking Scheme Marks 1 22 K1 × × 14 × 14 4 7 K1 1 22 1 22 × × 7 × 7 + ( 14 X 14 − × × 14 × 14 ) N1 2 7 4 7 7 119 11 ∠VPR or ∠VPT P1 6 2 + 8 2 ( seen ) K1 5 Tan ∠VPR = K2 5 ∠ VPR = 45° N1 5 Section B [48 marks] No Marking Scheme Marks 12 (a) Age (years) Frequency Cumulative frequency Upper boundary (I) ( II ) 10 – 14 0 0 14.5 15 - 19 10 10 19.5 20 – 24 20 30 24.5 25 – 29 50 80 29.5 30 – 34 60 140 34.5 35 - 39 36 176 39.5 40 - 44 18 194 44.5 45 - 49 6 200 49.5 P1 All values in Column ( I ) correct excluding Row I correct. P2 All values in Column ( II ) correct excluding Row I correct. (b) x-axis is drawn with the right direction and in uniform scale from K1 14.5 ≤ x ≤ 49.5 y-axis is drawn with the right direction and in uniform scale from K1 0 ≤ y ≤ 200 K2 All eight points* plotted correctly. Note : Seven or six points* plotted correctly. 1 P1 K1 (14.5, 0) plotted or passed through N1 All the right eight points plotted correctly and ogive is drawn smoothly passing through all the points. K1 (c) (i) 35.5 – 27.5 N1 8–9 N1 12 (ii) 150 participants aged 35.5 ± 0.5 13 5