1. This document appears to be an answer key or marking scheme for a mathematics exam with 25 questions. It provides the answers, workings, or mark schemes for each question on the exam. 2. For each question, it lists the number of marks awarded for the full or partial answers. The total marks are tallied at the end. 3. The document contains detailed mathematical solutions and workings for the questions, evaluating answers for correctness according to set schemes.

1. w
SULIT 3472/1
w
w
.c
ik
gu
ro
h
ai
END OF QUESTION PAPER
MARKING SCHEME
za
.c
ADDITIONAL MATHEMATICS 3472/1
o
KERTAS SOALAN TAMAT
m
PKBS 3 / TRIAL SPM 2010
SUB TOTAL
NO MARK SCHEME
MARKS MARKS
1 (a) many to one 1 2
(b) f(x) = x2 1
2 1
k= , p = -3 [both]
2
3 3
1
B2: k = or p = -3
2
x−6 x− p
B1 : or
2 k
3 (a) 2x -7 2 4
B1: g(x) + 4 = 2x -3
(b) 2 2
B1: 2(x + 4) -7 = 5
4 10 8 2 2
3 x 2 + 10x - 8 = 0 or x + x− =0
2
3 3
2 2
B1: x 2 -( -4 + ) x + (-4 × ) = 0 OR
3 3
2
( x + 4)( x − ) = 0 or (x + 4)(3x – 2) = 0
3
3472/1 [ Lihat sebelah
SULIT

2. w
SULIT 3472/1
w
w
.c
ik
gu
ro
h
ai
za
.c
mo
5 (a) 2 1 3
(b) 5 1
(c) x = -2 or x + 2 = 0 1
6 x < 2 , x > 3 (both) 4 4
B3 :
2 3
B2 : (x – 2)(x – 3) > 0
B1 : x 2 - 5x + 6 > 0
7 2 3 3
B2 : 3x = 9
B1 : 3x (32 − 3) = 54
8 4+h–k 3 3
B2 : log 3 81 + log3 x − log3 y
B1 : log 81x − log y or log 81 + log x
9 4m 2 2 2
p= or p = 1.333 m 2
3
2m p
B1: =
3 2m
10 .(a) 6 2 4
8
B1: [ 2(5) + (8 − 1)d ]
2
3472/1 [ Lihat sebelah
SULIT

3. w
SULIT 3472/1
w
w
.c
ik
gu
ro
(b) 59
h
ai
za
.c
B1: 5 + (10 – 1)6 2
mo
11 1 2 4
.(a) r= or 0.5 , a = 96
2
B1: 24(1+ r) = 36
2
(b) 192
96
B1: 1
1−
2
12 1 p 1 4
.(a) = +q
y x
(b) p = -2 , q = 11 (both)
3
B2: p = -2 or q = 11
7 −3
B1: p = OR 7 = 2p +q or 3 = 4p + q
2−4
13 2 3 3
h= k
3
10
(1)(k ) + (2)(6h) (1)(2h) + (2)( k)
B2: = 3k or 3 = 4h
2 +1
2 +1
10
(1)(2h) + (2)( k)
B1: (1)(k ) + (2)(6h) 3
or
2 +1 2 +1
14 0.784 3 3
B2: 6(2π − θ ) = 33
B1: 2π − θ or 3600 - θ
15 3 2 2
B1 : or =
3472/1 [ Lihat sebelah
SULIT

4. w
SULIT 3472/1
w
w
.c
ik
gu
ro
16 (a) -3 + 4 1 3
h
ai
za
.c
o
3 4
m
(b) − i + j
5 5 2
B1 : (−3) 2 + 42
17 k 2 3
(a) −
1− k 2
B1 : 1 − k 2 or see in diagram
(b) - 2k 1 − k 2 1
18 90 , 210 , 330 4 4
B3: 90o, 210o
B2: (2sin A + 1)(sin A − 1) = 0
B1: sin A + 2(1 − sin 2 A) = 1
19 2 3 3
or 0.6667
3
B2 : 18 p − 4(3) = 0
dy
B1 : = 18 p − 4 x
dx
20 28h 3 3
B2 : ∂y ≈ [8(3) + 4] × h
dy
B1 : = 8 x + 4 or δx =h
dx
21 (a) 4 1 4
(b) -7 3
B2 : 2(4)-[3(6)-3(1)]
3472/1 [ Lihat sebelah
SULIT

5. w
SULIT 3472/1
w
w
.c
ik
gu
ro
h
B1 : ∫ 2 g ( x)dx − ∫ 3dx or 2∫ g ( x)dx or 3x
ai
za
.c
mo
22 p 2 + 20 p2 3 3
k= or k = +4
5 5
25k
B2: p2 = –( 20 )2
5
B1 : x = 20 or ∑x 2
= 25k or σ = p
23 (a) 495 1 4
(b) 12 3
B2 :
5
C5 ×3 C2 ×4 C1
B1 :
5
C5 ×4 C1 or
4
C1 ×3 C2 or 5
C5 ×3 C2
24 20 5 3 3
or or 0.2778
72 18
 2 1  3 2  4 3
B2 :  ×  +  × +  × 
 9 8 9 8  9 8
 2 1  3 2  4 3
B1 :  ×  or  ×  or  × 
 9 8 9 8 9 8
25 (a) 0.76 2 4
B1 : P(z > k) = 0.5 – 0.2764
(b) 49.38 2
50.9 − µ
B1 : 0.76 =
2
3472/1 [ Lihat sebelah
SULIT