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LECTURE UNIT 001
  Fundamental Units:


                                                     SI units                        English / Engineering units
                    Length                       meters, m                                     feet, ft
                    Time                         seconds, s                                    seconds, sec

                    Mass                         kilogram, kg                                  slugs, or pound mass, lbm
                    Force                        Newton, N                                     pound force, lbf
                    Pressure                     Pascal, Pa                                    psi
                                                 o                                             o
                    Temperature                      C                                             F
                                                 o
                    Absolute Temperature             R                                         K
                    Heat Energy                  N-m or J                                      Btu

                    Power                        J/s or W                                      Hp, ft-lbf/sec, Btu/hr


  Nomenclatures:
             H - Total Enthalpy (kJ, Btu)                                            h - Specific Enthalpy (kJ/kg, Btu/lbm)
             V - Total Volume (m3, ft3)                                              v - Total Volume (m3/kg, ft3/lbm)
             U - Total Internal Energy (kJ, Btu)                                     u - Total Internal Energy (kJ/kg, Btu/lbm)
             S - Total Entropy (kJ/K, Btu/oR)                                        s - Total Entropy (kJ/kg.K, Btu/lbm. oR)
             Q - Total Heat (kJ, Btu)                                                q - Total Heat (kJ/kg, Btu/lbm)
A. Thermodynamics
       That branch of science which deals with transformation of energy from one form to another, and the movement of energy
               from one location to another.
B. Thermodynamic System
       A             that occupies a given                  , has a                                    , and contains a
             mass.


                                                                  m

                                                                  V




      ILLUSTRATION: (Piston-cylinder arrangement)
                                     TDC                                      BDC

                               m


                                 V
                             Q


C. Three Basic Types of Thermodynamic Systems
         1. Open System or Steady Flow System
                In this system, heat, work and mass (with its associated energy) all crosses the system boundary.
                                                           Win         Wout




                                           PE1                                                 PE1
                                                 min                   TS               mout
                                           KE1                                                 KE1
                                           U1                                                  U1
                                           Wf1                                                 Wf1




                                                                 Qin          Qout



              “Those who try to do something and fail are infinitely better than those who try to
                                         do nothing and succeed.”
ILLUSTRATION: (Steam Turbine)

                          PE1
                          KE1
                          U1
                                                                                                WT
                          Wf1                            ST
                                               1
                                                       (S=C)
                                                                                      2




                                                        PE2 KE2 U2 Wf2
      2. Closed System or Non-Flow System
              In this system, there is no mass flow, heat and work can cross the system boundary.
                                                          Win          Wout




                                          min = 0                      TS                        mout = 0




                                                                 Qin          Qout


         ILLUSTRATION: (Standard Vapor Compression Refrigeration System)
                                                         Qout




                                                      Condenser
                                          mR                                              mR




                                           E.V.
                                                                                     mR
                                                                                                            WC
                                                                                               Compressor
                                          mR
                                                      Evaporator
                                               Room

                                                           Qin

      3. Isolated System
               In this system nothing crosses the system boundary, (no heat, no work, no mass)
                                                      Win = 0          Wout = 0




                                          min = 0                      TS                        mout = 0




                                                          Qin = 0           Qout = 0


         ILLUSTRATION: (Piston Cylinder Arrangement)




Matter
         Anything that occupies space and has weight.

Isaac Newton’s Second Law of Motion
       States that if an unbalanced force acts in a body:
                1. The body will accelerate in the direction of the unbalanced force.
                2. The acceleration will be proportional to the unbalanced force and inversely proportional to the mass of
                            the body.

             “People cannot be managed. Inventories can be managed, but people must be led.”
ILLUSTRATION:
                          goA                                                                                goA
                                        Where:                                                                         Where:
  FA               mA                                                               FA                 mA
                                               m A = mB                                                                        m A > mB
                                          and,                                                                           and,
                                               FA > FB                                                                          FA = FB
                          goB                                                                                goB
                                          so,                                                                            so,
                                            goA > goB                                                                          goA > goB
  FB                 mB                                                             FB                 mB
                                          thus,                                                                          thus,
                                               go       F         eq. 1                                                              1


                                                    8
                                                                                                                               go          eq. 2




                                                                                                                                 8
                                                                                                                                     m
                     Hence; combining eq. 1 and eq. 2

                                                            go    F

                                                              8
                                                                  m
                      Therefore;
                                                                      F
                                                            go = gc
                                                                      m

                                                                  m go
                                                            F=                    Units:      Eng’g units:         lbf
                                                                   gc                                              kgm - m
                                                                                              SI units:
                                                                                                                           or N
            Where:                                                                                                     s2
                          F = force of gravity
                          m = mass of the substance, slugs or lbm, kgm
                          go = observed or local gravitational acceleration,                ft , m
                                                                                           sec2  s2
                          gc = proportionality constant
                          gs = standard gravitational acceleration
                                               Eng’g units                    SI units
                                               32.2 lbm - ft                   kgm - m
                                        gc =                 =            1
                                                lbf - sec2                      N - s2

                                                         ft         m
                                        gs = 32. 2           = 9.81 2
                                                        sec2        s
            NOTE:
            Use standard gravitational acceleration gs if the observed or local gravitational
            acceleration go is not given.
            1 kgf = 2.2 lbf = 9.81 N

 FORMS OF ENERGY
        Energies possessed by a body which has to be considered when analyzing a thermodynamic system.
 Types or Forms of Energy
             A. Stored Energy
                     Energies stored within the body which goes or dependent upon the flow of the mass.
                             1. Potential Energy (PE)
                             2. Kinetic Energy (KE)
                             3. Internal Energy (U)
                             4. Flow Work         (Wf)
             B. Transition Energy
                     Energies in transit (on the move) which are dependent upon the flow of the mass.
                                    5. Heat (Q)
                                    6. Mechanical Work (W)



                                “Humor is to life what shock absorbers are to automobiles.”
1. Potential Energy (PE)
        Stored energy due to its elevation above any arbitrary datum plane.
              ILLUSTRATION:
                                                                        m
                                                                            2


                                                                            F

                                        z2                              m
                                                                            1

                                                      z1
                                                                            F
                        Datum

              DERIVATION:
                                2                 2

                                dPE = F dz
                                1                 1


                               PE = F ( z)
                        PE2 - PE1 = F (z2 - z1)

                                                  m go                            Units:    Eng’g units:    lbf - ft
                                    PE =                                    z)
                                                   gc (                                     SI units:       N - m or J
             Where:
                       m = mass of the substance
                       go = local or observed gravitational acceleration
                       gc = proportionality constant
                        z = change in elevation
             NOTE:
             Mechanical equivalent of heat energy
             1 Btu = 779 lbf - ft
             1 kcal = 428.1 kgf - m
2. Kinetic Energy (KE)
        Stored energy of a body by virtue of its motion (velocity).
                   ILLUSTRATION:

                                                  1                               2



                                                                   dx
                    DERIVATION:
                                             2                 2

                                             dKE = F dx
                                             1                 1
                    Where:
                                      m go
                             F=        gc
                                      m
                                          dv dx
                                    = g
                                        c dt   dx
                                      m
                                          dv dx
                                    =
                                      gc dx dt
                                      m
                                             dv
                                    =     v
                                      gc     dx
                      So;
                                         2
                                                  m
                                                                   dv
                            KE =                           v
                                                  gc               dx
                                        1

                                             m                              v2
                                                       v1+1
                            KE = g
                                  c                    1+1
                                             m                              v1
                                                       v22 - v21
                                    =        gc                2
                                                  m
                                        1                      v2                Units:    Eng’g units:    lbf - ft
                            KE =                  gc
                                        2                                                  SI units:       N - m or J

                                     “Whatever is worth doing at all is worth doing well.”
3. Internal Energy (U)
        Stored energy due to its motion of molecules and forces of attraction between them.
              ILLUSTRATION:


                                                  Change of

                                                       state


                                  Q


                                                               Units:        English Units:         lbf - ft
                          U = (U2 - U1) = m Cv     T
                                                                             SI Units:                            J or
                                                               kJ
                                  Where:
                                           m = mass of the substance, units: lbm, kg
                                           Cv = specific heat at constant volume, units:                   Btu   , kJ
                                                                                                         lbm - oR kg - K
                                           T = change in Absolute temperature, units: oR, K
4. Flow Work (Wf)
        Is the energy required to move the fluid across the boundary of the system.
              ILLUSTRATION:
                                PE1
                                KE1
                                                                                              WSF
                                U1
                                                                                 n
                                Wf1


                                                               TS

                                                                                              PE1
                                                                                              KE1
                                                                                              U1
                                                                                              Wf1
                                                   Q



                                                               Units:        English Units:         lbf - ft
                        Wf = (P2V2 - P1V1) =     PV
                                                                             SI Units:                            J or
                                                               kJ
                              * Enthalpy (H)
                                      combination energy or useful energy.
                                               H = U + Wf
                                               H = U + Wf
                                                 = mCv T + PV
                                                 = mCv T + mR T
                                                 = m (Cv + R)
                                                         But;       R = Cp - Cv
                                                                         Cp = Cv + R
                                                                        Units:       English Units:            lbf - ft
                                               H = mCp              T
                                                                                     SI Units:                            J or
                                                                        kJ
                                                 Where:
                                                                m = mass of the substance, units: lbm, kg
                                                                                                                                   Btu   , kJ
                                                                Cp = specific heat at constant pressure, units:
                                                                                                                                 lbm - oR kg - K
                                                                T = change in Absolute temperature, units: oR, K
                                                               R = ideal gas constant             Btu   , kJ
                                                                                                lbm - oR kg - K
                                                 NOTE:
                                                                use Cp when dealing with enthalpy, H
                                                                use Cv when dealing with internal energy, U


                    “Celebrate the happiness that friends are always giving, make every day a holiday
                                               and celebrate just living.”
5. Heat Energy, (Q)
        Is the energy crossing a systems boundary because of a temperature difference between the system and surroundings.
              ILLUSTRATION:


                                                                   Change of

                                                                     state


                                       Q




                                Q = Tds                  General equation for Ideal gas or vapor process



                          Q=mC              T

                                     Where:
                                                      m = mass of the substance, units: lbm, kg
                                                      C = specific heat (depending upon the process involved
                                                                    during the change of state),Btu
                                                                                                 units:  kJ ,
                                                                                                 lbm - oR       kg - K
                                                                                                     o
                                            T = change in Absolute temperature, units: R, K
6. Mechanical Work (W)
       When force acts in the direction of motion.

                           s2

                    W=      F ds
                          s1


                                           Units:         English Units:       lbf - ft
                    W = (F)(s)
                                                          SI Units:                       J or
                                           kJ

                        Where:
                                   F = force acting on the object.
                                   s = distance moved or the displacement of the object.
                        NOTE:
                                   (+) W = work is done by the system (direction is going out of the system)
                                   (-) W = work is done on the system (direction is going into the system)
                                   (+) Q = heat is added on the system (direction is going into the system)
                                   (-) Q = heat is rejected by the system (direction is going out of the system)
         DIESEL ENGINE:               EC

                           mair                       mexhaust




                                                TDC




                                                BDC


                                                        Flywheel




                                                                    BP

    Entropy, S
           Property which measures the microscopic disorder or randomness of the molecules of a thermodynamic substance.


          “True leadership must be for the benefit of the people, not the enrichment of the institution.”

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001 thermodynamic system

  • 1. LECTURE UNIT 001 Fundamental Units: SI units English / Engineering units Length meters, m feet, ft Time seconds, s seconds, sec Mass kilogram, kg slugs, or pound mass, lbm Force Newton, N pound force, lbf Pressure Pascal, Pa psi o o Temperature C F o Absolute Temperature R K Heat Energy N-m or J Btu Power J/s or W Hp, ft-lbf/sec, Btu/hr Nomenclatures: H - Total Enthalpy (kJ, Btu) h - Specific Enthalpy (kJ/kg, Btu/lbm) V - Total Volume (m3, ft3) v - Total Volume (m3/kg, ft3/lbm) U - Total Internal Energy (kJ, Btu) u - Total Internal Energy (kJ/kg, Btu/lbm) S - Total Entropy (kJ/K, Btu/oR) s - Total Entropy (kJ/kg.K, Btu/lbm. oR) Q - Total Heat (kJ, Btu) q - Total Heat (kJ/kg, Btu/lbm) A. Thermodynamics That branch of science which deals with transformation of energy from one form to another, and the movement of energy from one location to another. B. Thermodynamic System A that occupies a given , has a , and contains a mass. m V ILLUSTRATION: (Piston-cylinder arrangement) TDC BDC m V Q C. Three Basic Types of Thermodynamic Systems 1. Open System or Steady Flow System In this system, heat, work and mass (with its associated energy) all crosses the system boundary. Win Wout PE1 PE1 min TS mout KE1 KE1 U1 U1 Wf1 Wf1 Qin Qout “Those who try to do something and fail are infinitely better than those who try to do nothing and succeed.”
  • 2. ILLUSTRATION: (Steam Turbine) PE1 KE1 U1 WT Wf1 ST 1 (S=C) 2 PE2 KE2 U2 Wf2 2. Closed System or Non-Flow System In this system, there is no mass flow, heat and work can cross the system boundary. Win Wout min = 0 TS mout = 0 Qin Qout ILLUSTRATION: (Standard Vapor Compression Refrigeration System) Qout Condenser mR mR E.V. mR WC Compressor mR Evaporator Room Qin 3. Isolated System In this system nothing crosses the system boundary, (no heat, no work, no mass) Win = 0 Wout = 0 min = 0 TS mout = 0 Qin = 0 Qout = 0 ILLUSTRATION: (Piston Cylinder Arrangement) Matter Anything that occupies space and has weight. Isaac Newton’s Second Law of Motion States that if an unbalanced force acts in a body: 1. The body will accelerate in the direction of the unbalanced force. 2. The acceleration will be proportional to the unbalanced force and inversely proportional to the mass of the body. “People cannot be managed. Inventories can be managed, but people must be led.”
  • 3. ILLUSTRATION: goA goA Where: Where: FA mA FA mA m A = mB m A > mB and, and, FA > FB FA = FB goB goB so, so, goA > goB goA > goB FB mB FB mB thus, thus, go F eq. 1 1 8 go eq. 2 8 m Hence; combining eq. 1 and eq. 2 go F 8 m Therefore; F go = gc m m go F= Units: Eng’g units: lbf gc kgm - m SI units: or N Where: s2 F = force of gravity m = mass of the substance, slugs or lbm, kgm go = observed or local gravitational acceleration, ft , m sec2 s2 gc = proportionality constant gs = standard gravitational acceleration Eng’g units SI units 32.2 lbm - ft kgm - m gc = = 1 lbf - sec2 N - s2 ft m gs = 32. 2 = 9.81 2 sec2 s NOTE: Use standard gravitational acceleration gs if the observed or local gravitational acceleration go is not given. 1 kgf = 2.2 lbf = 9.81 N FORMS OF ENERGY Energies possessed by a body which has to be considered when analyzing a thermodynamic system. Types or Forms of Energy A. Stored Energy Energies stored within the body which goes or dependent upon the flow of the mass. 1. Potential Energy (PE) 2. Kinetic Energy (KE) 3. Internal Energy (U) 4. Flow Work (Wf) B. Transition Energy Energies in transit (on the move) which are dependent upon the flow of the mass. 5. Heat (Q) 6. Mechanical Work (W) “Humor is to life what shock absorbers are to automobiles.”
  • 4. 1. Potential Energy (PE) Stored energy due to its elevation above any arbitrary datum plane. ILLUSTRATION: m 2 F z2 m 1 z1 F Datum DERIVATION: 2 2 dPE = F dz 1 1 PE = F ( z) PE2 - PE1 = F (z2 - z1) m go Units: Eng’g units: lbf - ft PE = z) gc ( SI units: N - m or J Where: m = mass of the substance go = local or observed gravitational acceleration gc = proportionality constant z = change in elevation NOTE: Mechanical equivalent of heat energy 1 Btu = 779 lbf - ft 1 kcal = 428.1 kgf - m 2. Kinetic Energy (KE) Stored energy of a body by virtue of its motion (velocity). ILLUSTRATION: 1 2 dx DERIVATION: 2 2 dKE = F dx 1 1 Where: m go F= gc m dv dx = g c dt dx m dv dx = gc dx dt m dv = v gc dx So; 2 m dv KE = v gc dx 1 m v2 v1+1 KE = g c 1+1 m v1 v22 - v21 = gc 2 m 1 v2 Units: Eng’g units: lbf - ft KE = gc 2 SI units: N - m or J “Whatever is worth doing at all is worth doing well.”
  • 5. 3. Internal Energy (U) Stored energy due to its motion of molecules and forces of attraction between them. ILLUSTRATION: Change of state Q Units: English Units: lbf - ft U = (U2 - U1) = m Cv T SI Units: J or kJ Where: m = mass of the substance, units: lbm, kg Cv = specific heat at constant volume, units: Btu , kJ lbm - oR kg - K T = change in Absolute temperature, units: oR, K 4. Flow Work (Wf) Is the energy required to move the fluid across the boundary of the system. ILLUSTRATION: PE1 KE1 WSF U1 n Wf1 TS PE1 KE1 U1 Wf1 Q Units: English Units: lbf - ft Wf = (P2V2 - P1V1) = PV SI Units: J or kJ * Enthalpy (H) combination energy or useful energy. H = U + Wf H = U + Wf = mCv T + PV = mCv T + mR T = m (Cv + R) But; R = Cp - Cv Cp = Cv + R Units: English Units: lbf - ft H = mCp T SI Units: J or kJ Where: m = mass of the substance, units: lbm, kg Btu , kJ Cp = specific heat at constant pressure, units: lbm - oR kg - K T = change in Absolute temperature, units: oR, K R = ideal gas constant Btu , kJ lbm - oR kg - K NOTE: use Cp when dealing with enthalpy, H use Cv when dealing with internal energy, U “Celebrate the happiness that friends are always giving, make every day a holiday and celebrate just living.”
  • 6. 5. Heat Energy, (Q) Is the energy crossing a systems boundary because of a temperature difference between the system and surroundings. ILLUSTRATION: Change of state Q Q = Tds General equation for Ideal gas or vapor process Q=mC T Where: m = mass of the substance, units: lbm, kg C = specific heat (depending upon the process involved during the change of state),Btu units: kJ , lbm - oR kg - K o T = change in Absolute temperature, units: R, K 6. Mechanical Work (W) When force acts in the direction of motion. s2 W= F ds s1 Units: English Units: lbf - ft W = (F)(s) SI Units: J or kJ Where: F = force acting on the object. s = distance moved or the displacement of the object. NOTE: (+) W = work is done by the system (direction is going out of the system) (-) W = work is done on the system (direction is going into the system) (+) Q = heat is added on the system (direction is going into the system) (-) Q = heat is rejected by the system (direction is going out of the system) DIESEL ENGINE: EC mair mexhaust TDC BDC Flywheel BP Entropy, S Property which measures the microscopic disorder or randomness of the molecules of a thermodynamic substance. “True leadership must be for the benefit of the people, not the enrichment of the institution.”