NANO106 is UCSD Department of NanoEngineering's core course on crystallography of materials taught by Prof Shyue Ping Ong. For more information, visit the course wiki at http://nano106.wikispaces.com.
UCSD NANO106 - 08 - Principal Directions and Representation Quadrics
1. Principal Directions and Representation
Quadrics
Shyue Ping Ong
Department of NanoEngineering
University of California, San Diego
2. Summary of rank 2 tensors for all
crystal systems
¡ Note that rank 2 tensors take these forms only when the
measurement axes are based on the crystal axes as per the analysis.
In a general direction, a rank 2 tensor has 9 non-zero components
(though considerably fewer independent components, as we shall see
later)
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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σij =
σ11 σ12 σ13
σ21 σ22 σ23
σ31 σ32 σ33
!
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Triclinic
σij =
σ11 0 σ13
0 σ22 0
σ31 0 σ33
!
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Monoclinic
σij =
σ11 0 0
0 σ22 0
0 0 σ33
!
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Orthorhombic
σij =
σ11 0 0
0 σ11 0
0 0 σ33
!
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Tetragonal, Trigonal, Hexagonal Cubic
σij =
σ11 0 0
0 σ11 0
0 0 σ11
!
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3. Principal Directions
¡ A general rank 2 tensor is simply a matrix with 9 non-zero
elements.
¡ However, in a certain basis, a rank 2 tensor will take the
form
¡ These basis vectors are known as the principal axes. Note
that these axes are not always orthogonal, unlike our
assumption thus far.
¡ When a “force” is applied in the principal directions, the
response is always parallel to the applied “force”.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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σij =
σ11 0 0
0 σ22 0
0 0 σ33
!
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4. Finding the Principal Axes
¡ Finding the principal axes is essentially an eigenvalue
problem. You are trying to find vectors where:
¡ Where we have used T to denote a general tensor and λ
is the eigenvalue. Rewriting the above equation, we have
¡ To obtain useful solutions, we look for values satisfying
the characteristic equation:
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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Tv = λv
(T − λI)v = 0
det(T − λI) = 0
5. Example
¡ Consider the following tensor with the form:
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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σij =
5 1 1
1 3 1
1 1 3
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Blackboard
6. Magnitude of Tensor in a Given
Direction
¡ Consider the electrical conductivity:
¡ A typical experimental measurement may involve applying the electric
field (voltage / unit length) in a particular direction (e.g., [111]) and
then measuring the current density (charge / time / area) in the same
direction. Note that j is in general not parallel to E, and the value of
the tensor is not given by
¡ Instead, we define the value of the tensor along that direction as the
component of j in the direction of E, divided by the magnitude of E, i.e.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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ji =σikEk
j
E
j111
E
7. Magnitude of Tensor in a Given
Direction
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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Consider j=σE
The experiment measures the component of j
in the direction of E. This is given by the dot product of
j with the unit vector in the direction of E. Hence, the tensor
σ in the direction of E is given by
σ[E] =
j⋅E
E
⋅
1
E
=
σE⋅E
E2
=
σikEkEi
E2
Now, if E = E(l1, l2, l3), where li are the direction cosines
for the vector E. Therefore,
σ[E] =σiklilk
The magnitude of a tensor in a given direction
is specified by the direction cosines of that direction.
8. Example
¡ Let’s say we are interested in the value of a tensor along
the [100] direction. We have
¡ Hence, the diagonal elements of the tensor is always the
value of the tensor along the three orthogonal axis
directions.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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Blackboard
9. The representation quadric
¡ The representation quadric is a useful geometric
representation of a rank 2 tensor property.
¡ Consider the following equation:
¡ This equation can be plotted as a 3-dimensional surface
that completely describes the tensor T.
¡ To make this easier to handle, let us consider the form of
the tensor in the principal axes, in which case the off-
diagonal elements of T are zero.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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Tij xi xj =1
T11x1
2
+T22 x2
2
+T33x3
2
+(T12 +T21)⋅ x1x2 +(T13 +T31)⋅ x1x3 +(T23 +T32 )⋅ x2 x3 =1
10. The representation quadric
¡In the principal directions, the representation
quadric equations becomes:
¡Which can be rewritten as:
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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T11x1
2
+T22 x2
2
+T33x3
2
=1
x1
2
1/T11
+
x2
2
1/T22
+
x3
2
1/T33
=1
11. Forms of the representation quadric
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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Ellipsoid, T11,T22,T33 > 0
12. Forms of the representation quadric
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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Hyperboloid of 1 sheet, T11 < 0, T22,T33 > 0
13. Forms of the representation quadric
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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Hyperboloid of 2 sheets, T11,T22 < 0, T33 > 0
14. Interpreting the representation surface
¡ Recall that the representation surface is given by:
¡ Let us now write , where li is the ith direction cosine for x
and r is the radius. We get
¡ Recall that we earlier showed that the value of a tensor in a
given direction is given by ! Hence, using the
representation surface, we can geometrically obtain the value
of a tensor in a direction simply by measuring the radius!
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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Tij xi xj =1
xi = rli
Tijrlirlj =1
Tijlilj =
1
r2
Tijlilj
15. The radius normal property
¡ Besides just the magnitude, we can also geometrically determine the
direction of the response. We will do this analysis again in the
principal axes to simplify the math. Consider the following:
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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p = Tq or pi = Tijqj
Let qj = qlj
Consider a point on the representation surface such that OQ is parallel to q.
This point is given by r(l1, l2, l3).
The tangent plane to this point is given by (substitute r(l1, l2, l3) into the quadric eqn).:
T11x1rl1 +T22 x2rl2 +T33x3rl3 =1
The normal to this plane is therefore r(T11l1,T22l2,T33l3), which is parallel
to p=q(T11l1,T22l2,T33l3)!
16. Example
¡ We will use an ellipsoid quadric surface (all principal values >0, which
is the most common form for property tensors). The analysis will be
done in 2D (assume qz component is 0) to facilitate visualization.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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R
Let's say the generalized force q is in the direction indicated by the blue
arrow, with magnitude q.
Using the representation quadric, we can determine that the magnitude
of the tensor in the direction of q is given by
T//q =
1
R2
The magnitude of the response p in the direction of q is therefore
p//q =
q
R2
The direction of the actual response is given by the purple arrow.
17. Example
¡Consider the following tensor:
¡Draw the projection of the representation quadric
in the X1-X2 plane.
¡Determine from the representation quadric the
value of the tensor in the [110] direction and the
direction of the response.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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σij =
5 0 1
0 3 1
1 1 3
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18. Stress & strain
¡ Before embarking on the journey beyond rank 2 tensors,
we will now go in-depth into stress (force / unit area) and
strain (change in length / unit length). Both of these are
rank-2 tensors, but they are not property tensors.
Typically, they are known as field tensors to distinguish
them from property tensors.
¡ Unlike property tensors, crystal symmetry restrictions do
not apply to stress and strain.
¡ We will subsequently discuss higher order tensors that
relate stress and strain to other measurements.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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19. Stress
¡ The stress tensor describes the force acting on a
specimen.
¡ First subscript refers to the direction of the force, the
second to the normal to the face on which the force acts.
To prevent translational motion, each force is balanced by
an equal and opposite force on the reverse side of the
specimen.
¡ Xii are tensile stresses in which both the force and the
normal are along Zi, and Xij are shear stresses in which a
force along Zi acts on a face normal to Zj.
¡ Static equilibrium requirement (balanced torques) =>
Stress tensor must be symmetric with Xij = Xji.
¡ Stress state is specified by six independent components:
three tensile stresses X11, X22, and X33, and three shear
components X12, X13, and X23.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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σij =
σ11 σ12 σ13
σ12 σ22 σ23
σ13 σ23 σ33
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20. Stress Quadric
¡ As stress is a rank-2 tensor, it can be represented as a
quadric.
¡ Everything we have derived about the representation
quadric for rank-2 tensors applies to the stress quadric as
well:
¡ The square of the radius to a point is the reciprocal of the value of
stress in that direction, given by . Note that for the stress
tensor, the direction cosines is based on the normal to the
surface of the generalized “displacement”.
¡ The radius normal property applies as well.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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σij xi xj =1
σijlilj
li
22. Strain
¡ Strain is the fractional change in shape of a specimen.
¡ Like stress, strain is represented by a symmetric rank 2
tensor.
¡ The symmetry of the strain tensor arises from the
elimination of pure rotations that do not involve any
deformation of the object.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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εij =
δui
δxj
=
ε11 ε12 ε13
ε12 ε22 ε23
ε13 ε23 ε33
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23. Displacement tensor
¡ To illustrate the symmetry of the strain tensor, let us
consider a generalized fractional displacement tensor
denoted by e (note that this is different from the symbol
used for strain!). e is in general not symmetric.
¡ For any non-symmetric tensor, we can always write it in
terms of the sum of a symmetric tensor ε and an anti-
symmetric tensor w as follows:
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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eij =εij + wij
where εij =
1
2
(eij +eji ) and wij =
1
2
(eij −eji )
24. Rigid body rotations
¡ For a rigid body rotation, we have a displacement vector u
that is always perpendicular to the vector r everywhere.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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u
r
Blackboard
25. Definition of strain
¡Rigid body rotations correspond to anti-symmetric
displacement tensors.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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eij =εij + wij
rotationActual strain
Graphical example using pure shear strain
26. Dilation
¡ What is the fractional volume change of a strained
specimen?
¡ For simplicity, we will again consider a diagonalized strain
tensor and work in the principal axes.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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Blackboard
27. Forms of the strain tensor
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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εij =
ε11 0 0
0 0 0
0 0 0
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Tensile or compressive strain
εij =
ε11 0 0
0 ε22 0
0 0 0
!
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Plane strain
εij =
ε 0 0
0 −ε 0
0 0 0
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Shear strain (special case of plane strain!)
Note that pure shear has no dilation, in line with our intuition
εij =
0 !ε 0
!ε 0 0
0 0 0
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29. Voigt notation, contd.
¡ Note that the off-diagonal strain elements has a factor of 2
in the vector notation. γij = 2εij are known as the
engineering shear strains.
¡ The benefit of this representation is that the following
scalar invariance is preserved:
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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E =σij ⋅εij =
σ1
σ2
σ3
σ4
σ5
σ6
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'
'
'
'
'
'
'
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⋅
ε1
ε2
ε3
γ4
γ5
γ6
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30. Voigt notation for higher order tensors
¡The same principle can be (and in fact is
frequently) applied to higher order tensors.
¡For example, the rank 3 piezoelectric tensor is
represented as a 6x3 matrix (or 3x6 in the case of
the converse piezoelectric effect), while the
elastic and compliance moduli tensor are
represented as 6x6 matrices.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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31. Electric polarization
¡ The electric polarization is the vector field that expresses
the density of permanent or induced electric dipole
moments in a dielectric material. When a dielectric is
placed in an external electric field, its molecules gain
electric dipole moment and the dielectric is said to be
polarized.
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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+-
32. Electric polarization
NANO 106 - Crystallography ofMaterials by Shyue Ping Ong - Lecture 8
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+-
d
Electric dipole moment p = qd
where d is the displacement vector
Polarization P =
p
V
(average dipole moment per unit volume)
¡ Electric polarization is a rank 1 field tensor.