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UUNNIITT 66..22 PPAARRAALLLLEELLOOGGRRAAMMSS TTOO 
QQUUAADDRRIILLAATTEERRAALLSS 
Holt Geometry
Warm Up 
Justify each statement. 
1. 
Reflex Prop. of @ 
2. 
Conv. of Alt. Int. Ðs Thm. 
Evaluate each expression for x = 12 and 
y = 8.5. 
3. 2x + 7 
4. 16x – 9 
5. (8y + 5)° 
31 
183 
73°
Objective 
Prove that a given quadrilateral is a 
parallelogram.
You have learned to identify the properties of a 
parallelogram. Now you will be given the properties 
of a quadrilateral and will have to tell if the 
quadrilateral is a parallelogram. To do this, you can 
use the definition of a parallelogram or the 
conditions below.
The two theorems below can also be used to show that 
a given quadrilateral is a parallelogram.
Example 1A: Verifying Figures are Parallelograms 
Show that JKLM is 
a parallelogram for 
a = 3 and b = 9. 
Step 1 Find JK and LM. 
Given 
Substitute 
and simplify. 
JK = 15a – 11 
JK = 15(3) – 11 = 34 
LM = 10a + 4 
LM = 10(3)+ 4 = 34
Example 1A Continued 
Step 2 Find KL and JM. 
Given 
Substitute 
and simplify. 
KL = 5b + 6 
KL = 5(9) + 6 = 51 
JM = 8b – 21 
JM = 8(9) – 21 = 51 
Since JK = LM and KL = JM, JKLM is a parallelogram 
by Theorem 6-3-2.
Example 1B: Verifying Figures are Parallelograms 
Show that PQRS is a 
parallelogram for x = 10 
and y = 6.5. 
Given 
Substitute 6.5 for y 
and simplify. 
Given 
Substitute 6.5 for y 
and simplify. 
mÐQ = (6y + 7)° 
mÐQ = [(6(6.5) + 7)]° = 46° 
mÐS = (8y – 6)° 
mÐS = [(8(6.5) – 6)]° = 46° 
mÐR = (15x – 16)° 
mÐR = [(15(10) – 16)]° = 134° 
Given 
Substitute 10 for x 
and simplify.
Example 1B Continued 
Since 46° + 134° = 180°, ÐR is supplementary to 
both ÐQ and ÐS. PQRS is a parallelogram by 
Theorem 6-3-4.
Check It Out! Example 1 
Show that PQRS is a 
parallelogram for a = 2.4 
and b = 9. 
PQ = RS = 16.8, so 
mÐQ = 74°, and mÐR = 106°, so ÐQ and ÐR 
are supplementary. 
Therefore, 
So one pair of opposite sides of PQRS are || and @. 
By Theorem 6-3-1, PQRS is a parallelogram.
Example 2A: Applying Conditions for Parallelograms 
Determine if the quadrilateral must be a 
parallelogram. Justify your answer. 
Yes. The 73° angle is 
supplementary to both 
its corresponding angles. 
By Theorem 6-3-4, the 
quadrilateral is a 
parallelogram.
Example 2B: Applying Conditions for Parallelograms 
Determine if the quadrilateral must be a 
parallelogram. Justify your answer. 
No. One pair of opposite 
angles are congruent. The 
other pair is not. The 
conditions for a 
parallelogram are not met.
Check It Out! Example 2a 
Determine if the 
quadrilateral must be a 
parallelogram. Justify your 
answer. 
Yes 
The diagonal of the quadrilateral forms 2 triangles. 
Two angles of one triangle are congruent to two 
angles of the other triangle, so the third pair of 
angles are congruent by the Third Angles Theorem. 
So both pairs of opposite angles of the quadrilateral 
are congruent . 
By Theorem 6-3-3, the quadrilateral is a parallelogram.
Check It Out! Example 2b 
Determine if each 
quadrilateral must be a 
parallelogram. Justify 
your answer. 
No. Two pairs of consective sides 
are congruent. 
None of the sets of conditions for a 
parallelogram are met.
Helpful Hint 
To say that a quadrilateral is a parallelogram by 
definition, you must show that both pairs of 
opposite sides are parallel.
Example 3A: Proving Parallelograms in the 
Coordinate Plane 
Show that quadrilateral JKLM is a parallelogram by 
using the definition of parallelogram. J(–1, –6), 
K(–4, –1), L(4, 5), M(7, 0). 
Find the slopes of both pairs of opposite sides. 
Since both pairs of opposite sides are parallel, 
JKLM is a parallelogram by definition.
Example 3B: Proving Parallelograms in the 
Coordinate Plane 
Show that quadrilateral ABCD is a parallelogram 
by using Theorem 6-3-1. A(2, 3), B(6, 2), C(5, 0), 
D(1, 1). 
Find the slopes and lengths of one pair of opposite 
sides. 
AB and CD have the same slope, so . Since 
AB = CD, . So by Theorem 6-3-1, ABCD is a 
parallelogram.
Check It Out! Example 3 
Use the definition of a parallelogram to show that 
the quadrilateral with vertices K(–3, 0), L(–5, 7), 
M(3, 5), and N(5, –2) is a parallelogram. 
Both pairs of opposite sides have the same 
slope so and by definition, 
KLMN is a parallelogram.
You have learned several ways to determine whether a 
quadrilateral is a parallelogram. You can use the given 
information about a figure to decide which condition is 
best to apply.
Helpful Hint 
To show that a quadrilateral is a parallelogram, 
you only have to show that it satisfies one of 
these sets of conditions.
Example 4: Application 
The legs of a keyboard tray are 
connected by a bolt at their 
midpoints, which allows the tray to 
be raised or lowered. Why is PQRS 
always a parallelogram? 
Since the bolt is at the midpoint of both legs, PE = ER 
and SE = EQ. So the diagonals of PQRS bisect each 
other, and by Theorem 6-3-5, PQRS is always a 
parallelogram.
Check It Out! Example 4 
The frame is attached to the tripod at points A 
and B such that AB = RS and BR = SA. So ABRS 
is also a parallelogram. How does this ensure 
that the angle of the binoculars stays the same? 
Since ABRS is a parallelogram, it is always true 
that . 
Since AB stays vertical, RS also remains vertical no 
matter how the frame is adjusted. 
Therefore the viewing Ð never changes.
Lesson Quiz: Part I 
1. Show that JKLM is a parallelogram 
for a = 4 and b = 5. 
JN = LN = 22; KN = MN = 10; so 
JKLM is a parallelogram by 
Theorem 6-3-5. 
2. Determine if QWRT must be a 
parallelogram. Justify your 
answer. 
No; One pair of consecutive Ðs are @, and one 
pair of opposite sides are ||. The conditions for a 
parallelogram are not met.
Lesson Quiz: Part II 
3. Show that the quadrilateral with vertices E(–1, 5), 
F(2, 4), G(0, –3), and H(–3, –2) is a parallelogram. 
Since one pair of opposite sides are || and @, EFGH 
is a parallelogram by Theorem 6-3-1.
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respective owners. 
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Section 107 of the 
Copyright Act 1976, 
allowance is made for "fair 
use" for purposes such as 
criticism, comment, news 
reporting, TEACHING, 
scholarship, and research. 
Fair use is a use permitted 
by copyright statute that 
might otherwise be 
infringing. 
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Geometry unit 6.2.2

  • 1. UUNNIITT 66..22 PPAARRAALLLLEELLOOGGRRAAMMSS TTOO QQUUAADDRRIILLAATTEERRAALLSS Holt Geometry
  • 2. Warm Up Justify each statement. 1. Reflex Prop. of @ 2. Conv. of Alt. Int. Ðs Thm. Evaluate each expression for x = 12 and y = 8.5. 3. 2x + 7 4. 16x – 9 5. (8y + 5)° 31 183 73°
  • 3. Objective Prove that a given quadrilateral is a parallelogram.
  • 4. You have learned to identify the properties of a parallelogram. Now you will be given the properties of a quadrilateral and will have to tell if the quadrilateral is a parallelogram. To do this, you can use the definition of a parallelogram or the conditions below.
  • 5.
  • 6. The two theorems below can also be used to show that a given quadrilateral is a parallelogram.
  • 7. Example 1A: Verifying Figures are Parallelograms Show that JKLM is a parallelogram for a = 3 and b = 9. Step 1 Find JK and LM. Given Substitute and simplify. JK = 15a – 11 JK = 15(3) – 11 = 34 LM = 10a + 4 LM = 10(3)+ 4 = 34
  • 8. Example 1A Continued Step 2 Find KL and JM. Given Substitute and simplify. KL = 5b + 6 KL = 5(9) + 6 = 51 JM = 8b – 21 JM = 8(9) – 21 = 51 Since JK = LM and KL = JM, JKLM is a parallelogram by Theorem 6-3-2.
  • 9. Example 1B: Verifying Figures are Parallelograms Show that PQRS is a parallelogram for x = 10 and y = 6.5. Given Substitute 6.5 for y and simplify. Given Substitute 6.5 for y and simplify. mÐQ = (6y + 7)° mÐQ = [(6(6.5) + 7)]° = 46° mÐS = (8y – 6)° mÐS = [(8(6.5) – 6)]° = 46° mÐR = (15x – 16)° mÐR = [(15(10) – 16)]° = 134° Given Substitute 10 for x and simplify.
  • 10. Example 1B Continued Since 46° + 134° = 180°, ÐR is supplementary to both ÐQ and ÐS. PQRS is a parallelogram by Theorem 6-3-4.
  • 11. Check It Out! Example 1 Show that PQRS is a parallelogram for a = 2.4 and b = 9. PQ = RS = 16.8, so mÐQ = 74°, and mÐR = 106°, so ÐQ and ÐR are supplementary. Therefore, So one pair of opposite sides of PQRS are || and @. By Theorem 6-3-1, PQRS is a parallelogram.
  • 12. Example 2A: Applying Conditions for Parallelograms Determine if the quadrilateral must be a parallelogram. Justify your answer. Yes. The 73° angle is supplementary to both its corresponding angles. By Theorem 6-3-4, the quadrilateral is a parallelogram.
  • 13. Example 2B: Applying Conditions for Parallelograms Determine if the quadrilateral must be a parallelogram. Justify your answer. No. One pair of opposite angles are congruent. The other pair is not. The conditions for a parallelogram are not met.
  • 14. Check It Out! Example 2a Determine if the quadrilateral must be a parallelogram. Justify your answer. Yes The diagonal of the quadrilateral forms 2 triangles. Two angles of one triangle are congruent to two angles of the other triangle, so the third pair of angles are congruent by the Third Angles Theorem. So both pairs of opposite angles of the quadrilateral are congruent . By Theorem 6-3-3, the quadrilateral is a parallelogram.
  • 15. Check It Out! Example 2b Determine if each quadrilateral must be a parallelogram. Justify your answer. No. Two pairs of consective sides are congruent. None of the sets of conditions for a parallelogram are met.
  • 16. Helpful Hint To say that a quadrilateral is a parallelogram by definition, you must show that both pairs of opposite sides are parallel.
  • 17. Example 3A: Proving Parallelograms in the Coordinate Plane Show that quadrilateral JKLM is a parallelogram by using the definition of parallelogram. J(–1, –6), K(–4, –1), L(4, 5), M(7, 0). Find the slopes of both pairs of opposite sides. Since both pairs of opposite sides are parallel, JKLM is a parallelogram by definition.
  • 18. Example 3B: Proving Parallelograms in the Coordinate Plane Show that quadrilateral ABCD is a parallelogram by using Theorem 6-3-1. A(2, 3), B(6, 2), C(5, 0), D(1, 1). Find the slopes and lengths of one pair of opposite sides. AB and CD have the same slope, so . Since AB = CD, . So by Theorem 6-3-1, ABCD is a parallelogram.
  • 19. Check It Out! Example 3 Use the definition of a parallelogram to show that the quadrilateral with vertices K(–3, 0), L(–5, 7), M(3, 5), and N(5, –2) is a parallelogram. Both pairs of opposite sides have the same slope so and by definition, KLMN is a parallelogram.
  • 20. You have learned several ways to determine whether a quadrilateral is a parallelogram. You can use the given information about a figure to decide which condition is best to apply.
  • 21. Helpful Hint To show that a quadrilateral is a parallelogram, you only have to show that it satisfies one of these sets of conditions.
  • 22. Example 4: Application The legs of a keyboard tray are connected by a bolt at their midpoints, which allows the tray to be raised or lowered. Why is PQRS always a parallelogram? Since the bolt is at the midpoint of both legs, PE = ER and SE = EQ. So the diagonals of PQRS bisect each other, and by Theorem 6-3-5, PQRS is always a parallelogram.
  • 23. Check It Out! Example 4 The frame is attached to the tripod at points A and B such that AB = RS and BR = SA. So ABRS is also a parallelogram. How does this ensure that the angle of the binoculars stays the same? Since ABRS is a parallelogram, it is always true that . Since AB stays vertical, RS also remains vertical no matter how the frame is adjusted. Therefore the viewing Ð never changes.
  • 24. Lesson Quiz: Part I 1. Show that JKLM is a parallelogram for a = 4 and b = 5. JN = LN = 22; KN = MN = 10; so JKLM is a parallelogram by Theorem 6-3-5. 2. Determine if QWRT must be a parallelogram. Justify your answer. No; One pair of consecutive Ðs are @, and one pair of opposite sides are ||. The conditions for a parallelogram are not met.
  • 25. Lesson Quiz: Part II 3. Show that the quadrilateral with vertices E(–1, 5), F(2, 4), G(0, –3), and H(–3, –2) is a parallelogram. Since one pair of opposite sides are || and @, EFGH is a parallelogram by Theorem 6-3-1.
  • 26. All rights belong to their respective owners. Copyright Disclaimer Under Section 107 of the Copyright Act 1976, allowance is made for "fair use" for purposes such as criticism, comment, news reporting, TEACHING, scholarship, and research. Fair use is a use permitted by copyright statute that might otherwise be infringing. Non-profit, EDUCATIONAL or personal use tips the balance in favor of fair use.