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Section 3-5
           Finding the Equation of a Line



...or th e Po in t-S lo pe Th eo re m se ct io n
Warm-up
Write an equation for the line through the pair of points


       a. (5, 9), (5, -2)         b. (9, 1), (6, 4)
Warm-up
Write an equation for the line through the pair of points


       a. (5, 9), (5, -2)         b. (9, 1), (6, 4)

             x=5
Warm-up
Write an equation for the line through the pair of points


       a. (5, 9), (5, -2)         b. (9, 1), (6, 4)

             x=5                    y = -x + 10
Warm-up
Write an equation for the line through the pair of points


       a. (5, 9), (5, -2)         b. (9, 1), (6, 4)

             x=5                    y = -x + 10


Not quite sure how this is done? We’ll see two ways today
Question

What determines a line?
Question

What determines a line?

      Two points
Question

               What determines a line?

                     Two points
...and once we have two points, we can find an equation
Example 1
 The formula relating blood pressure and age is linear.
Normal systolic blood pressures are 110 for a 20 year old
 and 130 for a 60 year old. Graph the line and find an
equation where blood pressure B is a function of age A.
Example 1
 The formula relating blood pressure and age is linear.
Normal systolic blood pressures are 110 for a 20 year old
 and 130 for a 60 year old. Graph the line and find an
equation where blood pressure B is a function of age A.
                     130.0
    Blood Pressure




                      97.5
                      65.0
                      32.5
                        0
                             0   15   30    45   60
                                      Age
Example 1 (con’t)
   (20, 110), (60, 130)
Example 1 (con’t)
  (20, 110), (60, 130)
    130 − 110
 m=
     60 − 20
Example 1 (con’t)
  (20, 110), (60, 130)
    130 − 110 20
 m=            =
     60 − 20     40
Example 1 (con’t)
  (20, 110), (60, 130)
    130 − 110 20 1
 m=            =     =
     60 − 20     40 2
Example 1 (con’t)
  (20, 110), (60, 130)
    130 − 110 20 1
 m=            =     =
     60 − 20     40 2
       B= 2 A+b
          1
Example 1 (con’t)
  (20, 110), (60, 130)
    130 − 110 20 1
 m=            =     =
     60 − 20     40 2
       B= 2 A+b
          1


     110 = (20) + b
          1
          2
Example 1 (con’t)
  (20, 110), (60, 130)
    130 − 110 20 1
 m=            =     =
     60 − 20     40 2
       B= 2 A+b
          1


     110 = (20) + b
          1
          2

     110 = 10 + b
Example 1 (con’t)
  (20, 110), (60, 130)
    130 − 110 20 1
 m=            =     =
     60 − 20     40 2
       B= 2 A+b
          1


     110 = (20) + b
          1
          2

     110 = 10 + b
       b = 100
Example 1 (con’t)
  (20, 110), (60, 130)
    130 − 110 20 1
 m=            =     =
     60 − 20     40 2
       B= 2 A+b
          1


     110 = (20) + b
          1
          2

     110 = 10 + b
       b = 100
      B = 2 A + 100
          1
Example 1 (con’t)
   (20, 110), (60, 130)
     130 − 110 20 1
  m=            =     =
      60 − 20     40 2
         B= 2 A+b
            1


       110 = (20) + b
            1
            2

       110 = 10 + b
         b = 100
        B = 2 A + 100
            1


There has to be a better way!
Point-Slope Theorem
Point-Slope Theorem


If a line contains (x1, y1) and has slope m, then it has
             the equation y - y1 = m(x - x1)
Point-Slope Theorem


If a line contains (x1, y1) and has slope m, then it has
             the equation y - y1 = m(x - x1)


  (In other words, you need a point and the slope)
Example 2
Find an equation for the line through (-3, 6) and (5, 0)
           using the point-slope theorem.
Example 2
Find an equation for the line through (-3, 6) and (5, 0)
           using the point-slope theorem.
                     6−0
               m=
                    −3 − 5
Example 2
Find an equation for the line through (-3, 6) and (5, 0)
           using the point-slope theorem.
                     6−0       6
               m=           =
                    −3 − 5 −8
Example 2
Find an equation for the line through (-3, 6) and (5, 0)
           using the point-slope theorem.
                     6−0       6     3
               m=           =     =−
                    −3 − 5 −8        4
Example 2
Find an equation for the line through (-3, 6) and (5, 0)
           using the point-slope theorem.
                     6−0       6      3
               m=           =     =−
                    −3 − 5 −8         4
                  y − y1 = m(x − x1 )
Example 2
Find an equation for the line through (-3, 6) and (5, 0)
           using the point-slope theorem.
                     6−0       6      3
               m=           =     =−
                    −3 − 5 −8         4
                  y − y1 = m(x − x1 )
                             3
                   y − 0 = − 4 (x − 5)
Example 2
Find an equation for the line through (-3, 6) and (5, 0)
           using the point-slope theorem.
                     6−0       6      3
               m=           =     =−
                    −3 − 5 −8         4
                  y − y1 = m(x − x1 )
                               3
                   y − 0 = − 4 (x − 5)

                           3       15
                   y=−4x+           4
When dealing with real world situations,
 deal with the problem as we always
  have: find the equation first, then
         answer the question.
Example 3
 The lightest recommended weight for a Martian with
 height 4’10” is 109 lbs. This weight increases 2 lbs/in
to a height of 5’1” and then goes up 3 lbs/in to a height
            of 6’ which is tall for a Martian.
                  a. Graph the situation
Example 3
 The lightest recommended weight for a Martian with
 height 4’10” is 109 lbs. This weight increases 2 lbs/in
to a height of 5’1” and then goes up 3 lbs/in to a height
            of 6’ which is tall for a Martian.
                  a. Graph the situation
    First, we need to convert all heights to inches
Example 3
 The lightest recommended weight for a Martian with
 height 4’10” is 109 lbs. This weight increases 2 lbs/in
to a height of 5’1” and then goes up 3 lbs/in to a height
            of 6’ which is tall for a Martian.
                  a. Graph the situation
    First, we need to convert all heights to inches
               4’10” =
Example 3
 The lightest recommended weight for a Martian with
 height 4’10” is 109 lbs. This weight increases 2 lbs/in
to a height of 5’1” and then goes up 3 lbs/in to a height
            of 6’ which is tall for a Martian.
                  a. Graph the situation
    First, we need to convert all heights to inches
               4’10” = 4(12) +10 =
Example 3
 The lightest recommended weight for a Martian with
 height 4’10” is 109 lbs. This weight increases 2 lbs/in
to a height of 5’1” and then goes up 3 lbs/in to a height
            of 6’ which is tall for a Martian.
                  a. Graph the situation
    First, we need to convert all heights to inches
               4’10” = 4(12) +10 = 58”
Example 3
 The lightest recommended weight for a Martian with
 height 4’10” is 109 lbs. This weight increases 2 lbs/in
to a height of 5’1” and then goes up 3 lbs/in to a height
            of 6’ which is tall for a Martian.
                  a. Graph the situation
    First, we need to convert all heights to inches
               4’10” = 4(12) +10 = 58”
                5’1” =
Example 3
 The lightest recommended weight for a Martian with
 height 4’10” is 109 lbs. This weight increases 2 lbs/in
to a height of 5’1” and then goes up 3 lbs/in to a height
            of 6’ which is tall for a Martian.
                  a. Graph the situation
    First, we need to convert all heights to inches
               4’10” = 4(12) +10 = 58”
                5’1” = 5(12) + 1 =
Example 3
 The lightest recommended weight for a Martian with
 height 4’10” is 109 lbs. This weight increases 2 lbs/in
to a height of 5’1” and then goes up 3 lbs/in to a height
            of 6’ which is tall for a Martian.
                  a. Graph the situation
    First, we need to convert all heights to inches
               4’10” = 4(12) +10 = 58”
                5’1” = 5(12) + 1 = 61”
Example 3
 The lightest recommended weight for a Martian with
 height 4’10” is 109 lbs. This weight increases 2 lbs/in
to a height of 5’1” and then goes up 3 lbs/in to a height
            of 6’ which is tall for a Martian.
                  a. Graph the situation
    First, we need to convert all heights to inches
               4’10” = 4(12) +10 = 58”
                5’1” = 5(12) + 1 = 61”
                    6’ = 6(12) = 72”
Example 3
 The lightest recommended weight for a Martian with
 height 4’10” is 109 lbs. This weight increases 2 lbs/in
to a height of 5’1” and then goes up 3 lbs/in to a height
            of 6’ which is tall for a Martian.
                  a. Graph the situation
    First, we need to convert all heights to inches
               4’10” = 4(12) +10 = 58”
                5’1” = 5(12) + 1 = 61”
                    6’ = 6(12) = 72”
 (58”, 109 lbs)
Example 3
 The lightest recommended weight for a Martian with
 height 4’10” is 109 lbs. This weight increases 2 lbs/in
to a height of 5’1” and then goes up 3 lbs/in to a height
            of 6’ which is tall for a Martian.
                  a. Graph the situation
    First, we need to convert all heights to inches
               4’10” = 4(12) +10 = 58”
                5’1” = 5(12) + 1 = 61”
                    6’ = 6(12) = 72”
 (58”, 109 lbs)      (61”, 115 lbs)
Example 3
 The lightest recommended weight for a Martian with
 height 4’10” is 109 lbs. This weight increases 2 lbs/in
to a height of 5’1” and then goes up 3 lbs/in to a height
            of 6’ which is tall for a Martian.
                  a. Graph the situation
    First, we need to convert all heights to inches
               4’10” = 4(12) +10 = 58”
                5’1” = 5(12) + 1 = 61”
                    6’ = 6(12) = 72”
 (58”, 109 lbs)      (61”, 115 lbs)      (72”, 148 lbs)
Example 3 (con’t)
(58”, 109 lbs)     (61”, 115 lbs)      (72”, 148 lbs)
b. Find two equations that describe these situations
Example 3 (con’t)
(58”, 109 lbs)     (61”, 115 lbs)      (72”, 148 lbs)
b. Find two equations that describe these situations

                  y - y1 = m(x - x1)
Example 3 (con’t)
(58”, 109 lbs)     (61”, 115 lbs)      (72”, 148 lbs)
b. Find two equations that describe these situations

                  y - y1 = m(x - x1)
   w - w1 = m(h - h1)
Example 3 (con’t)
(58”, 109 lbs)     (61”, 115 lbs)      (72”, 148 lbs)
b. Find two equations that describe these situations

                  y - y1 = m(x - x1)
   w - w1 = m(h - h1)
   w - 109 = 2(h - 58)
Example 3 (con’t)
(58”, 109 lbs)     (61”, 115 lbs)      (72”, 148 lbs)
b. Find two equations that describe these situations

                    y - y1 = m(x - x1)
   w - w1 = m(h - h1)
   w - 109 = 2(h - 58)
       w = 2h - 7
Example 3 (con’t)
(58”, 109 lbs)     (61”, 115 lbs)      (72”, 148 lbs)
b. Find two equations that describe these situations

                  y - y1 = m(x - x1)
   w - w1 = m(h - h1)
   w - 109 = 2(h - 58)
       w = 2h - 7
     for 58 ≤ h ≤ 61
Example 3 (con’t)
(58”, 109 lbs)     (61”, 115 lbs)      (72”, 148 lbs)
b. Find two equations that describe these situations

                  y - y1 = m(x - x1)
   w - w1 = m(h - h1)           w - w1 = m(h - h1)
   w - 109 = 2(h - 58)
       w = 2h - 7
     for 58 ≤ h ≤ 61
Example 3 (con’t)
(58”, 109 lbs)     (61”, 115 lbs)      (72”, 148 lbs)
b. Find two equations that describe these situations

                  y - y1 = m(x - x1)
   w - w1 = m(h - h1)           w - w1 = m(h - h1)
   w - 109 = 2(h - 58)          w - 115 = 3(h - 61)
       w = 2h - 7
     for 58 ≤ h ≤ 61
Example 3 (con’t)
(58”, 109 lbs)     (61”, 115 lbs)      (72”, 148 lbs)
b. Find two equations that describe these situations

                  y - y1 = m(x - x1)
   w - w1 = m(h - h1)           w - w1 = m(h - h1)
   w - 109 = 2(h - 58)          w - 115 = 3(h - 61)
       w = 2h - 7                  w = 3h - 68
     for 58 ≤ h ≤ 61
Example 3 (con’t)
(58”, 109 lbs)     (61”, 115 lbs)      (72”, 148 lbs)
b. Find two equations that describe these situations

                  y - y1 = m(x - x1)
   w - w1 = m(h - h1)           w - w1 = m(h - h1)
   w - 109 = 2(h - 58)          w - 115 = 3(h - 61)
       w = 2h - 7                   w = 3h - 68
     for 58 ≤ h ≤ 61              for 61 < h ≤ 72
Homework
Homework


                     p. 165 #1 - 21




“ I’m not sure I want popular opinion on my side -- I’ve
  noticed those with the most opinions often have the
          fewest facts.” - Bethania McKenstry

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AA Section 3-5

  • 1. Section 3-5 Finding the Equation of a Line ...or th e Po in t-S lo pe Th eo re m se ct io n
  • 2. Warm-up Write an equation for the line through the pair of points a. (5, 9), (5, -2) b. (9, 1), (6, 4)
  • 3. Warm-up Write an equation for the line through the pair of points a. (5, 9), (5, -2) b. (9, 1), (6, 4) x=5
  • 4. Warm-up Write an equation for the line through the pair of points a. (5, 9), (5, -2) b. (9, 1), (6, 4) x=5 y = -x + 10
  • 5. Warm-up Write an equation for the line through the pair of points a. (5, 9), (5, -2) b. (9, 1), (6, 4) x=5 y = -x + 10 Not quite sure how this is done? We’ll see two ways today
  • 7. Question What determines a line? Two points
  • 8. Question What determines a line? Two points ...and once we have two points, we can find an equation
  • 9. Example 1 The formula relating blood pressure and age is linear. Normal systolic blood pressures are 110 for a 20 year old and 130 for a 60 year old. Graph the line and find an equation where blood pressure B is a function of age A.
  • 10. Example 1 The formula relating blood pressure and age is linear. Normal systolic blood pressures are 110 for a 20 year old and 130 for a 60 year old. Graph the line and find an equation where blood pressure B is a function of age A. 130.0 Blood Pressure 97.5 65.0 32.5 0 0 15 30 45 60 Age
  • 11. Example 1 (con’t) (20, 110), (60, 130)
  • 12. Example 1 (con’t) (20, 110), (60, 130) 130 − 110 m= 60 − 20
  • 13. Example 1 (con’t) (20, 110), (60, 130) 130 − 110 20 m= = 60 − 20 40
  • 14. Example 1 (con’t) (20, 110), (60, 130) 130 − 110 20 1 m= = = 60 − 20 40 2
  • 15. Example 1 (con’t) (20, 110), (60, 130) 130 − 110 20 1 m= = = 60 − 20 40 2 B= 2 A+b 1
  • 16. Example 1 (con’t) (20, 110), (60, 130) 130 − 110 20 1 m= = = 60 − 20 40 2 B= 2 A+b 1 110 = (20) + b 1 2
  • 17. Example 1 (con’t) (20, 110), (60, 130) 130 − 110 20 1 m= = = 60 − 20 40 2 B= 2 A+b 1 110 = (20) + b 1 2 110 = 10 + b
  • 18. Example 1 (con’t) (20, 110), (60, 130) 130 − 110 20 1 m= = = 60 − 20 40 2 B= 2 A+b 1 110 = (20) + b 1 2 110 = 10 + b b = 100
  • 19. Example 1 (con’t) (20, 110), (60, 130) 130 − 110 20 1 m= = = 60 − 20 40 2 B= 2 A+b 1 110 = (20) + b 1 2 110 = 10 + b b = 100 B = 2 A + 100 1
  • 20. Example 1 (con’t) (20, 110), (60, 130) 130 − 110 20 1 m= = = 60 − 20 40 2 B= 2 A+b 1 110 = (20) + b 1 2 110 = 10 + b b = 100 B = 2 A + 100 1 There has to be a better way!
  • 22. Point-Slope Theorem If a line contains (x1, y1) and has slope m, then it has the equation y - y1 = m(x - x1)
  • 23. Point-Slope Theorem If a line contains (x1, y1) and has slope m, then it has the equation y - y1 = m(x - x1) (In other words, you need a point and the slope)
  • 24. Example 2 Find an equation for the line through (-3, 6) and (5, 0) using the point-slope theorem.
  • 25. Example 2 Find an equation for the line through (-3, 6) and (5, 0) using the point-slope theorem. 6−0 m= −3 − 5
  • 26. Example 2 Find an equation for the line through (-3, 6) and (5, 0) using the point-slope theorem. 6−0 6 m= = −3 − 5 −8
  • 27. Example 2 Find an equation for the line through (-3, 6) and (5, 0) using the point-slope theorem. 6−0 6 3 m= = =− −3 − 5 −8 4
  • 28. Example 2 Find an equation for the line through (-3, 6) and (5, 0) using the point-slope theorem. 6−0 6 3 m= = =− −3 − 5 −8 4 y − y1 = m(x − x1 )
  • 29. Example 2 Find an equation for the line through (-3, 6) and (5, 0) using the point-slope theorem. 6−0 6 3 m= = =− −3 − 5 −8 4 y − y1 = m(x − x1 ) 3 y − 0 = − 4 (x − 5)
  • 30. Example 2 Find an equation for the line through (-3, 6) and (5, 0) using the point-slope theorem. 6−0 6 3 m= = =− −3 − 5 −8 4 y − y1 = m(x − x1 ) 3 y − 0 = − 4 (x − 5) 3 15 y=−4x+ 4
  • 31. When dealing with real world situations, deal with the problem as we always have: find the equation first, then answer the question.
  • 32. Example 3 The lightest recommended weight for a Martian with height 4’10” is 109 lbs. This weight increases 2 lbs/in to a height of 5’1” and then goes up 3 lbs/in to a height of 6’ which is tall for a Martian. a. Graph the situation
  • 33. Example 3 The lightest recommended weight for a Martian with height 4’10” is 109 lbs. This weight increases 2 lbs/in to a height of 5’1” and then goes up 3 lbs/in to a height of 6’ which is tall for a Martian. a. Graph the situation First, we need to convert all heights to inches
  • 34. Example 3 The lightest recommended weight for a Martian with height 4’10” is 109 lbs. This weight increases 2 lbs/in to a height of 5’1” and then goes up 3 lbs/in to a height of 6’ which is tall for a Martian. a. Graph the situation First, we need to convert all heights to inches 4’10” =
  • 35. Example 3 The lightest recommended weight for a Martian with height 4’10” is 109 lbs. This weight increases 2 lbs/in to a height of 5’1” and then goes up 3 lbs/in to a height of 6’ which is tall for a Martian. a. Graph the situation First, we need to convert all heights to inches 4’10” = 4(12) +10 =
  • 36. Example 3 The lightest recommended weight for a Martian with height 4’10” is 109 lbs. This weight increases 2 lbs/in to a height of 5’1” and then goes up 3 lbs/in to a height of 6’ which is tall for a Martian. a. Graph the situation First, we need to convert all heights to inches 4’10” = 4(12) +10 = 58”
  • 37. Example 3 The lightest recommended weight for a Martian with height 4’10” is 109 lbs. This weight increases 2 lbs/in to a height of 5’1” and then goes up 3 lbs/in to a height of 6’ which is tall for a Martian. a. Graph the situation First, we need to convert all heights to inches 4’10” = 4(12) +10 = 58” 5’1” =
  • 38. Example 3 The lightest recommended weight for a Martian with height 4’10” is 109 lbs. This weight increases 2 lbs/in to a height of 5’1” and then goes up 3 lbs/in to a height of 6’ which is tall for a Martian. a. Graph the situation First, we need to convert all heights to inches 4’10” = 4(12) +10 = 58” 5’1” = 5(12) + 1 =
  • 39. Example 3 The lightest recommended weight for a Martian with height 4’10” is 109 lbs. This weight increases 2 lbs/in to a height of 5’1” and then goes up 3 lbs/in to a height of 6’ which is tall for a Martian. a. Graph the situation First, we need to convert all heights to inches 4’10” = 4(12) +10 = 58” 5’1” = 5(12) + 1 = 61”
  • 40. Example 3 The lightest recommended weight for a Martian with height 4’10” is 109 lbs. This weight increases 2 lbs/in to a height of 5’1” and then goes up 3 lbs/in to a height of 6’ which is tall for a Martian. a. Graph the situation First, we need to convert all heights to inches 4’10” = 4(12) +10 = 58” 5’1” = 5(12) + 1 = 61” 6’ = 6(12) = 72”
  • 41. Example 3 The lightest recommended weight for a Martian with height 4’10” is 109 lbs. This weight increases 2 lbs/in to a height of 5’1” and then goes up 3 lbs/in to a height of 6’ which is tall for a Martian. a. Graph the situation First, we need to convert all heights to inches 4’10” = 4(12) +10 = 58” 5’1” = 5(12) + 1 = 61” 6’ = 6(12) = 72” (58”, 109 lbs)
  • 42. Example 3 The lightest recommended weight for a Martian with height 4’10” is 109 lbs. This weight increases 2 lbs/in to a height of 5’1” and then goes up 3 lbs/in to a height of 6’ which is tall for a Martian. a. Graph the situation First, we need to convert all heights to inches 4’10” = 4(12) +10 = 58” 5’1” = 5(12) + 1 = 61” 6’ = 6(12) = 72” (58”, 109 lbs) (61”, 115 lbs)
  • 43. Example 3 The lightest recommended weight for a Martian with height 4’10” is 109 lbs. This weight increases 2 lbs/in to a height of 5’1” and then goes up 3 lbs/in to a height of 6’ which is tall for a Martian. a. Graph the situation First, we need to convert all heights to inches 4’10” = 4(12) +10 = 58” 5’1” = 5(12) + 1 = 61” 6’ = 6(12) = 72” (58”, 109 lbs) (61”, 115 lbs) (72”, 148 lbs)
  • 44. Example 3 (con’t) (58”, 109 lbs) (61”, 115 lbs) (72”, 148 lbs) b. Find two equations that describe these situations
  • 45. Example 3 (con’t) (58”, 109 lbs) (61”, 115 lbs) (72”, 148 lbs) b. Find two equations that describe these situations y - y1 = m(x - x1)
  • 46. Example 3 (con’t) (58”, 109 lbs) (61”, 115 lbs) (72”, 148 lbs) b. Find two equations that describe these situations y - y1 = m(x - x1) w - w1 = m(h - h1)
  • 47. Example 3 (con’t) (58”, 109 lbs) (61”, 115 lbs) (72”, 148 lbs) b. Find two equations that describe these situations y - y1 = m(x - x1) w - w1 = m(h - h1) w - 109 = 2(h - 58)
  • 48. Example 3 (con’t) (58”, 109 lbs) (61”, 115 lbs) (72”, 148 lbs) b. Find two equations that describe these situations y - y1 = m(x - x1) w - w1 = m(h - h1) w - 109 = 2(h - 58) w = 2h - 7
  • 49. Example 3 (con’t) (58”, 109 lbs) (61”, 115 lbs) (72”, 148 lbs) b. Find two equations that describe these situations y - y1 = m(x - x1) w - w1 = m(h - h1) w - 109 = 2(h - 58) w = 2h - 7 for 58 ≤ h ≤ 61
  • 50. Example 3 (con’t) (58”, 109 lbs) (61”, 115 lbs) (72”, 148 lbs) b. Find two equations that describe these situations y - y1 = m(x - x1) w - w1 = m(h - h1) w - w1 = m(h - h1) w - 109 = 2(h - 58) w = 2h - 7 for 58 ≤ h ≤ 61
  • 51. Example 3 (con’t) (58”, 109 lbs) (61”, 115 lbs) (72”, 148 lbs) b. Find two equations that describe these situations y - y1 = m(x - x1) w - w1 = m(h - h1) w - w1 = m(h - h1) w - 109 = 2(h - 58) w - 115 = 3(h - 61) w = 2h - 7 for 58 ≤ h ≤ 61
  • 52. Example 3 (con’t) (58”, 109 lbs) (61”, 115 lbs) (72”, 148 lbs) b. Find two equations that describe these situations y - y1 = m(x - x1) w - w1 = m(h - h1) w - w1 = m(h - h1) w - 109 = 2(h - 58) w - 115 = 3(h - 61) w = 2h - 7 w = 3h - 68 for 58 ≤ h ≤ 61
  • 53. Example 3 (con’t) (58”, 109 lbs) (61”, 115 lbs) (72”, 148 lbs) b. Find two equations that describe these situations y - y1 = m(x - x1) w - w1 = m(h - h1) w - w1 = m(h - h1) w - 109 = 2(h - 58) w - 115 = 3(h - 61) w = 2h - 7 w = 3h - 68 for 58 ≤ h ≤ 61 for 61 < h ≤ 72
  • 55. Homework p. 165 #1 - 21 “ I’m not sure I want popular opinion on my side -- I’ve noticed those with the most opinions often have the fewest facts.” - Bethania McKenstry