Physical changes are those that do not change the identity of the ch.pdf

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Physical changes are those that do not change the identity of the chemical undergoing the change. Thus, physical changes include: 1. Ice melting to water (the material is still H2O) 2. water boiling to form steam (again, still H2O) 3. dry ice subliming to form carbon dioxide gas (still CO2) 4. tearing a piece of paper in half (still paper) 5. salt precipitating from a super saturated solution (NaCl) 6. carbon dioxide fizzing out of a soda (still CO2). Chemical changes, however lead to changes in the chemical structures and identities of the materials: 1. Burning paper to form CO2 and water 2. Reacting sodium metal with water to form H2 and NaOH 3. Cooking sugar to make caramel 4. An iron nail rusting 5. reacting an acid (such as vinegar) with a base (such as ammonia) 6. photosynthesis - carbon dioxide and water converted to sugar + oxygen. Another way of looking at it is that chemical changes involve breaking of chemical bonds, while physical changes do not. Solution Physical changes are those that do not change the identity of the chemical undergoing the change. Thus, physical changes include: 1. Ice melting to water (the material is still H2O) 2. water boiling to form steam (again, still H2O) 3. dry ice subliming to form carbon dioxide gas (still CO2) 4. tearing a piece of paper in half (still paper) 5. salt precipitating from a super saturated solution (NaCl) 6. carbon dioxide fizzing out of a soda (still CO2). Chemical changes, however lead to changes in the chemical structures and identities of the materials: 1. Burning paper to form CO2 and water 2. Reacting sodium metal with water to form H2 and NaOH 3. Cooking sugar to make caramel 4. An iron nail rusting 5. reacting an acid (such as vinegar) with a base (such as ammonia) 6. photosynthesis - carbon dioxide and water converted to sugar + oxygen. Another way of looking at it is that chemical changes involve breaking of chemical bonds, while physical changes do not..

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a) Here, H2PO4- Acts as acid and HPO42- as salt. In equation pKa of acid is used, Hence. pKa = 7.21 b) pH = pKa + log (salt/acid) moles of salt = 30/142 moles of acid = 17/136 pH = 7.21 - 0.228 = 6.982 Solution a) Here, H2PO4- Acts as acid and HPO42- as salt. In equation pKa of acid is used, Hence. pKa = 7.21 b) pH = pKa + log (salt/acid) moles of salt = 30/142 moles of acid = 17/136 pH = 7.21 - 0.228 = 6.982.

a) Here, H2PO4- Acts as acid and HPO42- as salt.In equation pKa of.pdf

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1. The evolution of transportation has generally led to changes in urban form. The more radical the changes in transport technology have been, the more the alterations on the urban form. Among the most fundamental changes in the urban form is the emergence of new clusters expressing new urban activities and new relationships between elements of the urban system. In many cities, the central business district (CBD), once the primary destination of commuters and serviced by public transportation, has been changed by new manufacturing, retailing and management practices. Whereas traditional manufacturing depended on centralized workplaces and transportation, technological and transportation developments rendered modern industry more flexible. In many cases, manufacturing relocated in a suburban setting, if not altogether to entirely new low cost locations offshore. Retail and office activities are also suburbanizing, producing changes in the urban form. Concomitantly, many important transport terminals, namely port facilities and railyards, have emerged in suburban areas following new requirements in modern freight distribution brought in part by containerization. 2 process is there for urban transporation- (a) Dispersed urban land development patterns (b) The decentralization of activities 2. Agency characterstics will operate them issue- the will conduct some surveying like road side interview,post card survey,tag on the vechile etc. Solution 1. The evolution of transportation has generally led to changes in urban form. The more radical the changes in transport technology have been, the more the alterations on the urban form. Among the most fundamental changes in the urban form is the emergence of new clusters expressing new urban activities and new relationships between elements of the urban system. In many cities, the central business district (CBD), once the primary destination of commuters and serviced by public transportation, has been changed by new manufacturing, retailing and management practices. Whereas traditional manufacturing depended on centralized workplaces and transportation, technological and transportation developments rendered modern industry more flexible. In many cases, manufacturing relocated in a suburban setting, if not altogether to entirely new low cost locations offshore. Retail and office activities are also suburbanizing, producing changes in the urban form. Concomitantly, many important transport terminals, namely port facilities and railyards, have emerged in suburban areas following new requirements in modern freight distribution brought in part by containerization. 2 process is there for urban transporation- (a) Dispersed urban land development patterns (b) The decentralization of activities 2. Agency characterstics will operate them issue- the will conduct some surveying like road side interview,post card survey,tag on the vechile etc..

1. The evolution of transportation has generally led to changes in u.pdf

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1) Transition state 2) Threshold energy 3) Catalysts or Intermediates 4) bond Dissociation energy 5) Lewis bases or Elecron donating species or electron rich species 6) Lewis acids or Electron accepting species or electron poor species Solution 1) Transition state 2) Threshold energy 3) Catalysts or Intermediates 4) bond Dissociation energy 5) Lewis bases or Elecron donating species or electron rich species 6) Lewis acids or Electron accepting species or electron poor species.

1) Transition state 2) Threshold energy 3) Catalysts or Intermed.pdf

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1) Name four properties of an OpenFileDialog that we often set prior.pdf

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//Main File (usestudentacc.cpp) #include #include \"studentacc.h\" using namespace std; int m_menu(); int aid_menu(); int f_aid(); int getCharge(); //Different charges for student account const int AID = 1, BALANCE = 2, QUIT = 3; const int SCHOLARSHIPS = 1, WORK = 2; int main() { Studentacc sa; float cash, amount; int choice, charge, aid; cout << \"Enter the amount availible for payment: $\"; cin >> cash; sa.setBalance(cash); cout << fixed << showpoint << setprecision(2); //School Fees charge = getCharge(); sa.addCharge(charge); amount = sa.getBalance(); sa.setBalance(amount); if(amount<0) { cout << \"You owe $\" << (-1) * amount << \"this semester\" << endl; } else { cout << \"Your balance is $\" << amount << endl; } choice = m_menu(); while(choice !=QUIT) { if(choice == AID) { aid = f_aid(); sa.addCharge(amount); } choice = m_menu(); } } int m_menu() { int choice; bool error = false; cout << endl; cout << \"MAIN MENU\" << endl; cout << \"1 Financial Aids\" << endl; cout << \"2 Balance\" << endl; cout << \"3 Quit\" << endl; do{ cout << \"Enter option number: \"; cin >> choice; if((choice > 3)||(choice < 1)) { cout << \"Invaid number. Choose 1 or 2, or 3.\ \"; error = true; } else { error = false; } }while(error == true); return choice; }//end intmenu int getCharge() { int hours, tuition, dorm_plan, meal_plan, SA_fee, Technology_fee, total_fee; char response; bool error; cout << \"How many credits hours are you taking this semester? (max = 21)\ \"; cin >> hours; do { if((hours>21)||(hours<0)) { cout << \"\ That is an invalid credit hour(s). Enter a valid credit hour\ \"; error = true; } }while(error==true); if(hours>17&&hours>12) { tuition = 9828; //Package deal cout << \"\ Your tuition is $9,828\ \"; } else if (hours>17) {//increment by 615 every 1 credit after 17 tuition = (hours-17)*615+9828; cout << \"\ Your tuition is $\"; } else { tuition = hours * 819; //Part-time school cout << \"\ Your tuition is $\" << tuition << endl; } do{ cout << \"\ A fixed Student Association fee is collected from each\" << endl; cout << \"\ enrolled student for the purpose of operating, maintaining,\" << endl; cout << \"\ improving and equipping the Student Association.\" << endl; cout << \"The Student Association fee is $\" << SA_fee << endl; SA_fee = 110; } while(error == true); do{ cout << \"\ The technology fee is $\" << Technology_fee << endl; Technology_fee = 200; } while(error == true); do { cout << \"\ Are you staying in the dorm? (yes or no) \ -->\"; cout << \"\ Enter y for yes or n for no. \ \"; cin >> response; if(response==\'y\') { cout << \"\ Dorm plan is $1,850\ \"; dorm_plan = 1850; error = false; } else if(response==\'n\') { cout << \"\ You don\'t have a dorm plan\ \"; dorm_plan = 0; error = false; } else { cout << \"\ Invalid character, please try again\ \"; error = true; } } while(error == true); do { cout << \"\ Do you have a meal plan? (y or n)\ -->\"; cout << \"\ Enter y for yes or n for no. \ \"; cin >> response; if(response==\'y\') { cou.

Main File (usestudentacc.cpp)#includeiostream #include .pdf

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Ecell = Eocell - (0.0592/n)*log (more dilute soln/more concd soln). Eocell = 0 since the two electrodes are the same; i.e, this is a concentration cell. I would plug in 0.001 for more dilute solution and 0.20 for the more concentrated solution and calculate E. I believe n=2. Solution Ecell = Eocell - (0.0592/n)*log (more dilute soln/more concd soln). Eocell = 0 since the two electrodes are the same; i.e, this is a concentration cell. I would plug in 0.001 for more dilute solution and 0.20 for the more concentrated solution and calculate E. I believe n=2..

Ecell = Eocell - (0.0592n)log (more dilute solnmore concd soln). .pdf

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DBA Company Income Statement For the period ended December 31, 2015 Revenues Service Revenue $2,80,500 Total Revenues $2,80,500 Costs and Expenses Salaries and Wages $1,09,000 Supplies Expenses $14,400 Maintenance $30,500 Advertising Expenses $9,400 Utilities Expenses $16,900 Property Tax Expenses $21,000 Insurance Expenses $28,000 Depreciation Expenses $5,800 Interest Expenses $12,000 Total Costs and Expenses $2,47,000 Net Income / (Net Loss) $33,500 DBA Company Statement of Retained Earnings For the year ended December 31, 2015 Retained Earnings - 1/1/15 $2,000 Add: Net Income $33,500 $35,500 Less: Dividends $14,000 Retained Earnings - 31-12-2015 $21,500 DBA Company Balance Sheet As on December 31, 2015 Assets Amount Amount Liabilities Amount Current Assets Current Liabilities Cash $37,400 Accounts Payable $14,600 Supplies $4,200 Property Tax Payable $3,000 Prepaid Insurance $3,900 Interest Payable $6,000 Unearned Service Revenue $700 Long-Term Assets Land $80,000 Long-Term Liabilities Equipment $1,20,000 Mortgage Payable $50,000 Less: Accumulated Depreciation $42,000 $78,000 Share Holders Equity Retained Earnings $21,500 Common Stock $1,07,700 Total Assets $2,03,500 Total Liabilites and Equity $2,03,500 Solution DBA Company Income Statement For the period ended December 31, 2015 Revenues Service Revenue $2,80,500 Total Revenues $2,80,500 Costs and Expenses Salaries and Wages $1,09,000 Supplies Expenses $14,400 Maintenance $30,500 Advertising Expenses $9,400 Utilities Expenses $16,900 Property Tax Expenses $21,000 Insurance Expenses $28,000 Depreciation Expenses $5,800 Interest Expenses $12,000 Total Costs and Expenses $2,47,000 Net Income / (Net Loss) $33,500 DBA Company Statement of Retained Earnings For the year ended December 31, 2015 Retained Earnings - 1/1/15 $2,000 Add: Net Income $33,500 $35,500 Less: Dividends $14,000 Retained Earnings - 31-12-2015 $21,500 DBA Company Balance Sheet As on December 31, 2015 Assets Amount Amount Liabilities Amount Current Assets Current Liabilities Cash $37,400 Accounts Payable $14,600 Supplies $4,200 Property Tax Payable $3,000 Prepaid Insurance $3,900 Interest Payable $6,000 Unearned Service Revenue $700 Long-Term Assets Land $80,000 Long-Term Liabilities Equipment $1,20,000 Mortgage Payable $50,000 Less: Accumulated Depreciation $42,000 $78,000 Share Holders Equity Retained Earnings $21,500 Common Stock $1,07,700 Total Assets $2,03,500 Total Liabilites and Equity $2,03,500.

DBA Company Income Statement For the period ended December 31,.pdf

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Indicate whether the solute solid is generally soluble or insoluble in each solvent liquid. Solute Solvent polar liquid nonpolar liquid Ionic Solid Soluble insoluble Polar Solid Soluble insoluble nonpolar solid insoluble soluble Solution Indicate whether the solute solid is generally soluble or insoluble in each solvent liquid. Solute Solvent polar liquid nonpolar liquid Ionic Solid Soluble insoluble Polar Solid Soluble insoluble nonpolar solid insoluble soluble.

Indicate whether the solute solid is generally so.pdf

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in HCl [H+] concentration = 0.12M pH of HCl = -log(o.12) =0.92 in Ca(OH)2 [OH-] concentration = 2*0.15 =0.3M pOH = -log([OH-] PH = 14-pH pH of Ca(OH)2 = 14+log(2*0.15) =13.477 we know Kw of water =10^-14 [H+][OH-] =10^-14 so both have equalconcentrations hence [H+] = [OH-] = 10^-7 M pH of water = -log(10^-7) = 7 Solution in HCl [H+] concentration = 0.12M pH of HCl = -log(o.12) =0.92 in Ca(OH)2 [OH-] concentration = 2*0.15 =0.3M pOH = -log([OH-] PH = 14-pH pH of Ca(OH)2 = 14+log(2*0.15) =13.477 we know Kw of water =10^-14 [H+][OH-] =10^-14 so both have equalconcentrations hence [H+] = [OH-] = 10^-7 M pH of water = -log(10^-7) = 7.

in HCl [H+] concentration = 0.12M pH of HCl = -lo.pdf

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Phenanthrene is a polycyclic aromatic hydrocarbon composed of three fused benzene rings. The name phenanthrene is a composite of phenyl and anthracene. In its pure form, it is found in cigarette smoke and is a known irritant, photosensitizing skin to light A classical phenanthrene synthesis is the Bardhan-Sengupta phenanthrene synthesis. Phenanthrene is nearly insoluble in water but is soluble in most organic solvents such astoluene,carbon tetrachloride,ether,chloroform,acetic acidandbenzene. The first step is an electrophilic aromatic substitution reaction, which is allowed when the diphosphorous pentoxide makes the alcohol a better leaving group. However, no alkenes outside of the initial aromatic ring are created. In the second step of this reaction 9,10- dihydrophenanthrene is oxidized with elemental selenium. The aromatization of six-membered rings by selenium is not clearly understood, but it does produce H2Se. Phenanthrene can also be obtained photochemically from certain diarylethenes. Reactions of phenanthrene typically occur at the 9 and 10 positions, including: Organic oxidation to phenanthrenequinone with chromic acid Organic reduction to[9,10-dihydrophenanthrene with hydrogen gas and raney nickel Electrophilic halogenation to 9-bromophenanthrene with bromine Aromatic sulfonation to 2 and 3-phenanthrenesulfonic acids with sulfuric acid Ozonolysis to diphenylaldehyde Canonical forms Phenanthrene is more stable than its linear isomer anthracene. A classic and well established explanation is based on Clar\'s rule. A novel theory invokes so-called stabilizing hydrogen- hydrogen bonds between the C4 and C5 hydrogen atoms. Natural occurrence Ravatite is a natural analog of synthetic phenanthrene. It is found in small amounts among a few coal burning sites. Ravatite represents a small group of organic minerals. Solution Phenanthrene is a polycyclic aromatic hydrocarbon composed of three fused benzene rings. The name phenanthrene is a composite of phenyl and anthracene. In its pure form, it is found in cigarette smoke and is a known irritant, photosensitizing skin to light A classical phenanthrene synthesis is the Bardhan-Sengupta phenanthrene synthesis. Phenanthrene is nearly insoluble in water but is soluble in most organic solvents such astoluene,carbon tetrachloride,ether,chloroform,acetic acidandbenzene. The first step is an electrophilic aromatic substitution reaction, which is allowed when the diphosphorous pentoxide makes the alcohol a better leaving group. However, no alkenes outside of the initial aromatic ring are created. In the second step of this reaction 9,10- dihydrophenanthrene is oxidized with elemental selenium. The aromatization of six-membered rings by selenium is not clearly understood, but it does produce H2Se. Phenanthrene can also be obtained photochemically from certain diarylethenes. Reactions of phenanthrene typically occur at the 9 and 10 positions, including: Organic oxidation to phenanthrenequinone with chro.

Phenanthrene is a polycyclic aromatic hydrocarbon composed of three .pdf

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B. When dissolved solute and undissolved solute exist in equilibrium with each other in a solution, that solution is said to be \"supersaturated\". a supersaturated solution has more undissolved solute than would be possible at equilibrium. Solution B. When dissolved solute and undissolved solute exist in equilibrium with each other in a solution, that solution is said to be \"supersaturated\". a supersaturated solution has more undissolved solute than would be possible at equilibrium..

B. When dissolved solute and undissolved solute e.pdf

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Yes both men and women differ in their thinking, research has proved that women brain used ten times more white matter when compared to men, this makes females multi tasking and can go for quick transition between tasks. When it comes to males, they use seven times more gray matter when compared to female from their activity and the gray matter is involved in information storing and action processing and this makes men to do better when given task focused projects. Bothe men and women shows differences in thinking, social behavior, and personality as they both process the same neurochemicals in different degrees (serotonin is one dominant neurochemical). This will make women more patient, can sit for long time, will not be stressed frequently and females will have absorb more emotive and even the sensorial information when compared to males due to their larger hippocampus (memory center) like women can sense or guess what is going on surrounding her. Due to influence right and left hemisphere, girls will be more in discussion with more different words and can express their feelings well and can adapt to the situation in a better way. Females will have more problem solving capacity. Females tend to show less aggressive behavior and they will calm and quiet and follow tend and befriend strategy. Men tend to be more aggressive and will not have adjustment attitude and follow the fight or flight response towards the stress situation. Yes the differences between men and women are significant. As we know conventional wisdom is what is generally accepted by everyone, commonsense is nothing but what you feel or understand by seeing or perceiving things. Men will try to understand and perceive things on their own by analyzing the things, but women will tend to go with common understanding what everyone is having about the issue. Solution Yes both men and women differ in their thinking, research has proved that women brain used ten times more white matter when compared to men, this makes females multi tasking and can go for quick transition between tasks. When it comes to males, they use seven times more gray matter when compared to female from their activity and the gray matter is involved in information storing and action processing and this makes men to do better when given task focused projects. Bothe men and women shows differences in thinking, social behavior, and personality as they both process the same neurochemicals in different degrees (serotonin is one dominant neurochemical). This will make women more patient, can sit for long time, will not be stressed frequently and females will have absorb more emotive and even the sensorial information when compared to males due to their larger hippocampus (memory center) like women can sense or guess what is going on surrounding her. Due to influence right and left hemisphere, girls will be more in discussion with more different words and can express their feelings well and can adapt to the situation .

Yes both men and women differ in their thinking, research has proved.pdf

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What is the probability that a five-card poker hand contains the ace of hearts? Solution P(getting the ace of heart in 5 cards) = P(1st is AH or 2nd is AH or 3rd is AH or ... or 5th is AH) Since these event are mutually exclusive (getting one excludes the others from happening), then you can just add the probabilities. = P(1st is AH) + P(2nd is AH) + ... + P(5th is AH) = 1/52 + 1/52 + ... + 1/52 (note that these are unconditional probabilities, so all are 1/52) = 5/52 = 0.096153846.

What is the probability that a five-card poker hand contains the a.pdf

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When using some Sounds and Audio Devices functions you see a message.pdf

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We can better understand it with the help of examples. Red flower - RR, white - rr Offspring - Rr In complete dominance - phenotype all red flowers, as red is completely dominant over white allele. In incomplete dominance- no complete dominance if any particular gene over the other. So in between of two phenotype we get a phenotype of pink colour and neither red not white. If Rr×Rr in complete dominance RR- red, 2Rr- red, RR- white. Hallo sufficiency as one copy of gene is enough to maintain the character. In incomplete dominance- RR- red, 2Rr- pink, RR- white. Haploinsufficiency as one copy if gene is not sufficient to maintain the character. Solution We can better understand it with the help of examples. Red flower - RR, white - rr Offspring - Rr In complete dominance - phenotype all red flowers, as red is completely dominant over white allele. In incomplete dominance- no complete dominance if any particular gene over the other. So in between of two phenotype we get a phenotype of pink colour and neither red not white. If Rr×Rr in complete dominance RR- red, 2Rr- red, RR- white. Hallo sufficiency as one copy of gene is enough to maintain the character. In incomplete dominance- RR- red, 2Rr- pink, RR- white. Haploinsufficiency as one copy if gene is not sufficient to maintain the character..

We can better understand it with the help of examples.Red flower -.pdf

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The racial and ethnic makeup of the American people is in flux. New immigrants from Asia and Latin America have added a large measure of cultural and phenotypic diversity to the American population in recent decades, just as waves of immigrants from Southern and Eastern Europe did a century ago. Moreover, the boundaries between racial and ethnic groups are becoming blurred by high rates of intermarriage and the growing number of persons with mixed ancestry. Descriptions and projections of the racial and ethnic composition of the American people appear kaleidoscopic, with varied accounts and interpretations. Some commentators anticipate a new melting pot, often labeled as the “browning of America,” characterized by continued blurring of once-distinct racial and ethnic divisions. This interpretation is consistent with the thesis of the declining significance of race and ethnicity in American society. Others see new racial divisions arising as some immigrant groups are allowed to integrate with an expanded and privileged white population, while other groups are “racialized” as disadvantaged brown and black minorities. These conflicting accounts arise, in part, because of differing ideological presuppositions, but also because racial and ethnic identities are not mutually exclusive or immutable. . In general, people do not change their ethnicities as a matter of fashion, but they may emphasize different aspects depending on the circumstances. For instance, a person who identifies as Mexican among relatives might identify as Hispanic at work and as American when overseas. A person of mixed heritage might be Native American in one context, but white in another. These possibilities exist in census data, just as they do in informal conversations and settings, because of the opportunities for varied responses to different census questions about race and ethnicity. Solution The racial and ethnic makeup of the American people is in flux. New immigrants from Asia and Latin America have added a large measure of cultural and phenotypic diversity to the American population in recent decades, just as waves of immigrants from Southern and Eastern Europe did a century ago. Moreover, the boundaries between racial and ethnic groups are becoming blurred by high rates of intermarriage and the growing number of persons with mixed ancestry. Descriptions and projections of the racial and ethnic composition of the American people appear kaleidoscopic, with varied accounts and interpretations. Some commentators anticipate a new melting pot, often labeled as the “browning of America,” characterized by continued blurring of once-distinct racial and ethnic divisions. This interpretation is consistent with the thesis of the declining significance of race and ethnicity in American society. Others see new racial divisions arising as some immigrant groups are allowed to integrate with an expanded and privileged white population, while other groups are “racialized” as disadvan.

The racial and ethnic makeup of the American people is in flux. New .pdf

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The ion responsible is HCO3-. HCO3- is the conjugate base of the weak acid H2CO3 and ionizes in water: HCO3- + H2O <=> H2CO3 + OH- Since OH- ions are produced by the hydrolysis, [OH-] > [H+] and the water is basic (pH > 7). Solution The ion responsible is HCO3-. HCO3- is the conjugate base of the weak acid H2CO3 and ionizes in water: HCO3- + H2O <=> H2CO3 + OH- Since OH- ions are produced by the hydrolysis, [OH-] > [H+] and the water is basic (pH > 7)..

The ion responsible is HCO3-.HCO3- is the conjugate base of the we.pdf

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The causal relationship in epidemiology is generally an observation rather than experiments.The criteria for studying this relationship are bias, chance or confounding. Also, according to the Bradford- Hill criteria, one can assess the strength of association, statistical findings of the recurrence of the problem in a particular set of population, biological gradient, the biological mechanism, the history of the disease and experiments performed for the removal of the disease. Solution The causal relationship in epidemiology is generally an observation rather than experiments.The criteria for studying this relationship are bias, chance or confounding. Also, according to the Bradford- Hill criteria, one can assess the strength of association, statistical findings of the recurrence of the problem in a particular set of population, biological gradient, the biological mechanism, the history of the disease and experiments performed for the removal of the disease..

The causal relationship in epidemiology is generally an observation .pdf

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Since Lithium sulfate is an ionic compound and is soluble in water, .pdf

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//operating system ubuntu,Linux,Mac public class SuperMarket { /*Variable declaration*/ private int employeeId; private double hourlyRate; private double regularHour; private double overtimeHour; private double grossPay; private double netpay; /*Getter and setter methods*/ public int getEmployeeId() { return employeeId; } public void setEmployeeId(int employeeId) { this.employeeId = employeeId; } public double getHourlyRate() { return hourlyRate; } public void setHourlyRate(double hourlyRate) { this.hourlyRate = hourlyRate; } public double getRegularHour() { return regularHour; } public void setRegularHour(double regularHour) { this.regularHour = regularHour; } public double getOvertimeHour() { return overtimeHour; } public void setOvertimeHour(double overtimeHour) { this.overtimeHour = overtimeHour; } public double getGrossPay() { return grossPay; } public void setGrossPay(double grossPay) { this.grossPay = grossPay; } public double getNetpay() { return netpay; } public void setNetpay(double netpay) { this.netpay = netpay; } } /********Driver class***********/ import java.util.ArrayList; import java.util.List; import java.util.ListIterator; import java.util.Scanner; public class SuperMarketDriver { /*Variable Declaration*/ private int numberOfEmployees; private final int tax=30; private final int parking=10; SuperMarket employees[]; /*List for storing Employee of Super market*/ List list=new ArrayList(); /*readInput method for reading employee information*/ public void readInput(){ /*User Input*/ Scanner input=new Scanner(System.in); System.out.println(\"Please enter the number of Employees\"); numberOfEmployees=input.nextInt(); /*Creating array of supermarket*/ employees=new SuperMarket[numberOfEmployees]; int i=0; /*Loop run number of employees times*/ while(numberOfEmployees>0){ employees[i]=new SuperMarket(); System.out.println(\"Please Enter Employee Id\"); employees[i].setEmployeeId(input.nextInt()); System.out.println(\"Please Enter Hourly Rate of Pay\"); employees[i].setHourlyRate(input.nextDouble()); System.out.println(\"Please Enter Number of regular hour\"); employees[i].setRegularHour(input.nextDouble()); System.out.println(\"Please Enter overtime hours\"); employees[i].setOvertimeHour(input.nextDouble()); /*Calculation of grosspay*/ double grossPay=(employees[i].getRegularHour()*employees[i].getHourlyRate())+(employees[i].getOv ertimeHour()*(employees[i].getHourlyRate()*1.5)); employees[i].setGrossPay(grossPay); /*Calculation of Netpay*/ double netPay=grossPay-(grossPay*tax/100)-parking; employees[i].setNetpay(netPay); /*Adding to list*/ list.add(employees[i]); i++; numberOfEmployees--; } } /*Printing employees details using List iterator*/ public void printData(){ ListIterator itr=list.listIterator(); SuperMarket employee; while(itr.hasNext()){ employee=itr.next(); System.out.println(\"********************\"); System.out.println(\"Employee Id: \"+employee.getEmployeeId()+\"\ \"+\"Employee Hourly Rate: \"+employee.getHourlyRate(.

operating system ubuntu,Linux,Macpublic class SuperMarket { .pdf

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