What is the probability that a five-card poker hand contains the ace of hearts? Solution P(getting the ace of heart in 5 cards) = P(1st is AH or 2nd is AH or 3rd is AH or ... or 5th is AH) Since these event are mutually exclusive (getting one excludes the others from happening), then you can just add the probabilities. = P(1st is AH) + P(2nd is AH) + ... + P(5th is AH) = 1/52 + 1/52 + ... + 1/52 (note that these are unconditional probabilities, so all are 1/52) = 5/52 = 0.096153846.