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a) Here, H2PO4- Acts as acid and HPO42- as salt.
In equation pKa of acid is used, Hence. pKa = 7.21
b) pH = pKa + log (salt/acid)
moles of salt = 30/142
moles of acid = 17/136
pH = 7.21 - 0.228 = 6.982
Solution
a) Here, H2PO4- Acts as acid and HPO42- as salt.
In equation pKa of acid is used, Hence. pKa = 7.21
b) pH = pKa + log (salt/acid)
moles of salt = 30/142
moles of acid = 17/136
pH = 7.21 - 0.228 = 6.982

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a) Here, H2PO4- Acts as acid and HPO42- as salt.In equation pKa of.pdf

  • 1. a) Here, H2PO4- Acts as acid and HPO42- as salt. In equation pKa of acid is used, Hence. pKa = 7.21 b) pH = pKa + log (salt/acid) moles of salt = 30/142 moles of acid = 17/136 pH = 7.21 - 0.228 = 6.982 Solution a) Here, H2PO4- Acts as acid and HPO42- as salt. In equation pKa of acid is used, Hence. pKa = 7.21 b) pH = pKa + log (salt/acid) moles of salt = 30/142 moles of acid = 17/136 pH = 7.21 - 0.228 = 6.982