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MEMBRANE ANALOGY
AND
TORSION OF THIN-WALLED
TUBES
Presented by,
ROLWYN MARIAN CARDOZA
1RV18MMD15
MTech MACHINE DESIGN
RV COLLEGE OF ENGINEERING.
MEMBRANE ANALOGY
• The analytical solutions are difficult for bar with
complicated cross- sections.
• Hence we search for some other techniques—
experimental or otherwise.
• The membrane analogy introduced by Prandtl is
one such technique that allows the stress
distribution on any cross section to be determined
experimentally.
• We connect this analogy to Torsion of general
prismatic bars–solid sections
• Let a thin homogeneous membrane like a thin rubber sheet be
stretched with uniform tension and fixed at its edge, which is a given
curve
• When the membrane is subjected to a uniform lateral pressure p, it
undergoes a small displacement z where z is a function of x and y.
• Consider the equilibrium of an infinitesimal element ABCD of the
membrane after deformation.
• Let F be the uniform tension per unit length of the membrane. The
value of the initial tension F is large enough to ignore its change when
the membrane is blown up by the small pressure p.
• Now, if we adjust the membrane tension F or the air
pressure p such that p/F becomes numerically equal to 2Gϴ,
then
of the membrane becomes
identical to of the torsion stress function φ.
• Further, if the membrane height z remains zero at the
boundary contour of the section, then the height z of the
membrane becomes numerically equal to the torsion stress
function .
• The slopes of the membrane are then equal to the shear
stresses and these are in a direction perpendicular to that of
the slope. The twisting moment is numerically equivalent to
twice the volume under the membrane
TORSION OF THIN-WALLED TUBES
• Consider a thin-walled tube
subjected to torsion.
• The thickness of the tube need
not be uniform
• Since thickness is small the
shear stress will be parallel to
boundary
• Let ‘τ ‘ be shear stress ‘t’ be
thickness.
• Consider the equilibrium of an element
• The areas of cut faces AB and CD are respectively.
• For equilibrium in z direction
1
2
3
Multiplying and dividing by t
4
5
Quiz
1. The membrane analogy was developed by ___________(Prandtl)
2. The membrane analogy is ____________technique. (experimental)
3. The twisting moment is numerically equivalent to ________ the volume
under the membrane.(twice)
4. The total elastic strain energy of a thin walled tube subjected to torsion is
given by _________
5. The twist of thin walled tube subjected to torsion is given by __________
Questions
1. Explain Prandtl’s membrane analogy in detail ?
2. Discuss in detail, the torsion of thin walled tubes ?
Reference
• Advances Mechanics of Solids – L S Srinath
membrane analogy and torsion of thin walled tube

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membrane analogy and torsion of thin walled tube

  • 1. MEMBRANE ANALOGY AND TORSION OF THIN-WALLED TUBES Presented by, ROLWYN MARIAN CARDOZA 1RV18MMD15 MTech MACHINE DESIGN RV COLLEGE OF ENGINEERING.
  • 2. MEMBRANE ANALOGY • The analytical solutions are difficult for bar with complicated cross- sections. • Hence we search for some other techniques— experimental or otherwise. • The membrane analogy introduced by Prandtl is one such technique that allows the stress distribution on any cross section to be determined experimentally. • We connect this analogy to Torsion of general prismatic bars–solid sections
  • 3. • Let a thin homogeneous membrane like a thin rubber sheet be stretched with uniform tension and fixed at its edge, which is a given curve • When the membrane is subjected to a uniform lateral pressure p, it undergoes a small displacement z where z is a function of x and y. • Consider the equilibrium of an infinitesimal element ABCD of the membrane after deformation. • Let F be the uniform tension per unit length of the membrane. The value of the initial tension F is large enough to ignore its change when the membrane is blown up by the small pressure p.
  • 4.
  • 5.
  • 6. • Now, if we adjust the membrane tension F or the air pressure p such that p/F becomes numerically equal to 2Gϴ, then of the membrane becomes identical to of the torsion stress function φ. • Further, if the membrane height z remains zero at the boundary contour of the section, then the height z of the membrane becomes numerically equal to the torsion stress function . • The slopes of the membrane are then equal to the shear stresses and these are in a direction perpendicular to that of the slope. The twisting moment is numerically equivalent to twice the volume under the membrane
  • 7. TORSION OF THIN-WALLED TUBES • Consider a thin-walled tube subjected to torsion. • The thickness of the tube need not be uniform • Since thickness is small the shear stress will be parallel to boundary • Let ‘τ ‘ be shear stress ‘t’ be thickness.
  • 8. • Consider the equilibrium of an element • The areas of cut faces AB and CD are respectively. • For equilibrium in z direction 1 2 3
  • 10.
  • 11. Quiz 1. The membrane analogy was developed by ___________(Prandtl) 2. The membrane analogy is ____________technique. (experimental) 3. The twisting moment is numerically equivalent to ________ the volume under the membrane.(twice) 4. The total elastic strain energy of a thin walled tube subjected to torsion is given by _________ 5. The twist of thin walled tube subjected to torsion is given by __________ Questions 1. Explain Prandtl’s membrane analogy in detail ? 2. Discuss in detail, the torsion of thin walled tubes ?
  • 12. Reference • Advances Mechanics of Solids – L S Srinath

Editor's Notes

  1. Phi is constant at boundary Torsion of general prismatic bars–solid sections
  2. The equation derived here is used to find internal energy twist per unit length
  3. 1) dA is the area of the triangle enclosed at A by the base X 2) A is the area enclosed by the centre line of the tube
  4. Shear strain = change in deformation / orginal length perpendicular to the axis of member due to shear stress