ih;iob;b

1. CALCULATOR
TECHNIQUES
that works for
CASIO 991 and 570 ES/PLUS

2. ALGEBRA

3. CALCULATOR TECHNIQUES
Problem:
Evaluate f(3,4) if
f(x,y) = 4x3y2 + 3x2y – 2xy2 + y3
a. 2061
b. 1804
c. 1602
d. 1408

4. CALCULATOR TECHNIQUES
ENTER: MODE 1
PRESS: 4 ALPHA ) SHIFT x2 ALPHA
x2 + 3 ALPHA ) x2 ALPHA – 2
ALPHA ) ALPHA x2 + ALPHA
SHIFT x2
DISPLAY: 4X3Y2 + 3X2Y – 2XY2 + Y3
PRESS: CALC 3 = 4 =
DISPLAY: 4X3Y2 + 3X2Y – 2XY2 + Y3
1804
S D
S D
S D
S D

5. CALCULATOR TECHNIQUES
Problem:
Solve for x: 37x+1 = 6561.
a. 1
b. 2
c. 3
d. 4

6. CALCULATOR TECHNIQUES
PRESS: MODE 1
ENTER: 3 𝑥∎
7 ALPHA ) + 1 ALPHA
CALC 6 5 6 1
DISPLAY: 37x+1=6561
PRESS: SHIFT CALC =
DISPLAY: 37x+1=6561
X= 1
L-R= 0

7. PRACTICE:
Problem: ME BOARD (APRIL 1998)
Find the value of x that will satisfy the
following expression.
𝑥 − 2 = - 𝑥 + 2
a. 3/2
b. 18/6
c. 9/4
d. none of these

8. CALCULATOR TECHNIQUES
Problem: EE BOARD EXAM (OCTOBER
1997)
Find the values of x and y from the
equations:
x – 4y + 2 = 0
2x + y – 4 = 0
a. 11/7, -5/7 c. 4/9, 8/9
b. 14/9, 8/9 d. 3/2, 5/3

9. CALCULATOR TECHNIQUES
ENTER: MODE 5 1
INPUT:
1 −4 −2
2 1 4
PRESS: =
DISPLAY: X=
14
9
PRESS: =
DISPLAY: Y=
8
9

10. CALCULATOR TECHNIQUES
Problem: ME BOARD (OCTOBER 1996)
Solve the simultaneous equations:
2x2 – 3y2 = 6
3x2 + 2y2 = 35
a. x = 3 or -3; y = 2 or -2
b. x = 3 or -3; y = -1 or 1
c. x = 4 or -4; y = 1 or -1
d. x = 1 or -1; y = 2 or -2

11. CALCULATOR TECHNIQUES
ENTER: MODE 5 1
INPUT:
2 −3 6
3 2 35
PRESS: =
DISPLAY:X=
9
PRESS: =
DISPLAY:Y=
4

12. PRACTICE:
Problem: ME BOARD (OCTOBER 1995)
Solve for the value of x and y.
4x + 2y = 5 13x – 3y = 2
a. y = ½, x = 3/2
b. y = 3/2, x = ½
c. y = 2, x = 1
d. y = 3, x = 1

13. CALCULATOR TECHNIQUES
Problem: CE BOARD (MAY 1997)
Find the value of w in the following
equations:
3x – 2y + w = 11
x + 5y - 2w = -9
2x + y – 3w = -6
a. 3 c. 4
b. 2 d. -2

14. CALCULATOR TECHNIQUES
ENTER: MODE 5 2
INPUT:
3 −2 1
1 5 −2
11
−9
2 1 −3 −6
PRESS: =
DISPLAY: X=
2

15. CALCULATOR TECHNIQUES
PRESS: =
DISPLAY: Y=
-1
PRESS: =
DISPLAY: Z=
3

16. PRACTICE:
Problem: CE BOARD (NOVEMBER 2001)
Solve for the sum A, B, and C from the
following equations
2A – 2B + 3C = 24
A + 3B – 2C = -15
3A + 4B + 3C = -2
a. 2 c. -5
b. 4 d. 1

17. CALCULATOR TECHNIQUES
Problem: ME BOARD EXAM (April 1998)
Factor the expression 16 – 10x + x2.
a. (x+8)(x-2) c. (x-8)(x+2)
b. (x-8)(x-2) d. (x+8)(x+2)

18. CALCULATOR TECHNIQUES
ENTER: MODE 5 3
INPUT: 1 −10 16
PRESS: =
DISPLAY: X1=
8
PRESS: =
DISPLAY: X2 =
2

19. PRACTICE:
Problem: ME BOARD (APRIL 1996)
Factor the expression x2 + 6x + 8 as
completely as possible.
a. (x+8)(x-2) c. (x+4)(x-2)
b. (x+4)(x+2) d. (x-8)(x-2)

20. CALCULATOR TECHNIQUES
Problem:
Factor x3 + 2x2 – x – 2
a. (x-2)(x+1)(x-1)
b. (x+1)(2x-1)(x+2)
c. (x-1)(x+1)(x+2)
d. (x-1)(x+2)(x-3)

21. CALCULATOR TECHNIQUES
ENTER: MODE 5 4
INPUT: 1 2 −1 −2
PRESS: =
DISPLAY: X1= 1 PRESS: =
X2= -1 PRESS: =
X3= -2
Therefore: (x-1)(x+1)(x+2)

22. PRACTICE:
Problem:
Factor x3 - 3x2 – 10x + 24
a. (x-3)(x+4)(x+2)
b. (x-3)(x-4)(x+2)
c. (x+3)(x-4)(x-2)
d. (x-3)(x-2)(x-4)

23. CALCULATOR TECHNIQUES
Problem: CE BOARD (NOVEMBER 1997 &
MAY 1999)
If (4y3 + 18y2 + 8y – 4) is divided by
(2y + 3), the remainder is:
a. 10 c. 12
b. 11 d. 13

24. CALCULATOR TECHNIQUES
ENTER: MODE 1
PRESS: 4 ALPHA SHIFT x2 + 1 8
ALPHA x2 + 8 ALPHA - 4
DISPLAY: 4Y3+18Y2+8Y-4
PRESS: CALC (-) 3
∎
∎
2 =
DISPLAY: 4Y3+18Y2+8Y-4
11
S D
S D S D

25. PRACTICE:
Problem: EE BOARD (APR. 1996 & MAY
1998)
The polynomial x3 + 4x2 – 3x + 8 is
divided by (x-5), then the remainder is
a. 175
b. 140
c. 218
d. 200

26. CALCULATOR TECHNIQUES
Problem: CE BOARD (MAY 2000)
There are four geometric means
between 3 and 729. Find the fourth term.
A. 81 C. 243
B. 27 D. 9

27. CALCULATOR TECHNIQUES
ENTER: MODE 3 6
INPUT:
PRESS: AC 4 SHIFT 1 5 5
DISPLAY: 4ŷ PRESS: =
DISPLAY: 4ŷ
81
x y
1 1 3
2 6 729
3

28. PRACTICE:
Problem:
The 3rd and 8th terms of a geometric
progression are 27 and 6561 respectively.
Find the 20th term.
a. 3486784401 c. 1162261467
b. 129140163 d. 387420489

29. CALCULATOR TECHNIQUES
Problem:
There are 9 arithmetic means between
6 and 18. What is the common difference?
A. 1.2 C. 1.4
B. 1 D. 0.8

30. CALCULATOR TECHNIQUES
ENTER: MODE 3 2
INPUT:
PRESS: AC SHIFT 1 5 2 =
DISPLAY: B
1.2
x y
1 1 6
2 11 18
3

31. PRACTICE:
Problem:
The 3rd and 8th terms of an arithmetic
progression are 9 and 24 respectively. Find
the 20th term and the common difference.
a. a20 = 36, d = 6
b. a20 = 60, d = 3
c. a20 = 63, d = 4
d. a20 = 66, d = 7

32. CALCULATOR TECHNIQUES
Problem:
What is the sum of the progression 4,
9, 14, 19 … up to the 20th term?
a. 1030
b. 1035
c. 1040
d. 1045

33. CALCULATOR TECHNIQUES
ENTER: MODE 3 2
INPUT:
PRESS: AC SHIFT 1 5 1 = SHIFT RCL (-)
DISPLAY: AnsA
-1
PRESS: SHIFT 1 5 2 = SHIFT RCL ˚’’’
DISPLAY: AnsB
5
x Y
1 1 4
2 2 9
3

34. CALCULATOR TECHNIQUES
ENTER: MODE 1 SHIFT log∎ ∎ RCL (-) + RCL ˚’’’
ALPHA ) 1 2 0
DISPLAY: 𝑥=1
20
𝐴 + 𝐵𝑋
PRESS: =
DISPLAY: 𝑥=1
20
𝐴 + 𝐵𝑋
1030

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