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“The goal in life is to be solid, whereas the way that life works is totally fluid, so you can never
actually achieve that goal.”
~Damien Hirst
by: Maria Faith L. Dalay
Let “S” be a solid that lies between x = a and
x = b, if the cross-sectional area of “S” in the
plane P(x) through x and perpendicular to the axis
is A(x) then,
𝑉 = න
𝑎
𝑏
𝐴 𝑥 𝑑𝑥
Methods of
finding the volume
1.Disc Method
2.Washer Method
3.Cylindrical/Shell Method
3
This method is useful when
the axis of rotation is part
of the boundary of the
plane area.
Useful when the axis
of rotation is not a
part of the boundary
of the plane area
Uses cylinder to
compute the volume
Find the volume of the solid obtained by rotating about the x−axis
the region under the curve y = √x from 0 to 1.
Find the volume of the solid obtained by rotating about the x−axis
the region under the curve y = √x from 0 to 1.
Radius = Top - Bottom
= √x - 0
= √x
Area of a circle
= πr2
Find the volume of the solid obtained by rotating about the x−axis
the region under the curve y = √x from 0 to 1.
Radius = Top - Bottom
= √x - 0
= √x
𝑉 = න
𝑎
𝑏
𝐴 𝑥 𝑑𝑥
𝑉 = න
𝑎
𝑏
𝐴𝑟𝑒𝑎 𝑜𝑓 𝑎 𝑐𝑖𝑟𝑐𝑙𝑒 𝑑𝑥
𝑉 = න
𝑎
𝑏
π𝑟2 𝑑𝑥
𝑉 = න
0
1
π( 𝑥)2
𝑑𝑥
𝑉 = π න
0
1
𝑥 𝑑𝑥
𝑉 = π
𝑥2
2
1
0
𝑉 = π
12
2
− 0
𝑉 =
π
2
unit 3
Find the volume of the solid obtained by rotating the region bounded
by y = x3, y=8, y=0 about the y-axis.
Find the volume of the solid obtained by rotating the region bounded
by y = x3, y=8, y=0 about the y-axis.
y = x3 → x = ∛y
Radius = Right - Left
= ∛y - 0
= ∛y
Find the volume of the solid obtained by rotating the region bounded
by y = x3, y=8, y=0 about the y-axis.
y = x3 → x = ∛y
Radius = Right – Left
= ∛y – 0
= ∛y
𝑉 = න
𝑎
𝑏
(𝐴𝑟𝑒𝑎) 𝑑𝑦
𝑉 = න
𝑎
𝑏
π𝑟2
𝑑𝑦
𝑉 = න
0
8
π(∛y)2
𝑑𝑦
𝑉 = π න
0
8
(𝑦
2
3) 𝑑𝑦
𝑉 = π [
3
5
𝑦
5
3]
8
0
𝑉 =
96π
5
unit 3
𝑉 = π න
𝑎
𝑏
𝑟2
𝑑𝑥
𝑉 = π න
𝑎
𝑏
(𝑟𝑜 𝑢𝑡)2
− (𝑟𝑖𝑛)2
𝑑𝑥
The region by the curves y = x and y = x2, is rotated about
the x-axis. Find the volume of the rotating solid
The region by the curves y = x and y = x2, is rotated about
the x-axis. Find the volume of the rotating solid
Rout = Top - Bottom
= x - 0
= x
Rin = Top - Bottom
= x2 - 0
= x2
The region by the curves y = x and y = x2, is rotated about
the x-axis. Find the volume of the rotating solid
Rout = Top - Bottom
= x - 0
= x
Rin = Top - Bottom
= x2 - 0
= x2
𝑉 = π න
𝑎
𝑏
(𝑟𝑜 𝑢𝑡)2
− (𝑟𝑖𝑛)2
𝑑𝑥
𝑉 = π න
0
1
(𝑥)2 − (𝑥2)2 𝑑𝑥
𝑉 = π න
0
1
𝑥2
− 𝑥4
𝑑𝑥
𝑉 = π
𝑥3
3
−
𝑥5
5
1
0
𝑉 = π
𝑥3
3
−
𝑥5
5
1
0
𝑉 = π
1
3
−
1
5
− 0
𝑉 = π
2
15
𝑉 =
2π
15
unit 3
𝑉 = 2π න
𝑎
𝑏
𝑥𝑦 𝑑𝑥
𝑉 = 2π න
𝑎
𝑏
𝑥𝑦 𝑑𝑦
Find the volume of the solid obtained by rotating about the x−axis
the region under the curve y = √x from 0 to 1.
Find the volume of the solid obtained by rotating about the x−axis
the region under the curve y = √x from 0 to 1.
𝑉 = 2π න
𝑎
𝑏
𝑥𝑦 𝑑𝑥 𝑉 = 2π න
𝑎
𝑏
𝑥𝑦 𝑑𝑦
radius
height
y
1
y2 1-y2
y = x → x =y2
Radius : y
Height: 1-y2
π
2
unit 3
Find the volume of the solid obtained by rotating about the x−axis
the region under the curve y = √x from 0 to 1.
Radius : y
Height : 1-y2
𝑉 = 2π න
𝑎
𝑏
𝑥𝑦 𝑑𝑦
𝑉 = 2π න
𝑎
𝑏
𝑥𝑦 𝑑𝑦
𝑉 = 2π න
0
1
(𝑦)(1 − 𝑦2)𝑑𝑥
𝑉 = 2π න
0
1
(𝑦 − 𝑦3)𝑑𝑥
𝑉 = 2π
1
2
𝑦2 −
1
4
𝑦4 1
0
𝑉 = 2π
1
2
𝑦2 −
1
4
𝑦4 1
0
𝑉 = 2π
1
4
− 0
𝑉 =
Find the volume of the solid obtained by rotating about the x−axis
the region under the curve y = √x from 0 to 1.
Radius = Top - Bottom
= √x - 0
= √x
𝑉 = න
𝑎
𝑏
𝐴 𝑥 𝑑𝑥
𝑉 = 𝑉 = න
𝑎
𝑏
π𝑟2 𝑑𝑥
𝑉 = න
0
1
π( 𝑥)2
𝑑𝑥
𝑉 = π න
0
1
𝑥 𝑑𝑥
𝑉 = π
𝑥2
2
1
0
𝑉 = π
12
2
− 0
𝑉 =
π
2
unit 3
The region by the curves y = x and y = x2, is rotated about
the x-axis. Find the volume of the rotating solid
The region by the curves y = x and y = x2, is rotated about
the x-axis. Find the volume of the rotating solid
𝑉 = 2π න
𝑎
𝑏
𝑥𝑦 𝑑𝑦
radius
height
y = x → x = y
y = x2 → x =√y
y
Radius: y
Height: √y − y
y
√y
Height = Right - Left
= √y − y
The region by the curves y = x and y = x2, is rotated about
the x-axis. Find the volume of the rotating solid
𝑉 = 2π න
𝑎
𝑏
𝑥𝑦 𝑑𝑦
𝑉 = 2π න
0
1
(𝑦)(√𝑦 − 𝑦)𝑑𝑦
𝑉 = 2π න
0
1
(𝑦
3
2 − 𝑦2)𝑑𝑦
𝑉 = 2π
2
5
𝑦
5
2 −
1
3
𝑦3 1
0
2π
15
unit 3
𝑉 = 2π
2
5
𝑦
5
2 −
1
3
𝑦3 1
0
𝑉 = 2π
2
5
−
1
3
− 0
𝑉 = 2π
1
15
𝑉 =
Radius: y
Height: √y − y
The region by the curves y = x and y = x2, is rotated about
the x-axis. Find the volume of the rotating solid
Rout = Top - Bottom
= x - 0
= x
Rin = Top - Bottom
= x2 - 0
= x2
𝑉 = π න
𝑎
𝑏
(𝑟𝑜 𝑢𝑡)2
− (𝑟𝑖𝑛)2
𝑑𝑥
𝑉 = π න
0
1
(𝑥)2 − (𝑥2)2 𝑑𝑥
𝑉 = π න
0
1
𝑥2
− 𝑥4
𝑑𝑥
𝑉 = π
𝑥3
3
−
𝑥5
5
1
0
𝑉 = π
𝑥3
3
−
𝑥5
5
1
0
𝑉 = π
1
3
−
1
5
− 0
𝑉 = π
2
15
𝑉 =
2π
15
unit 3
by: Maria Faith L. Dalay
Rotate the region bounded by y=√x, y=3 and the
y-axis about the y-axis.
Rotate the region bounded by x = y2 – 6y +10 and
x = 5 about the y-axis.
1
2
Exercises:

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Volumes of solid (slicing, disc, washer, cylindrical shell)

  • 1. “The goal in life is to be solid, whereas the way that life works is totally fluid, so you can never actually achieve that goal.” ~Damien Hirst by: Maria Faith L. Dalay
  • 2. Let “S” be a solid that lies between x = a and x = b, if the cross-sectional area of “S” in the plane P(x) through x and perpendicular to the axis is A(x) then, 𝑉 = න 𝑎 𝑏 𝐴 𝑥 𝑑𝑥
  • 3.
  • 4. Methods of finding the volume 1.Disc Method 2.Washer Method 3.Cylindrical/Shell Method 3
  • 5. This method is useful when the axis of rotation is part of the boundary of the plane area.
  • 6. Useful when the axis of rotation is not a part of the boundary of the plane area
  • 8. Find the volume of the solid obtained by rotating about the x−axis the region under the curve y = √x from 0 to 1.
  • 9. Find the volume of the solid obtained by rotating about the x−axis the region under the curve y = √x from 0 to 1. Radius = Top - Bottom = √x - 0 = √x Area of a circle = πr2
  • 10. Find the volume of the solid obtained by rotating about the x−axis the region under the curve y = √x from 0 to 1. Radius = Top - Bottom = √x - 0 = √x 𝑉 = න 𝑎 𝑏 𝐴 𝑥 𝑑𝑥 𝑉 = න 𝑎 𝑏 𝐴𝑟𝑒𝑎 𝑜𝑓 𝑎 𝑐𝑖𝑟𝑐𝑙𝑒 𝑑𝑥 𝑉 = න 𝑎 𝑏 π𝑟2 𝑑𝑥 𝑉 = න 0 1 π( 𝑥)2 𝑑𝑥 𝑉 = π න 0 1 𝑥 𝑑𝑥 𝑉 = π 𝑥2 2 1 0 𝑉 = π 12 2 − 0 𝑉 = π 2 unit 3
  • 11. Find the volume of the solid obtained by rotating the region bounded by y = x3, y=8, y=0 about the y-axis.
  • 12. Find the volume of the solid obtained by rotating the region bounded by y = x3, y=8, y=0 about the y-axis. y = x3 → x = ∛y Radius = Right - Left = ∛y - 0 = ∛y
  • 13. Find the volume of the solid obtained by rotating the region bounded by y = x3, y=8, y=0 about the y-axis. y = x3 → x = ∛y Radius = Right – Left = ∛y – 0 = ∛y 𝑉 = න 𝑎 𝑏 (𝐴𝑟𝑒𝑎) 𝑑𝑦 𝑉 = න 𝑎 𝑏 π𝑟2 𝑑𝑦 𝑉 = න 0 8 π(∛y)2 𝑑𝑦 𝑉 = π න 0 8 (𝑦 2 3) 𝑑𝑦 𝑉 = π [ 3 5 𝑦 5 3] 8 0 𝑉 = 96π 5 unit 3
  • 14. 𝑉 = π න 𝑎 𝑏 𝑟2 𝑑𝑥
  • 15. 𝑉 = π න 𝑎 𝑏 (𝑟𝑜 𝑢𝑡)2 − (𝑟𝑖𝑛)2 𝑑𝑥
  • 16. The region by the curves y = x and y = x2, is rotated about the x-axis. Find the volume of the rotating solid
  • 17. The region by the curves y = x and y = x2, is rotated about the x-axis. Find the volume of the rotating solid Rout = Top - Bottom = x - 0 = x Rin = Top - Bottom = x2 - 0 = x2
  • 18. The region by the curves y = x and y = x2, is rotated about the x-axis. Find the volume of the rotating solid Rout = Top - Bottom = x - 0 = x Rin = Top - Bottom = x2 - 0 = x2 𝑉 = π න 𝑎 𝑏 (𝑟𝑜 𝑢𝑡)2 − (𝑟𝑖𝑛)2 𝑑𝑥 𝑉 = π න 0 1 (𝑥)2 − (𝑥2)2 𝑑𝑥 𝑉 = π න 0 1 𝑥2 − 𝑥4 𝑑𝑥 𝑉 = π 𝑥3 3 − 𝑥5 5 1 0 𝑉 = π 𝑥3 3 − 𝑥5 5 1 0 𝑉 = π 1 3 − 1 5 − 0 𝑉 = π 2 15 𝑉 = 2π 15 unit 3
  • 19. 𝑉 = 2π න 𝑎 𝑏 𝑥𝑦 𝑑𝑥 𝑉 = 2π න 𝑎 𝑏 𝑥𝑦 𝑑𝑦
  • 20. Find the volume of the solid obtained by rotating about the x−axis the region under the curve y = √x from 0 to 1.
  • 21. Find the volume of the solid obtained by rotating about the x−axis the region under the curve y = √x from 0 to 1. 𝑉 = 2π න 𝑎 𝑏 𝑥𝑦 𝑑𝑥 𝑉 = 2π න 𝑎 𝑏 𝑥𝑦 𝑑𝑦 radius height y 1 y2 1-y2 y = x → x =y2 Radius : y Height: 1-y2
  • 22. π 2 unit 3 Find the volume of the solid obtained by rotating about the x−axis the region under the curve y = √x from 0 to 1. Radius : y Height : 1-y2 𝑉 = 2π න 𝑎 𝑏 𝑥𝑦 𝑑𝑦 𝑉 = 2π න 𝑎 𝑏 𝑥𝑦 𝑑𝑦 𝑉 = 2π න 0 1 (𝑦)(1 − 𝑦2)𝑑𝑥 𝑉 = 2π න 0 1 (𝑦 − 𝑦3)𝑑𝑥 𝑉 = 2π 1 2 𝑦2 − 1 4 𝑦4 1 0 𝑉 = 2π 1 2 𝑦2 − 1 4 𝑦4 1 0 𝑉 = 2π 1 4 − 0 𝑉 =
  • 23. Find the volume of the solid obtained by rotating about the x−axis the region under the curve y = √x from 0 to 1. Radius = Top - Bottom = √x - 0 = √x 𝑉 = න 𝑎 𝑏 𝐴 𝑥 𝑑𝑥 𝑉 = 𝑉 = න 𝑎 𝑏 π𝑟2 𝑑𝑥 𝑉 = න 0 1 π( 𝑥)2 𝑑𝑥 𝑉 = π න 0 1 𝑥 𝑑𝑥 𝑉 = π 𝑥2 2 1 0 𝑉 = π 12 2 − 0 𝑉 = π 2 unit 3
  • 24. The region by the curves y = x and y = x2, is rotated about the x-axis. Find the volume of the rotating solid
  • 25. The region by the curves y = x and y = x2, is rotated about the x-axis. Find the volume of the rotating solid 𝑉 = 2π න 𝑎 𝑏 𝑥𝑦 𝑑𝑦 radius height y = x → x = y y = x2 → x =√y y Radius: y Height: √y − y y √y Height = Right - Left = √y − y
  • 26. The region by the curves y = x and y = x2, is rotated about the x-axis. Find the volume of the rotating solid 𝑉 = 2π න 𝑎 𝑏 𝑥𝑦 𝑑𝑦 𝑉 = 2π න 0 1 (𝑦)(√𝑦 − 𝑦)𝑑𝑦 𝑉 = 2π න 0 1 (𝑦 3 2 − 𝑦2)𝑑𝑦 𝑉 = 2π 2 5 𝑦 5 2 − 1 3 𝑦3 1 0 2π 15 unit 3 𝑉 = 2π 2 5 𝑦 5 2 − 1 3 𝑦3 1 0 𝑉 = 2π 2 5 − 1 3 − 0 𝑉 = 2π 1 15 𝑉 = Radius: y Height: √y − y
  • 27. The region by the curves y = x and y = x2, is rotated about the x-axis. Find the volume of the rotating solid Rout = Top - Bottom = x - 0 = x Rin = Top - Bottom = x2 - 0 = x2 𝑉 = π න 𝑎 𝑏 (𝑟𝑜 𝑢𝑡)2 − (𝑟𝑖𝑛)2 𝑑𝑥 𝑉 = π න 0 1 (𝑥)2 − (𝑥2)2 𝑑𝑥 𝑉 = π න 0 1 𝑥2 − 𝑥4 𝑑𝑥 𝑉 = π 𝑥3 3 − 𝑥5 5 1 0 𝑉 = π 𝑥3 3 − 𝑥5 5 1 0 𝑉 = π 1 3 − 1 5 − 0 𝑉 = π 2 15 𝑉 = 2π 15 unit 3
  • 28. by: Maria Faith L. Dalay
  • 29. Rotate the region bounded by y=√x, y=3 and the y-axis about the y-axis. Rotate the region bounded by x = y2 – 6y +10 and x = 5 about the y-axis. 1 2 Exercises: