The presentation explains various Vedic math techniques that can be used for simplified manual calculations. It is a must learn mathematics technique for young students for better calculations.
ملزمة الرياضيات للصف السادس الاحيائي الفصل الثاني القطوع المخروطية 2022 anasKhalaf4
طبعة جديدة ومنقحة
حل تمارين الكتاب
شرح المواضيع الرياضية بالتفصيل وبأسلوب واضح ومفهوم لجميع المستويات
حلول الاسألة الوزارية
اعداد الدكتور أنس ذياب خلف
email: anasdhyiab@gmail.com
ملزمة الرياضيات للصف السادس الاحيائي الفصل الثاني القطوع المخروطية 2022 anasKhalaf4
طبعة جديدة ومنقحة
حل تمارين الكتاب
شرح المواضيع الرياضية بالتفصيل وبأسلوب واضح ومفهوم لجميع المستويات
حلول الاسألة الوزارية
اعداد الدكتور أنس ذياب خلف
email: anasdhyiab@gmail.com
More companies in the process of recruitment, play more emphasis in the topic of numbers in numerical aptitude. Especially for AMCAT aspirants this is very much useful.
The presentation tells about all the aspects that led to the great economic depression in 1929. All the historical, financial and other factors are looked upon with the help of online available data.
The presentation tells about the concept of lean logistics in the field of lean management. One can easily understand the full concept of lean logistics going though the slides of the presentation.
We all have good and bad thoughts from time to time and situation to situation. We are bombarded daily with spiraling thoughts(both negative and positive) creating all-consuming feel , making us difficult to manage with associated suffering. Good thoughts are like our Mob Signal (Positive thought) amidst noise(negative thought) in the atmosphere. Negative thoughts like noise outweigh positive thoughts. These thoughts often create unwanted confusion, trouble, stress and frustration in our mind as well as chaos in our physical world. Negative thoughts are also known as “distorted thinking”.
How to Create Map Views in the Odoo 17 ERPCeline George
The map views are useful for providing a geographical representation of data. They allow users to visualize and analyze the data in a more intuitive manner.
Ethnobotany and Ethnopharmacology:
Ethnobotany in herbal drug evaluation,
Impact of Ethnobotany in traditional medicine,
New development in herbals,
Bio-prospecting tools for drug discovery,
Role of Ethnopharmacology in drug evaluation,
Reverse Pharmacology.
2024.06.01 Introducing a competency framework for languag learning materials ...Sandy Millin
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
The Art Pastor's Guide to Sabbath | Steve ThomasonSteve Thomason
What is the purpose of the Sabbath Law in the Torah. It is interesting to compare how the context of the law shifts from Exodus to Deuteronomy. Who gets to rest, and why?
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
Operation “Blue Star” is the only event in the history of Independent India where the state went into war with its own people. Even after about 40 years it is not clear if it was culmination of states anger over people of the region, a political game of power or start of dictatorial chapter in the democratic setup.
The people of Punjab felt alienated from main stream due to denial of their just demands during a long democratic struggle since independence. As it happen all over the word, it led to militant struggle with great loss of lives of military, police and civilian personnel. Killing of Indira Gandhi and massacre of innocent Sikhs in Delhi and other India cities was also associated with this movement.
The Indian economy is classified into different sectors to simplify the analysis and understanding of economic activities. For Class 10, it's essential to grasp the sectors of the Indian economy, understand their characteristics, and recognize their importance. This guide will provide detailed notes on the Sectors of the Indian Economy Class 10, using specific long-tail keywords to enhance comprehension.
For more information, visit-www.vavaclasses.com
How to Split Bills in the Odoo 17 POS ModuleCeline George
Bills have a main role in point of sale procedure. It will help to track sales, handling payments and giving receipts to customers. Bill splitting also has an important role in POS. For example, If some friends come together for dinner and if they want to divide the bill then it is possible by POS bill splitting. This slide will show how to split bills in odoo 17 POS.
3. 6 5 9 6 x 11
7 2 5 5 6
6
w
r
i
t
t
e
n
a
s
i
t
i
s
9
+
6
=
1
5
9
+
5
+
1
=
1
5
6
+
5
+
1
=
1
2
6
+
1
=
7
Start the calculation from
one's digit of the answer*
7. 1 3 2 4 3 x 12
1 5 8 9 1 6
3
x
2
(
4
x
2
)
+
3
=
1
1
(
2
x
2
)
+
4
+
1
=
9
(
3
x
2
)
+
2
=
8
(
1
x
2
)
+
3
=
5
F
i
r
s
t
D
i
g
i
t
a
s
i
t
i
s
Start the calculation from
one's digit of the answer*
11. 14 x 18
18 + 4 = 22
22 x 10 = 220
4 x 8 = 32
220 + 32 = 252
Adding larger number to one's
digit of smaller number
Multiplying one's digit of both
numbers
28. 341 / 9
10
-9
1
Splitting 341 as
34 (quotient
part) and 1
(remainder part)
(nearest
power of 10)
3 4 | 1
3 7
3 7 | 8
As
it
is
Multiply 3 with the
deficiency and write below 4
and add; Repeat same step
with the addition result, i.e.
7
Quotient Remainder
30. 432 / 11
10
-11
1
Splitting 432 as
43 (quotient
part) and 2
(remainder part)
(nearest
power of 10)
4 3 | 2
4 1
4 1 | 3
As
it
is
Multiply 4 with the
deficiency and write below 3
and add; Repeat same step
with the addition result, i.e.
-1 or 1bar
Quotient Remainder
4 1 = 40 - 1 = 39
31. Division when the divisor is
not closer to the power of 10
and it is a two digit number
32. 1011 / 23
Splitting 1011 as
10 (quotient
part) and 11
(remainder part)
1 0 | 1 1
8
1 0 | 9 1
As
it
is
0
0 0
23 x 4 = 92
x4
4 0 | 9 1
91 = 3 x 23 + 22
100-92 = 08
As divisor is a 2
digit number, we
will write the
difference as 08
Final Quotient = 43
Final Remainder = 22
As 91> 23
55. 10000 - 8697
9-8=1 9-6=3 9-9=0 10-7=3
Subtract every digit of the
subtrahend (number being
subtracted) from 9 but the
one’s digit from 10
1303
56. Subtraction when subtrahend
is less than minuend (number
from which subtrahend is
being subtracted) but both
have equal digits
57. 3625 - 1789
9-1=8 9-7=2 9-8=1 10-9=1
Subtract the subtrahend from
the next nearest power of 10
rule
8211 + 3625 = 11863
Add the result to the
minuend (number
from which
subtrahend is being
subtracted)
1863
Removing
the
first
digit
59. 45827 - 398
Subtract the subtrahend from
the next nearest power of 10
rule
Add the result to the
minuend (number
from which
subtrahend is being
subtracted)
45429
Rem
oving
the first digit
0 0 3 9 8
9-0=9 9-0=9 9-3=6 9-9=0
10-8=2
Making the digits of subtrahend
equal to minuend
99602+45827=145429
61. 351- 497
9-3=6 9-5=4 10-1=9
Subtract the minuend
from the next nearest
power of 10 rule
649 + 497 = 1146
Add the result to the
subtrahend
-146
Removing
the
first
digit
Putting
the
negative
sign
66. 46 x 46
46-50 = (-4)
46 + (-4) = 42
42 x 50 = 2100
(-4) x (-4) = 16
2116
Difference between number and the
nearest base
Add the difference to the number
Multiply the result to the base
Square of the
difference
Add both the results
69. 1221 x 1221
D(1)=1x1 = 1
D(12)= 2x1x2=4
D(122)=2x1x2+2x2=8
D(1221)= 2x1x1 + 2x2x2 = 10
D(221)= 2x2x1 + 2x2= 8
D(21)= 2x2x1 = 4
D(1) = 1
14810841 1490841
Write the results of the D method calculation
from right to left and add the carry over
digits to get the final answer
71. 53 x 53 x 53 a = 5 ; b = 3
Using equation (a+b)
3
= a + a b + ab + b
3 3
2 2
2a b 2ab
+ +
2 2
= 125 75 25 27
+150 +90
125| 225|135| 27
125 | 225 | 137 | 7 125 | 238 | 7 | 7 148 | 8 | 7 | 7
write the result from right to left
and carry forward the extra
digits and add to the next
number which gives the final
answer
148877
73. 996 x 996 x 996
996-1000 = (-4)
996-8=988 (-12)x(-4)=048
(-4)x((-4)x(-4)=(-064)
1000-064=936
Finding the deficiency
Multiply
the
deficiency
with
2
and
add
to
the
number
Multiply
new
deficiency
(-12)
with
old
deficiency(-4)
,
which
gives
result
048
Equalling
the
number
of
digits
in
answer
to
the
number
of
0s
in
nearest
power
of
10
Cube
of
old
deficiency
and
then
transpoising
it
as
it
was
negative
988048936
75. Pre-Requisites for Square Root
1). Squares of numbers from 1 to 9 are 1, 4, 9, 16, 25, 36, 49, 64, 81, and 100.
2). Square of a number cannot end with 2, 3, 7, and 8. OR number ending with 2 ,
3, 7 and 8 cannot have perfect square root.
3). Square root of a number ending with 1 (1, 81) ends with either 1 or 9 (10’s
compliment of each other).
4). Square root of a number ending with 4 (4, 64) ends with either 2 or 8 (10’s
compliment of each other).
5). Square root of a number ending with 9 (9, 49) ends with either 3 or 7 (10’s
compliment of each other).
6). Square root of a number ending with 6 (16, 36) ends with either 4 or 6 (10’s
compliment of each other).
7). If number is of ‘n’ digits then square root will be ‘n/2’ when n is even OR ‘(n+1)/2’
digits when n is odd.
76. Find the nearest perfect square root of
the left most pair (73) which is 8, To the
left of first vertical line, write 8 and add
same to it. Below 73, write the same
square root (8) and write the carry
forward of difference of the actual
number (73) and the square(64), i.e. 9
Square root of 732108
Group the digits of the number in pair of
2 starting from right to left which makes
the pair
73 | 21 | 08
77. Calculate D of the number present
after the second vertical line, i.e.
D(5)=25. Subtract this D from the
highlighted 121 which gives 96. Now
divide this 96 from 16 which gives
quotient as 6 and remainder as 0.
Write the quotient below and carry
forward the remainder.
Now divide the highlighted 92 by the
obtained 16. Write the quotient (5)
below and carry forward the remainder
(12).
78. Now we again calculate D of the numbers
present after the vertical line, i.e. D(56)=
60. Now subtract this from the highlighted
00 which gives a negative number (-60).
Thus, we change the quotient and
remainder we got from the previous step.
We will take quotient as 5 and remainder
as 16. (Dividing 96 by 16, we will take one
lesser number than 6).
79. Calculate D of the number
present after the second vertical
line, i.e. D(55)=50. Subtract this D
from the highlighted 160 which
gives 110. Now divide this 110
from 16 which gives quotient as 6
and remainder as 14. Write the
quotient below and carry forward
the remainder.
This process can be continued as long as required. Since the given number 732108
has even(6) digits, its square root will have n/2 = 6/2 = 3 digits. Thus our final
answer, i.e. square root of 732108 comes out to be
855.6
81. Pre-Requisities for the cube root of a
perfect cube
To find the unit place of the cube root always remember
the following points:
1). If the last digit of the number is 8 then the unit digit will be 2.
2). If the last digit of the number is 2 then the unit digit will be 8.
3). If the last digit of the number is 3 then the unit digit will be 7.
4). If the last digit of the number is 7 then the unit digit will be 3.
5). If the last digit of the number is other than 2, 3, 7 and 8 then
put the same number as the unit digit.
82. Cube root of 39304
As the number ends with
4, the ones digit of the
cube root will also be
4
Strike off last 3 digits
39
27
Nearest
Perfect
Cube
3
Cube
Root
(Tens Digit of the cube root)
34
84. Digital Root of 45769486
4+5+7+6+9+4+8+6 = 49
4+9 = 13
1+3 =
Add up the digits
As the result is not a single digit number,
repeat the process with the result
As the result is not a single digit number,
repeat the process with the result
4
86. The area of the square drawn on the
diagonal (considering it as one of the
sides) of a rectangle (ABCD) is equal
to the sum of the areas of the
square drawn separately on its
breadth (considering it as one of the
sides) and on its length(considering
it as one of the sides).
Area of DBFE = Area ABPQ + Area ADYX
(DB) = (AB) + (AD)
2 2 2
Now comparing the above equation for
the right triangle DAB
(Hypotenuse) = (Side) + (Side)
2 2 2
88. Pre-Requisities for Pythagorean Triples
The integer solutions to the Pythagorean Theorem, a + b = c are called
Pythagorean Triples which contains three positive integers a, b, and c, where
the biggest number is c and other two are a and b
Example: (3, 4, 5)
By evaluating we get:
3 + 4 = 5
9+16 = 25
Hence, 3,4 and 5 are
the Pythagorean triples.
2 2 2
2 2 2
89. Method1: Every odd number is the a side of a Pythagorean triplet and the b
side of a Pythagorean triplet is simply (a – 1)/2. c is calculated by adding the
square of a and b
2
92. Convert 0.45 to a fraction
Number of digits after
the decimal is 2 (i.e. 4
and 5) thus, our
denominator will have
these many number
of 9s, i.e. 99
Our numerator will be the
number recurring, i.e. 45
45
99
94. 1 / 19
The new divisor will be =(1+ the
digit before 9)
i.e. (1+1)= 2
1/2
Quotient 0, Remainder 1
Write remainder in subscript before the quotient
0. 1
0
10/2 Using previous step results as new dividend; i.e. 10
Quotient 5, Remainder 0
0. 1
0 5
5/2 Using previous step results as new dividend; i.e. 05
Quotient 2, Remainder 1
0. 0 5 2
1 1
Continue the above procedure till we get remainder 0 and quotient as we started the
calculation from 01, and the final result comes out to be
0. 052631578947368421
96. Find x and y when
2x+3y=7 and 3x+4y=6
ax + by = e cx + dy = f
a=2, b=3, c=3, d=4, e=7, f=6
x =
bf - de
bc - ad
(3∗6)-(4∗7)
(3∗3)-(4∗2)
18-28
9-8
-10
= = =
y =
af - ce
ae - bd
(2∗6)-(3∗7)
(2∗4)-(3∗3)
12-21
8-9
= = = 9
97. Area of a triangle when its co-
ordinates are given
98. A= (4,1) , B= (5,3), C=(7,3)
Let A be the origin or centre position
B - A = (1 , 2) C - A = (3 , 2)
Difference of other co-ordinates
from the origin
1 2
3 2
Matrix of the distance co-ordinates
|(1x2) - (2x3)| = 4
Determinant of
the matrix
Divide by 2 to get the final answer
4/2 = 2 sq. units
