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Real Numbers
Rational Number
A rational number can be made by dividing two integers.
Given that π‘Ž and 𝑏 are two integers, then π‘Ž
𝑏
is a rational number.
π‘Ž
𝑏
numerator
denominator
Writing fractions as decimals
Rational numbers are commonly referred to as fractions. A fraction can
be written as a decimal by dividing the numerator by the denominator.
For example,
2
5
can be written as a decimal by dividing 2 by 5 as follows:
25
0
.
.
0
4
.02
Hence,
2
5
= 0.4
From the preciously given method, the following fractions can be
written into decimals as follow:
3
2
= 1.5
4
25
= 0.16
19
20
= 0.95
21
8
= 2.625
1
3
is written as a decimal by dividing 1 by 3 as follows:
13
0
.
.
0
3
9
1
0
0
9
1
3
0
0
3
9
1
0
0
3
9
1
…
From the above, if we repeatedly divide by 3, we will get
1
3
= 0.3333…
Using the shown method, we can write the following fractions in terms
of decimals as follow:
7
9
= 0.777 …
16
45
= 0.3555…
171
99
= 1.7272 …
9
37
= 0.243243243 …
3
7
= 0.428571428571 …
Repeating decimals
= 0. 7
zero point seven,
seven repeating
= 0. 35
zero point three five,
five repeating
= 1. 72
one point seven two,
seven two repeating
= 0. 243
zero point two four three,
two four three repeating
= 0. 428571
zero point four two eight five seven one,
four two eight five seven one repeating
Case 1: If there is one repeated digit, write βˆ™ above that digit such as
0.5888… = 0.58
Case 2: If there are two or more repeated digits, writeβˆ™ above the firstβˆ™
repeated digit and the last repeated digit such as
1.8383… = 1. 83
2.0367367… = 2.0367
4.2583198319… = 4.258319
Any decimals, such as 1.5 and 2.83, are repeating decimals because
1.5 = 1.5000… and 2.83 = 83000… are called zero repeating
decimals.
Writing repeating decimals as fractions
Case 1. Zero Repeating Decimals
1 3 6 . 4 2 7
integer part
decimal point
decimal part
Place Value
Integer Decimal
… Hundreds Tens Ones Tenths Hundredths Thousandths Ten-thousandths …
… 102 10 1 1
10
1
102
1
103
1
104
…
The number 136.427 can be written in the expanded form as follows:
136 . 427
1 is in the hundreds place 1 Γ— 102
3 is in the tens place 3 Γ— 10
6 is in the ones place 6 Γ— 1
4 is in the tenths place 4 Γ—
1
10
2 is in the hundredths place 2 Γ—
1
102
7 is in the thousandths place 7 Γ—
1
103
= 1 Γ— 102
+ 3 Γ— 10 + 6 Γ— 1 + 4 Γ—
1
10
+ 2 Γ—
1
102
+ 7 Γ—
1
103
Write the following numbers in the expanded form:
1) 125.2
2) 28.313
3) 0.576
= 1 Γ— 102 + 2 Γ— 10 + 5 Γ— 1 + 2 Γ—
1
10
= 2 Γ— 10 + 8 Γ— 1 + 3 Γ—
1
10
+ 1 Γ—
1
102
+ 3 Γ—
1
103
= 5 Γ—
1
10
+ 7 Γ—
1
102
+ 6 Γ—
1
103
The number 0.37 can be converted into fraction as follows:
0.37 = 3 Γ—
1
10
+ 7 Γ—
1
102
=
3
10
+
7
100
=
30
100
+
7
100
=
37
100
Write the following numbers as fractions.
1) 0.5
2) 3.25
= 5 Γ—
1
10
=
5
10
=
1
2
= 3 Γ— 1 + 2 Γ—
1
10
+ 5 Γ—
1
102
= 3 +
2
10
+
5
100
=
300
100
+
20
100
+
5
100
=
325
100
Write the following numbers as fractions.
3) 12.379 = 1 Γ— 10 + 2 Γ— 1 + 3 Γ—
1
10
+ 7 Γ—
1
102 + 9 Γ—
1
103
= 10 + 2 +
3
10
+
7
100
+
9
1000
=
10000
1000
+
2000
1000
+
300
1000
+
70
1000
+
9
1000
=
12379
1000
Write the following numbers as fractions.
1) 0.5
2) 3.25
= 5 Γ—
1
10
=
5
10
=
1
2
= 3 Γ— 1 + 2 Γ—
1
10
+ 5 Γ—
1
102
= 3 +
2
10
+
5
100
=
300
100
+
20
100
+
5
100
=
325
100
0.5 is a decimal with one decimal place. When
it is written as fraction, the numerator is equal
to the same number without the point and the
denominator is 10.
3.25 is a decimal with two decimal
places. When it is written as
fraction, the numerator is equal to
the same number without the point
and the denominator is 100.
Write the following numbers as fractions.
0.8
0.37
1.382
2.2545
= 8
10
= 37
100
= 1382
1000
= 6951
500
= 22545
10000
= 4509
2000
Write the following numbers as fractions.
1. 3.7
2. 4.82
= 37
10
= 482
100
= 241
50
3. 0.1257 = 1257
10000
Writing repeating decimals as fractions
Case 2. Non-zero Repeating Decimals
Repeating decimals that are not zero repeating decimals can be
converted into fractions as follow:
1. Write 0.7 as a fraction.
Let 𝑁 = 0. 7 = 0.777 … (1)
Multiply both sides of equation (1) by 10
10𝑁 = 7.777 … (2)
From equations (2) and (1), we have,
10𝑁 βˆ’ 𝑁 = 7.777 … βˆ’ (0.777 … )
7.777…
0.777…
7.000…
9𝑁 = 7
𝑁 =
7
9
0. 7 =
7
9
0. 7 is a repeating decimal with one
digit repeated from the first
decimal place. The number used for
multiplication is 10.
2. Write 0.42 as a fraction.
Let 𝑁 = 0. 42 = 0.4242 … (1)
Multiply both sides of equation (1) by 10
10𝑁 = 7.777 … (2)
From equations (2) and (1), we have,
10𝑁 βˆ’ 𝑁 = 4.2422 … βˆ’ (0.4242 … )
The difference is complicated and
cannot be written as a fraction easily.
Multiply both sides of equation (1) by 100
100𝑁 = 42.4242 … (3)
From equations (3) and (1), we have,
100𝑁 βˆ’ 𝑁 = 42.4242 … βˆ’ (0.4242 … )
42.4242…
0.4242…
42.0000…
99𝑁 = 42
𝑁 =
42
99
0. 42 =
42
99
=
14
33
0. 42 is a repeating decimal with
two digits repeated from the first
decimal place. The number used for
multiplication is 100.
3. Write 0.348 as a fraction.
Let 𝑁 = 0.348 = 0.348348 … (1)
Multiply both sides of equation (1) by 10
10𝑁 = 3.48348 … (2)
From equations (2) and (1), we have,
10𝑁 βˆ’ 𝑁 = 3.483483 … βˆ’ (0.348348 … )
The difference is complicated and cannot be
written as a fraction easily.
Multiply both sides of equation (1) by 100
100𝑁 = 34.8348 … (3)
From equations (3) and (1), we have,
100𝑁 βˆ’ 𝑁 = 34.834834 … βˆ’ (0.348348 … )
The difference is complicated and cannot be
written as a fraction easily.
Multiply both sides of equation (1) by 1000
1000𝑁 = 348.348348 … (4)
From equations (4) and (1), we have,
1000𝑁 βˆ’ 𝑁 = 348.348348 … βˆ’ (0.348348 … )
348.348348…
0.348348…
348.000000…
999𝑁 = 348
𝑁 =
348
999
0.348 =
348
999
=
116
333
0.348 is a repeating decimal with
three digits repeated from the first
decimal place. The number used for
multiplication is 1000.
0. 7 is converted into a fraction as
7
9
.
That is, if there is a repeating decimal with one digit repeated from the
first decimal place, when it is written as a fraction, the denominator is 9
and the numerator is the repeated digit.
0. 42 is converted into a fraction as
42
99
.
That is, if there is a repeating decimal with two digits repeated from the
first decimal place, when it is written as a fraction, the denominator is 99
and the numerator are the repeated digits.
0. 348 is converted into a fraction as
348
999
.
That is, if there is a repeating decimal with three digits repeated from the
first decimal place, when it is written as a fraction, the denominator is 999
and the numerator are the repeated digits.
From the previous method, the repeating decimals with non-zero
repeating digits can be written as fractions as follow:
0.2
0. 27
=
2
9
=
27
99
=
3
11
3.5
1. 257
= 3
5
9
= 1
257
999
Write the following repeating decimals as fractions.
1. 0.3
2. 0. 12
3. 0. 175
4. 1.6
5. 2. 163
6. 10.25
=
3
9
=
1
3
=
12
99
=
4
33
=
175
999
= 1
6
9
= 1
2
3
= 2
163
999
= 10
25
99
4. Write 0.62 as a fraction.
Let 𝑁 = 0.62 = 0.6222 … (1)
Multiply both sides of equation (1) by 10
10𝑁 = 6.222 … (2)
Multiply both sides of equation (1) by 100
100𝑁 = 62.222 … (3)
From equations (3) and (2), we have,
100𝑁 βˆ’ 10𝑁 = 62.222 … βˆ’ (6.222 …)
90𝑁 = 56
𝑁 =
56
90
5. Write 0.637 as a fraction.
Let 𝑁 = 0.637 = 0.63777 … (1)
Multiply both sides of equation (1) by 100
100𝑁 = 63.777 … (2)
Multiply both sides of equation (1) by 1000
1000𝑁 = 637.777 … (3)
From equations (3) and (2), we have,
1000𝑁 βˆ’ 100𝑁 = 637.777 … βˆ’ (63.777 …)
900𝑁 = 574
𝑁 =
574
900
=
287
450
6. Write 0.625 as a fraction.
Let 𝑁 = 0.625 = 0.62525 … (1)
Multiply both sides of equation (1) by 10
10𝑁 = 6.2525 … (2)
Multiply both sides of equation (1) by 1000
1000𝑁 = 625.2525 … (3)
From equations (3) and (2), we have,
1000𝑁 βˆ’ 10𝑁 = 625.2525 … βˆ’ (6.2525 …)
990𝑁 = 619
𝑁 =
619
990
625 βˆ’ 6
990
637 βˆ’ 63
900
From example 5, write 0.637 as a fraction.
62 βˆ’ 6
90
From example 4, write 0.62 as a fraction.
We have
56
90
=
Observe that the subtrahend is 6 which
is the digit that is not repeated
It is found that there is one 9 when
there is only one digit that is repeated
It is found that there is only one 0 when
there is only one digit that is not repeated
We have
574
900
=
Observe that the subtrahend is 63
which is the digit that is not repeated
It is found that there is one 9 when
there is only one digit that is repeated
It is found that there are two 0s when
there are two digits that are not repeated
From example 6, write 0.625 as a fraction.
We have
619
990
=
Observe that the subtrahend is 6 which
is the digit that is not repeated
It is found that there are two 9s when
there are two digits that are repeated
It is found that there is only one 0 when
there is only one digit that is not repeated
Write the following repeating decimals as fractions.
0.74 =
74 βˆ’ 7
90
=
67
90
0.234 =
234 βˆ’ 23
900
=
211
900
1.3642 = 1
3642 βˆ’ 36
9900
= 1
3606
9900
= 1
601
1650
Write the following repeating decimals as fractions.
0.63
0.572
0.572
1.34
2.237
3.534
=
63 βˆ’ 6
90
=
57
90
=
572 βˆ’ 57
900
=
515
900
=
572 βˆ’ 5
990
=
567
990
= 1
34 βˆ’ 3
90
= 1
31
90
= 2
237 βˆ’ 23
900
= 2
214
900
= 3
534 βˆ’ 4
990
= 3
529
990

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Rational numbers

  • 2. Rational Number A rational number can be made by dividing two integers. Given that π‘Ž and 𝑏 are two integers, then π‘Ž 𝑏 is a rational number. π‘Ž 𝑏 numerator denominator Writing fractions as decimals Rational numbers are commonly referred to as fractions. A fraction can be written as a decimal by dividing the numerator by the denominator. For example, 2 5 can be written as a decimal by dividing 2 by 5 as follows: 25 0 . . 0 4 .02 Hence, 2 5 = 0.4
  • 3. From the preciously given method, the following fractions can be written into decimals as follow: 3 2 = 1.5 4 25 = 0.16 19 20 = 0.95 21 8 = 2.625
  • 4. 1 3 is written as a decimal by dividing 1 by 3 as follows: 13 0 . . 0 3 9 1 0 0 9 1 3 0 0 3 9 1 0 0 3 9 1 … From the above, if we repeatedly divide by 3, we will get 1 3 = 0.3333…
  • 5. Using the shown method, we can write the following fractions in terms of decimals as follow: 7 9 = 0.777 … 16 45 = 0.3555… 171 99 = 1.7272 … 9 37 = 0.243243243 … 3 7 = 0.428571428571 … Repeating decimals = 0. 7 zero point seven, seven repeating = 0. 35 zero point three five, five repeating = 1. 72 one point seven two, seven two repeating = 0. 243 zero point two four three, two four three repeating = 0. 428571 zero point four two eight five seven one, four two eight five seven one repeating
  • 6. Case 1: If there is one repeated digit, write βˆ™ above that digit such as 0.5888… = 0.58 Case 2: If there are two or more repeated digits, writeβˆ™ above the firstβˆ™ repeated digit and the last repeated digit such as 1.8383… = 1. 83 2.0367367… = 2.0367 4.2583198319… = 4.258319
  • 7. Any decimals, such as 1.5 and 2.83, are repeating decimals because 1.5 = 1.5000… and 2.83 = 83000… are called zero repeating decimals.
  • 8. Writing repeating decimals as fractions Case 1. Zero Repeating Decimals 1 3 6 . 4 2 7 integer part decimal point decimal part Place Value Integer Decimal … Hundreds Tens Ones Tenths Hundredths Thousandths Ten-thousandths … … 102 10 1 1 10 1 102 1 103 1 104 …
  • 9. The number 136.427 can be written in the expanded form as follows: 136 . 427 1 is in the hundreds place 1 Γ— 102 3 is in the tens place 3 Γ— 10 6 is in the ones place 6 Γ— 1 4 is in the tenths place 4 Γ— 1 10 2 is in the hundredths place 2 Γ— 1 102 7 is in the thousandths place 7 Γ— 1 103 = 1 Γ— 102 + 3 Γ— 10 + 6 Γ— 1 + 4 Γ— 1 10 + 2 Γ— 1 102 + 7 Γ— 1 103
  • 10. Write the following numbers in the expanded form: 1) 125.2 2) 28.313 3) 0.576 = 1 Γ— 102 + 2 Γ— 10 + 5 Γ— 1 + 2 Γ— 1 10 = 2 Γ— 10 + 8 Γ— 1 + 3 Γ— 1 10 + 1 Γ— 1 102 + 3 Γ— 1 103 = 5 Γ— 1 10 + 7 Γ— 1 102 + 6 Γ— 1 103
  • 11. The number 0.37 can be converted into fraction as follows: 0.37 = 3 Γ— 1 10 + 7 Γ— 1 102 = 3 10 + 7 100 = 30 100 + 7 100 = 37 100
  • 12. Write the following numbers as fractions. 1) 0.5 2) 3.25 = 5 Γ— 1 10 = 5 10 = 1 2 = 3 Γ— 1 + 2 Γ— 1 10 + 5 Γ— 1 102 = 3 + 2 10 + 5 100 = 300 100 + 20 100 + 5 100 = 325 100
  • 13. Write the following numbers as fractions. 3) 12.379 = 1 Γ— 10 + 2 Γ— 1 + 3 Γ— 1 10 + 7 Γ— 1 102 + 9 Γ— 1 103 = 10 + 2 + 3 10 + 7 100 + 9 1000 = 10000 1000 + 2000 1000 + 300 1000 + 70 1000 + 9 1000 = 12379 1000
  • 14. Write the following numbers as fractions. 1) 0.5 2) 3.25 = 5 Γ— 1 10 = 5 10 = 1 2 = 3 Γ— 1 + 2 Γ— 1 10 + 5 Γ— 1 102 = 3 + 2 10 + 5 100 = 300 100 + 20 100 + 5 100 = 325 100 0.5 is a decimal with one decimal place. When it is written as fraction, the numerator is equal to the same number without the point and the denominator is 10. 3.25 is a decimal with two decimal places. When it is written as fraction, the numerator is equal to the same number without the point and the denominator is 100.
  • 15. Write the following numbers as fractions. 0.8 0.37 1.382 2.2545 = 8 10 = 37 100 = 1382 1000 = 6951 500 = 22545 10000 = 4509 2000
  • 16. Write the following numbers as fractions. 1. 3.7 2. 4.82 = 37 10 = 482 100 = 241 50 3. 0.1257 = 1257 10000
  • 17. Writing repeating decimals as fractions Case 2. Non-zero Repeating Decimals Repeating decimals that are not zero repeating decimals can be converted into fractions as follow: 1. Write 0.7 as a fraction. Let 𝑁 = 0. 7 = 0.777 … (1) Multiply both sides of equation (1) by 10 10𝑁 = 7.777 … (2) From equations (2) and (1), we have, 10𝑁 βˆ’ 𝑁 = 7.777 … βˆ’ (0.777 … ) 7.777… 0.777… 7.000… 9𝑁 = 7 𝑁 = 7 9 0. 7 = 7 9 0. 7 is a repeating decimal with one digit repeated from the first decimal place. The number used for multiplication is 10.
  • 18. 2. Write 0.42 as a fraction. Let 𝑁 = 0. 42 = 0.4242 … (1) Multiply both sides of equation (1) by 10 10𝑁 = 7.777 … (2) From equations (2) and (1), we have, 10𝑁 βˆ’ 𝑁 = 4.2422 … βˆ’ (0.4242 … ) The difference is complicated and cannot be written as a fraction easily. Multiply both sides of equation (1) by 100 100𝑁 = 42.4242 … (3) From equations (3) and (1), we have, 100𝑁 βˆ’ 𝑁 = 42.4242 … βˆ’ (0.4242 … ) 42.4242… 0.4242… 42.0000… 99𝑁 = 42 𝑁 = 42 99 0. 42 = 42 99 = 14 33 0. 42 is a repeating decimal with two digits repeated from the first decimal place. The number used for multiplication is 100.
  • 19. 3. Write 0.348 as a fraction. Let 𝑁 = 0.348 = 0.348348 … (1) Multiply both sides of equation (1) by 10 10𝑁 = 3.48348 … (2) From equations (2) and (1), we have, 10𝑁 βˆ’ 𝑁 = 3.483483 … βˆ’ (0.348348 … ) The difference is complicated and cannot be written as a fraction easily. Multiply both sides of equation (1) by 100 100𝑁 = 34.8348 … (3) From equations (3) and (1), we have, 100𝑁 βˆ’ 𝑁 = 34.834834 … βˆ’ (0.348348 … ) The difference is complicated and cannot be written as a fraction easily. Multiply both sides of equation (1) by 1000 1000𝑁 = 348.348348 … (4) From equations (4) and (1), we have, 1000𝑁 βˆ’ 𝑁 = 348.348348 … βˆ’ (0.348348 … ) 348.348348… 0.348348… 348.000000… 999𝑁 = 348 𝑁 = 348 999 0.348 = 348 999 = 116 333 0.348 is a repeating decimal with three digits repeated from the first decimal place. The number used for multiplication is 1000.
  • 20. 0. 7 is converted into a fraction as 7 9 . That is, if there is a repeating decimal with one digit repeated from the first decimal place, when it is written as a fraction, the denominator is 9 and the numerator is the repeated digit. 0. 42 is converted into a fraction as 42 99 . That is, if there is a repeating decimal with two digits repeated from the first decimal place, when it is written as a fraction, the denominator is 99 and the numerator are the repeated digits. 0. 348 is converted into a fraction as 348 999 . That is, if there is a repeating decimal with three digits repeated from the first decimal place, when it is written as a fraction, the denominator is 999 and the numerator are the repeated digits.
  • 21. From the previous method, the repeating decimals with non-zero repeating digits can be written as fractions as follow: 0.2 0. 27 = 2 9 = 27 99 = 3 11 3.5 1. 257 = 3 5 9 = 1 257 999
  • 22. Write the following repeating decimals as fractions. 1. 0.3 2. 0. 12 3. 0. 175 4. 1.6 5. 2. 163 6. 10.25 = 3 9 = 1 3 = 12 99 = 4 33 = 175 999 = 1 6 9 = 1 2 3 = 2 163 999 = 10 25 99
  • 23. 4. Write 0.62 as a fraction. Let 𝑁 = 0.62 = 0.6222 … (1) Multiply both sides of equation (1) by 10 10𝑁 = 6.222 … (2) Multiply both sides of equation (1) by 100 100𝑁 = 62.222 … (3) From equations (3) and (2), we have, 100𝑁 βˆ’ 10𝑁 = 62.222 … βˆ’ (6.222 …) 90𝑁 = 56 𝑁 = 56 90
  • 24. 5. Write 0.637 as a fraction. Let 𝑁 = 0.637 = 0.63777 … (1) Multiply both sides of equation (1) by 100 100𝑁 = 63.777 … (2) Multiply both sides of equation (1) by 1000 1000𝑁 = 637.777 … (3) From equations (3) and (2), we have, 1000𝑁 βˆ’ 100𝑁 = 637.777 … βˆ’ (63.777 …) 900𝑁 = 574 𝑁 = 574 900 = 287 450
  • 25. 6. Write 0.625 as a fraction. Let 𝑁 = 0.625 = 0.62525 … (1) Multiply both sides of equation (1) by 10 10𝑁 = 6.2525 … (2) Multiply both sides of equation (1) by 1000 1000𝑁 = 625.2525 … (3) From equations (3) and (2), we have, 1000𝑁 βˆ’ 10𝑁 = 625.2525 … βˆ’ (6.2525 …) 990𝑁 = 619 𝑁 = 619 990
  • 26. 625 βˆ’ 6 990 637 βˆ’ 63 900 From example 5, write 0.637 as a fraction. 62 βˆ’ 6 90 From example 4, write 0.62 as a fraction. We have 56 90 = Observe that the subtrahend is 6 which is the digit that is not repeated It is found that there is one 9 when there is only one digit that is repeated It is found that there is only one 0 when there is only one digit that is not repeated We have 574 900 = Observe that the subtrahend is 63 which is the digit that is not repeated It is found that there is one 9 when there is only one digit that is repeated It is found that there are two 0s when there are two digits that are not repeated From example 6, write 0.625 as a fraction. We have 619 990 = Observe that the subtrahend is 6 which is the digit that is not repeated It is found that there are two 9s when there are two digits that are repeated It is found that there is only one 0 when there is only one digit that is not repeated
  • 27. Write the following repeating decimals as fractions. 0.74 = 74 βˆ’ 7 90 = 67 90 0.234 = 234 βˆ’ 23 900 = 211 900 1.3642 = 1 3642 βˆ’ 36 9900 = 1 3606 9900 = 1 601 1650
  • 28. Write the following repeating decimals as fractions. 0.63 0.572 0.572 1.34 2.237 3.534 = 63 βˆ’ 6 90 = 57 90 = 572 βˆ’ 57 900 = 515 900 = 572 βˆ’ 5 990 = 567 990 = 1 34 βˆ’ 3 90 = 1 31 90 = 2 237 βˆ’ 23 900 = 2 214 900 = 3 534 βˆ’ 4 990 = 3 529 990