Topic 10.3

Second Law of Thermodynamics
and Entropy
The 2nd Law of Thermodynamics
• Heat can be completely converted into work in a single process


• but continuous conversion of heat in to work requires a cyclic
 process ( a heat engine)

• All attempts to construct a heat engine that is 100% efficient
 have failed

• The Kelvin- Planck statement of the 2nd Law of
 thermodynamics is a qualitative statement of the impossibility
 of certain types of processes
The Law states….
• It is impossible for an engine working in a cycle to
 transform a given amount of heat from a reservoir
 completely into work


                           or
• Not all the thermal energy in a thermal system is
 available to do work
The Clausius Statement
• No device has been observed for which     W=0

• This leads to a second way to state the second Law of
 Thermodynamics

• It is impossible to make a cyclic engine whose only
 effect is to transfer thermal energy from a colder
 body to a hotter body
…and The Second Law of
Thermodynamics
• Recall that in thermodynamics, a system in an
  equilibrium state is characterised by its state
  variables.
• p, V, T, U, n ..
• The change in a state variable for a complete cycle
  is zero.
• In contrast, the net thermal energy and net work
  factors for a cycle are not equal to zero.
History

  • In the latter half of the nineteenth century, Rudolf
   Clausius proposed a general statement of the
   second Law in terms of a quantity called entropy.
Entropy
• Is a thermodynamic function of the state of the
 system

• Can be interpreted as the amount of order or disorder
 of a system

• As with internal energy, it is the change in entropy is
 important and not its absolute value.
Change in Entropy
The change in entropy ∆S of a system when an amount
of thermal energy Q is added to a system by a
reversible process at constant absolute temperature T
is given by:


                    ∆S = Q / T
The units of the change in entropy are JK-1
Example
A heat engine removes 100 J each cycle from a heat
reservoir at 400 K and exhausts 85 J of thermal energy
to a reservoir at 300 K.

Compute the change in entropy for each reservoir:
Solution
Since the hot reservoir loses heat, we have that:

∆S = Q / T = -100 J / 400 K = -0.25 JK-1
For the cold reservoir we have:
∆S=Q/T =          85 J / 300 K =    0.283 JK-1

Therefore:
The increase in entropy of the cold reservoir is
greater than the decrease for the hot reservoir.
Natural Systems
• In this example and all other cases, it has been found
  that the total entropy increases.
• This infers that total entropy increases in all natural
  systems.
• The entropy of a given system can increase or decrease


 but the change in entropy of the system ∆S, plus the
  change in entropy of the environment ∆Senv must be
             greater than or equal to zero.
That is



  ∆ S = ∆SS + ∆ Senv > 0
The Second Law of Thermodynamics
In terms of entropy, the Second Law of Thermodynamics
can be stated as:

3.The total entropy of any system plus that of its
environment increases as a result of all natural processes
4.The entropy of the Universe increases
5.Natural processes tend to move toward a state of
greater disorder.
Irreversible processes




   A block of ice can slide down an incline plane if the frictional
    force is overcome
   But the ice cannot spontaneously move up the incline of its
    own accord
   The conversion of mechanical energy to thermal energy by
    friction as it slides is irreversible
Explanation
• If the thermal energy could be converted completely
 to mechanical energy, the Kelvin-Planck statement of
 the second Law would be violated.

• In terms of entropy, the system tends to greater
 disorder, and the entropy increases.

• In another case, the conduction of thermal energy
 from a hot body to a cold body is irreversible.
• Flow of thermal energy completely from a
 cold body to a hot body violates the Clausius
 statement of the Second Law.

• In terms of entropy, a hot body causes
 greater disorder of the cold body and the
 entropy increases.

• If thermal energy was given by a cold body
 to a hot body there would be greater order
 in the hot body
• And the entropy would decrease.

• This is not allowed by the Second Law.

• Irreversibility can also occur if there is
 turbulence or an explosion causing a non-
 equilibrium state of the gaseous system.

• The degree of disorder increases and the
 entropy increases.
• Entropy indicates the direction in which
 processes occur.

• Hence entropy is often called the arrow
 of time.
Statistical approach
• This was first applied to the definition of entropy
 by Ludwig Boltzmann (1844-1906).

• If a coin is flipped 100 times, it is not improbable
 for the one hundred coins to land heads up.
• But it is highly improbable.

• The probability of rolling 100 sixes from 100 dice
 is even less.
• A small sample of a gas contains billions of
 molecules and the molecules have many
 possible microstates.

• It is impossible to know the position and
 velocity of each molecule at a given point in
 time.
• The probability that these microstates suddenly
 coming together into some improbable
 arrangement is infinitesimal.

• In reality, the macrostate is the only measurable
 part of the system.
• The Second Law in terms of probability does not
 infer that a decrease in entropy is not allowed but
 it suggests that the probability of this occurring is
 low.
Heat Degradation
• A final consequence of the Second Law is the heat
 degradation of the Universe.

• It can be reasoned that in any natural process,
 some energy becomes unavailable to do useful
 work.

• An outcome of this suggests that the Universe will
 eventually reach a state of maximum disorder.
• An equilibrium temperature will be reached
 and no work will be able to be done.

• All change of state will cease as all the energy
 in the Universe becomes degraded to thermal
 energy.

• This point in time is often referred to the heat
 death of the Universe.

10.3 - Second law of thermodynamics

  • 1.
    Topic 10.3 Second Lawof Thermodynamics and Entropy
  • 2.
    The 2nd Lawof Thermodynamics • Heat can be completely converted into work in a single process • but continuous conversion of heat in to work requires a cyclic process ( a heat engine) • All attempts to construct a heat engine that is 100% efficient have failed • The Kelvin- Planck statement of the 2nd Law of thermodynamics is a qualitative statement of the impossibility of certain types of processes
  • 3.
    The Law states…. •It is impossible for an engine working in a cycle to transform a given amount of heat from a reservoir completely into work or • Not all the thermal energy in a thermal system is available to do work
  • 4.
    The Clausius Statement •No device has been observed for which W=0 • This leads to a second way to state the second Law of Thermodynamics • It is impossible to make a cyclic engine whose only effect is to transfer thermal energy from a colder body to a hotter body
  • 6.
    …and The SecondLaw of Thermodynamics • Recall that in thermodynamics, a system in an equilibrium state is characterised by its state variables. • p, V, T, U, n .. • The change in a state variable for a complete cycle is zero. • In contrast, the net thermal energy and net work factors for a cycle are not equal to zero.
  • 7.
    History •In the latter half of the nineteenth century, Rudolf Clausius proposed a general statement of the second Law in terms of a quantity called entropy.
  • 8.
    Entropy • Is athermodynamic function of the state of the system • Can be interpreted as the amount of order or disorder of a system • As with internal energy, it is the change in entropy is important and not its absolute value.
  • 9.
    Change in Entropy Thechange in entropy ∆S of a system when an amount of thermal energy Q is added to a system by a reversible process at constant absolute temperature T is given by: ∆S = Q / T The units of the change in entropy are JK-1
  • 10.
    Example A heat engineremoves 100 J each cycle from a heat reservoir at 400 K and exhausts 85 J of thermal energy to a reservoir at 300 K. Compute the change in entropy for each reservoir:
  • 11.
    Solution Since the hotreservoir loses heat, we have that: ∆S = Q / T = -100 J / 400 K = -0.25 JK-1 For the cold reservoir we have: ∆S=Q/T = 85 J / 300 K = 0.283 JK-1 Therefore: The increase in entropy of the cold reservoir is greater than the decrease for the hot reservoir.
  • 12.
    Natural Systems • Inthis example and all other cases, it has been found that the total entropy increases. • This infers that total entropy increases in all natural systems. • The entropy of a given system can increase or decrease but the change in entropy of the system ∆S, plus the change in entropy of the environment ∆Senv must be greater than or equal to zero.
  • 13.
    That is ∆ S = ∆SS + ∆ Senv > 0
  • 14.
    The Second Lawof Thermodynamics In terms of entropy, the Second Law of Thermodynamics can be stated as: 3.The total entropy of any system plus that of its environment increases as a result of all natural processes 4.The entropy of the Universe increases 5.Natural processes tend to move toward a state of greater disorder.
  • 15.
    Irreversible processes  A block of ice can slide down an incline plane if the frictional force is overcome  But the ice cannot spontaneously move up the incline of its own accord  The conversion of mechanical energy to thermal energy by friction as it slides is irreversible
  • 16.
    Explanation • If thethermal energy could be converted completely to mechanical energy, the Kelvin-Planck statement of the second Law would be violated. • In terms of entropy, the system tends to greater disorder, and the entropy increases. • In another case, the conduction of thermal energy from a hot body to a cold body is irreversible.
  • 17.
    • Flow ofthermal energy completely from a cold body to a hot body violates the Clausius statement of the Second Law. • In terms of entropy, a hot body causes greater disorder of the cold body and the entropy increases. • If thermal energy was given by a cold body to a hot body there would be greater order in the hot body
  • 18.
    • And theentropy would decrease. • This is not allowed by the Second Law. • Irreversibility can also occur if there is turbulence or an explosion causing a non- equilibrium state of the gaseous system. • The degree of disorder increases and the entropy increases.
  • 19.
    • Entropy indicatesthe direction in which processes occur. • Hence entropy is often called the arrow of time.
  • 20.
    Statistical approach • Thiswas first applied to the definition of entropy by Ludwig Boltzmann (1844-1906). • If a coin is flipped 100 times, it is not improbable for the one hundred coins to land heads up. • But it is highly improbable. • The probability of rolling 100 sixes from 100 dice is even less.
  • 21.
    • A smallsample of a gas contains billions of molecules and the molecules have many possible microstates. • It is impossible to know the position and velocity of each molecule at a given point in time.
  • 22.
    • The probabilitythat these microstates suddenly coming together into some improbable arrangement is infinitesimal. • In reality, the macrostate is the only measurable part of the system. • The Second Law in terms of probability does not infer that a decrease in entropy is not allowed but it suggests that the probability of this occurring is low.
  • 23.
    Heat Degradation • Afinal consequence of the Second Law is the heat degradation of the Universe. • It can be reasoned that in any natural process, some energy becomes unavailable to do useful work. • An outcome of this suggests that the Universe will eventually reach a state of maximum disorder.
  • 24.
    • An equilibriumtemperature will be reached and no work will be able to be done. • All change of state will cease as all the energy in the Universe becomes degraded to thermal energy. • This point in time is often referred to the heat death of the Universe.