This document contains code and explanations for linear search and binary search algorithms. It begins with an example of linear search on an array of numbers to find the position of the number 2. It then shows the C code for linear search. Next, it explains binary search with an example of finding the number 36 in a sorted array. It provides pseudocode and the C code implementation of binary search. It ends with an example run of the binary search code to find the number 67 in a sorted array of numbers.

2. Mehedi Hassan
161-15-7667
Arafat Rahman
152-15-5983
Nazmul Islam 152-
15-5652
Taijul Islam 152-
15-5613

3. Name :
Ms. Rifat Ara Shams
Designation :
Senior Lecturer
Department :
Department of
Computer Science and
Engineering
E-mail :
rifat.cse@diu.edu.bd
Cell-Phone :
+880-1723256560

5. LINEAR BINARY
SEARCH

6. LINEAR SEARCH
10 46 8 996 2 34 19578
ENTER THE ARRAY ELEMENTS
ENTER THE NUMBER TO BE SEARCHED
2
M[0] M[1] M[2] M[3] M[4] M[5] M[6] M{7] M[8] M[9]

7. LINEAR SEARCH
10 46 8 996 2 34 19578
2 2 2 2 2 2
THE NUMBER IS FOUND IN THE 6TH
POSITION

8. #include <stdio.h>
int main()
{
int array[100], search, c, n;
printf("Enter the number of elements in
arrayn");
scanf("%d",&n);
printf("Enter %d integer(s)n", n);
for (c = 0; c < n; c++)
scanf("%d", &array[c]);
CODE

9. printf("Enter the number to searchn");
scanf("%d", &search);
for (c = 0; c < n; c++)
{
if (array[c] == search) /* if required
element found */
{
printf("%d is present at location
%d.n", search, c+1);
break;
}
}
if (c == n)
printf("%d is not present in array.n",
search);
return 0;
}

11. BINARY SEARCH
1 5 8 2412 36 48 876754
ENTER THE ARRAY ELEMENTS
ENTER THE NUMBER TO BE SEARCHED
36
M[0] M[1] M[2] M[3] M[4] M[5] M[6] M{7] M[8] M[9]

12. BINARY SEARCH
1 5 8 2412 36 48 876754
ENTER THE ARRAY ELEMENTS
ENTER THE NUMBER TO BE SEARCHED 36
M[0] M[1] M[2] M[3] M[4] M[5] M[6] M{7] M[8] M[9]
LB UB

13. P=LB+UB/2
24
STEP 1
FIND THE MIDDLE ELEMENT
P=0+9/2

14. 24 36<
36 48 54 67 87
THE SEARCH ELEMENT LIES IN THE UB
0 1 2 3 4
COMPARING SEARCH WITH MIDDLE ELEMENT
STEP 2

15. P=LB+UB/2 54
54 > 36
36 48
STEP 3
DIVIDE THE ARRAY FURTHER
COMPARING SEARCH WITH MIDDLE ELEMENT
THE SEARCH ELEMENT LIES IN THE LB

16. 3636
=
NUMBER FOUND
STEP 4
36 48
MIDDLE ELEMENT IS COMPARED WITH THE ELEMENTS IN THE ARRAY

17. #include<stdio.h>
int main(){
int a[10],i,n,m,c=0,l,u,mid;
printf("Enter the size of an
array: ");
scanf("%d",&n);
printf("Enter the elements in
ascending order: ");
for(i=0;i<n;i++){
scanf("%d",&a[i]);
}
printf("Enter the number to be
search: ");
scanf("%d",&m);
CODE

18. l=0,u=n-1;
while(l<=u){
mid=(l+u)/2;
if(m==a[mid]){
c=1;
break;
}
else if(m<a[mid]){
u=mid-1;
}
else
l=mid+1;
}
if(c==0)
printf("The number is not found.");
else
printf("The number is found.");
return 0;
}

19. Enter the elements of the array in ascending order
12
Enter the elements of the array in ascending order
23
Enter the elements of the array in ascending order
34
Enter the elements of the array in ascending order
45
Enter the elements of the array in ascending order
56
Enter the elements of the array in ascending order
67
Enter the elements of the array in ascending order
78
Enter the elements of the array in ascending order
89
Enter the elements of the array in ascending order
98
Enter the elements of the array in ascending order
100
Enter the number to be searched
67
found