The document defines a quotient ring R/I as the set of cosets {a + I | a ∈ R} where I is an ideal of a ring R. Addition and multiplication are defined on the cosets. It is proven that R/I forms a ring by showing it satisfies the ring axioms. The mapping φ: R → R/I defined by φ(a) = a + I is a ring homomorphism. It is also proven that if I is an ideal of R, there exists an epimorphism from R onto R/I with kernel I. The 1st Isomorphism Theorem states that if φ: R → R' is an epimorphism with kernel I, then
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Arithmetic progression - Introduction to Arithmetic progressions for class 10...Let's Tute
Arithmetic progression - Introduction to Arithmetic progressions for class 10 maths.
Lets tute is an online learning centre. We provide quality education for all learners and 24/7 academic guidance through E-tutoring.
Our Mission- Our aspiration is to be a renowned unpaid school on Web-World.
Contact Us -
Website - www.letstute.com
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Linear
active content progresses often without any navigational control for the viewer such as a cinema presentation
Non-linear
uses interactivity to control progress as with a video game or self-paced computer-based training. Hypermedia is an example of non-linear content.
Digital
expressed as series of the digits 0 and 1, typically represented by values of a physical quantity such as voltage or magnetic polarization
Advantages
Disadvantage
Analogue
relating to or using signals or information represented by a continuously variable physical quantity such as spatial position, voltage, etc.
advantages
Gives idea about function, one to one function, inverse function, which functions are invertible, how to invert a function and application of inverse functions.
Factor Theorem and Remainder Theorem. Mathematics10 Project under Mrs. Marissa De Ocampo. Prepared by Danielle Diva, Ronalie Mejos, Rafael Vallejos and Mark Lenon Dacir of 10- Einstein. CNSTHS.
All the best to all students of class IX...This PPT will makes your difficulties easy to do....You will understand the polynomial chapter easily by seeing this ....Thanks for watching this ..Please Share, Like and Subscribe the PPT
Linear
active content progresses often without any navigational control for the viewer such as a cinema presentation
Non-linear
uses interactivity to control progress as with a video game or self-paced computer-based training. Hypermedia is an example of non-linear content.
Digital
expressed as series of the digits 0 and 1, typically represented by values of a physical quantity such as voltage or magnetic polarization
Advantages
Disadvantage
Analogue
relating to or using signals or information represented by a continuously variable physical quantity such as spatial position, voltage, etc.
advantages
INC and DEC Instructions
ADD Instruction
SUB Instruction
NEG Instruction
Implementing Arithmetic Expressions
Flags Affected by Addition and Subtraction
Example Program (AddSub3)
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Quotient ring
1. Quotient Ring
Let I be an ideal of a ring R then the set R/I = { a + I : aϵ R } is called cosets of I in R is
A ring called Quotient ring where addition and multiplication are defined as
(a + I ) + (b + I) = (a + b) + I a , b ϵ R
(a + I ) + (b + I) = ab + I a , b ϵ R
Note
(i) If R is a commutative ring with unity then R/I is also a commutative ring with
unity
(ii) 1 + I is the multiplicative identity of R/I and 0 + I = I is the additive identity of R/I
2. Theorem
If I is an ideal of a ring R then R/I is a ring
Proof
First we show that R/I is an abelian group under addition
R/I = { a + I : a ϵ R }
Let a + I , b + I ϵ R/I
(a + I) + (b + I) = ( a + b) + I
a , b ϵ R => a + b ϵ R
=> ( a + b) + I ϵ R
(a + I) + (b + I) ϵ R/I
Clouser law holds in R/I under addition
3. Now
let ( a + I) , (b + I) , (c + I) ϵ R/I ; a , b , c ϵ R
( a + I) , (b + I) , (c + I) = ( a + I) , (b + I) + I
= [ a + (b + c )] + I
= [ ( a + b ) + c ] + I
= ( a + b) + I + (c + I)
= [ (a + I ) + (b + I )] + ( c + I)
Thus associative law holds in R/I under addition
Since 0 ϵ R thus 0 + I ϵ R/I
a + I ϵ R/I
(0 + I) + ( a + I) = ( 0 + a ) + I = a + I
and
(a + I) + ( 0 + I ) = ( a + I ) + I = a + I
a ϵ R ; - a ϵ R (R is ring)
Thus a + I ϵ R/I and ( - a) + I ϵ R/I
4. ( a + I) and ( - a ) + I are the additive inverse of each other ; since
(a + I ) + ((-a) + I) = (a + (-a)) + I
= 0 + I
Thus each element of R/I has its additive inverse in R/I
For ( a + I ) , ( b + I ) ϵ R/I
( a + I) + (b + I) = (a + b) + I
= (b + a ) + I
= (b + I) + (a + I)
Thus R/I is commutative under addition
Hence R/I is abelian under addition
5. now we show that R/I is semi group under multiplication
Let
(a + I) , (b + I) ϵ R/I a , b ϵ R
(a + I)(b + I ) = ab + I
since a , b ϵ R => ab ϵ R
Thus ab + I ϵ R/I
I . e (a + I ) (b + I) ϵ R/I
Clouser law holds in R/I under multiplication
For (a + I) , (b + I) , (c + I) ϵ R/I a,b,c ϵ R
(a + I) [ (b + I)(c + I)] = (a + I) (bc + I)
= a (bc) + I
= (ab) c + I
= (ab +I) (c + I)
Thus associative law holds in R/I under multiplication
Hence R/I is semi group under multiplication
6. Now we show that both left and right distributive laws holds in R/I
Let
(a + I) , (b + I) , (c + I) ϵ R/I for a,b,c ϵ R
and
(a + I) [ (b + I) + (c + I)] = (a + I) [ (b + c) + I ]
= a ( b + c ) + I
= (ab + I ) + (ac + I )
=(a + I ) ( b + I ) + ( a + I )( c + I )
Left distributive law holds in R/I
Also
[ (b + I) + (c + I)] (a + I) = [ (b + c ) + I ] (a + I)
= (b + c)a + I
= (ba + ca) + I
= (ba + I ) + (ca + I)
= (b + I)(a + I) + (c + I) (a + I)
Right distributive law holds in R/I
Hence R/I is a ring
7. Theorem
If I is an ideal of a ring R then the mapping ɸ : R R/I defined by
ɸ (a) = a + I
Is a homomorphism
Proof
for a , b ϵ R a + b ϵ R
ɸ ( a + b) = (a + b) + I
= (a + I) + (b + I)
= ɸ (a) + (b)
And
ɸ(ab) = ab + I
= (a + I) + (b + I)
= ɸ(a) ɸ(b)
Hence ɸ is a homomorphism
8. Theorem
Let I be an ideal of a ring R; then there always exists an epimorphism
(homomorphism + Onto) ɸ: R R/I with ker ɸ = I
Proof
Define a mapping ɸ : R R/I define by
ɸ(a) = a + I a ϵ R
for a ,b ϵ R a + b ϵ R
ɸ (a + b) = (a + b) + I
= (a + I ) + ( b + I )
= ɸ(a) + ɸ (b)
And
ɸ(ab) = ab + I
= (a + I) + (b + I)
= ɸ(a) ɸ(b)
Hence ɸ is a homomorphism
9. Now we show that ɸ is onto
For each a + I ϵ R/I ; there exists an elements a ϵ R
such that ɸ (a) = a +I
Hence ɸ is an onto mapping
Thus ɸ is an epimorphism
Now we have to show that ker ɸ = I
let a ϵ ker ɸ ɸ (a) = I I is additive identity of R/I
but ɸ(a) = a + I
a + I = I a ϵ I
ker ɸ I ------- (1)
Now let b ϵ I
ɸ (b) = b+ I
b + I = I ɸ(b) = I
b ϵ ker ɸ
I ker ɸ -------(2)
From 1 and 2 ker ɸ = I
10. Theorem : 1st Fundamental theorem
Let I be an ideal of a ring R and Ѱ : R R’ be an epimorphism with ker Ѱ = I
Then R/I ≈ R’
Proof
Define a mapping ɸ : R R’ by
ɸ (a + I) = Ѱ (a) a ϵ R
First we show that ɸ is well defined for this
Let
a + I = b + I
a – b ϵ I
a – b ϵ ker Ѱ I = ker Ѱ
Ѱ (a - b) = 0’ where 0’ ϵ R’
Ѱ (a) – Ѱ(b) = 0’
Ѱ(a) = Ѱ (b)
ɸ (a + I) = ɸ (b+ I)
hence ɸ is well defined
11. To show that ɸ is homomorphism let
ɸ [(a + I ) + ( b + I ) ] = ɸ [ (a + b) + I ]
= Ѱ (a + b )
= Ѱ(a) + Ѱ (b)
= ɸ(a + I ) + ɸ ( b + I )
Also
ɸ[(a + I)(b + I)] = ɸ [ab + I]
= Ѱ (ab)
= Ѱ(a) + Ѱ(b)
= ɸ(a + I) ɸ(b + I)
Thus ɸ is a homomorphism
To show that ɸ is onto
Let r’ ϵ R’ be any element of R
Since Ѱ is onto (epimorphism) there exists an elements r ϵ R such that Ѱ (r) = r’
ɸ (r + I) = r’
Thus there will be exists an element r + I ϵ R/I
Such that ɸ (r + I) = r’
ɸ is onto
12. to show that ɸ is one – one
Let
ɸ (a + I ) = ɸ (b + I)
Ѱ(a) = Ѱ (b)
Ѱ(a) – Ѱ (b) = 0’
Ѱ(a – b ) = 0’
a – b ϵ ker Ѱ
but ker Ѱ = I
Thus a - b ϵ I
Now a ϵ b + I ------(i)
but a ϵ a + I ----- (ii)
From i and ii
a + I = b + I
This shows that ɸ is one – one
ɸ is an isomorphism from R/I R’
Hence
R/I ≈ R’