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Name : SARAVANAN P
Dept no: 22-EDM-16
Level 2
TOPIC:PYTHAGORAS
THEOREM
INTRODUCTION
INTRODUCTION
Pythagoras theorem is basically
used to find the length of an
unknown side and the angle of a
triangle.
By this theorem, we can derive the
base,perpendicular & hypotenuse
formulas.
INTRODUCTION
INTRODUCTION
pythagoras Theorem (also called Pythagorean
Theorem) is an important topic in Mathematics,
which explains the relation between the sides of
a right-angled triangle.
The sides of the right triangle are also called
Pythagorean triples.
STATEMENT
pythagoras theorem states that
“In a right-angled triangle, the
square of the hypotenuse side is
equal to the sum of squares of
the other two sides“
The sides of this triangle have been named
Perpendicular, Base and Hypotenuse. Here,
the hypotenuse is the longest side, as it is
opposite to the angle 90°. The sides of a
right triangle (say a, b and c) which have
positive integer values, when squared, are
put into an equation, also called a
Pythagorean triple.
FORMULA
FORMULA
Consider the triangle given above:
Where “a” is the perpendicular,
“b” is the base,
“c” is the hypotenuse.
According to the definition, the Pythagoras Theorem
formula is given as:
" Hypotenuse² = Perpendicular² + Base²
c² = a² + b² "
PROOF
PROOF
The side opposite to the right angle (90°) is the
longest side (known as Hypotenuse) because the
side opposite to the greatest angle is the longest.
PROOF
PROOF
Consider three squares of sides a, b, c mounted
on the three sides of a triangle having the same
sides as shown.
By Pythagoras Theorem –
Area of square “a” + Area of square “b” = Area
of square “c”
PROOF
PROOF
We know, △ADB ~ △aBC
therefore,
ADAB= ABAC(corresponding sides of similar
triangle)
Or,
AB² = AD ×AC……………………………..……..(1)
Also, △BDC ~△ABC
therefore,
CD/BC=BC/AC
OR,
BC²= CD × AC ……………………………………..(2)
Adding the equations (1) and (2) we get,
AB²+ BC² = AD × AC + CD × AC
AB² + BC²= AC (AD + CD)
Since, AD + CD = AC
Therefore,
AC² = AB² + BC²
hence, The Pythagoras Theorem is proved
EXAMPLE
NOTE
NOTE
PYTHAGOREAN THEOREM
IS ONLY APPLICABLE TO
RIGHT-ANGLED TRIANGLE.
THANK YOU
THANK YOU

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PYTHAGORAS THEOREM

  • 1. Name : SARAVANAN P Dept no: 22-EDM-16 Level 2 TOPIC:PYTHAGORAS THEOREM
  • 2. INTRODUCTION INTRODUCTION Pythagoras theorem is basically used to find the length of an unknown side and the angle of a triangle. By this theorem, we can derive the base,perpendicular & hypotenuse formulas.
  • 3. INTRODUCTION INTRODUCTION pythagoras Theorem (also called Pythagorean Theorem) is an important topic in Mathematics, which explains the relation between the sides of a right-angled triangle. The sides of the right triangle are also called Pythagorean triples.
  • 4. STATEMENT pythagoras theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides“
  • 5. The sides of this triangle have been named Perpendicular, Base and Hypotenuse. Here, the hypotenuse is the longest side, as it is opposite to the angle 90°. The sides of a right triangle (say a, b and c) which have positive integer values, when squared, are put into an equation, also called a Pythagorean triple.
  • 6.
  • 7. FORMULA FORMULA Consider the triangle given above: Where “a” is the perpendicular, “b” is the base, “c” is the hypotenuse. According to the definition, the Pythagoras Theorem formula is given as: " Hypotenuse² = Perpendicular² + Base² c² = a² + b² "
  • 8.
  • 9.
  • 10. PROOF PROOF The side opposite to the right angle (90°) is the longest side (known as Hypotenuse) because the side opposite to the greatest angle is the longest.
  • 11.
  • 12. PROOF PROOF Consider three squares of sides a, b, c mounted on the three sides of a triangle having the same sides as shown. By Pythagoras Theorem – Area of square “a” + Area of square “b” = Area of square “c”
  • 13. PROOF PROOF We know, △ADB ~ △aBC therefore, ADAB= ABAC(corresponding sides of similar triangle) Or, AB² = AD ×AC……………………………..……..(1) Also, △BDC ~△ABC therefore,
  • 14. CD/BC=BC/AC OR, BC²= CD × AC ……………………………………..(2) Adding the equations (1) and (2) we get, AB²+ BC² = AD × AC + CD × AC AB² + BC²= AC (AD + CD) Since, AD + CD = AC Therefore, AC² = AB² + BC² hence, The Pythagoras Theorem is proved
  • 16. NOTE NOTE PYTHAGOREAN THEOREM IS ONLY APPLICABLE TO RIGHT-ANGLED TRIANGLE.