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Solution of Problems from several topics like- Electric Potential Energy; Current, Resistance & Power; Capacitance; RC Circuit
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This document discusses basic electrical concepts including circuits, current, voltage, resistance, and power. It defines current as the flow of electric charge measured in amperes. Voltage or electric potential difference (PD) is the amount of energy given to each coulomb of charge and is measured in volts. Resistance is a material's ability to prevent electron flow and is calculated using Ohm's Law. Circuits can be connected in series or parallel, and power is calculated as voltage times current, measured in watts. Examples of calculations using these concepts are also provided.
Ch25 ssm
1) The document discusses various concepts related to electric current and direct current circuits, including resistance, resistivity, Ohm's law, temperature dependence of resistance, and drift velocity of electrons.
2) It provides examples and conceptual problems involving calculating resistance, current, power, drift velocity, and other quantities using relationships like Ohm's law, relationships between resistance and resistivity, and how resistance changes with temperature.
3) Sample problems include calculating the resistance of wires with different lengths and gauges, the drift speed of electrons in copper wires carrying different currents, the potential difference required across a wire to produce a given current, and the temperature at which a copper wire's resistance would be 10% greater than at 20
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Practice problems
- 10. 1. An electron is accelerated from rest through a potential difference 12 V. What is the change in electric potential energy of the electron ? Answer in Next Page >>>
- 12. 3. What distance must separate two charges of + 5.6×10-4C and -6.3×10-4 C in order to have an electric potential energy with a magnitude of 5.0 J in the system of the two charges?
- 13. Question>> What is the electric potential at point P, located at the center of the square of point charges shown in Fig. 1a? The distance d is 1.3 m, and the charges are q1=+12 nC, q2=-24 nC, q3=+31 nC and q4=+17 nC, which are held at the corners of a square as shown in Fig. 1a. (a) Calculate the net electric potential at point P, at the center of the square. Answer in Next Page>>
- 15. • A rectangular block of iron has dimensions 1.2 cm & 1.2 cm & 15 cm. A potential difference is to be applied to the block between parallel sides and in such a way that those sides are equipotential surfaces (as in Fig. 2). What is the resistance of the block if the two parallel sides are (1) the square ends (with dimensions 1.2 cm & 1.2 cm) and (2) two rectangular sides (with dimensions 1.2 cm & 15 cm)? Answer in Next Page >>> Figure 2
- 19. • A bulb is rated as 25-Watt -250 Volt. On connecting this bulb to a mains of 250 volts, what will be the value of current (I) flowing in it, and how much resistance (R) will the bulb provide to this flow of current?
- 20. Question>> A heating element is made by maintaining a potential difference of 75.0 V across the length of a Nichrome wire that has a 2.60 x 10-6 m2 cross section. Nichrome has a resistivity of 5.00 x 10-7 Ω m. (a) If the element dissipates 5000W, what is its length? (b) If a potential difference of 100 V is used to obtain the same dissipation what should the length be?
- 21. 3. Two resistors are wired in series. The second resistor has twice the resistance as the first. Current passes through the combination. Compared to the current let us say 3 amp flowing through the first resistor, what would be the current through the second resistor?
- 22. 4. What will happen to the brightness of the bulb in the side Fig. 4, if the resistance of R2 is increased and R1 remains constant? The resistance of the bulb is Rbulb. Answer : The relationship between brightness and resistance of bulbs connected in a series is directly proportional. Therefore, the bulb with the higher resistance will shine brighter. Therefore, the bulb with the lower resistance will shine brighter. In parallel, both bulbs have the same voltage across them. The bulb with the lower resistance will conduct more current and therefore have a higher power dissipation and brightness.