The document discusses a mathematics problem regarding the formation of integers greater than 6000 using the digits 3, 5, 6, 7, and 8 without repetition. It outlines the calculations for both 5-digit and 4-digit numbers, concluding that the total numbers greater than 6000 is 192. Additional details and resources are provided for further assistance.

1. Physics Helpline
L K Satapathy
Permutation & Combination 2

2. 10/11/2015
Permutation and Combination 2
Physics Helpline
L K Satapathy
Correct option = (b)
Question : The number of integers greater than 6000 , that can be formed , using
the digits 3 , 5 , 6 , 7 and 8 , without repetition is
(a) 216 (b) 192 (c) 120 (d) 72
Answer :
Any 5 digit number is > 6000  5 digit numbers using 5 digits = 5  = 120
4 digit numbers using 5 digits : 1000th place can have 3 digits ( 6 , 7 or 8 )
 1000th place can be filled in 3 ways
For each of these , the 100th place can be filled in 4 ways
For each of these , the 10th place can be filled in 3 ways
For each of these , the unit place can be filled in 2 ways
 Total 4-digit numbers = 3432 = 72
 Total numbers > 6000 = 120 + 72 = 192

3. 10/11/2015
Physics Helpline
L K Satapathy
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