Solving simultaneous
equations graphically
y = 2x + 1
y = 4 - x
Solve the simultaneous equations.
The Question:
Solution (by Elimination)
y = 2x + 1
y = 4 – x
y = 2x + 1
y = -x + 4
y = 2x + 1
2y = -2x + 8 (x2)
3y = 9
y = 3
x = 4 – y = 4 – 3 = 1
Solution: x = 1, y = 3
Substitute y to find the value of x
y = 2x + 1
y = 4 - x
Solve the simultaneous equations graphically.
The Question:
y = 2x + 1 y = 4 - x
Begin by constructing a table of values:
x
y
y = 2x + 1
-2 0 2 4
Use the equation to fill in the y value when x = -2
-3
Now fill in the rest of the table
1 5 9
y = 2x + 1 y = 4 - x
x
y
-2
-3
0
1
2
5
4
9
y = 2x + 1
Use the
table to draw
the graph of
the equation.
-4
-2
0
2
4
6
8
10
-3 -2 -1 0 1 2 3 4 5
x
y
y = 2x + 1
y = 2x + 1 y = 4 - x
Now construct a second table of values:
6 4 2
x
y
-2 0 2 4
0
Y = 4 - x
Plot this line on the axes you used earlier...
-4
-2
0
2
4
6
8
10
-3 -2 -1 0 1 2 3 4 5
x
y
y = 2x + 1
y = 4 - x
The solution is where the 2 lines cross:
Read the x-value from the x-axis... 1
Now read off the y-value... 3
So the solution of y = 2x + 1 and
y = 4 - x is...
x = 1 y = 3and
So the solution of y = 2x + 1 and
y = 4 - x is...
x = 1 y = 3and

P1 graphical simultaneousequations

  • 1.
  • 2.
    y = 2x+ 1 y = 4 - x Solve the simultaneous equations. The Question:
  • 3.
    Solution (by Elimination) y= 2x + 1 y = 4 – x y = 2x + 1 y = -x + 4 y = 2x + 1 2y = -2x + 8 (x2) 3y = 9 y = 3 x = 4 – y = 4 – 3 = 1 Solution: x = 1, y = 3 Substitute y to find the value of x
  • 4.
    y = 2x+ 1 y = 4 - x Solve the simultaneous equations graphically. The Question:
  • 5.
    y = 2x+ 1 y = 4 - x Begin by constructing a table of values: x y y = 2x + 1 -2 0 2 4 Use the equation to fill in the y value when x = -2 -3 Now fill in the rest of the table 1 5 9
  • 6.
    y = 2x+ 1 y = 4 - x x y -2 -3 0 1 2 5 4 9 y = 2x + 1 Use the table to draw the graph of the equation. -4 -2 0 2 4 6 8 10 -3 -2 -1 0 1 2 3 4 5 x y y = 2x + 1
  • 7.
    y = 2x+ 1 y = 4 - x Now construct a second table of values: 6 4 2 x y -2 0 2 4 0 Y = 4 - x Plot this line on the axes you used earlier...
  • 8.
    -4 -2 0 2 4 6 8 10 -3 -2 -10 1 2 3 4 5 x y y = 2x + 1 y = 4 - x The solution is where the 2 lines cross: Read the x-value from the x-axis... 1 Now read off the y-value... 3
  • 9.
    So the solutionof y = 2x + 1 and y = 4 - x is... x = 1 y = 3and
  • 10.
    So the solutionof y = 2x + 1 and y = 4 - x is... x = 1 y = 3and