This document discusses sinusoidal waveforms and solving for properties of an alternating current. It defines periodic time and peak-to-peak voltage for sinusoidal waves. It shows that a shifted waveform is represented by an expression with a phase angle added to or subtracted from the angular frequency term. As an example, it is given that i = 30 sin(100πt + 0.27) amperes, and it solves this to find the amplitude of 30 amperes, periodic time of 0.02 seconds (frequency of 50Hz), phase angle of 0.27 radians (15.46 degrees), and angular frequency ω of 100π.

1. P7 – SinusoidalWaveforms

2. T = Periodic Time
EP-P = Peak to peak
voltage

6. ftAtA mm  2sinsin 

7. )sin( tAm 
 If the waveform is shifted to the right or
left, the expression becomes:

10.  An alternating current is given by i = 30 sin(100πt +
0.27) amperes. Find the amplitude, periodic
time, frequency and phase angle.
 i = 30 sin(100πt + 0.27)
 i = A sin (ωt + Θ)
 Amplitude A = 30A
 phase angle Θ = 0.27rads = 15.46
 ω = 2fπ = 100π, frequency f = 50Hz
 T = 1/f = 1/50 = 0.02s