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Solid State Transformers for the Future Distribution Systems
Tao Yang, Dr. Terence O'Donnell
University College Dublin
May, 2016
University of Manchester
1/28
Conference for the Next Generation of
Researchers in Power Systems 2016
Content
 Introduction
 Solid State Transformer: State of the Art
 Motivations
 Research Objectives & Methodology
 Applications
 Conclusion and Future Work
2/28
What are Solid State Transformers(SST)? Basic Concept
 Take 50/60 Hz input voltage
 Use power electronics switches to chop 50/60 Hz into much higher frequency
AC (e.g. 10’s kHz)
 Pass this high frequency through a transformer
 Use power electronics to “re-make” and regulate the 50 Hz voltage.
3/28
Introduction
Why Solid State Transformers?
 Advantages
– Reduced size and weight
– SST is active, controllable device
• Output and input waveforms can
be decoupled
• Eliminate harmonic distortion
• Improve voltage regulation
• Control active and reactive power
– Could have a DC input/output for
connection of DG, energy storage
 Disadvantages
‒ Efficiency,
‒ Reliability
‒ Cost
4/28
Solid State Transformers (SST)
Low-Frequency Transformer(LFT)
Motivation
 The high voltages and power level of distribution system transformers are
currently still beyond the rating capability of current commercial semiconductor
switches.
Source: S. Bernet, “Recent Developments of High Power Converters for Industry and Traction Applications,” IEEE Transactions on Power
Electronics, 2000, vol. 15, no. 6, pp. 1102- 1117.
5/28
 Low Power
 High Frequency
 High Power
 Low Frequency
State-of-Art of Solid State Transformers
6/28
Size/Weight Reduction of
Transformers Realized
SST Applications Research over the
Last 10 Years
What has been achieved to date?
Source: Solid State Transformer Concepts in Traction and Smart Grid Applications, J.W. Kolar, G.I. Ortiz, ETH, Zurich
 Not many examples of fully functional tested SSTs
 Modelling suggests efficiencies in the range of 90 – 95%
Solid State Transformers Applications
● Hugo (ABB, 2006)
- Total Power:
1.2MVA/15kV
- Module Power: 75kW
- Frequency: 400Hz
Potential applications of SST in the future
distribution system
7/28
Source: X. She, R. Burgos, G. Y. Wang, F. Wang, and A. Q. Huang, “Review of solid state transformer in the distribution system: From implementation to filed application,” in Proc. IEEE
Energy Convers. Congr. Expo., 2012, pp. 4077–4084
8/28
Research Questions & Objectives
Research Objectives?
 SST application in the distribution power system—Modular design.
 Find out the system advantages of replacing the LFT with modular SST
in the distribution network.
Research Questions?
 Modular approach to design can improve reliability and facilitate cost
reduction but:
How best to build a modular SST?
What efficiency and size advantage is possible?
 SST Efficiency can never match that of an LFT but is it possible to make
savings elsewhere in the system?
Modular Design of Solid State Transformer
for the Distribution system
9/28
Interleaved (DAB)
Interleaved Inverter
Three Level Rectifier
a
b
c
n
M
N
10 kV
rms
14.1 kV
DC
14.1 kV
DC
0.8 kV
DC
0.4 kV
rms
or
The Definition of Modular Design
Built up the overall system
from a large number of lower
power sub-modules.
Methodology
10/28
Modular SST Optimization
 Individual modular optimization for three stages of SST
 Three Objective Functions:
Frectifier (P, V) = f1( Pinductor+Pbridge) 2 + f2 ( Vinductor+Vbridge) 2
FDAB (P, V) = f1 ( PMFT+Pbridge+Pcapacitors) 2 +f2 ( VMFT+Vbridge+Vcapacitors) 2
Finverter (P, V) = f1 ( Pinductor+Pcapacitors+Pbridge)2 +f2 ( Vinductor+Vcapacitors+Vbridge)2
P-Power Loss, V-Volume,
f1, f2-Minimization Functions with Normalization. Specific weighting factors for
each minimized function. GRG Nonlinear Solver.
 Optimization variables:
Number of Modules, Switching Frequency, Topology, MFT Optimization Parameters,
Inductor Optimization Parameters
 Constraints:
Temperature Rise, Isaturation>Iinput (Inductor Optimization Design),
Leakage inductance Limitation (MFT).
Results: Modular SST Optimization
11/28
Total SST(Optimization)
PT(w
)
VT(d
m3)
Efficiency
(%)
Power
Density(kW/L)
1459
8.4
110.8
5
96.48 3.61
AC/DC 3
AC/DC 2
AC/DC 1
DAB1-1
DC/AC
1
DC/AC
2
DC/AC
n
10 kV 5.3 kV
0.8 kV 0.4 kV
13.33 A
3.33 kV
3.33 kV
3.33 kV
1 kV
166.67
A
0.4 kV
0.4 kV
0.4 kVDAB1-2
DAB2-1
DAB2-2
DAB3-1
DAB3-2
DAB4-1
DAB4-2
1 kV
1 kV
1 kV
0.4 kV
0.4 kV
0.4 kV
0.4 kV
0.4 kV
n=3 n=7, m=1&2 n=30
Increase or Reduce Number of
Modules depending on Loading
Flexible Number Modules
Fix Number
Modules
Application to a 400 kVA, 10 kV/0.4 kV Distribution Network
10 kV Bus
0.4 kV Bus
10 kV/0.4 kV
400 kVA
External Grid
AC
DC
DC
AC
DualActiveBridge
(DAB)
Loads
LFT
SST
Distribution system with SST and LFT.
Winter and summer daily loading profile for a
400 kVA distribution system
Source: McKenna, K.; Keane, A., "Discrete Elastic Residential Load Response under Variable Pricing Schemes," Innovative Smart Grid Technologies Europe (ISGT EUROPE),
2014 5th IEEE/PES, 12-15 Oct. 2014
 A 400 kVA, 10 kV/400 V distribution system with 144 residential customers
has been modelled.
 A winter and summer day loading profile with 1 minute resolution based on
the average yearly energy consumption is used
12/28
Peak Loading Modular SST 50 HZ LFT
Efficiency[%] 95 98.11
Weight[kg] 773.18
(x0.58)
1350
Volume[m3]
Factor
0.568
(x0.333)
1.7061
Comparison Results under daily loading profile
13/28
Imbalanced Loading in the Distribution System
Modern Distribution Grid Three Phase
Imbalanced Loads
In an SST-fed distribution system, Can
SST ensure that certain tolerances on
phase loads imbalance at its output
terminals.(few publications have
addressed the issue )
• Unevenly distributed
single-phase load.
• Balanced three-
phase load running
at a fault
condition.
0 500 1000 1500
0
1
2
3
4
5
6
7
8
x 10
4
Time (min)(a Day)
ApparentPower(VA)
Load A
Load B
Load C
Applications
14/28
15/28
Positive
Sequence
Negative
Sequence
Zero
Sequence
Imbalance
• Imbalanced phase loading causes negative
sequence and zero sequence to flow into the
power system.
SST Solutions to the Imbalanced Load
16/28
A
B
C
20 kV RMS
16.3kV
Four Single-
Phase Rectifier
with series
connection
Four Single-
Phase Rectifier
with series
connection
Four Single-
Phase Rectifier
with series
connection
Four DAB
with
parallel
connection
Four DAB
with
parallel
connection
Four DAB
with
parallel
connection
………
ILa
ILb
ILc
L
LnIn
C
Load
6 kV
800 V
VA VB VC
Sn1
Sn2
Sa1
Sa2
Sb1
Sb2
Sc1
Sc2
+
380 V
IOa
IOc
IOb
dq
abcVA
VB
VC
dq
abcVA
VB
VC
Notch Filter
Notch Filter
Notch Filter
Notch Filter
dq
abcILa
ILb
ILc
dq
abcILa
ILb
ILc
Notch Filter
Notch Filter
Notch Filter
Notch Filter
dq
abcIOa
IOb
IOc
dq
abcIOa
IOb
IOc
Notch Filter
Notch Filter
Notch Filter
Notch Filter
Vd
Vq
V-d
V-q
ILd
ILd
IL-d
IL-q
IOd
IOq
IO-d
IO-q
Σ/3 V0
- --
Σ/3 IO_0
PLL
abc
dq
VA
VB
VC
PLL
Transformation
0
Vore
f
+
xPI
Vd
C
0xPI
VqC
x
x
IOq
IOd
ILd
ILq
L
L
x
x
PI
PI
x
x
-
++
-
+
+
+
+
-
+
-
+
-
+
+
-
+
+
+
ILrefd
ILrefq
0+
xPI
V-d
C
0xPI
V-qC
x
x
IO-q
IO-d
IL-d
IL-q
L
L
x
x
PI
PI
x
x
-
++
-
+
+
+
+
-
+
-
+
-
+
+
-
+
+
+
Ilref-d
Ilref-q
xPIxPI
x
x
Sa
Sb
Sc
Sn
dq
αβ
dq
αβ
αβ
dq
dq0
αβγ
Vα*
Vβ*
Vγ*
V0In
+
-
+
-
+
+
+
+
Vd*
V0*
Vq*
Positive
Sequence
Control
Negative
Sequence
Control
Zero
Sequence
Control
Controller for
3-Phase 4-Leg
Inverter +
IO_0
Ic*
x
+
+
VL0*
V0
3-D
SVPWM
Balancing the output voltage
3-phase 4-leg SST
 Control all three sequence
components separately, by
regulating the positive
sequence to the correct value,
while eliminating the negative
and zero-sequence.
17/28
Balanced Loads Imbalanced Loads
In Neutral Current
Va VbVc
Phase C Open Fault
Sometimes, the large neutral current is not allowed.
18/28
Neutral Current Elimination under the Imbalanced loads
𝑖 𝑁 = 𝐼 𝑎 cos 𝜃 + 𝜃 𝑎 + 𝐼 𝑏 cos 𝜃 + 𝜃 𝑏 + 𝐼𝑐 cos 𝜃 + 𝜃𝑐
Where, Ia,Ib,Ic are the amplitude of output phase current,
θa,θb,θcare the current phase angle.
Phase Shifting Control
Voltage Amplitude Control
Phase Shifting and Voltage Amplitude Combination Control
19/28
0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1
-400
-300
-200
-100
0
100
200
300
400
Time (s)
Voltage(V)
0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1
-5
-4
-3
-2
-1
0
1
2
3
4
5
Time (s)
NeutralCurrent(A)
Balanced Output Control Phase Shifting Control
0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1
-400
-300
-200
-100
0
100
200
300
400
Time (s)
Voltage(V)
0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1
-6
-4
-2
0
2
4
6
Time (s)
NeutralCurrent(A)
0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1
-300
-200
-100
0
100
200
300
400
Time (s)
Voltage(V)
0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1
-8
-6
-4
-2
0
2
4
6
8
10
12
Time (s)
NeutralCurrent(A)
Combination Control
Voltage Amplitude Control
Simulation Results under the Imbalanced loads
Neutral Current
Output Voltage
Do these output voltage imbalance
degree meet the standard document
requirements?
Optimal Minimum Losses Control
• The EN 50160 standard: imbalanced voltage degree in the distribution system
should be below 2% for 95% of the time.
20/28
Voltage Imbalanced % = PVUR =
𝑉𝑚𝑎𝑥 − 𝑉 𝑚𝑖𝑛
𝑉𝑎𝑣𝑔
× 100%
Voltage Imbalanced % = UBF =
𝑉𝑛
𝑉𝑝
× 100%
Objective Function: 𝐹 𝑀𝑖𝑛 𝑡𝑜𝑡𝑎𝑙 𝑙𝑜𝑠𝑠𝑒𝑠 = (𝐼 𝑎∠𝜃a)2+(𝐼 𝑏∠𝜃b)2+(𝐼𝑐∠𝜃c)2+ 𝑖 𝑛
2
Constrains:
•
𝑉 𝑚𝑎𝑥−𝑉 𝑚𝑖𝑛
𝑉𝑎𝑣𝑔
≤ 2%
•
𝑉𝑛
𝑉𝑝
≤ 2%
21/28
0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1
-400
-300
-200
-100
0
100
200
300
400
Time (s)
Voltage(V)
0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1
-6
-4
-2
0
2
4
6
Time (s)
NeutralCurrent(A)
Balanced Output Control Optimal Control
Balanced Output Optimal Control
Voltage Amplitude (V) 300;300;300 294.08;294.08;300
Phase shifting angle (degree) 0;0;0 2.4788;-2.1937;2.0328
Current Amplitude (A) 15;12;10 14.70 11.76 10
Neutral Current Amplitude (A) 4.36 3.23
Total Losses (W) 243.2 231.8
Total Output Power (W) 5543 5379
PVUR 0% 2%
UBF 0% 2%
Results for the Optimal Control
Neutral Current
22/28
Experimental Validation
Rated Power 2 kVA
DC Bus
voltage
440 V
Load
Resistors
25/39/98Ω
Output
Voltage
220 V
Switching
Frequency
3 kHz LC Filter
80µF
65mH
Inductors
OPAL-RT
Control Board
Inverter
Bridges
Power
Supply
Prototype parameters
23/28
0 500 1000 1500
0
1
2
3
4
5
6
7
8
x 10
4
Time (min)(a Day)
ApparentPower(VA)
Load A
Load B
Load C
The Distribution Network with three phase Imbalanced Daily Load
Source: McKenna, K.; Keane, A., "Discrete Elastic Residential Load Response under Variable Pricing Schemes," Innovative Smart Grid Technologies Europe (ISGT EUROPE),
2014 5th IEEE/PES, 12-15 Oct. 2014
0 500 1000 1500
0
20
40
60
80
100
120
140
Time (min)LoadImbalanceDegree(%)
Imbalance Degree VS Time
Three Phase Loading Imbalance DegreeThree Phase Imbalance Daily Loading
24/28
0 20 40 60 80 100 120
0
20
40
60
80
100
Load Imbalance Degree(%)
OutputVoltageImbalanceDegree(%)
Balanced Output Control
Phase Shifting Control
Voltage Amplitude Control
Combination Control
Optimal Control
IEEE Standard Limitation
Application Results
0 20 40 60 80 100 120
0
10
20
30
40
50
60
70
80
90
100
Load Imbalanced Degree (%)
NeutralCurrent(A)
Balanced Output Control
Phase Shifting Control
Votlage Amplitude Control
Combination Control
Optimal Control
Apply the Optimal Control for a Typical Distribution Network Under the three phase
imbalanced daily load
Conclusion
 SST System benefits
 SSTs can ensure distribution level feeder voltage balance in the face of significant
loads imbalance.
 Can both balance the output voltage within the standard requirement and reduce the
neutral current somehow.
 Modular SST’s Distribution Level Application(Daily Loading)
 The efficiencies of SSTs significantly lower
 Different numbers of modules switch on for the different
loading is available for reducing the power loss.
 70% reduction of volume compared to LFT
 Further investigate for efficiency gains and size reduction
25/28
Future Work
 Further investigate potential efficiency gains and size reduction of the SSTs
 Full SST vs Transformers + PE (e.g. FACTS Devices) vs. Hybrid Solutions
 Impact of new switch technologies
 Protection
 Reliability
26/28
27/28
Acknowledgements
This work was conducted in the Electricity Research Centre, University College
Dublin, Ireland, which is supported by the Commission for Energy Regulation,
Bord Gais Energy, Bord na Mona Energy, Cylon Controls, EirGrid, Electric
Ireland, EPRI, ESB International, ESB Networks, Gaelectric, Intel, SSE
Renewables and Energia. T. Yang is partly funded by the UCD-Chinese
Scholarship Council Scheme. T. Yang and T. O'Donnell are funded through the
Sustainable Electrical Energy Systems Strategic Research Cluster (SEES Cluster)
under grant number 09/SRC/E1780.
Thank you for listening!
28/28

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Next Generation Researchers in Power Systems_Tao Yang_UCD EI

  • 1. Solid State Transformers for the Future Distribution Systems Tao Yang, Dr. Terence O'Donnell University College Dublin May, 2016 University of Manchester 1/28 Conference for the Next Generation of Researchers in Power Systems 2016
  • 2. Content  Introduction  Solid State Transformer: State of the Art  Motivations  Research Objectives & Methodology  Applications  Conclusion and Future Work 2/28
  • 3. What are Solid State Transformers(SST)? Basic Concept  Take 50/60 Hz input voltage  Use power electronics switches to chop 50/60 Hz into much higher frequency AC (e.g. 10’s kHz)  Pass this high frequency through a transformer  Use power electronics to “re-make” and regulate the 50 Hz voltage. 3/28 Introduction
  • 4. Why Solid State Transformers?  Advantages – Reduced size and weight – SST is active, controllable device • Output and input waveforms can be decoupled • Eliminate harmonic distortion • Improve voltage regulation • Control active and reactive power – Could have a DC input/output for connection of DG, energy storage  Disadvantages ‒ Efficiency, ‒ Reliability ‒ Cost 4/28 Solid State Transformers (SST) Low-Frequency Transformer(LFT) Motivation
  • 5.  The high voltages and power level of distribution system transformers are currently still beyond the rating capability of current commercial semiconductor switches. Source: S. Bernet, “Recent Developments of High Power Converters for Industry and Traction Applications,” IEEE Transactions on Power Electronics, 2000, vol. 15, no. 6, pp. 1102- 1117. 5/28  Low Power  High Frequency  High Power  Low Frequency
  • 6. State-of-Art of Solid State Transformers 6/28 Size/Weight Reduction of Transformers Realized SST Applications Research over the Last 10 Years What has been achieved to date? Source: Solid State Transformer Concepts in Traction and Smart Grid Applications, J.W. Kolar, G.I. Ortiz, ETH, Zurich  Not many examples of fully functional tested SSTs  Modelling suggests efficiencies in the range of 90 – 95%
  • 7. Solid State Transformers Applications ● Hugo (ABB, 2006) - Total Power: 1.2MVA/15kV - Module Power: 75kW - Frequency: 400Hz Potential applications of SST in the future distribution system 7/28 Source: X. She, R. Burgos, G. Y. Wang, F. Wang, and A. Q. Huang, “Review of solid state transformer in the distribution system: From implementation to filed application,” in Proc. IEEE Energy Convers. Congr. Expo., 2012, pp. 4077–4084
  • 8. 8/28 Research Questions & Objectives Research Objectives?  SST application in the distribution power system—Modular design.  Find out the system advantages of replacing the LFT with modular SST in the distribution network. Research Questions?  Modular approach to design can improve reliability and facilitate cost reduction but: How best to build a modular SST? What efficiency and size advantage is possible?  SST Efficiency can never match that of an LFT but is it possible to make savings elsewhere in the system?
  • 9. Modular Design of Solid State Transformer for the Distribution system 9/28 Interleaved (DAB) Interleaved Inverter Three Level Rectifier a b c n M N 10 kV rms 14.1 kV DC 14.1 kV DC 0.8 kV DC 0.4 kV rms or The Definition of Modular Design Built up the overall system from a large number of lower power sub-modules. Methodology
  • 10. 10/28 Modular SST Optimization  Individual modular optimization for three stages of SST  Three Objective Functions: Frectifier (P, V) = f1( Pinductor+Pbridge) 2 + f2 ( Vinductor+Vbridge) 2 FDAB (P, V) = f1 ( PMFT+Pbridge+Pcapacitors) 2 +f2 ( VMFT+Vbridge+Vcapacitors) 2 Finverter (P, V) = f1 ( Pinductor+Pcapacitors+Pbridge)2 +f2 ( Vinductor+Vcapacitors+Vbridge)2 P-Power Loss, V-Volume, f1, f2-Minimization Functions with Normalization. Specific weighting factors for each minimized function. GRG Nonlinear Solver.  Optimization variables: Number of Modules, Switching Frequency, Topology, MFT Optimization Parameters, Inductor Optimization Parameters  Constraints: Temperature Rise, Isaturation>Iinput (Inductor Optimization Design), Leakage inductance Limitation (MFT).
  • 11. Results: Modular SST Optimization 11/28 Total SST(Optimization) PT(w ) VT(d m3) Efficiency (%) Power Density(kW/L) 1459 8.4 110.8 5 96.48 3.61 AC/DC 3 AC/DC 2 AC/DC 1 DAB1-1 DC/AC 1 DC/AC 2 DC/AC n 10 kV 5.3 kV 0.8 kV 0.4 kV 13.33 A 3.33 kV 3.33 kV 3.33 kV 1 kV 166.67 A 0.4 kV 0.4 kV 0.4 kVDAB1-2 DAB2-1 DAB2-2 DAB3-1 DAB3-2 DAB4-1 DAB4-2 1 kV 1 kV 1 kV 0.4 kV 0.4 kV 0.4 kV 0.4 kV 0.4 kV n=3 n=7, m=1&2 n=30 Increase or Reduce Number of Modules depending on Loading Flexible Number Modules Fix Number Modules
  • 12. Application to a 400 kVA, 10 kV/0.4 kV Distribution Network 10 kV Bus 0.4 kV Bus 10 kV/0.4 kV 400 kVA External Grid AC DC DC AC DualActiveBridge (DAB) Loads LFT SST Distribution system with SST and LFT. Winter and summer daily loading profile for a 400 kVA distribution system Source: McKenna, K.; Keane, A., "Discrete Elastic Residential Load Response under Variable Pricing Schemes," Innovative Smart Grid Technologies Europe (ISGT EUROPE), 2014 5th IEEE/PES, 12-15 Oct. 2014  A 400 kVA, 10 kV/400 V distribution system with 144 residential customers has been modelled.  A winter and summer day loading profile with 1 minute resolution based on the average yearly energy consumption is used 12/28
  • 13. Peak Loading Modular SST 50 HZ LFT Efficiency[%] 95 98.11 Weight[kg] 773.18 (x0.58) 1350 Volume[m3] Factor 0.568 (x0.333) 1.7061 Comparison Results under daily loading profile 13/28
  • 14. Imbalanced Loading in the Distribution System Modern Distribution Grid Three Phase Imbalanced Loads In an SST-fed distribution system, Can SST ensure that certain tolerances on phase loads imbalance at its output terminals.(few publications have addressed the issue ) • Unevenly distributed single-phase load. • Balanced three- phase load running at a fault condition. 0 500 1000 1500 0 1 2 3 4 5 6 7 8 x 10 4 Time (min)(a Day) ApparentPower(VA) Load A Load B Load C Applications 14/28
  • 15. 15/28 Positive Sequence Negative Sequence Zero Sequence Imbalance • Imbalanced phase loading causes negative sequence and zero sequence to flow into the power system. SST Solutions to the Imbalanced Load
  • 16. 16/28 A B C 20 kV RMS 16.3kV Four Single- Phase Rectifier with series connection Four Single- Phase Rectifier with series connection Four Single- Phase Rectifier with series connection Four DAB with parallel connection Four DAB with parallel connection Four DAB with parallel connection ……… ILa ILb ILc L LnIn C Load 6 kV 800 V VA VB VC Sn1 Sn2 Sa1 Sa2 Sb1 Sb2 Sc1 Sc2 + 380 V IOa IOc IOb dq abcVA VB VC dq abcVA VB VC Notch Filter Notch Filter Notch Filter Notch Filter dq abcILa ILb ILc dq abcILa ILb ILc Notch Filter Notch Filter Notch Filter Notch Filter dq abcIOa IOb IOc dq abcIOa IOb IOc Notch Filter Notch Filter Notch Filter Notch Filter Vd Vq V-d V-q ILd ILd IL-d IL-q IOd IOq IO-d IO-q Σ/3 V0 - -- Σ/3 IO_0 PLL abc dq VA VB VC PLL Transformation 0 Vore f + xPI Vd C 0xPI VqC x x IOq IOd ILd ILq L L x x PI PI x x - ++ - + + + + - + - + - + + - + + + ILrefd ILrefq 0+ xPI V-d C 0xPI V-qC x x IO-q IO-d IL-d IL-q L L x x PI PI x x - ++ - + + + + - + - + - + + - + + + Ilref-d Ilref-q xPIxPI x x Sa Sb Sc Sn dq αβ dq αβ αβ dq dq0 αβγ Vα* Vβ* Vγ* V0In + - + - + + + + Vd* V0* Vq* Positive Sequence Control Negative Sequence Control Zero Sequence Control Controller for 3-Phase 4-Leg Inverter + IO_0 Ic* x + + VL0* V0 3-D SVPWM Balancing the output voltage 3-phase 4-leg SST  Control all three sequence components separately, by regulating the positive sequence to the correct value, while eliminating the negative and zero-sequence.
  • 17. 17/28 Balanced Loads Imbalanced Loads In Neutral Current Va VbVc Phase C Open Fault Sometimes, the large neutral current is not allowed.
  • 18. 18/28 Neutral Current Elimination under the Imbalanced loads 𝑖 𝑁 = 𝐼 𝑎 cos 𝜃 + 𝜃 𝑎 + 𝐼 𝑏 cos 𝜃 + 𝜃 𝑏 + 𝐼𝑐 cos 𝜃 + 𝜃𝑐 Where, Ia,Ib,Ic are the amplitude of output phase current, θa,θb,θcare the current phase angle. Phase Shifting Control Voltage Amplitude Control Phase Shifting and Voltage Amplitude Combination Control
  • 19. 19/28 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1 -400 -300 -200 -100 0 100 200 300 400 Time (s) Voltage(V) 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1 -5 -4 -3 -2 -1 0 1 2 3 4 5 Time (s) NeutralCurrent(A) Balanced Output Control Phase Shifting Control 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1 -400 -300 -200 -100 0 100 200 300 400 Time (s) Voltage(V) 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1 -6 -4 -2 0 2 4 6 Time (s) NeutralCurrent(A) 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1 -300 -200 -100 0 100 200 300 400 Time (s) Voltage(V) 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1 -8 -6 -4 -2 0 2 4 6 8 10 12 Time (s) NeutralCurrent(A) Combination Control Voltage Amplitude Control Simulation Results under the Imbalanced loads Neutral Current Output Voltage Do these output voltage imbalance degree meet the standard document requirements?
  • 20. Optimal Minimum Losses Control • The EN 50160 standard: imbalanced voltage degree in the distribution system should be below 2% for 95% of the time. 20/28 Voltage Imbalanced % = PVUR = 𝑉𝑚𝑎𝑥 − 𝑉 𝑚𝑖𝑛 𝑉𝑎𝑣𝑔 × 100% Voltage Imbalanced % = UBF = 𝑉𝑛 𝑉𝑝 × 100% Objective Function: 𝐹 𝑀𝑖𝑛 𝑡𝑜𝑡𝑎𝑙 𝑙𝑜𝑠𝑠𝑒𝑠 = (𝐼 𝑎∠𝜃a)2+(𝐼 𝑏∠𝜃b)2+(𝐼𝑐∠𝜃c)2+ 𝑖 𝑛 2 Constrains: • 𝑉 𝑚𝑎𝑥−𝑉 𝑚𝑖𝑛 𝑉𝑎𝑣𝑔 ≤ 2% • 𝑉𝑛 𝑉𝑝 ≤ 2%
  • 21. 21/28 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1 -400 -300 -200 -100 0 100 200 300 400 Time (s) Voltage(V) 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1 -6 -4 -2 0 2 4 6 Time (s) NeutralCurrent(A) Balanced Output Control Optimal Control Balanced Output Optimal Control Voltage Amplitude (V) 300;300;300 294.08;294.08;300 Phase shifting angle (degree) 0;0;0 2.4788;-2.1937;2.0328 Current Amplitude (A) 15;12;10 14.70 11.76 10 Neutral Current Amplitude (A) 4.36 3.23 Total Losses (W) 243.2 231.8 Total Output Power (W) 5543 5379 PVUR 0% 2% UBF 0% 2% Results for the Optimal Control Neutral Current
  • 22. 22/28 Experimental Validation Rated Power 2 kVA DC Bus voltage 440 V Load Resistors 25/39/98Ω Output Voltage 220 V Switching Frequency 3 kHz LC Filter 80µF 65mH Inductors OPAL-RT Control Board Inverter Bridges Power Supply Prototype parameters
  • 23. 23/28 0 500 1000 1500 0 1 2 3 4 5 6 7 8 x 10 4 Time (min)(a Day) ApparentPower(VA) Load A Load B Load C The Distribution Network with three phase Imbalanced Daily Load Source: McKenna, K.; Keane, A., "Discrete Elastic Residential Load Response under Variable Pricing Schemes," Innovative Smart Grid Technologies Europe (ISGT EUROPE), 2014 5th IEEE/PES, 12-15 Oct. 2014 0 500 1000 1500 0 20 40 60 80 100 120 140 Time (min)LoadImbalanceDegree(%) Imbalance Degree VS Time Three Phase Loading Imbalance DegreeThree Phase Imbalance Daily Loading
  • 24. 24/28 0 20 40 60 80 100 120 0 20 40 60 80 100 Load Imbalance Degree(%) OutputVoltageImbalanceDegree(%) Balanced Output Control Phase Shifting Control Voltage Amplitude Control Combination Control Optimal Control IEEE Standard Limitation Application Results 0 20 40 60 80 100 120 0 10 20 30 40 50 60 70 80 90 100 Load Imbalanced Degree (%) NeutralCurrent(A) Balanced Output Control Phase Shifting Control Votlage Amplitude Control Combination Control Optimal Control Apply the Optimal Control for a Typical Distribution Network Under the three phase imbalanced daily load
  • 25. Conclusion  SST System benefits  SSTs can ensure distribution level feeder voltage balance in the face of significant loads imbalance.  Can both balance the output voltage within the standard requirement and reduce the neutral current somehow.  Modular SST’s Distribution Level Application(Daily Loading)  The efficiencies of SSTs significantly lower  Different numbers of modules switch on for the different loading is available for reducing the power loss.  70% reduction of volume compared to LFT  Further investigate for efficiency gains and size reduction 25/28
  • 26. Future Work  Further investigate potential efficiency gains and size reduction of the SSTs  Full SST vs Transformers + PE (e.g. FACTS Devices) vs. Hybrid Solutions  Impact of new switch technologies  Protection  Reliability 26/28
  • 27. 27/28 Acknowledgements This work was conducted in the Electricity Research Centre, University College Dublin, Ireland, which is supported by the Commission for Energy Regulation, Bord Gais Energy, Bord na Mona Energy, Cylon Controls, EirGrid, Electric Ireland, EPRI, ESB International, ESB Networks, Gaelectric, Intel, SSE Renewables and Energia. T. Yang is partly funded by the UCD-Chinese Scholarship Council Scheme. T. Yang and T. O'Donnell are funded through the Sustainable Electrical Energy Systems Strategic Research Cluster (SEES Cluster) under grant number 09/SRC/E1780.
  • 28. Thank you for listening! 28/28