NEONATAL RESPIRATORY
MECHANICS
Dr. Murtaza Kamal
MBBS, MD, DNB
Division of Neonatology
Department of Pediatrics
Safdarjung Hospital &VMMC, New Delhi
DOP-07/11/2015
What is expected of us post
talk??
 Compliance
 Resistance
 Time Constant
 Lung Volumes
 Oxygenation
 CO2 removal
 Clinical implications
COMPLIANCE
Compliance
 Measurement of distensibility
 C= Volume change (V) / Pressure
change(P)
 Volume change per unit pressure
 Lung which is more compliant is more
distensible and vice versa
Clinical Implications
In RDS
 Less compliant lungs
 Requires more pressure to ensure tidal
volume delivery
Clinical Implications (cont.)
Role of Surfactant
 Improves compliance
 Results in a rapid decline in pressures
required to deliver the tidal volumes
after surfactant administration
Lets try this
 3kg neonate, tidal volume delivered-
14ml, pressure required to drive this
volume is PIP of 18 and PEEP of 4
 Calculate compliance=??
So we got…
 Compliance=
Tidal volume/ Pressure gradient
=14/ (PIP-PEEP)
=14/14
=1ml/cm Hg
Clinical Implications (cont.)
 Collapsed/ overstretched lungs poor
compliance
 PEEP Pressure required to open the
lungs and keep it inflated
 High PIP (excess pressure) which over
distends the lungs, does not result in
better volume delivery
Clinical Implications (cont.)
 These lung
propertiesTypical
sigmoid shape curve
to pressure-volume
loop
 Operate on the
rapid slope (middle
segment) during
ventilation
 Fig.1
RESISTANCE
Resistance
 The oppositional force for air flow into
the lungs
 Higher the resistance, greater is the
pressure required to drive the gases
into the lungs
 Depends on:
 Airway diameter
 Airway length
 Viscosity of gas
Resistance
 Resistance is directly proportional to:
 Length
 Viscosity
 1/r4
 Pressure required to drive 1L/min of gas
flow into the lungs
Clinical Implications
 As length increases- resistance
increases
 Eg: long ET tube
flow sensor or capnograph
 Trim the ET tube to 2.5cm outside the
upper lip
Clinical Implications (cont.)
 A small decrease in airway diameter
causes a large change in resistance
 Removal of airway secretions and
largest diameter ET tube that fits the
glottis to be chosen
 Higher air flows increases the
resistance by causing turbulence to gas
flow
TIME CONSTANT
Time Constant
 Time taken to empty the gases from
lungs
 It nearly takes 3-5 time constants to
completely empty the lungs
 Time constant(sec)= Compliance x
Resistance
Time Constant
Time Constant
Clinical Implications
RDS:
 Low compliance, normal resistance
 Hence time constant-> less
 Time required to inflate (Ti) or deflate
(Te) the lungs ->Hence short
Clinical Implications(cont.)
MAS
 Resistance is high, Compliance
decreases little bit
 Hence, time constant increases
 Time required to inflate (Ti) or deflate
(Te) the lungs hence is long
 A short set expiratory time on
ventilator can lead to inadequate lung
emptying and hence gas trapping
Clinical Implications(cont.)
LUNG VOLUMES
Lung Volumes of our Importance
 Tidal volume
 Minute volume
 Functional residual volume
TIDAL VOLUME
Tidal Volume
 Volume of the gas going in and out with
each breath
 5-8ml/kg
 Ideally inspiratory and expiratory tidal
volumes are equal
Clinical Implications
 Whenever peritubal leak during MV, air
leaks more during inspiration (higher
PIP and wider airways)
 Hence, in modes of ventilation where
tidal volume is being targeted, it is
better to measure the expiratory
volume (volume of gas that actually goes
to the lungs)
DEAD SPACE
Dead Space
 Respiratory component-
 Terminal bronchiole,
 Alveolar sacs
 Alveoli
 Anatomical dead space- Part of tidal
volume which is not a part of gas exchange
(airways)
 2ml/kg
Dead Space
 Some gas in alveoli, due to ill
perfusion, is not a part of gas
exchange
 Physiological dead space- Anatomical+ ill
perfused alveoli
So Tidal Volume is…
Alveolar tidal volume+ Anatomical dead
space+ ill perfused alveoli’s vol
Alveolar tidal volume+ Physiological dead
space
MINUTE VOLUME
Minute Volume
 Total volume of the gas moving in and
out of the lungs per minute
 MV=TV X RR
 200-480 ml/kg/min
 Alveolar MV= ??
Clinical Implications
 MV, esp the alveolar MV, is determinant
of CO2 removal
 Co2 removal hastened either by
increasing the TV or rate
 Better to increase the TV more
energy efficient (Increasing TV--dead
space is constant but increasing rate–
increases dead space too)
FUNCTIONAL RESIDUAL
CAPACITY
FRC
 Volume of the gas present in the lungs
at the end of expiration
 Allows gas exchange to be a continuous
process
 25-30ml/kg
 RDS-FRC low
 MAS-FRC high
Clinical Implications
 PVR- Least at normal FRC
 PVR increases as FRC increases of decreases
 Indicators of normal FRC:
 6-8 intercostal spaces on CXR
 Fall in FiO2 when increasing the PEEP when a
neonate is on CPAP or MV
 CPAP and surfactant—Interventions done to allow
normal FRC in neonatal lungs
OXYGENATION
Oxygenation
 Parameters determining oxygenation
are:
 Mean Airway pressure (directly
proportional)
 FiO2 (directly proportional)
Mean Airway Pressure
 The average pressure exerted on the
airway and the lungs from the beginning
of inspiration until the beginning of
next inspiration
 Most powerful influence on oxygenation
 MAP=K(PIP*Ti)+(PEEP*Te) / Ti+Te
Pressure-Time Graph
MAP is the area
under the curve
for one
respiratory cycle
Slope of pressure
rise is dependent
on flow
K depends on the
slope
High MAP will lead to…
 Decreased cardiac output
 Pulmonary hypoperfusion
 Increased risk of barotrauma
(Levels>12cm H2O contributes to
barotrauma)
Clinical Implications
 MAP can be increased by:
 Increasing PIP
 Increasing PEEP
 Increasing I/E ratio
 Increase the flow rate( converts the
sign wave pressure time graph to a
square wave)
So for increasing oxygenation…
 Prefer increasing MAP when:
 Lung disease is severe (Pneumonia)
 Lung volume is small (RDS)
 Prefer increasing FiO2 when:
 Lung volume is increased(MAS)
 When there is air leak
So lets scratch our heads now…
 PIP=22
 PEEP=4
 Rate=40/min
 IT=.4 sec
 Calculate MAP-??
Lets get it…
 Rate =40/min
 So, one cycle of breath=60/40=1.5 sec
 IT=0.4sec
 So, ET=1.5-0.4=1.1sec
 So, MAP=K(PIP*Ti)+(PEEP*Te) / Ti+Te
 =1(22*0.4)+(4*1.1)/1.5
 =1(8.8)+(4.4)/1.5
 =13.2/1.5
 =8.8cm H20
C02 ELIMINATION
CO2 Elimination
 Depends on MV (alveolar minute volume
more specifically) and RR
 CO2 elimination directly proportional to
alveolar tidal volume and respiratory
rate
 =(PIP-PEEP)*RR
Achieve CO2 elimination by:
 Decreasing dead space
 Excess ET tube
 Secretions
 Partial block
 Increasing PIP
 Increasing rate
 Decreasing PEEP (only if there is lung
hyperinflation)
LETS TRY OUT THESE…
Question 1
1]True about RDS is?
 A] Low compliance, High resistance
 B]High compliance, Low resistance
 C]Low compliance, Normal Resistance
 D]High compliance, High resistance
Question 2
 2]Which of the following will affect
PaCO2 maximum?
 A]Secretions in the ET tube
 B]Respiratory Rate
 C]Tidal volume
 D]Dead space
Question 3
 3] Which is a wrong match?
 A] FRC—PVR
 B] PaO2—MAP
 C] PaCO2—TV
 D] MAP—FiO2
KEY CONCEPTS
Key Concepts
 Compliance is distensibility, resistance
is the oppositional force and time
constant is the time required to empty
the lungs
 Lung tissue determine the compliance,
airways determine the resistance and
both compliance and resistance
determine the time constant
Key Concepts(cont…)
 Ventilation is intermittent but gas
exchange is continuous. Alveolar Minute
Volume is a measure of ventilation and
FRC influences gas exchange
 MAP and FiO2 regulate oxygenation
while alveolar tidal volume and
respiratory rate regulate PaCO2 when a
neonate is on MV
NEONATAL RESPIRATORY MECHANICS

NEONATAL RESPIRATORY MECHANICS

  • 1.
    NEONATAL RESPIRATORY MECHANICS Dr. MurtazaKamal MBBS, MD, DNB Division of Neonatology Department of Pediatrics Safdarjung Hospital &VMMC, New Delhi DOP-07/11/2015
  • 2.
    What is expectedof us post talk??  Compliance  Resistance  Time Constant  Lung Volumes  Oxygenation  CO2 removal  Clinical implications
  • 3.
  • 4.
    Compliance  Measurement ofdistensibility  C= Volume change (V) / Pressure change(P)  Volume change per unit pressure  Lung which is more compliant is more distensible and vice versa
  • 5.
    Clinical Implications In RDS Less compliant lungs  Requires more pressure to ensure tidal volume delivery
  • 6.
    Clinical Implications (cont.) Roleof Surfactant  Improves compliance  Results in a rapid decline in pressures required to deliver the tidal volumes after surfactant administration
  • 7.
    Lets try this 3kg neonate, tidal volume delivered- 14ml, pressure required to drive this volume is PIP of 18 and PEEP of 4  Calculate compliance=??
  • 8.
    So we got… Compliance= Tidal volume/ Pressure gradient =14/ (PIP-PEEP) =14/14 =1ml/cm Hg
  • 9.
    Clinical Implications (cont.) Collapsed/ overstretched lungs poor compliance  PEEP Pressure required to open the lungs and keep it inflated  High PIP (excess pressure) which over distends the lungs, does not result in better volume delivery
  • 10.
    Clinical Implications (cont.) These lung propertiesTypical sigmoid shape curve to pressure-volume loop  Operate on the rapid slope (middle segment) during ventilation  Fig.1
  • 11.
  • 12.
    Resistance  The oppositionalforce for air flow into the lungs  Higher the resistance, greater is the pressure required to drive the gases into the lungs  Depends on:  Airway diameter  Airway length  Viscosity of gas
  • 13.
    Resistance  Resistance isdirectly proportional to:  Length  Viscosity  1/r4  Pressure required to drive 1L/min of gas flow into the lungs
  • 14.
    Clinical Implications  Aslength increases- resistance increases  Eg: long ET tube flow sensor or capnograph  Trim the ET tube to 2.5cm outside the upper lip
  • 15.
    Clinical Implications (cont.) A small decrease in airway diameter causes a large change in resistance  Removal of airway secretions and largest diameter ET tube that fits the glottis to be chosen  Higher air flows increases the resistance by causing turbulence to gas flow
  • 16.
  • 17.
    Time Constant  Timetaken to empty the gases from lungs  It nearly takes 3-5 time constants to completely empty the lungs  Time constant(sec)= Compliance x Resistance
  • 18.
  • 19.
  • 20.
    Clinical Implications RDS:  Lowcompliance, normal resistance  Hence time constant-> less  Time required to inflate (Ti) or deflate (Te) the lungs ->Hence short
  • 21.
    Clinical Implications(cont.) MAS  Resistanceis high, Compliance decreases little bit  Hence, time constant increases  Time required to inflate (Ti) or deflate (Te) the lungs hence is long  A short set expiratory time on ventilator can lead to inadequate lung emptying and hence gas trapping
  • 22.
  • 23.
  • 24.
    Lung Volumes ofour Importance  Tidal volume  Minute volume  Functional residual volume
  • 25.
  • 26.
    Tidal Volume  Volumeof the gas going in and out with each breath  5-8ml/kg  Ideally inspiratory and expiratory tidal volumes are equal
  • 27.
    Clinical Implications  Wheneverperitubal leak during MV, air leaks more during inspiration (higher PIP and wider airways)  Hence, in modes of ventilation where tidal volume is being targeted, it is better to measure the expiratory volume (volume of gas that actually goes to the lungs)
  • 28.
  • 29.
    Dead Space  Respiratorycomponent-  Terminal bronchiole,  Alveolar sacs  Alveoli  Anatomical dead space- Part of tidal volume which is not a part of gas exchange (airways)  2ml/kg
  • 30.
    Dead Space  Somegas in alveoli, due to ill perfusion, is not a part of gas exchange  Physiological dead space- Anatomical+ ill perfused alveoli
  • 31.
    So Tidal Volumeis… Alveolar tidal volume+ Anatomical dead space+ ill perfused alveoli’s vol Alveolar tidal volume+ Physiological dead space
  • 32.
  • 33.
    Minute Volume  Totalvolume of the gas moving in and out of the lungs per minute  MV=TV X RR  200-480 ml/kg/min  Alveolar MV= ??
  • 34.
    Clinical Implications  MV,esp the alveolar MV, is determinant of CO2 removal  Co2 removal hastened either by increasing the TV or rate  Better to increase the TV more energy efficient (Increasing TV--dead space is constant but increasing rate– increases dead space too)
  • 35.
  • 36.
    FRC  Volume ofthe gas present in the lungs at the end of expiration  Allows gas exchange to be a continuous process  25-30ml/kg  RDS-FRC low  MAS-FRC high
  • 37.
    Clinical Implications  PVR-Least at normal FRC  PVR increases as FRC increases of decreases  Indicators of normal FRC:  6-8 intercostal spaces on CXR  Fall in FiO2 when increasing the PEEP when a neonate is on CPAP or MV  CPAP and surfactant—Interventions done to allow normal FRC in neonatal lungs
  • 38.
  • 39.
    Oxygenation  Parameters determiningoxygenation are:  Mean Airway pressure (directly proportional)  FiO2 (directly proportional)
  • 40.
    Mean Airway Pressure The average pressure exerted on the airway and the lungs from the beginning of inspiration until the beginning of next inspiration  Most powerful influence on oxygenation  MAP=K(PIP*Ti)+(PEEP*Te) / Ti+Te
  • 41.
    Pressure-Time Graph MAP isthe area under the curve for one respiratory cycle Slope of pressure rise is dependent on flow K depends on the slope
  • 42.
    High MAP willlead to…  Decreased cardiac output  Pulmonary hypoperfusion  Increased risk of barotrauma (Levels>12cm H2O contributes to barotrauma)
  • 43.
    Clinical Implications  MAPcan be increased by:  Increasing PIP  Increasing PEEP  Increasing I/E ratio  Increase the flow rate( converts the sign wave pressure time graph to a square wave)
  • 44.
    So for increasingoxygenation…  Prefer increasing MAP when:  Lung disease is severe (Pneumonia)  Lung volume is small (RDS)  Prefer increasing FiO2 when:  Lung volume is increased(MAS)  When there is air leak
  • 45.
    So lets scratchour heads now…  PIP=22  PEEP=4  Rate=40/min  IT=.4 sec  Calculate MAP-??
  • 46.
    Lets get it… Rate =40/min  So, one cycle of breath=60/40=1.5 sec  IT=0.4sec  So, ET=1.5-0.4=1.1sec  So, MAP=K(PIP*Ti)+(PEEP*Te) / Ti+Te  =1(22*0.4)+(4*1.1)/1.5  =1(8.8)+(4.4)/1.5  =13.2/1.5  =8.8cm H20
  • 47.
  • 48.
    CO2 Elimination  Dependson MV (alveolar minute volume more specifically) and RR  CO2 elimination directly proportional to alveolar tidal volume and respiratory rate  =(PIP-PEEP)*RR
  • 49.
    Achieve CO2 eliminationby:  Decreasing dead space  Excess ET tube  Secretions  Partial block  Increasing PIP  Increasing rate  Decreasing PEEP (only if there is lung hyperinflation)
  • 50.
    LETS TRY OUTTHESE…
  • 51.
    Question 1 1]True aboutRDS is?  A] Low compliance, High resistance  B]High compliance, Low resistance  C]Low compliance, Normal Resistance  D]High compliance, High resistance
  • 52.
    Question 2  2]Whichof the following will affect PaCO2 maximum?  A]Secretions in the ET tube  B]Respiratory Rate  C]Tidal volume  D]Dead space
  • 53.
    Question 3  3]Which is a wrong match?  A] FRC—PVR  B] PaO2—MAP  C] PaCO2—TV  D] MAP—FiO2
  • 54.
  • 55.
    Key Concepts  Complianceis distensibility, resistance is the oppositional force and time constant is the time required to empty the lungs  Lung tissue determine the compliance, airways determine the resistance and both compliance and resistance determine the time constant
  • 56.
    Key Concepts(cont…)  Ventilationis intermittent but gas exchange is continuous. Alveolar Minute Volume is a measure of ventilation and FRC influences gas exchange  MAP and FiO2 regulate oxygenation while alveolar tidal volume and respiratory rate regulate PaCO2 when a neonate is on MV