This document contains:
1) A key for a quadratic functions test with graphing and solving problems.
2) The test asks students to graph and solve quadratic equations, identify true statements about discriminants and solutions, and solve word problems involving quadratic models.
3) The key provides the full worked out solutions and answers to all problems on the test.
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The software team must secure its software delivery process to avoid vulnerability and security breaches. This needs to be achieved with existing tool chains and without extensive rework of the delivery processes. This talk will present strategies and techniques for providing visibility into the true risk of the existing vulnerabilities, preventing the introduction of security issues in the software, resolving vulnerabilities in production environments quickly, and capturing the deployment bill of materials (DBOM).
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Bob Boule
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1. Insights into SAP testing best practices
2. Heatmap utilization for testing
3. Optimization of testing processes
4. Demo
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Execution from the test manager
Orchestrator execution result
Defect reporting
SAP heatmap example with demo
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The latest edition of the OT/ICS and IoT security Threat Landscape Report 2024 also covers:
State of global ICS asset and network exposure
Sectoral targets and attacks as well as the cost of ransom
Global APT activity, AI usage, actor and tactic profiles, and implications
Rise in volumes of AI-powered cyberattacks
Major cyber events in 2024
Malware and malicious payload trends
Cyberattack types and targets
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Cyber risk predictions
Axis of attacks – Europe
Systemic attacks in the Middle East
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This video focuses on the notifications, alerts, and approval requests using Slack for Bonterra Impact Management. The solutions covered in this webinar can also be deployed for Microsoft Teams.
Interested in deploying notification automations for Bonterra Impact Management? Contact us at sales@sidekicksolutionsllc.com to discuss next steps.
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Watch this recorded webinar about real-time monitoring of application performance. See how to integrate Apache JMeter, the open-source leader in performance testing, with InfluxDB, the open-source time-series database, and Grafana, the open-source analytics and visualization application.
In this webinar, we will review the benefits of leveraging InfluxDB and Grafana when executing load tests and demonstrate how these tools are used to visualize performance metrics.
Length: 30 minutes
Session Overview
-------------------------------------------
During this webinar, we will cover the following topics while demonstrating the integrations of JMeter, InfluxDB and Grafana:
- What out-of-the-box solutions are available for real-time monitoring JMeter tests?
- What are the benefits of integrating InfluxDB and Grafana into the load testing stack?
- Which features are provided by Grafana?
- Demonstration of InfluxDB and Grafana using a practice web application
To view the webinar recording, go to:
https://www.rttsweb.com/jmeter-integration-webinar
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Guy Korland, CEO and Co-founder of FalkorDB, will review two articles on the integration of language models with knowledge graphs.
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https://arxiv.org/abs/2306.08302
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https://www.microsoft.com/en-us/research/blog/graphrag-unlocking-llm-discovery-on-narrative-private-data/
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Are you looking to streamline your workflows and boost your projects’ efficiency? Do you find yourself searching for ways to add flexibility and control over your FME workflows? If so, you’re in the right place.
Join us for an insightful dive into the world of FME parameters, a critical element in optimizing workflow efficiency. This webinar marks the beginning of our three-part “Essentials of Automation” series. This first webinar is designed to equip you with the knowledge and skills to utilize parameters effectively: enhancing the flexibility, maintainability, and user control of your FME projects.
Here’s what you’ll gain:
- Essentials of FME Parameters: Understand the pivotal role of parameters, including Reader/Writer, Transformer, User, and FME Flow categories. Discover how they are the key to unlocking automation and optimization within your workflows.
- Practical Applications in FME Form: Delve into key user parameter types including choice, connections, and file URLs. Allow users to control how a workflow runs, making your workflows more reusable. Learn to import values and deliver the best user experience for your workflows while enhancing accuracy.
- Optimization Strategies in FME Flow: Explore the creation and strategic deployment of parameters in FME Flow, including the use of deployment and geometry parameters, to maximize workflow efficiency.
- Pro Tips for Success: Gain insights on parameterizing connections and leveraging new features like Conditional Visibility for clarity and simplicity.
We’ll wrap up with a glimpse into future webinars, followed by a Q&A session to address your specific questions surrounding this topic.
Don’t miss this opportunity to elevate your FME expertise and drive your projects to new heights of efficiency.
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Let me take this questions and provide you a short journey through existing deployment models and use cases for AI software. On practical examples, we discuss what cloud/on-premise strategy we may need for applying it to our own infrastructure to get it to work from an enterprise perspective. I want to give an overview about infrastructure requirements and technologies, what could be beneficial or limiting your AI use cases in an enterprise environment. An interactive Demo will give you some insides, what approaches I got already working for real.
Kubernetes & AI - Beauty and the Beast !?! @KCD Istanbul 2024
Mth 4108-1 b (ans)
1. MTH-4108 B
Quadratic Functions
ANSWER KEY
1. Graph the following equations. Be sure to include the coordinates of at least 5
points, including the vertex, the zeros (if any), axis of symmetry and the y-
intercept.
a) y = 1/3x2 – 5
y
−b −∆
,
2a 4a
Vertex: 0 − 6.667
,
0.667 1.333
( 0,−5)
−b± ∆
x
2a
Zeros: 0 ± 6.667
1.33
{ − 1.936,1.936}
y = 0.333(0) − 5
y-intercept:
y = −5
b) y = 4/5x2 – 5x + 8.5
y
Vertex:
−b −∆
,
2a 4a
5 − ( 25 − 4( 0.8)( 8.5) )
,
1.6 3.2
( 3.125,0.6875)
x −b± ∆
2a
Zeros: 5 ± − 2.2
1.6
{ ∅}
y-intercept:
y = 0.8(0) − 5(0) + 8.5
y = 8.5
2. Vertex:
c) y = –0.2x2 + x – 3 −b −∆
,
y 2a 4a
− 1 − (1 − 4( − 0.2)( − 3) )
,
− 0.4 − 0.8
( 2.5,−1.75)
−b± ∆
2a
Zeros: − 1 ± − 1.4
x
− 0.4
{ ∅}
y-intercept:
y = −0.2(0) + 1(0) − 3
y = −3
/30
2. Solve the following equations by factoring:
a) 49x2 – 169 = 0 ( 7 x − 13) ⇒ 7 x = 13 ⇒ x = 13 7 = 1.857
( 7 x + 13) ⇒ 7 x = −13 ⇒ x = − 13 7 = −1.857
b) 1/4x2 – 6x + 20 = 0 1 2
x − x − 5 x + 20 = 0
4
1
x( x − 4) − 5( x − 4)
4
1 1
x − 5 ⇒ x = 5 ⇒ x = 20
4 4
( x − 4) ⇒ x = 4 /5
3. Identify the true statement(s) below:
a) If ∆ = 0 for a quadratic equation, it means that there is one solution and it
is equal to 0. FALSE
b) If the discriminant is less than 0, it means that there are two real solutions
for this equation.
FALSE
c) If an equation has two zeros, one postitive and one negative, it means that ∆ is
negative.
FALSE
d) If an equation has one negative solution, it is impossible that the other
solution is also negative if ∆ > 0. FALSE
e) If the discriminant is equal to zero then the equation has two solutions.
FALSE
/5
3. 4. Solve the following equations using the quadratic formula. Clearly indicate the
value of ∆ and round your answers to the nearest thousandth when necessary.
a) 3.6x2 + 3.1x – 1 = 0 Zeros:
−b± ∆
2a
− 3.1 ± ( 9.61 − 4( 3.6 )( − 1) )
7.2
{ − 1.111,0.25}
b) -1x2 + 5x – 24 = 0
Zeros:
6
−b± ∆
2a
− 5 ± ( 25 − 4( − 0.1667 )( − 24 ) )
− 0.333
{ 6,24}
/10
5. Marjorie makes friendship bracelets and sells them for a profit of $4.50. She must
sell at least 10 bracelets to break even. For each additional bracelet she sells, she
can offer the buyer a discount of $0.15. The table below illustrates the her total
profit as a function of how many bracelets she sells.
No. of additional Number of Discount price Total profit
bracelets sold bracelets sold
0 10 4.50 – (0.15 × 0) 10 × 4.50 = 45.00
1 10 + 1 = 11 4.50 – (0.15 × 1) = 4.35 11 × 4.35 = 47.85
2 10 + 2 = 12 4.50 – (0.15 × 2) = 4.20 12 × 4.20 = 50.40
x 10 + x 4.50 – (0.15 × x) (10 + x)(4.5 – 0.15x)
Write the equation in the form ax2 + bx + c which illustrates this situation.
(10 + x )( 4.5 − 0.15 x )
45 + 1.5 x + 4.5 x + 0.15 x 2
y = 0.15 x 2 + 6 x + 45 /10
6. Without calculating, write the equation in the form ax2 + bx + c which illustrates
the following situation:
The sum of the squares of two consecutive even numbers is 1060. What are the
two numbers?
Let x = 1st number
Let x + 1 = 2nd number
x 2 + ( x + 1) = 1060
2
/5
x 2 + x 2 + 2 x + 1 = 1060
2 x 2 + 2 x − 1059 = 0
4. 7. Answer the following questions using the graph below: y = –x2 + 2x + 8
y
x
a) What are the coordinates of the vertex? Vertex:
− b − ∆ − 2 − ( 4 − 4( − 1)( 8) )
, ⇒ , ⇒ (1,9 )
2a 4a − 2 −4
b) What is the equation of the axis of symmetry? x=1
c) Is there a maximum or a minimum?
Maximum of 9
d) What are the zeros?
−b± ∆ − 2 ± 36
Zeros: ⇒ ⇒ { − 2,4}
2a −2
e) What is the y-intercept?
y-intercept: y = −1(0) + 2(0) + 8 ⇒ y = 8
/5
8. The small diagonal of a rhombus measures 2 cm more than one quarter of the
large diagonal. The area of the rhombus is 66.56 cm2. What are the measurements
of the small diagonal and the large diagonal of this rhombus?
Let x = LARGE diagonal
Let ¼x + 2 = small diagonal
−b± ∆
(
x 1 x+2 ) 2a
4
2
= 66.56 −2± 4−4 1 ( 4 )( − 133.12)
1 x 2 + 2 x = 133.12 Zeros: 0.5
4
1 x 2 + 2 x − 133.12 = 0 − 3 ± 137.12
4 0.5
{ − 29.4196,17.4196}
0.25(17.4196) + 2 = 6.3549
ANS: 17.4196 cm and 6.3549 cm /5
5. 9. A school superintendent is deciding on how many students per class there should
be. The classes are 120 minutes long, with a certain number of students in each
room. If 10 students are added to the classes, the time spent per student declines
by 1 minute. How many students are in the room?
Let x = number of students in the classroom
−b± ∆
120 120
−1 = 2a
x x + 10
120 − x 120 − 10 ± 100 − 4(1)( − 1200 )
= Zeros: 2
x x + 10
120 x + 1200 − x 2 − 10 x = 120 x − 10 ± 70
2
x 2 + 10 x − 1200 = 0
{ − 40,30}
ANS: There are 30 students in the classroom.
/10
10. A hot air balloon lifts off the ground from the point (2, 0). The equation of the
height (y) of the balloon in metres is: y = –t2 + 38t – 72 where t represents the time
in minutes.
a) What is the maximum height obtained by the balloon?
Vertex:
− b − ∆ − 38 − (1444 − 4( − 1)( − 72 ) )
, ⇒ , ⇒ (19,289 )
2a 4a − 2 −4
b) After how many seconds is the maximum height obtained?
Vertex:
− b − ∆ − 38 − (1444 − 4( − 1)( − 72 ) )
, ⇒ , ⇒ (19,289 )
2a 4a − 2 −4
c) How many minutes is the balloon in the air?
−b± ∆ − 8.75 ± 1444 − 4( −1)(−72) − 38 ± 1156
⇒ ⇒
Zeros: 2a −2 −2
{ 2,36}
ANS: The balloon is in the air for 34 minutes.
Round your answers to the nearest hundredth.
/15