Magnifying glass
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This document discusses magnifying glasses and their use. It explains that magnifying glasses produce enlarged images of objects and can be used to ignite paper by concentrating sunlight. Ray tracing is used to demonstrate how a convex lens forms an upright, magnified virtual image between the lens and its focal point. The document provides an example problem using ray tracing to determine the location and size of an image formed by a magnifying glass positioned 10 cm from a 1 cm object, finding the image is located 15 cm from the lens and is 3 cm tall.
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Magnifying glass
- 1. BY DZ
- 2. PURPOSE LEARNING After learnt optical instruments, student able to identify the principle application of the magnifying glass, The students can use the magnifying glass well
- 3. MAGNIFYING GLASS Magnifying glasses normally are used to produce images that are larger than the related objects, but they also can produce images that are smaller than the related objects
- 4. A converging lens can be used to ignite paper (a). Light entering parallel to the principal axis converges at the focal point of the lens, concentrating solar energy
- 5. The two principal rays show that a convex lens forms a virtual image that is upright and larger compared to the object when the object is located between the lens and the focal point. Because the principal rays are simply part of a model to help locate an image, they do not have to pass through the picture of the lens in a diagram. In reality, the image is formed only by the light that passes through the actual lens.
- 6. Look at the picture
- 7. Magnification of the magnifying glasses Observe with the accommodation eyes 𝑆𝑛 M= +1 𝑓 Observe with non accommodation eyes 𝑆𝑛 M= 𝑓
- 8. Example problem A magnifier with a focal length of 30 cm is used to view a 1-cm- tall object. Use ray tracing to determine the location and size of the image when the magnifier is positioned 10 cm from the object.
- 9. THE ANSWER Analyze and Sketch the Problem • Sketch the situation, locating the object and the lens. • Draw the two principal rays. Known: Unknown: do 10.0 cm di ? ho 1.0 cm hi ? f 30.0 cm
- 10. a. Use the thin lens to determine d1 1 𝑓 = 1 𝑑1 do = = + 1 𝑑0 𝑓𝑑 𝑜 𝑑 𝑜−𝑓 (30 𝑐𝑚)(10 𝑐𝑚) (10 𝑐𝑚) −(30 𝑐𝑚) = - 15 cm( 15 cm away from the lens on the side opposite the object)
- 11. Use the magnification equation and solve for image height. M= h1 = ℎ1 −𝑑1 = ℎ0 𝑑0 −𝑑1.ℎ0 𝑑𝑜 = −(−15 𝑐𝑚)(2 𝑐𝑚) 10 𝑐𝑚 = 3 cm (3 cm tall) The positive means that the image is erect.
- 12. ConcluSion The image which is formed by magnifying glass is a virtual, erect and magnified.
- 13. Thank you for your attention…