Learning Object Physics 101

1. Mass On A Horizontal
Spring Clicker Question
Series
By: Jasmeen Dhaliwal
Section: LM2
Student #: 26368143

2. Compare the Energy’s of the Two
Systems
System A System B
a)Both systems have the same energy
b)System A has four times the energy of System B
c)System A has double the energy of System B
d)System B has double the energy of System A
e)System B has four times the energy of System A
Volume=V
Density=ρ
K=2K
A=A
Volume=V
Density=2ρ
K=K
A=2A

3. Answer: D
Solution:
Energy=(1/2)K(A)2
System A
Energy=(1/2)(2K)(A)2=K(A)2
System B
Energy=(1/2)(K)(2A)2=2K(A)2
System B has double the energy than that of System A.
Notice that the Amplitude of a system has a greater
impact on the total energy of the system as oppose to the
spring constant.

4. Compare the Angular Velocity’s of the
Two Systems
System A System B
a)System A has double the ω of System B
b)System B has double the ω of System A
c)Both systems have the same ω
d)System B has four times the ω of System A
e)System A has four times the ω of System B
Volume=V
Density=ρ
K=2K
A=A
Volume=V
Density=2ρ
K=K
A=2A

5. Answer: ESolution:
ω =(k/m)1/2
System A
ω =(k/m)1/2=(2k/ρv)1/2
System B
ω =(k/m)1/2=(k/2ρv)1/2
System A has double the angular velocity than that of
System B. This is interesting because we would usually
assume that a system with greater energy would have
greater angular velocity. However if you recall the
amplitude of System B is greater and System’s B greater
energy would be a result of a greater potential energy.

6. Which System Has A Greater Period
System A System B
a)System A
b)System B
c)Both have the same period
Volume=V
Density=ρ
K=2K
A=A
Volume=V
Density=2ρ
K=K
A=2A

7. Answer: B
Solution:
T=2π(m/k)1/2
System A
T=2π(m/k)1/2=2π(ρv/2k)1/2
System B
T=2π(m/k)1/2=2π(2ρv/k)1/2
The spring constant and the mass of the object
determine a spring systems period. As we can see the
greater mass and the smaller spring constant of System
B results in a greater period.