This Presentation will Use to develop your knowledge and doubts in Knapsack problem. This Slide also include Memory function part. Use this Slides to Develop your knowledge on Knapsack and Memory function
The document discusses the knapsack problem, which involves selecting a subset of items that fit within a knapsack of limited capacity to maximize the total value. There are two versions - the 0-1 knapsack problem where items can only be selected entirely or not at all, and the fractional knapsack problem where items can be partially selected. Solutions include brute force, greedy algorithms, and dynamic programming. Dynamic programming builds up the optimal solution by considering all sub-problems.
This presentation discusses the knapsack problem and its two main versions: 0/1 and fractional. The 0/1 knapsack problem involves indivisible items that are either fully included or not included, and is solved using dynamic programming. The fractional knapsack problem allows items to be partially included, and is solved using a greedy algorithm. Examples are provided of solving each version using their respective algorithms. The time complexity of these algorithms is also presented. Real-world applications of the knapsack problem include cutting raw materials and selecting investments.
The document discusses the knapsack problem and greedy algorithms. It defines the knapsack problem as an optimization problem where given constraints and an objective function, the goal is to find the feasible solution that maximizes or minimizes the objective. It describes the knapsack problem has having two versions: 0-1 where items are indivisible, and fractional where items can be divided. The fractional knapsack problem can be solved using a greedy approach by sorting items by value to weight ratio and filling the knapsack accordingly until full.
The document discusses the 0-1 knapsack problem and how it can be solved using dynamic programming. It first defines the 0-1 knapsack problem and provides an example. It then explains how a brute force solution would work in exponential time. Next, it describes how to define the problem as subproblems and derive a recursive formula to solve the subproblems in a bottom-up manner using dynamic programming. This builds up the solutions in a table and solves the problem in polynomial time. Finally, it walks through an example applying the dynamic programming algorithm to a sample problem instance.
Knapsack problem ==>>
Given some items, pack the knapsack to get
the maximum total value. Each item has some
weight and some value. Total weight that we can
carry is no more than some fixed number W.
So we must consider weights of items as well as
their values.
The document discusses the 0/1 knapsack problem and dynamic programming algorithm to solve it. The 0/1 knapsack problem involves selecting a subset of items to pack in a knapsack that maximizes the total value without exceeding the knapsack's weight capacity. The dynamic programming algorithm solves this by building up a table where each entry represents the maximum value for a given weight. It iterates through items, checking if including each item increases the maximum value for that weight.
The document discusses the knapsack problem, which involves selecting a subset of items that fit within a knapsack of limited capacity to maximize the total value. There are two versions - the 0-1 knapsack problem where items can only be selected entirely or not at all, and the fractional knapsack problem where items can be partially selected. Solutions include brute force, greedy algorithms, and dynamic programming. Dynamic programming builds up the optimal solution by considering all sub-problems.
This presentation discusses the knapsack problem and its two main versions: 0/1 and fractional. The 0/1 knapsack problem involves indivisible items that are either fully included or not included, and is solved using dynamic programming. The fractional knapsack problem allows items to be partially included, and is solved using a greedy algorithm. Examples are provided of solving each version using their respective algorithms. The time complexity of these algorithms is also presented. Real-world applications of the knapsack problem include cutting raw materials and selecting investments.
The document discusses the knapsack problem and greedy algorithms. It defines the knapsack problem as an optimization problem where given constraints and an objective function, the goal is to find the feasible solution that maximizes or minimizes the objective. It describes the knapsack problem has having two versions: 0-1 where items are indivisible, and fractional where items can be divided. The fractional knapsack problem can be solved using a greedy approach by sorting items by value to weight ratio and filling the knapsack accordingly until full.
The document discusses the 0-1 knapsack problem and how it can be solved using dynamic programming. It first defines the 0-1 knapsack problem and provides an example. It then explains how a brute force solution would work in exponential time. Next, it describes how to define the problem as subproblems and derive a recursive formula to solve the subproblems in a bottom-up manner using dynamic programming. This builds up the solutions in a table and solves the problem in polynomial time. Finally, it walks through an example applying the dynamic programming algorithm to a sample problem instance.
Knapsack problem ==>>
Given some items, pack the knapsack to get
the maximum total value. Each item has some
weight and some value. Total weight that we can
carry is no more than some fixed number W.
So we must consider weights of items as well as
their values.
The document discusses the 0/1 knapsack problem and dynamic programming algorithm to solve it. The 0/1 knapsack problem involves selecting a subset of items to pack in a knapsack that maximizes the total value without exceeding the knapsack's weight capacity. The dynamic programming algorithm solves this by building up a table where each entry represents the maximum value for a given weight. It iterates through items, checking if including each item increases the maximum value for that weight.
The document provides an introduction to the knapsack problem. It defines the knapsack problem as determining the number of each item to include in a collection so that the total weight is less than or equal to a given limit and the total value is as large as possible, given a set of items each with a mass and value. It notes there are two versions: the 0-1 knapsack problem, where items are indivisible and you either take an item or not, and the fractional knapsack problem, where items are divisible and you can take fractions of items.
Knapsack problem using dynamic programmingkhush_boo31
The document describes the 0-1 knapsack problem and provides an example of solving it using dynamic programming. Specifically, it defines the 0-1 knapsack problem, provides the formula for solving it dynamically using a 2D array C, walks through populating the C array and backtracking to find the optimal solution for a sample problem instance, and analyzes the time complexity of the dynamic programming algorithm.
The 0-1 knapsack problem involves selecting items with given values and weights to maximize the total value without exceeding a weight capacity. It can be solved using a brute force approach in O(2^n) time or dynamic programming in O(n*c) time. Dynamic programming constructs a value matrix where each cell represents the maximum value for a given item and weight. The cell value is either from the item above or adding the item's value if the weight is less than remaining capacity. The last cell provides the maximum value solution.
Given weights and values of n items, put these items in a knapsack of capacity W to get the maximum total value in the knapsack. In other words, given two integer arrays val[0..n-1] and wt[0..n-1] which represent values and weights associated with n items respectively. Also given an integer W which represents knapsack capacity, find out the maximum value subset of val[] such that sum of the weights of this subset is smaller than or equal to W. You cannot break an item, either pick the complete item or don’t pick it (0-1 property).
Method 1: Recursion by Brute-Force algorithm OR Exhaustive Search.
Approach: A simple solution is to consider all subsets of items and calculate the total weight and value of all subsets. Consider the only subsets whose total weight is smaller than W. From all such subsets, pick the maximum value subset.
Optimal Sub-structure: To consider all subsets of items, there can be two cases for every item.
Case 1: The item is included in the optimal subset.
Case 2: The item is not included in the optimal set.
Therefore, the maximum value that can be obtained from ‘n’ items is the max of the following two values.
Maximum value obtained by n-1 items and W weight (excluding nth item).
Value of nth item plus maximum value obtained by n-1 items and W minus the weight of the nth item (including nth item).
If the weight of the ‘nth’ item is greater than ‘W’, then the nth item cannot be included and Case 1 is the only possibility.
This document discusses the greedy algorithm approach and the knapsack problem. It defines greedy algorithms as choosing locally optimal solutions at each step in hopes of reaching a global optimum. The knapsack problem is described as packing items into a knapsack to maximize total value without exceeding weight capacity. An optimal knapsack algorithm is presented that sorts by value-to-weight ratio and fills highest ratios first. An example applies this to maximize profit of 440 by selecting full quantities of items B and A, and half of item C for a knapsack with capacity of 60.
The document presents an overview of fractional and 0/1 knapsack problems. It defines the fractional knapsack problem as choosing items with maximum total benefit but fractional amounts allowed, with total weight at most W. An algorithm is provided that takes the item with highest benefit-to-weight ratio in each step. The 0/1 knapsack problem requires choosing whole items. Solutions like greedy and dynamic programming are discussed. An example illustrates applying dynamic programming to a sample 0/1 knapsack problem.
Given two integer arrays val[0...n-1] and wt[0...n-1] that represents values and weights associated with n items respectively. Find out the maximum value subset of val[] such that sum of the weights of this subset is smaller than or equal to knapsack capacity W. Here the BRANCH AND BOUND ALGORITHM is discussed .
Greedy algorithms work by making locally optimal choices at each step to arrive at a global optimal solution. They require that the problem exhibits the greedy choice property and optimal substructure. Examples that can be solved with greedy algorithms include fractional knapsack problem, minimum spanning tree, and activity selection. The fractional knapsack problem is solved greedily by sorting items by value/weight ratio and filling the knapsack completely. The 0/1 knapsack problem differs in that items are indivisible.
The document describes the traveling salesman problem (TSP) and how to solve it using a branch and bound approach. The TSP aims to find the shortest route for a salesman to visit each city once and return to the starting city. It can be represented as a weighted graph. The branch and bound method involves reducing the cost matrix by subtracting minimum row/column values, building a state space tree of paths, and choosing the path with the lowest cost at each step. An example demonstrates these steps to find the optimal solution of 24 for a 5 city TSP problem.
The document discusses two types of knapsack problems - the 0-1 knapsack problem and the fractional knapsack problem. The 0-1 knapsack problem uses dynamic programming to determine how to fill a knapsack to maximize the total value of items without exceeding the knapsack's weight limit, where each item is either fully included or not included. The fractional knapsack problem allows partial inclusion of items and can be solved greedily by always including a fraction of the highest value per unit weight item until the knapsack is full.
The document discusses the divide and conquer algorithm design technique. It begins by explaining the basic approach of divide and conquer which is to (1) divide the problem into subproblems, (2) conquer the subproblems by solving them recursively, and (3) combine the solutions to the subproblems into a solution for the original problem. It then provides merge sort as a specific example of a divide and conquer algorithm for sorting a sequence. It explains that merge sort divides the sequence in half recursively until individual elements remain, then combines the sorted halves back together to produce the fully sorted sequence.
The document discusses the sum of subsets problem, which involves finding all subsets of positive integers that sum to a given number. It describes the problem, provides an example, and explains that backtracking can be used to systematically consider subsets. A pruned state space tree is shown for a sample problem to illustrate the backtracking approach. An algorithm for the backtracking solution to the sum of subsets problem is presented.
This document discusses greedy algorithms and dynamic programming techniques for solving optimization problems. It covers the activity selection problem, which can be solved greedily by always selecting the shortest remaining activity. It also discusses the knapsack problem and how the fractional version can be solved greedily while the 0-1 version requires dynamic programming due to its optimal substructure but non-greedy nature. Dynamic programming builds up solutions by combining optimal solutions to overlapping subproblems.
- NP-hard problems are at least as hard as problems in NP. A problem is NP-hard if any problem in NP can be reduced to it in polynomial time.
- Cook's theorem states that if the SAT problem can be solved in polynomial time, then every problem in NP can be solved in polynomial time.
- Vertex cover problem is proven to be NP-hard by showing that independent set problem reduces to it in polynomial time, meaning there is a polynomial time algorithm that converts any instance of independent set into an instance of vertex cover.
- Therefore, if there was a polynomial time algorithm for vertex cover, it could be used to solve independent set in polynomial time. Since independent set is NP-complete
The document discusses divide and conquer algorithms. It describes divide and conquer as a design strategy that involves dividing a problem into smaller subproblems, solving the subproblems recursively, and combining the solutions. It provides examples of divide and conquer algorithms like merge sort, quicksort, and binary search. Merge sort works by recursively sorting halves of an array until it is fully sorted. Quicksort selects a pivot element and partitions the array into subarrays of smaller and larger elements, recursively sorting the subarrays. Binary search recursively searches half-intervals of a sorted array to find a target value.
This document discusses two methods for finding the maximum and minimum values in an array: the naive method and divide and conquer approach. The naive method compares all elements to find the max and min in 2n-2 comparisons. The divide and conquer approach recursively divides the array in half, finds the max and min of each half, and returns the overall max and min, reducing the number of comparisons. Pseudocode is provided for the MAXMIN algorithm that implements this divide and conquer solution.
1) NP-Completeness refers to problems that are in NP (can be verified in polynomial time) and are as hard as any problem in NP.
2) The first problem proven to be NP-Complete was the Circuit Satisfiability problem, which asks whether there exists an input assignment that makes a Boolean circuit output 1.
3) To prove a problem P is NP-Complete, it must be shown that P is in NP and that any problem in NP can be reduced to P in polynomial time. This establishes P as at least as hard as any problem in NP.
The document discusses the all pairs shortest path problem, which aims to find the shortest distance between every pair of vertices in a graph. It explains that the algorithm works by calculating the minimum cost to traverse between nodes using intermediate nodes, according to the equation A_k(i,j)=min{A_{k-1}(i,j), A_{k-1}(i,k), A_{k-1}(k,j)}. An example is provided to illustrate calculating the shortest path between nodes over multiple iterations of the algorithm.
The document discusses the 0-1 knapsack problem and provides an example of solving it using dynamic programming. The 0-1 knapsack problem aims to maximize the total value of items selected from a list that have a total weight less than or equal to the knapsack's capacity, where each item must either be fully included or excluded. The document outlines a dynamic programming algorithm that builds a table to store the maximum value for each item subset at each possible weight, recursively considering whether or not to include each additional item.
This document discusses dynamic programming and its application to solve the knapsack problem.
It begins by defining dynamic programming as a technique for solving problems with overlapping subproblems where each subproblem is solved only once and the results are stored in a table.
It then defines the knapsack problem as selecting a subset of items with weights and values that fit in a knapsack of capacity W to maximize the total value.
The document shows how to solve the knapsack problem using dynamic programming by constructing a table where each entry table[i,j] represents the maximum value for items 1 to i with weight ≤ j. It provides an example problem and walks through filling the table and backtracking to find
The document provides an introduction to the knapsack problem. It defines the knapsack problem as determining the number of each item to include in a collection so that the total weight is less than or equal to a given limit and the total value is as large as possible, given a set of items each with a mass and value. It notes there are two versions: the 0-1 knapsack problem, where items are indivisible and you either take an item or not, and the fractional knapsack problem, where items are divisible and you can take fractions of items.
Knapsack problem using dynamic programmingkhush_boo31
The document describes the 0-1 knapsack problem and provides an example of solving it using dynamic programming. Specifically, it defines the 0-1 knapsack problem, provides the formula for solving it dynamically using a 2D array C, walks through populating the C array and backtracking to find the optimal solution for a sample problem instance, and analyzes the time complexity of the dynamic programming algorithm.
The 0-1 knapsack problem involves selecting items with given values and weights to maximize the total value without exceeding a weight capacity. It can be solved using a brute force approach in O(2^n) time or dynamic programming in O(n*c) time. Dynamic programming constructs a value matrix where each cell represents the maximum value for a given item and weight. The cell value is either from the item above or adding the item's value if the weight is less than remaining capacity. The last cell provides the maximum value solution.
Given weights and values of n items, put these items in a knapsack of capacity W to get the maximum total value in the knapsack. In other words, given two integer arrays val[0..n-1] and wt[0..n-1] which represent values and weights associated with n items respectively. Also given an integer W which represents knapsack capacity, find out the maximum value subset of val[] such that sum of the weights of this subset is smaller than or equal to W. You cannot break an item, either pick the complete item or don’t pick it (0-1 property).
Method 1: Recursion by Brute-Force algorithm OR Exhaustive Search.
Approach: A simple solution is to consider all subsets of items and calculate the total weight and value of all subsets. Consider the only subsets whose total weight is smaller than W. From all such subsets, pick the maximum value subset.
Optimal Sub-structure: To consider all subsets of items, there can be two cases for every item.
Case 1: The item is included in the optimal subset.
Case 2: The item is not included in the optimal set.
Therefore, the maximum value that can be obtained from ‘n’ items is the max of the following two values.
Maximum value obtained by n-1 items and W weight (excluding nth item).
Value of nth item plus maximum value obtained by n-1 items and W minus the weight of the nth item (including nth item).
If the weight of the ‘nth’ item is greater than ‘W’, then the nth item cannot be included and Case 1 is the only possibility.
This document discusses the greedy algorithm approach and the knapsack problem. It defines greedy algorithms as choosing locally optimal solutions at each step in hopes of reaching a global optimum. The knapsack problem is described as packing items into a knapsack to maximize total value without exceeding weight capacity. An optimal knapsack algorithm is presented that sorts by value-to-weight ratio and fills highest ratios first. An example applies this to maximize profit of 440 by selecting full quantities of items B and A, and half of item C for a knapsack with capacity of 60.
The document presents an overview of fractional and 0/1 knapsack problems. It defines the fractional knapsack problem as choosing items with maximum total benefit but fractional amounts allowed, with total weight at most W. An algorithm is provided that takes the item with highest benefit-to-weight ratio in each step. The 0/1 knapsack problem requires choosing whole items. Solutions like greedy and dynamic programming are discussed. An example illustrates applying dynamic programming to a sample 0/1 knapsack problem.
Given two integer arrays val[0...n-1] and wt[0...n-1] that represents values and weights associated with n items respectively. Find out the maximum value subset of val[] such that sum of the weights of this subset is smaller than or equal to knapsack capacity W. Here the BRANCH AND BOUND ALGORITHM is discussed .
Greedy algorithms work by making locally optimal choices at each step to arrive at a global optimal solution. They require that the problem exhibits the greedy choice property and optimal substructure. Examples that can be solved with greedy algorithms include fractional knapsack problem, minimum spanning tree, and activity selection. The fractional knapsack problem is solved greedily by sorting items by value/weight ratio and filling the knapsack completely. The 0/1 knapsack problem differs in that items are indivisible.
The document describes the traveling salesman problem (TSP) and how to solve it using a branch and bound approach. The TSP aims to find the shortest route for a salesman to visit each city once and return to the starting city. It can be represented as a weighted graph. The branch and bound method involves reducing the cost matrix by subtracting minimum row/column values, building a state space tree of paths, and choosing the path with the lowest cost at each step. An example demonstrates these steps to find the optimal solution of 24 for a 5 city TSP problem.
The document discusses two types of knapsack problems - the 0-1 knapsack problem and the fractional knapsack problem. The 0-1 knapsack problem uses dynamic programming to determine how to fill a knapsack to maximize the total value of items without exceeding the knapsack's weight limit, where each item is either fully included or not included. The fractional knapsack problem allows partial inclusion of items and can be solved greedily by always including a fraction of the highest value per unit weight item until the knapsack is full.
The document discusses the divide and conquer algorithm design technique. It begins by explaining the basic approach of divide and conquer which is to (1) divide the problem into subproblems, (2) conquer the subproblems by solving them recursively, and (3) combine the solutions to the subproblems into a solution for the original problem. It then provides merge sort as a specific example of a divide and conquer algorithm for sorting a sequence. It explains that merge sort divides the sequence in half recursively until individual elements remain, then combines the sorted halves back together to produce the fully sorted sequence.
The document discusses the sum of subsets problem, which involves finding all subsets of positive integers that sum to a given number. It describes the problem, provides an example, and explains that backtracking can be used to systematically consider subsets. A pruned state space tree is shown for a sample problem to illustrate the backtracking approach. An algorithm for the backtracking solution to the sum of subsets problem is presented.
This document discusses greedy algorithms and dynamic programming techniques for solving optimization problems. It covers the activity selection problem, which can be solved greedily by always selecting the shortest remaining activity. It also discusses the knapsack problem and how the fractional version can be solved greedily while the 0-1 version requires dynamic programming due to its optimal substructure but non-greedy nature. Dynamic programming builds up solutions by combining optimal solutions to overlapping subproblems.
- NP-hard problems are at least as hard as problems in NP. A problem is NP-hard if any problem in NP can be reduced to it in polynomial time.
- Cook's theorem states that if the SAT problem can be solved in polynomial time, then every problem in NP can be solved in polynomial time.
- Vertex cover problem is proven to be NP-hard by showing that independent set problem reduces to it in polynomial time, meaning there is a polynomial time algorithm that converts any instance of independent set into an instance of vertex cover.
- Therefore, if there was a polynomial time algorithm for vertex cover, it could be used to solve independent set in polynomial time. Since independent set is NP-complete
The document discusses divide and conquer algorithms. It describes divide and conquer as a design strategy that involves dividing a problem into smaller subproblems, solving the subproblems recursively, and combining the solutions. It provides examples of divide and conquer algorithms like merge sort, quicksort, and binary search. Merge sort works by recursively sorting halves of an array until it is fully sorted. Quicksort selects a pivot element and partitions the array into subarrays of smaller and larger elements, recursively sorting the subarrays. Binary search recursively searches half-intervals of a sorted array to find a target value.
This document discusses two methods for finding the maximum and minimum values in an array: the naive method and divide and conquer approach. The naive method compares all elements to find the max and min in 2n-2 comparisons. The divide and conquer approach recursively divides the array in half, finds the max and min of each half, and returns the overall max and min, reducing the number of comparisons. Pseudocode is provided for the MAXMIN algorithm that implements this divide and conquer solution.
1) NP-Completeness refers to problems that are in NP (can be verified in polynomial time) and are as hard as any problem in NP.
2) The first problem proven to be NP-Complete was the Circuit Satisfiability problem, which asks whether there exists an input assignment that makes a Boolean circuit output 1.
3) To prove a problem P is NP-Complete, it must be shown that P is in NP and that any problem in NP can be reduced to P in polynomial time. This establishes P as at least as hard as any problem in NP.
The document discusses the all pairs shortest path problem, which aims to find the shortest distance between every pair of vertices in a graph. It explains that the algorithm works by calculating the minimum cost to traverse between nodes using intermediate nodes, according to the equation A_k(i,j)=min{A_{k-1}(i,j), A_{k-1}(i,k), A_{k-1}(k,j)}. An example is provided to illustrate calculating the shortest path between nodes over multiple iterations of the algorithm.
The document discusses the 0-1 knapsack problem and provides an example of solving it using dynamic programming. The 0-1 knapsack problem aims to maximize the total value of items selected from a list that have a total weight less than or equal to the knapsack's capacity, where each item must either be fully included or excluded. The document outlines a dynamic programming algorithm that builds a table to store the maximum value for each item subset at each possible weight, recursively considering whether or not to include each additional item.
This document discusses dynamic programming and its application to solve the knapsack problem.
It begins by defining dynamic programming as a technique for solving problems with overlapping subproblems where each subproblem is solved only once and the results are stored in a table.
It then defines the knapsack problem as selecting a subset of items with weights and values that fit in a knapsack of capacity W to maximize the total value.
The document shows how to solve the knapsack problem using dynamic programming by constructing a table where each entry table[i,j] represents the maximum value for items 1 to i with weight ≤ j. It provides an example problem and walks through filling the table and backtracking to find
The document describes the 0-1 knapsack problem and how to solve it using dynamic programming. The 0-1 knapsack problem involves packing items of different weights and values into a knapsack of maximum capacity to maximize the total value without exceeding the weight limit. A dynamic programming algorithm is presented that breaks the problem down into subproblems and uses optimal substructure and overlapping subproblems to arrive at the optimal solution in O(nW) time, improving on the brute force O(2^n) time. An example is shown step-by-step to illustrate the algorithm.
Design and analysis of Algorithms - Lecture 15.pptQurbanAli72
The document describes the 0/1 knapsack problem, which involves selecting a subset of items to pack in a knapsack without exceeding the knapsack's weight limit, in order to maximize the total value of the items. It presents a dynamic programming algorithm that solves the problem in polynomial time by building up the optimal solution for subproblems. The algorithm fills a two-dimensional table where each entry represents the maximum value achievable for a given subset of items with a particular remaining weight capacity.
0 1 knapsack using naive recursive approach and top-down dynamic programming ...Abhishek Singh
This slide contains 0-1 knapsack problem using naive recursive approach and using top-down dynamic programming approach. Here we have used memorization to optimize the recursive approach.
The document describes the 0-1 knapsack problem and provides an example of solving it using dynamic programming. The 0-1 knapsack problem involves packing items into a knapsack of maximum capacity W to maximize the total value of packed items, where each item has a weight and value. The document defines the problem as a recursive subproblem and provides pseudocode for a dynamic programming algorithm that runs in O(nW) time, improving on the brute force O(2^n) time. It then works through an example application of the algorithm to a sample problem with 4 items and knapsack capacity of 5.
Dynamic programming is a technique for solving problems with overlapping subproblems by breaking them down into smaller subproblems and storing the results of already solved subproblems in a table to build up the solution. It was developed in the 1950s and involves setting up recurrences relating solutions to larger instances to smaller instances and solving the smaller instances once to extract the solution. Examples given include computing the nth Fibonacci number and solving the knapsack problem by filling a table and using solutions to smaller capacities and numbers of items.
The document discusses different types of knapsack problems. It provides an example of a 0/1 knapsack problem where items must either be fully included or excluded from a knapsack with limited capacity. Brute force and greedy algorithms are presented as approaches to solve such problems. The document also briefly introduces fractional knapsack problems and provides pseudocode for a greedy algorithm solution.
The document discusses the 0-1 knapsack problem and presents a dynamic programming algorithm to solve it. The 0-1 knapsack problem aims to maximize the total value of items selected without exceeding the knapsack's weight capacity, where each item must either be fully included or excluded. The algorithm uses a table B to store the maximum value for each sub-problem of filling weight w with the first i items, calculating entries recursively to find the overall optimal value B[n,W]. An example demonstrates filling the table to solve an instance of the problem.
The document discusses greedy algorithms and how they work. It provides an example of using a greedy algorithm to solve the fractional knapsack problem in 3 steps: (1) sorting items by value to weight ratio, (2) initializing a selection array, (3) iteratively selecting highest ratio items that fit in the knapsack until full. While fast, greedy algorithms may not always find the optimal solution. The document also covers using Huffman coding to create efficient variable-length codes.
This document discusses inner product spaces and properties of the inner product. It provides examples of determining the inner product of vectors and applying properties like commutativity, distributivity, and associativity. It also defines length in Rn and discusses the Euclidean plane E2, defining distance between points as the absolute value of their difference. Students will learn to determine if a function defines an inner product, find inner products of vectors, and solve for distances in E2.
Dynamic programming can be used to solve optimization problems involving overlapping subproblems, such as finding the most valuable subset of items that fit in a knapsack. The knapsack problem is solved by considering all possible subsets incrementally, storing the optimal values in a table. Warshall's and Floyd's algorithms also use dynamic programming to find the transitive closure and shortest paths in graphs by iteratively building up the solution from smaller subsets. Optimal binary search trees can also be constructed using dynamic programming by considering optimal substructures.
This paper analyze few algorithms of the 0/1 Knapsack Problem and fractional
knapsack problem. This problem is a combinatorial optimization problem in which one has
to maximize the benefit of objects without exceeding capacity. As it is an NP-complete
problem, an exact solution for a large input is not possible. Hence, paper presents a
comparative study of the Greedy and dynamic methods. It also gives complexity of each
algorithm with respect to time and space requirements. Our experimental results show that
the most promising approaches are dynamic programming.
Dynamic Programming is a method for solving a complex problem by breaking it down into a collection of simpler subproblems, solving each of those subproblems just once, and storing their solutions using a memory-based data structure (array, map,etc).
The document discusses greedy algorithms and provides examples of how they can be applied to solve optimization problems like the knapsack problem. It defines greedy techniques as making locally optimal choices at each step to arrive at a global solution. Examples where greedy algorithms are used include finding the shortest path, minimum spanning tree (using Prim's and Kruskal's algorithms), job sequencing with deadlines, and the fractional knapsack problem. Pseudocode and examples are provided to demonstrate how greedy algorithms work for the knapsack problem and job sequencing problem.
The document describes the 0/1 knapsack problem and an algorithm to solve it using branch and bound. Specifically, it discusses:
- The knapsack problem involves finding the maximum value subset of items whose total weight is less than or equal to the knapsack capacity, given item values and weights.
- Branch and bound is used because greedy approaches do not work if weights are not fractional and brute force has exponential time complexity.
- The algorithm sorts items by value/weight ratio, initializes variables, and uses a queue to iteratively explore branches, pruning branches that cannot improve the best solution found so far.
This document discusses dynamic programming and provides examples of how it can be applied to optimize algorithms to solve problems with overlapping subproblems. It summarizes dynamic programming, provides examples for the Fibonacci numbers, binomial coefficients, and knapsack problems, and analyzes the time and space complexity of algorithms developed using dynamic programming approaches.
Dynamic programming is used to solve optimization problems by breaking them down into subproblems. It solves each subproblem only once, storing the results in a table to lookup when the subproblem recurs. This avoids recomputing solutions and reduces computation. The key is determining the optimal substructure of problems. It involves characterizing optimal solutions recursively, computing values in a bottom-up table, and tracing back the optimal solution. An example is the 0/1 knapsack problem to maximize profit fitting items in a knapsack of limited capacity.
Similar to Knapsack problem and Memory Function (20)
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DEEP LEARNING FOR SMART GRID INTRUSION DETECTION: A HYBRID CNN-LSTM-BASED MODEL
Knapsack problem and Memory Function
1. KNAPSACK PROBLEM AND MEMORY
FUNCTION
PREPARED BY
M. Baranitharan
Kings College of Engineering
2. Given some items, pack the knapsack to get
the maximum total value. Each item has some
weight and some value. Total weight that we can
carry is no more than some fixed number W.
So we must consider weights of items as well as
their values.
Item # Weight Value
1 1 8
2 3 6
3 5 5
3. There are two versions of the problem:
1. “0-1 knapsack problem”
Items are indivisible; you either take an item or not.
Some special instances can be solved with dynamic
programming
1. “Fractional knapsack problem”
Items are divisible: you can take any fraction of an
item
4. Given a knapsack with maximum capacity W, and
a set S consisting of n items
Each item i has some weight wi and benefit value
bi (all wi and W are integer values)
Problem: How to pack the knapsack to achieve
maximum total value of packed items?
5. Problem, in other words, is to find
∑∑ ∈∈
≤
Ti
i
Ti
i Wwb subject tomax
The problem is called a “0-1” problem,
because each item must be entirely
accepted or rejected.
6. Let’s first solve this problem with a
straightforward algorithm
Since there are n items, there are 2n
possible
combinations of items.
We go through all combinations and find the
one with maximum value and with total weight
less or equal to W
Running time will be O(2n
)
7. We can do better with an algorithm based on
dynamic programming
We need to carefully identify the subproblems
8. Given a knapsack with maximum capacity W, and
a set S consisting of n items
Each item i has some weight wi and benefit value
bi (all wi and W are integer values)
Problem: How to pack the knapsack to achieve
maximum total value of packed items?
9. We can do better with an algorithm based on
dynamic programming
We need to carefully identify the subproblems
Let’s try this:
If items are labeled 1..n, then a subproblem
would be to find an optimal solution for
Sk = {items labeled 1, 2, .. k}
10. If items are labeled 1..n, then a subproblem
would be to find an optimal solution for Sk =
{items labeled 1, 2, .. k}
This is a reasonable subproblem definition.
The question is: can we describe the final
solution (Sn ) in terms of subproblems (Sk)?
Unfortunately, we can’t do that.
11. Max weight: W = 20
For S4:
Total weight: 14
Maximum benefit: 20
w1 =2
b1 =3
w2 =4
b2 =5
w3 =5
b3 =8
w4 =3
b4 =4 wi bi
10
85
54
43
32
Weight Benefit
9
Item
#
4
3
2
1
5
S4
S5
w1 =2
b1 =3
w2 =4
b2 =5
w3 =5
b3 =8
w5 =9
b5 =10
For S5:
Total weight: 20
Maximum benefit: 26
Solution for S4 is
not part of the
solution for S !!!
?
12. As we have seen, the solution for S4 is not part of
the solution for S5
So our definition of a subproblem is flawed and we
need another one!
13. Given a knapsack with maximum capacity W, and
a set S consisting of n items
Each item i has some weight wi and benefit value
bi (all wi and W are integer values)
Problem: How to pack the knapsack to achieve
maximum total value of packed items?
14. Let’s add another parameter: w, which will
represent the maximum weight for each subset of
items
The subproblem then will be to compute V[k,w],
i.e., to find an optimal solution for Sk = {items
labeled 1, 2, .. k} in a knapsack of size w
15. The subproblem will then be to compute V[k,w],
i.e., to find an optimal solution for Sk = {items
labeled 1, 2, .. k} in a knapsack of size w
Assuming knowing V[i, j], where i=0,1, 2, … k-1,
j=0,1,2, …w, how to derive V[k,w]?
16. It means, that the best subset of Sk that has total
weight w is:
1) the best subset of Sk-1 that has total weight ≤ w, or
2) the best subset of Sk-1 that has total weight ≤ w-wk plus
the item k
+−−−
>−
=
else}],1[],,1[max{
if],1[
],[
kk
k
bwwkVwkV
wwwkV
wkV
Recursive formula for subproblems:
17. The best subset of Sk that has the total weight ≤ w,
either contains item k or not.
First case: wk>w. Item k can’t be part of the solution,
since if it was, the total weight would be > w, which is
unacceptable.
Second case: wk ≤ w. Then the item k can be in the
solution, and we choose the case with greater value.
+−−−
>−
=
else}],1[],,1[max{
if],1[
],[
kk
k
bwwkVwkV
wwwkV
wkV
18. for w = 0 to W
V[0,w] = 0
for i = 1 to n
V[i,0] = 0
for i = 1 to n
for w = 0 to W
if wi <= w // item i can be part of the solution
if bi + V[i-1,w-wi] > V[i-1,w]
V[i,w] = bi + V[i-1,w- wi]
else
V[i,w] = V[i-1,w]
else V[i,w] = V[i-1,w] // wi > w
19. for w = 0 to W
V[0,w] = 0
for i = 1 to n
V[i,0] = 0
for i = 1 to n
for w = 0 to W
< the rest of the code >
What is the running time of this
algorithm?
O(W)
O(W)
Repeat n times
O(n*W)
Remember that the brute-force algorithm
takes O(2n
)
20. Let’s run our algorithm on the
following data:
n = 4 (# of elements)
W = 5 (max weight)
Elements (weight, benefit):
(2,3), (3,4), (4,5), (5,6)
21. for w = 0 to W
V[0,w] = 0
0 0 0 0 000
1
2
3
4 50 1 2 3
4
iW
22. for i = 1 to n
V[i,0] = 0
0
0
0
0
0 0 0 0 000
1
2
3
4 50 1 2 3
4
iW
23. if wi <= w // item i can be part of the solution
if bi + V[i-1,w-wi] > V[i-1,w]
V[i,w] = bi + V[i-1,w- wi]
else
V[i,w] = V[i-1,w]
else V[i,w] = V[i-1,w] // wi > w
0
Items:
1: (2,3)
2: (3,4)
3: (4,5)
4: (5,6)
0
i=1
bi=3
wi=2
w=1
w-wi =-1
0 0 0 0 000
1
2
3
4 50 1 2 3
4
iW
0
0
0
24. Items:
1: (2,3)
2: (3,4)
3: (4,5)
4: (5,6)
300
0
0
0
0 0 0 0 000
1
2
3
4 50 1 2 3
4
iW
i=1
bi=3
wi=2
w=4
w-wi =2
if wi <= w // item i can be part of the solution
if bi + V[i-1,w-wi] > V[i-1,w]
V[i,w] = bi + V[i-1,w- wi]
else
V[i,w] = V[i-1,w]
else V[i,w] = V[i-1,w] // wi > w
3 3
25. Items:
1: (2,3)
2: (3,4)
3: (4,5)
4: (5,6)
300
0
0
0
0 0 0 0 000
1
2
3
4 50 1 2 3
4
iW
i=1
bi=3
wi=2
w=5
w-wi =3
if wi <= w // item i can be part of the solution
if bi + V[i-1,w-wi] > V[i-1,w]
V[i,w] = bi + V[i-1,w- wi]
else
V[i,w] = V[i-1,w]
else V[i,w] = V[i-1,w] // wi > w
3 3 3
26. Items:
1: (2,3)
2: (3,4)
3: (4,5)
4: (5,6)
00
0
0
0
0 0 0 0 000
1
2
3
4 50 1 2 3
4
iW
i=2
bi=4
wi=3
w=2
w-wi =-1
3 3 3 3
3
if wi <= w // item i can be part of the solution
if bi + V[i-1,w-wi] > V[i-1,w]
V[i,w] = bi + V[i-1,w- wi]
else
V[i,w] = V[i-1,w]
else V[i,w] = V[i-1,w] // wi > w
0
27. Items:
1: (2,3)
2: (3,4)
3: (4,5)
4: (5,6)
00
0
0
0
0 0 0 0 000
1
2
3
4 50 1 2 3
4
iW
i=2
bi=4
wi=3
w=3
w-wi =0
3 3 3 3
0
if wi <= w // item i can be part of the solution
if bi + V[i-1,w-wi] > V[i-1,w]
V[i,w] = bi + V[i-1,w- wi]
else
V[i,w] = V[i-1,w]
else V[i,w] = V[i-1,w] // wi > w
43
28. Items:
1: (2,3)
2: (3,4)
3: (4,5)
4: (5,6)
00
0
0
0
0 0 0 0 000
1
2
3
4 50 1 2 3
4
iW
i=3
bi=5
wi=4
w= 1..3
3 3 3 3
0 3 4 4
if wi <= w // item i can be part of the solution
if bi + V[i-1,w-wi] > V[i-1,w]
V[i,w] = bi + V[i-1,w- wi]
else
V[i,w] = V[i-1,w]
else V[i,w] = V[i-1,w] // wi > w
7
3 40
29. Items:
1: (2,3)
2: (3,4)
3: (4,5)
4: (5,6)
00
0
0
0
0 0 0 0 000
1
2
3
4 50 1 2 3
4
iW
i=4
bi=6
wi=5
w= 1..4
3 3 3 3
0 3 4 4
if wi <= w // item i can be part of the solution
if bi + V[i-1,w-wi] > V[i-1,w]
V[i,w] = bi + V[i-1,w- wi]
else
V[i,w] = V[i-1,w]
else V[i,w] = V[i-1,w] // wi > w
7
3 40
70 3 4 5
5
30. Items:
1: (2,3)
2: (3,4)
3: (4,5)
4: (5,6)
00
0
0
0
0 0 0 0 000
1
2
3
4 50 1 2 3
4
iW
i=4
bi=6
wi=5
w= 5
w- wi=0
3 3 3 3
0 3 4 4 7
0 3 4
if wi <= w // item i can be part of the solution
if bi + V[i-1,w-wi] > V[i-1,w]
V[i,w] = bi + V[i-1,w- wi]
else
V[i,w] = V[i-1,w]
else V[i,w] = V[i-1,w] // wi > w
5
7
7
0 3 4 5
31. This algorithm only finds the max possible value
that can be carried in the knapsack
◦ i.e., the value in V[n,W]
To know the items that make this maximum value,
an addition to this algorithm is necessary
32. All of the information we need is in the table.
V[n,W] is the maximal value of items that can be
placed in the Knapsack.
Let i=n and k=W
if V[i,k] ≠ V[i−1,k] then
mark the ith
item as in the knapsack
i = i−1, k = k-wi
else
i = i−1 // Assume the ith
item is not in the knapsack
// Could it be in the optimally packed
knapsack?
33. Goal:
◦ Solve only subproblems that are necessary and solve it only once
Memorization is another way to deal with overlapping subproblems
in dynamic programming
With memorization, we implement the algorithm recursively:
◦ If we encounter a new subproblem, we compute and store the solution.
◦ If we encounter a subproblem we have seen, we look up the answer
Most useful when the algorithm is easiest to implement recursively
◦ Especially if we do not need solutions to all subproblems.
34. for i = 1 to n
for w = 1 to W
V[i,w] = -1
for w = 0 to W
V[0,w] = 0
for i = 1 to n
V[i,0] = 0
MFKnapsack(i, w)
if V[i,w] < 0
if w < wi
value = MFKnapsack(i-1, w)
else
value = max(MFKnapsack(i-1, w),
bi + MFKnapsack(i-1, w-wi))
V[i,w] = value
return V[i,w]
35. Dynamic programming is a useful technique of
solving certain kind of problems
When the solution can be recursively described
in terms of partial solutions, we can store these
partial solutions and re-use them as necessary
(memorization)
Running time of dynamic programming
algorithm vs. naïve algorithm:
◦ 0-1 Knapsack problem: O(W*n) vs. O(2n
)