Today:
             News & Notes
                Warm-Up
     Review: Graphing Inequalities
    Khan Academy Practice Questions
Introduce: parallel & Perpendicular Lines
News & Notes:
  1. very nice work on Khan Academy this past week and weekend. I
  am sincerely impressed.
     Day:          total minutes:      hours:

   Thursday                         829              13.82
   Friday                 1158                    19.30
   Saturday                         1154                 19.22
   3-day totals:          3141                    52.35

2. Test this week (thurs. or Fri.) on graphing inequalities, parallel and
perpendicular lines. what you do, (or don't do) everyday affects your
grade. Be responsible, you'll feel good, really.
Warm-Up:
1.




2. From the table, determine the function, fill in the missing values,
and write the equation solving for y (y = )
Warm-Up:
3. From the table, determine the function, fill in the missing values,
and write the equation solving for y (y = )



                     4.



  4.   (7x + 2) - (3x - 5)              5.    (3x + 2) (5x + 4)

            6.
Warm-Up:
  7.   Find the GCF:    6a²c² + 2ac² + 10ab²c3
  8. Simplify:


9.

                                          a. What's wrong
                                          with this picture?
10.

                                          b. 40 ounces cost $5.20.
                                          What's the unit price?
Khan Academy Practice
Khan Academy Practice
Khan Academy Practice
Khan Academy Practice
Parallel & Perpendicular Lines

          Two lines
             are
           parallel



Slopes
                      The lines
 are
                        never
equal
                      intersect
Parallel & Perpendicular Lines
        parallel lines have the same slopes so find
        the slope of the given line and the slope you
        want for a parallel line will be the same.




        Perpendicular lines have negative reciprocal
        slopes. take the slope of the given line, switch
        the numerator and denominator and change
        the sign for the slope of its perpendicular line.
Parallel & Perpendicular Lines
                          Let's find the equation of a line parallel to
                          y = - x that passes through the point (2, 4)
y=-x
                                   What is the slope of the first line,
                          (2, 4)   y=- x?              1
                                        This is in slope intercept form so y
                                        = mx + b which means the slope is
use the point-slope                     1.
formula to find
the equation of the
line



y -y1= -(x - x1)      y -4 = -(x - 2)         y = -x + 6
Parallel & Perpendicular Lines
                        Let's find the equation of a line
                        perpendicular to y = - x that passes thru
y=-x                    the point (2, 4)
                                   The slope of the first line is
                       (2, 4)      still –1.

                                The slope of a line perpendicular
                                is the negative reciporical so
                                take –1 and "flip" it over and
                                make it negative.
                                           1              1

                                          1                1

So the slope of a perpendicular line is 1 and it passes
through (2, 4).
Parallel & Perpendicular Lines
Parallel & Perpendicular Lines
Class Work:
January 14

January 14

  • 1.
    Today: News & Notes Warm-Up Review: Graphing Inequalities Khan Academy Practice Questions Introduce: parallel & Perpendicular Lines
  • 2.
    News & Notes: 1. very nice work on Khan Academy this past week and weekend. I am sincerely impressed. Day: total minutes: hours: Thursday 829 13.82 Friday 1158 19.30 Saturday 1154 19.22 3-day totals: 3141 52.35 2. Test this week (thurs. or Fri.) on graphing inequalities, parallel and perpendicular lines. what you do, (or don't do) everyday affects your grade. Be responsible, you'll feel good, really.
  • 3.
    Warm-Up: 1. 2. From thetable, determine the function, fill in the missing values, and write the equation solving for y (y = )
  • 4.
    Warm-Up: 3. From thetable, determine the function, fill in the missing values, and write the equation solving for y (y = ) 4. 4. (7x + 2) - (3x - 5) 5. (3x + 2) (5x + 4) 6.
  • 5.
    Warm-Up: 7. Find the GCF: 6a²c² + 2ac² + 10ab²c3 8. Simplify: 9. a. What's wrong with this picture? 10. b. 40 ounces cost $5.20. What's the unit price?
  • 6.
  • 7.
  • 8.
  • 9.
  • 10.
    Parallel & PerpendicularLines Two lines are parallel Slopes The lines are never equal intersect
  • 11.
    Parallel & PerpendicularLines parallel lines have the same slopes so find the slope of the given line and the slope you want for a parallel line will be the same. Perpendicular lines have negative reciprocal slopes. take the slope of the given line, switch the numerator and denominator and change the sign for the slope of its perpendicular line.
  • 12.
    Parallel & PerpendicularLines Let's find the equation of a line parallel to y = - x that passes through the point (2, 4) y=-x What is the slope of the first line, (2, 4) y=- x? 1 This is in slope intercept form so y = mx + b which means the slope is use the point-slope 1. formula to find the equation of the line y -y1= -(x - x1) y -4 = -(x - 2) y = -x + 6
  • 13.
    Parallel & PerpendicularLines Let's find the equation of a line perpendicular to y = - x that passes thru y=-x the point (2, 4) The slope of the first line is (2, 4) still –1. The slope of a line perpendicular is the negative reciporical so take –1 and "flip" it over and make it negative. 1 1 1 1 So the slope of a perpendicular line is 1 and it passes through (2, 4).
  • 14.
  • 15.
  • 16.